ws calculation
DESCRIPTION
WS CalculationTRANSCRIPT
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed Data * You are allowed to change
Calculated dataNo. of Rooms = 1No. of persons per room = 1Building Lowest level (m) = 0Building Highest level (m) = 10Total No. of persons = 1
* You are NOT ALLOWED to change
Project : XXX DateLocation : Jeddah Designed
Assumed DataCalculated data
Table of total fixtures
Fixture type private
FIXTURES / POINT NO. B3 B2 B1 G.F. F.F
Water closet (flush valve)
Water closet (flush tank)
Water Bidet
Hose for W.C
Lavatory (& H.B.)
Janitor Sink
Service sink
Shower
Bath tub
Kitchen sink
Dishwashing machine
Laundry
Ablution (Public)
Urinal (1" flush valve)
Urinal (3/4" flush valve)
Urinal (flush tank)
: August 31, 2009: SAK-EC
* You are allowed to change
2nd.F 3rd F 4th F. 5th F 6th F 7th F 8th F 9th F 10th F
* You are NOT ALLOWED to change
11th F 12th F 13th F 14th F
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
Total fixtures
Project : XXX DateLocation : Jeddah Designed
Assumed DataCalculated data
Table of total fixtures
Fixture type private
FIXTURES / POINT NO. B3 B2 B1 G.F. F.F
Water closet (flush valve) 0 0 0 0 0
Water closet (flush tank) 0 0 0 0 0
Water Bidet 0 0 0 0 0
Hose for W.C 0 0 0 0 0
Lavatory (& H.B.) 0 0 0 0 0
Janitor Sink 0 0 0 0 0
Service sink 0 0 0 0 0
Shower 0 0 0 0 0
Bath tub 0 0 0 0 0
Kitchen sink 0 0 0 0 0
Dishwashing machine 0 0 0 0 0
Laundry 0 0 0 0 0
Ablution (Public) 0 0 0 0 0
Urinal (1" flush valve) 0 0 0 0 0
Urinal (3/4" flush valve) 0 0 0 0 0
Urinal (flush tank) 0 0 0 0 0
TOTAL DOMESTIC WATER DEMAND CALCULATION Fixtures type : private
FIXTURESWeight in Fixture units
QuantityCold Hot Total
Water closet (flush valve) 6 0 6 0
Water closet (flush tank) 3 0 3 0
Water Bidet 0.75 0.75 1 0
Hose for W.C 0.75 0.75 1 0
Lavatory (& H.B.) 0.75 0.75 1 0
Janitor Sink 0.75 0.75 1 0
Service sink 1.5 1.5 2 0
Shower 1.5 1.5 2 0
Bath tub 1.5 1.5 2 0
Kitchen sink 1.5 1.5 2 0
Dishwashing machine 0 1 1 0
Laundry 1.5 1.5 2 0
Ablution (Public) 1 1 1.5 0
Urinal (1" flush valve) 10 0 10 0
Urinal (3/4" flush valve) 5 0 5 0
Urinal (flush tank) 3 0 3 0
Total Fixture Units
WATER DEMAND ( GPM )
flush tank valve0 0.0 0.0
0 0.0 0
0 0.0 0
0 0 06 5 278 6.5 27
10 8 2712 9.2 28.614 10.4 30.216 11.6 31.818 12.8 33.420 14 3525 17 3830 20 4135 22.5 43.840 24.8 46.545 27 4950 29 51.560 32 5570 35 58.580 38 6290 41 64.8
100 43.5 67.5120 48 72.5140 52.5 77.5160 57 82.5180 61 87200 65 91.5225 70 97250 75 101275 80 105.5300 85 110400 105 126500 125 142750 170 178
1000 208 2081250 240 2401500 267 2671750 294 2942000 321 3212250 348 3482500 375 3752750 402 402
WATER DEMAND ( m3/ h )
3000 432 4324000 525 5255000 593 5936000 643 6437000 685 6858000 718 7189000 745 745
10000 769 769
Public Private
Cold Hot Total Cold Hot
Water closet (flush valve) 10 0 10 6
Water closet (flush tank) 5 5 3
Water Bidet 1.5 1.5 2 0.75 0.75
Hose for W.C 1.5 1.5 2 0.75 0.75
Lavatory (& H.B.) 1.5 1.5 2 0.75 0.75
Janitor Sink 1.5 1.5 2 0.75 0.75
Service sink 2.25 2.25 3 1.5 1.5
Shower 3 3 4 1.5 1.5
Bath tub 3 3 4 1.5 1.5
Kitchen sink 3 3 4 1.5 1.5
Dishwashing machine 1 1 1
Laundry 3 3 4 1.5 1.5
Ablution (Public) 1 1 1.5 1 1
Urinal (1" flush valve) 10 10 10
Urinal (3/4" flush valve) 5 5 5
Urinal (flush tank) 3 3 3
: August 31, 2009: SAK-EC
* You are allowed to change
2nd.F 3rd F 4th F. 5th F 6th F 7th F 8th F 9th F 10th F
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
Total weight in fixture units
Cold Hot Total
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
* You are NOT ALLOWED to change
0.0 GPM 0.0 GPM 0.0 GPM0.00 m3/h 0.00 m3/h 0.00 m3/h
Private
Total
6
3
1
1
1
1
2
2
2
2
1
2
1.5
10
5
3
11th F 12th F 13th F 14th F
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
Total fixtures
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed Data * You are allowed to changeCalculated data
Given Data:Number of persons = 1
Design Basis of Water Supply SystemWater Supply Demand:
Water Consumption(L/person/day) = 400Water demand per day(m3/ day) = 1
Main Water Feeder :
Flow rate required ; Q(m3/ sec) = 0.000
Under Ground Water Tank :
Duration Assumption (day) = 2Storage Fire Fighting Demand (m3) = 150
Storage water supply Demand (m3) = 3Total Storage Demand (m3) = 153
Tank depth (m) = 3 * Could be changed according to Arch. RequirementTank Length (m) = 10 * Could be changed according to Arch. RequirementTank Width (m) = 6Actual Area of Tank (m2) = 51Tank depth (m) = 3Tank Length (m) = 10Tank Width (m) = 6
Upper Roof Water Tank :
* You are NOT ALLOWED to change
Duration Assumption (day) = 0.5Tank Storage Required (m3) = 1
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed Data * You are allowed to change
Calculated dataQ (m3/day) = 1Pump working hours = 12Then
Lifting Pump Calculations
Pump Discharge
Q (GPM) = 1
Pump Head
Static Head Hs (m) = 11Losses = 5.55
Pump Head (m) = 19
Time Required to Fill Upper Roof Tank
T (Hr) = 4.64
Power
Pump Efficiency = 0.8Power (Hp) = 1
Booster Pump Calculations
Pump Discharge
Q (L/s) = 0Pump Head (m) = 11
Power
Pump Efficiency = 0.8Power (Hp) = 0
* You are NOT ALLOWED to change
Project : XXX Date : August 31, 2009Location : Jeddah Designe : SAK-EC
Assumed Data * You are allowed to changeCalculated data
Head loss calculation using ( 1 ) COLBROOK Formula For DOMESTIC WATER BOOSTER
K P
ipe
roug
hnes
s
Local factors of fittings
F L
iner
loss
fact
or
Loss
m
per
100
m
dh(1
) Li
ner l
oss
dh(2
) Lo
cal l
oss
DH
Tot
al lo
ss
Tota
l hea
d (D
H+G
H) /
pip
e
Acc
umul
ativ
e P
ress
ure
gate
val
ve
Mul
timed
ia fi
lter
Foot
val
ve
chec
k va
lve
elbo
w (
45 le
g.)
elbo
w (
90 le
g.)
tee
redu
cer
Stra
iner
disc
harg
e ou
tlet
Tota
l loc
al fa
ctor
s
no. DN mm m mm GPM l/s 0.2
1.0
1.0
2.0
0.3
0.3
0.9
0.5
2.0
1.0 1/1 m m/s 1/1 1/1 m m m m m m
PUMP TO A 63 PVC 53.6 10 0.01 42 2.646 1 1 1 1 1 1 1 7.4 5 1.17266 62854.325 0.0206 2.69 0.3 0.519 0.79 5.79 5.788
A TO B 50 PVC 42.6 2.5 0.01 40 2.52 1 0.9 0 1.76804 75318.396 0.02011 7.52 0.2 0.143 0.33 0.33 6.119
B TO C 50 PVC 42.6 25 0.01 28 1.764 2 4 1 2.5 5 1.23763 52722.877 0.02148 3.94 1 0.195 1.18 6.18 12.3
C TO D 40 PVC 34 15 0.01 19 1.197 1 1 1 1 1.9 0 1.3184 44825.522 0.02236 5.83 0.9 0.168 1.04 1.04 7.161
D TO E 25 PVC 21.2 15 0.01 6 0.378 1 1 1 1 1.9 0 1.07085 22702.101 0.02614 7.21 1.1 0.111 1.19 1.19 8.353
E TO F 20 PVC 17 5 0.01 5 0.315 1 1 1 1 2.7 0 1.38779 23592.38 0.02619 15.1 0.8 0.265 1.02 1.02 9.374
TOTAL 73 5 1 1 1 1 7 6 3 1 1 17.3 10 7.95536 282015.6 0.13686 42.3 4 1 6 15.55
###
Static head = 10.00 m ###
Outlet pressure 35 PSI = 5.00 m ###
total friction loss = 5.55 m ###
total dynamic head = 20.55 m ###
Add 10 % safety 0.00 = 22.61 m ###
* You are NOT ALLOWED to change
no.
part
of p
ipe
DN
Nom
inal
dia
met
er
ID P
ipe
Inne
r dia
met
er
L P
ipe
leng
th
Q F
low
rate
GH
Sta
tic h
ead
V M
ean
Vel
ocity
RE
Rey
nold
s nu
mbe
r
Head Loss Calculations:
The total friction loss Hs Consist of:
Hs = Hs1 + Hs2 …………………………………………………….…… (1)
Where: Hs1 : Friction loss Inside pipesHs2 : Friction loss inside fittings
Linear friction loss equation:
Hs = J . L …………………………………… ……………………………………... .... (2)
Where: J : linear loss factorL : length Of the pipe (m.)
: friction loss factor (COLBROOK-WHITE formula)V : velocity of water (m/s)g : gravity acceleration (9.81 m/s²)D : pipe inside diameter (m.)
COLBROOK WHITE formula:……………………………………………………………….. ( 4 )
1 = - 2 x log [
k+
2.51)
3.7 x D
Where: K : pipe inside Surface roughness (m.)D : pipe inside diameter (m.)
RE : REYNOLD’S no. is given as follows: (1/1)
Where: n 1E-06V : velocity of water (m/s)D : pipe inside diameter (m.)
V = Q / A ………………………………………...………………………………………. ( 6 )
Where: Q : flow rate (m³/s)A : cross section are of the pipe (m²)
J = l . V² / ( 2 g D ) ………..…………………………………………………………….. (3)
l
sqr(l) Re x sqr( l )
RE = V x D / n …………………………………………………………………………. ( 5 )
: water viscosity= ( n = m2/s)
Data for the First pipe : 300 PVC Pipe type & size 300315 mm Out side diameter (mm)23.8 mm Wall thickness (mm)
D = 0.2674 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 400.0 GPM = 25.2 l/s = 0.0252 m³/sec
A = 3.14 x 0.267 ² / 4 = 0.05616 m²
V = Q / A = 0.449 m/s
0.449 x 0.2674 / 0.000001 = 119991.16
1 = - 2 log [
0.00001+
2.51 ]
3.7 x 0.267 119991.2
By solving above equation :
0.01754
0.01754 x 0.4487 x 0.449= 0.00067 m/m
2 x 9.81 x 0.2674
Loss m per 100 m = J x 100 = 0.00067 x 100 m = 0.067 m / 100m
Pipe length L = 10.0 m
dh(1) Liner loss = J x L = 0.00067 x 10.0 = 0.007 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G ) …..…………………………………………………….. (7)
Where: G : Gravity acceleration (9.81 m/s²)V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors
SUM ZE = gate valve 3 x 0.2 = 0.6Multimedia filter 1 x 1 = 1Foot valve 1 x 1 = 1check valve 1 x 2 = 2elbow ( 45 leg.) 1 x 0.3 = 0.3elbow ( 90 leg.) 0 x 0.3 = 0tee 0 x 0.9 = 0reducer 0 x 0.5 = 0
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
Strainer 1 x 2 = 2discharge outlet 0 x 1 = 0Total local factors = 6.90
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 6.9 x 0.4487 X 0.4487
= 0.0708 m 2 x 9.81
DH Total loss = HS1 + HS2 = 0.007 + 0.071 = 0.078 m
Total head (DH+GH) / pipe = Static head + Friction losses ………………………. ( 8 )
= 10.0 + 0.078 = 10.078 m
Data for the Second pipe : 300 PVC Pipe type & size =f_loss!B11315 mm Out side diameter (mm)23.8 mm Wall thickness (mm)
D = 0.2674 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 400.0 GPM = 25.2 l/s = 0.0252 m³/sec
A = 3.14 x 0.267 ² / 4 = 0.05616 m²
V = Q / A = 0.177 m/s
.177 x 0.2674 / 0.000001 = 37694.59
1 = - 2 log [
0.00001+
2.51 ]
3.7 x 0.267 37694.6
By solving above equation : 0.02241
0.02241 x 0.1771 x 0.177= 0.00017 m/m
2 x 9.81 x 0.2674
Loss m per 100 m = J x 100 = 0.00017 x 100 m = 0.017 m / 100m
Pipe length L = 83.0 m
dh(1) Liner loss = J x L = 0.00067 x 83.0 = 0.056 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G )
SUM ZE = gate valve 0 x 0.2 = 0Multimedia filter 0 x 1 = 0Foot valve 0 x 1 = 0check valve 0 x 2 = 0elbow ( 45 leg.) 0 x 0.3 = 0elbow ( 90 leg.) 0 x 0.3 = 0tee 1 x 0.9 = 0.9reducer 0 x 0.5 = 0Strainer 0 x 2 = 0discharge outlet 0 x 1 = 0Total local factors = 0.90
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 0.9 x 0.1771 X 0.1771
= 0.0018 m
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
HS(2) = SUM ZE.x V² / ( 2 g ) = 0.9 x 2 x 9.81
= 0.0018 m
DH Total loss = HS1 + HS2 = 0.056 + 0.009 = 0.065 m
Total head (DH+GH) / pipe = Static head + Friction losses
= 0.0 + 0.035 = 0.035 m
Data for the Third pipe : 350 PVC Pipe type & size355 mm Out side diameter (mm)26.3 mm Wall thickness (mm)
D = 0.3024 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 350.0 GPM = 22.05 l/s = 0.02205 m³/sec
A = 3.14 x 0.302 ² / 4 = 0.07182 m²
V = Q / A = 0.307 m/s
.307 x 0.3024 / 0.3 = 92840.38
1 = - 2 log [ 0.00001 + 2.51 ]3.7 x 0.302 47129.3
By solving above equation : 0.01844
0.01844 x 0.307 x 0.307 = 0.0 m/m 2 x 9.81 x 0.3024
Loss m per 100 m = J x 100 = 0.00029 x 100 m = 0.029 m / 100m
Pipe length L = 879.0 m
dh(1) Liner loss = J x L = 0.00029 x 879.0 = 0.257 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G )
SUM ZE = gate valve 0 x 0.2 = 0Multimedia filter 0 x 1 = 0Foot valve 0 x 1 = 0check valve 0 x 2 = 0elbow ( 45 leg.) 0 x 0.3 = 0elbow ( 90 leg.) 8 x 0.3 = 2.4tee 0 x 0.9 = 0reducer 1 x 0.5 = 0.5Strainer 0 x 2 = 0discharge outlet 0 x 1 = 0
0 = 2.90
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 2.9 x 0.307 X 0.307 = 0.0 m 2 x 9.81
= HS1 + HS2 = 0.257 + 0.014 = 0.271 m
= Static head + Friction losses
= 0.0 + 0.271 = 0.271 m
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
Data for the Fourth pipe : 250 PVC Pipe type & size 250250 mm Out side diameter (mm)18.6 mm Wall thickness (mm)
D = 0.2128 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 100.0 GPM = 06.3 l/s = 0.0063 m³/sec
A = 3.14 x 0.213 ² / 4 = 0.03556 m²
V = Q / A = 0.177 m/s
.177 x 0.2128 / = 92840.38
1 = - 2 log [
0.00001+
2.51 ]
3.7 x 0.213 0.0
By solving above equation :
0.02241
0.02241 x 0.1771 x 0.177= 0.0 m/m
2 x 9.81 x 0.2128
Loss m per 100 m = J x 100 = 0.00017 x 100 m = 0.017 m / 100m
Pipe length L = 195.0 m
dh(1) Liner loss = J x L = 0.00017 x 195.0 = 0.033 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G ) …..…………………………………………………….. (7)
Where: G : Gravity acceleration (9.81 m/s²)V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors
SUM ZE = gate valve 0 x 0.2 = 0Multimedia filter 0 x 1 = 0Foot valve 0 x 1 = 0check valve 0 x 2 = 0elbow ( 45 leg.) 0 x 0.3 = 0elbow ( 90 leg.) 2 x 0.3 = 0.6tee 0 x 0.9 = 0reducer 1 x 0.5 = 0.5
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
Strainer 0 x 2 = 0discharge outlet 0 x 1 = 0Total local factors = 1.10
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 1.1 x 0.1771 X 0.1771
= 0.0018 m 2 x 9.81
= HS1 + HS2 = 0.033 + 0.002 = 0.035 m
= Static head + Friction losses ………………………. ( 8 )
= 0.0 + 0.035 = 0.035 m
Data for the Fifth pipe : 200 PVC Pipe type & size 200200 mm Out side diameter (mm)14.9 mm Wall thickness (mm)
D = 0.1702 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 100.0 GPM = 06.3 l/s = 0.0063 m³/sec
A = 3.14 x 0.17 ² / 4 = 0.02275 m²
V = Q / A = 0.277 m/s
0.277 x 0.1702 / = 47129.31
1 = - 2 log [
0.00001+
2.51 ]
3.7 x 0.17 47129.3
By solving above equation :
0.02137
0.02137 x 0.2769 x 0.277= 0.00049 m/m
2 x 9.81 x 0.1702
Loss m per 100 m = J x 100 = 0.00049 x 100 m = 0.049 m / 100m
Pipe length L = 322.0 m
dh(1) Liner loss = J x L = 0.00049 x 322.0 = 0.158 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G ) …..…………………………………………………….. (7)
Where: G : Gravity acceleration (9.81 m/s²)V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors
SUM ZE = gate valve 0 x 0.2 = 0Multimedia filter 0 x 1 = 0Foot valve 0 x 1 = 0check valve 0 x 2 = 0elbow ( 45 leg.) 0 x 0.3 = 0elbow ( 90 leg.) 3 x 0.3 = 0.9tee 0 x 0.9 = 0reducer 1 x 0.5 = 0.5
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
Strainer 1 x 2 = 2discharge outlet 0 x 1 = 0Total local factors = 3.40
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 3.4 x 0.2769 X 0.2769
= 0.0133 m 2 x 9.81
= HS1 + HS2 = 0.158 + 0.013 = 0.171 m
= Static head + Friction losses ………………………. ( 8 )
= 0.0 + 0.171 = 0.171 m
Data for the Sexth pipe : 150 PVC Pipe type & size 150160 mm Out side diameter (mm)11.9 mm Wall thickness (mm)
D = 0.1362 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 50.0 GPM = 03.15 l/s = 0.00315 m³/sec
A = 3.14 x 0.136 ² / 4 = 0.01457 m²
V = Q / A = 0.216 m/s
0.216 x 0.1362 / = 29447.17
1 = - 2 log [ 0.00001 + 2.51 ]3.7 x 0.136 0.0
By solving above equation :
0.02377
0.02377 x 0.2162 x 0.216 = 0.0 m/m 2 x 9.81 x 0.1362
Loss m per 100 m = J x 100 = 0.00042 x 100 m = 0.042 m / 100m
Pipe length L = 47.0 m
dh(1) Liner loss = J x L = 0.00042 x 47.0 = 0.02 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G ) …..…………………………………………………….. (7)
Where: G : Gravity acceleration (9.81 m/s²)V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors
SUM ZE = 0 0 x 0.2 = 00 0 x 1 = 00 0 x 1 = 00 0 x 2 = 00 0 x 0.3 = 00 2 x 0.3 = 0.60 0 x 0.9 = 00 1 x 0.5 = 0.50 0 x 2 = 00 0 x 1 = 00 = 1.10
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 1.1 x 0.2162 X 0.2162 = 0.0026 m 2 x 9.81
= HS1 + HS2 = 0.02 + 0.003 = 0.022 m
= Static head + Friction losses ………………………. ( 8 )
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
= 0.0 + 0.022 = 0.022 m
Data for the Seventh pipe : 63 PVC Pipe type & size 6363 mm Out side diameter (mm)
4.7 mm Wall thickness (mm)
D = 0.0536 m : pipe inside diameter (m.)K = 0.00001 m : pipe inside Surface roughness (m.)
Flow : Q = 50.0 GPM = 03.15 l/s = 0.00315 m³/sec
A = 3.14 x 0.054 ² / 4 = 0.00226 m²
V = Q / A = 1.396 m/s
1.396 x 0.0536 / = 74826.58
1 = - 2 log [ 0.00001 + 2.51 ]3.7 x 0.054 0.0
By solving above equation :
0.01993
0.01993 x 1.396 x 1.396 = 0.0 m/m 2 x 9.81 x 0.0536
Loss m per 100 m = J x 100 = 0.03694 x 100 m = 3.694 m / 100m
Pipe length L = 32.0 m
dh(1) Liner loss = J x L = 0.03694 x 32.0 = 1.182 m
Local losses equation is given as follows:
HS2 = SUM ZE . V ² / ( 2 . G ) …..…………………………………………………….. (7)
Where: G : Gravity acceleration (9.81 m/s²)V : Velocity of water (m/s)
SUM ZE : Sum of local loss factors
SUM ZE = 0 0 x 0.2 = 00 0 x 1 = 00 0 x 1 = 00 0 x 2 = 00 0 x 0.3 = 00 1 x 0.3 = 0.30 0 x 0.9 = 00 1 x 0.5 = 0.50 0 x 2 = 00 1 x 1 = 10 = 1.80
HS2 = SUM ZE . V ² / ( 2 . g )
HS(2) = SUM ZE.x V² / ( 2 g ) = 1.8 x 1.396 X 1.396 = 0.1788 m 2 x 9.81
= HS1 + HS2 = 1.182 + 0.179 = 1.361 m
= Static head + Friction losses ………………………. ( 8 )
p x D2 / 4 =
Re = V x D / n =
sqr(l) x sqr( l )
l =
J = l . V² / ( 2 g D ) =
= 30.0 + 1.361 = 31.361 m
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed * You are allowed to change
Calculated
Given Data:Number of persons = 1
Boiler Design
Water Consumption(L/person/day) = 400Hot Water Consumption (L) = 120Hot Water demand per day(m3/ day) = 1Average Demand per Hour (m3/h) = 1Peak Duration (h) = 3Volume of Heated Water (m3) = 3Cold Water Tank Volume % = 25%Tank Volume (m3) = 4
Tank Diameter (m) = 2Tank Length (m) = 2
* You are NOT ALLOWED to change
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed * You are allowed to change
Calculated
Design of Circulating Pump
Q (m3/h) = 1Q (l/s) = 1Head (m) = 11Pump Efficiency = 0.8Power (Hp) = 1
* You are NOT ALLOWED to change
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed * You are allowed to change
Calculated
Drain Sump
Sewer DrainageNo. of Drainage Fixtures = 0Fixtures Flow Rate (L / min) = 0
Parking Area Drainage Car Demand (L / car / day) = 30No. of cars = 20Parking Drainage (L / min) = 1
Laundry DrainageLaundry Demand (L / bed / day) = 130No. of beds = 1Laundry Drainage (L / min) = 1
Kitchen DrainageKitchen Demand (L / person / day) = 160No. of persons = 1Kitchen Drainage (L / min) = 1
Total Drainage Flow (L / min) = 3
Duration Time of Empting Sump (min) = 10
Sump Capacity (m3) = 0
Sump Depth (m) = 1.5Water Surface Area (m2) = 1
Pump occupancy of Sump Area = 40%Water occupancy of Sump Area = 60%Sump Surface Area (m2) = 2
Sump DimensionSump depth (m) = 2Sump Length (m) = 2Sump Width (m) = 2
* You are NOT ALLOWED to change
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed * You are allowed to change
Calculated
Design of submersible PumpSump Capacity (m3) = 8Sump Empting Time (min) = 10
Q (L/S) = 14Q (m3/s) = 0.014Main Pipe Velocity (m/s) = 1Main Pipe Diameter (mm) = 140 * Take the larger Standard Size
Pump Head
Static Head Hs (m) = 6 *From Sump Bottom Level to Septic TankAssume Losses (m) = 0.1 of static HeadLosses = 0.6
Pump Head (m) = 8
Power
Pump Efficiency = 0.8Power (Hp) = 2
* You are NOT ALLOWED to change
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed D* You are allowed to change
Calculated
Design of Reaction Tank
Q (m3/day) = 1Q Sewer (m3/day) = 1Sewerage Flow to Be Treated (m3/day) = 1
Assume
Reaction Tank Dimension Length (m) = 3Width (m) = 3Depth (m) = 3Water DimensionsLength (m) = 3Width (m) = 3Depth (m) = 2.5
Reaction Tank Capacity (m3) = 22.5
Times to Fill Tank (time/day) = 1
Filter Design
Filtration Rate (m3/m2/h) = 22.5Qpump (m3/h) = 4Filter Area (m2) = 5.63
* You are NOT ALLOWED to change
Filter Diameter (m) = 2.68
Project : XXX Date : August 31, 2009Location : Jeddah Designed : SAK-EC
Assumed * You are allowed to change
Calculated
Filtration Pump
Capacity (m3) = 23Pump working hours = 12Working time (h) = 12.0Qpump (L/S) = 1Pump Head (m) = 11Pump Efficiency = 0.8Power (Hp) = 1
* You are NOT ALLOWED to change