+... · web viewcin>> p[i].price;} printprod (p, i);} philadelphia university . faculty of...

Chapter 01

ArraysPrepared By:

Dr. Murad Magableh

2013

One Dimensional

Q1: Write a program that declares two arrays of integers and fills them from the user. Then exchanges their values and display the resulted two arrays.

Solution:

#include<iostream>using namespace std;

void main(){

int arr1[10], arr2[10];cout << "Enter the first array values\n";for (int i=0; i<10; i++)

cin >> arr1[i];cout << "Enter the second array values\n";

for (int i=0; i<10; i++) cin >> arr2[i];

int temp; for (int i=0; i<10; i++) { temp = arr1[i]; arr1[i] = arr2[i]; arr2[i] = temp; }

cout << "The first array values now are:\n"; for (int i=0; i<10; i++) cout << arr1[i] << " ";

cout << endl;

cout << "The second array values now are:\n"; for (int i=0; i<10; i++) cout << arr2[i] << " ";

cout << endl;}

2 | P a g e

Q2: Write a program that takes 10 integers as input and prints the largest integer and its location in the array.

Solution:


void main(){

int arr[10]; cout << "Enter the array values\n"; for (int i=0; i<10; i++) cin >> arr[i];

int max = arr[0], loc = 0, i;

for (i=1; i<10; i++) { if (arr[i] > max) { max = arr[i]; loc = i; }

}

cout << "The maximum value is: " << max << " and it is in location " << loc << endl;

}

3 | P a g e

Q3: Write a program that defines a one dimensional array of integers of size 10 and fill it from the user. Then find the negative values and store them in another array and display new array.

Solution:


void main(){

int arr[10];cout << "Enter the array values\n";for (int i=0; i<10; i++)

cin >> arr[i];

int new_arr[10], index = 0;for (int i=0; i<10; i++)

if (arr[i] < 0)new_arr[index++] = arr[i];

cout << "The new array values are:\n";for (int i=0; i<index; i++)

cout << new_arr[i] << " ";cout << endl;

}

4 | P a g e

Q4: Write a program that defines a one dimensional array of integers of size 11 and fill the first 10 values from the user. Then calculate the summation of the 10 values and store it in the 11th location.

Solution:


void main(){

int arr[11];arr[10] = 0;cout << "Enter the array values\n";for (int i=0; i<10; i++){

cin >> arr[i];arr[10] += arr[i];

}

cout << "The new array values are:\n";for (int i=0; i<11; i++)

cout << arr[i] << " ";cout << endl;

}

5 | P a g e

Q5: Write a C++ program that reverses the order of a one-dimensional array of size 10 without using another array.

Solution:


void main(){

int x, j=9, a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

for(int i=0; i<(10/2); i++){x = a[i];a[i] = a[j];a[j] = x;j--;

}

for(int i=0; i<10; i++)cout << a[i] << " ";

cout << endl;}

6 | P a g e

Q6: Write a C++ program that declares two arrays of size 5. Read the first array from the user and store the factorial of each element in this array in its corresponding location in the second array.

Solution:


void main(){

double a[5], b[5];int fact;cout << "Enter the first array values\n";for(int i=0; i<5; i++){

cin >> a[i];fact = 1;for(int j=1; j<=a[i]; j++)

fact *= j;b[i] = fact;

}

cout << "The factorials array values are:\n";for (int i=0; i<5; i++)

cout << b[i] << " ";cout << endl;

}

7 | P a g e

Two Dimensional

Q7: Write a program that adds up two [4x4] arrays and stores the sum in a third array.

Solution:


void main(){

int a[4][4], b[4][4];cout << "Enter the first array values\n";for(int i=0; i<4; i++)

for(int j=0; j<4; j++)cin >> a[i][j];

cout << "Enter the second array values\n";for(int i=0; i<4; i++)

for(int j=0; j<4; j++)cin >> b[i][j];

int c[4][4];for(int i=0; i<4; i++)

for(int j=0; j<4; j++)c[i][j] = a[i][j] + b[i][j];

cout << "The array values are:\n";for(int i=0; i<4; i++){

for(int j=0; j<4; j++)cout << c[i][j] << " ";

cout << endl;}cout << endl;

}

8 | P a g e

Q8: Write a C++ program that declares a two dimensional array of size [4x4] and generates the values of its elements using conditional statements as the following:

The main diagonal contains 0 in all its locations The upper triangle contains 1 in all its locations The lower triangle contains 2 in all its locations

Solution:


void main(){int a[4][4];for(int i=0; i<4; i++)

for(int j=0; j<4; j++){

if(i<j) a[i][j] = 1;else if (i==j) a[i][j] = 0;else a[i][j] = 2;

}

cout << "The array values are:\n";for(int i=0; i<4; i++){

for(int j=0; j<4; j++)cout << a[i][j] << " ";


}

9 | P a g e

Q9: Write a program that defines a two-dimensional array of integers of size 4*4. The program will fill the array of values using the equation array_name[i][j] = i+j+2 (i refers to the row index, j refers to the column index). Then, define a one-dimensional array of size 4. The one-dimensional array should be filled with the values along the main diagonal of the two-dimensional array.

For example:

If the two-dimensional array is:

V1V2V3V4

V5V6V7V8

V9V10V11V12

V13V14V15V16

The one-dimensional array will be:

V1V6V11V16

Solution:

#include <iostream>using namespace std;


for(int j=0; j<4; j++)a[i][j] = i+j+2;

int b[4], index=0;for(int i=0; i<4; i++)

for(int j=0; j<4; j++)if(i==j){

b[index] = a[i][j];index++;

}}

10 | P a g e

Q10: Write a program that defines a two-dimensional array of integers of size 10*10. The program will fill each location of the array by its index summation (array[i][j] = i+j). Then print the summation of the elements on the array circumference as shown below:

Solution:



for(int j=0; j<4; j++)a[i][j] = i+j;

int sum = 0;for(int i=0; i<4; i++)

for(int j=0; j<4; j++)if(i==0 || j==0 || i==9 || j==9)sum += a[i][j];

cout << "The result is: " << sum << endl;}

11 | P a g e

Q11: Write a program that stores the grades of 5 students in a two-dimensional array. Each student has 3 marks. Each row will represent a student and the last cell in the row will store the calculated average for the student's marks. Finally, display the average of all student averages.

Solution:#include <iostream>using namespace std;

void main(){float a[5][4], sum;for(int i=0; i<5; i++){

sum = 0;cout << "Enter the 3 marks for the

student number: " << i+1 << endl;for(int j=0; j<3; j++){

cin >> a[i][j];sum += a[i][j];

}a[i][3] = sum/3;

}

cout << "The students marks and averages are:" << endl;

for(int i=0; i<5; i++){

for(int j=0; j<4; j++)cout << a[i][j] << " ";


sum = 0;for(int i=0; i<5; i++)

sum += a[i][3];

cout << "The AVG for all sudents is: " << (float)sum/5 << endl;

}

12 | P a g e

Chapter 02

FunctionsPrepared By:

Dr. Murad Magableh

2013

13 | P a g e

Q1: Write a program to take a depth (in kilometers) inside the earth as input data; compute and display the temperature at this depth in degrees Celsius and degrees Fahrenheit, The relevant formulas are:

Celsius = 10 (depth) + 20 Fahrenheit = 1.8 (Celsius) + 32

Include two functions in your program:

1. Function celsius_at_depth should compute and return the Celsius temperature at a depth measured in kilometers.

2. Function fahrenheit should convert a Celsius temperature to Fahrenheit.

Solution:


float celsius_at_depth(float depth){

return ( 10 * depth + 20);}

float fehrenheit(float celsius){

return ( 1.8 * celsius + 32);}

void main(){

float depth, celsius;cout << "Enter the depth inside the earth:\n";cin >> depth;celsius = celsius_at_depth(depth);cout << "The temperature at this depth in degree Celsius is: " << celsius << endl;cout << "The temperature at this depth in degree Fehrenheit is: " << fehrenheit(celsius) << endl;

}

14 | P a g e

Q2: Write a program to find the following using functions:

1. Sphere surface area (4 π r2)2. Sphere volume (4/3 π r3)

NOTE: Use functions to find powers of the radius

Solution:


float power2(float radius){

return ( radius * radius);}

float power3(float radius){

return ( radius * radius * radius);}float surface_area(float radius){

return ( 4 * 3.14 * power2(radius));}

float volume(float radius){

return ( 4.0/3.0 * 3.14 * power3(radius));}

void main(){

float radius;cout << "Enter the radius of the sphere: ";cin >> radius;cout << "The surface area is: " << surface_area(radius) << endl;cout << "The volume is: " << volume(radius) << endl;

}

15 | P a g e

Q3: Write a program (using a function) that takes a positive number with a fractional part and rounds it to two decimal places. For example, 32.4851 would round to 32.49, and 32.4431 would round to 32.44

Solution:


float round(float number){

int num = number * 100;if ( (number*100-num) >= 0.5) num++;return num/100.0;

}

void main(){

float number;cout << "Enter a number: ";cin >> number;cout << "The round to two decimal places is: " << round(number) << endl;

}

16 | P a g e

Q4: Write a program (using a function) that takes a positive integer number and displays PRIME if the number is prime and NOT PRIME otherwise.

NOTE: a prime number is an integer that has no integral factors but itself and 1

Solution:


void isPrime(int x){

int flag = 0;for(int i=1; i<=x; i++)

if(x%i==0) flag++;if(flag<=2) cout << "Prime" << endl;else cout << "Not Prime" << endl;

}

void main(){

int number;cout << "Enter a number: ";cin >> number;isPrime(number);

}

17 | P a g e

Q5: Write a function that takes a positive integer number and returns TRUE if the number is prime and FALSE otherwise. Use the function in the main to display PRIME if the number is prime and NOT PRIME otherwise.

NOTE: a prime number is an integer that has no integral factors but itself and 1

Solution:


bool isPrime(int x){


if(x%i==0) flag++;if(flag<=2) return true;

return false; // "else" is not necessary here. WHY???}

void main(){

int number;cout << "Enter a number: ";cin >> number;if(isPrime(number)) cout << "Prime" << endl;else cout << "Not Prime" << endl;

}

18 | P a g e

Q6: Write a function that displays the perfect numbers between 1 and 1000.

NOTE: A perfect number is a positive integer that is equal to the sum of its positive integral factors, including 1 but excluding itself.

Solution:


bool isPerfect(int x){

int flag = 0;for(int j=1; j<x; j++)

if(x%j==0) flag += j;if(flag == x) return true;else return false; // You can omit the "else" keyword

}

void perfect_list(){

int sum = 0, index = 1;for(int i=1; i<=1000; i++)

if(isPerfect(i))cout << "Perfect number no. " << index++ << " is: "

<< i << endl;}

void main(){

perfect_list();}

19 | P a g e

Q7: Write a function that takes a salary of an employee and increases it by 100 (Just to introduce the concept of Call-By-Reference).

Solution 01 (Call-By-Reference):


void sal_inc(int &sal){

sal += 100;}

void main(){

int salary;cout << "Enter a salary: " ;cin >> salary;sal_inc(salary);cout << "The salary after the increment is: " << salary << endl;

}

Solution 01 (Call-By-Value):


int sal_inc(int sal){

return sal + 100;}

void main(){

int salary;cout << "Enter a salary: " ;cin >> salary;salary = sal_inc(salary);cout << "The salary after the increment is: " << salary << endl;

}

20 | P a g e

Q8: Write a function that takes a one-dimensional array and its size, and then fill each location in the array by the factorial of the location's index.

NOTE: The factorial of an integer number is the product of that integer and all the integers below it.

Solution:


int fact(int x){

int f = 1;for(int j=1; j<=x; j++)

f *= j;return f;

}

void fill_array(int a[], int size){

a[0] = 1; // The factorial of Zero is 1for(int i=1; i<size; i++)

a[i] = fact(i);}

void main(){

int a[5] = {2, 4, 1, 9, -3};cout << "The array before calling the function: " << endl;for(int i=0; i<5; i++)

cout << a[i] << " ";

fill_array(a, 5);

cout << "\nThe array after calling the function: " << endl;for(int i=0; i<5; i++)

cout << a[i] << " ";}

21 | P a g e

Q9: Write a function that takes a one-dimensional array and its size, and then returns the summation of prime numbers in the array.

Solution:


bool isPrime(int x){


if(x%i==0) flag++;if(flag<=2) return true;

return false; // "else" is not necessary here. WHY???}

int array_sum(int a[], int size){

int sum = 0;for(int i=0; i<size; i++)

if(isPrime(a[i])) sum += a[i];return sum;

}

void main(){

int arr[10] = {1, 2, 3, 17, 5, 4, 8, 11, 20, 30};cout << "The summation of prime numbers in this array is: " << array_sum(arr, 10) << endl;

}

22 | P a g e

Chapter 03

PointersPrepared By:

Dr. Murad Magableh

2013

23 | P a g e

Q1: Write the output of the following code:


void main(){

int a = 8;int b = 4;int *p, *q;p = &a;q = &b;cout << a << " " << b << " "

<< *p << " " << *q << endl;*p+=12;a++;cout << a << " " << b << " "

<< *p << " " << *q << endl;*p = 100;*q = 200;cout << a << " " << b << " "

<< *p << " " << *q << endl;int * t;t = q;q = p;p = t;cout << a << " " << b << " "

<< *p << " " << *q << endl;t = &a;p = t;q = t;cout << a << " " << b << " "

<< *p << " " << *q << endl;}

Solution:

8 4 8 4

21 4 21 4

100 200 100 200

100 200 200 100

100 200 100 100

24 | P a g e


#include<iostream>using namespace std;void main(){

int a[5] = {2, 4, 6, 8, 10};int *p;p = a;if(a==p) p++;cout << *p << endl;p+=3;cout << *p << endl;for(int i=100; i<105; i++){

cout << *p << " ";--p;

}cout << endl;p = a;for(int i=0; i<5; i++)

cout << p[i] << " ";cout << endl;for(int i=0; i<5; i++)

cout << a[i] << " ";cout << endl;for(int i=4; i>=0; i--)

cout << *(p+i) << " ";cout << endl;for(int i=1; i<5; i+=2)

cout << *(p+i) << " ";cout << endl;for(int i=0; i<5; i++)

cout << *p << " ";cout << endl;

}

Solution:

4

10

10 8 6 4 2

2 4 6 8 10

2 4 6 8 10

10 8 6 4 2

4 8

2 2 2 2 2

25 | P a g e

Q3: Write a program that reads a size of a one-dimensional array from the user. The size will be passed to a function that creates an array of this size. The function will also fill the array elements with the square of each element's index. Finally, the function will print the array.

Solution:


void dynamic_array_size(int size){

int *arr = new int[size];for(int i=0; i<size; i++)

arr[i] = i*i;for(int i=0; i<size; i++)


}

void main(){

int s;cout << "Please insert the array size: ";cin >> s;dynamic_array_size(s);

}

26 | P a g e

Q4: Write a program that reads 10 integers from the user and stores them in a one-dimensional array. Then, store the odd values in another array. The size of the new array should be exactly the same as the number of the odd values (No empty locations is allowed in the new array).

Solution:


void main(){

int a[10];int count = 0;cout << "Please enter 10 values:" << endl;for(int i=0; i<10; i++){

cin >> a[i];if(a[i]%2==1) count++;

}int *new_arr = new int[count];int index = 0;for(int i=0; i<10; i++)

if(a[i]%2==1) new_arr[index++] = a[i];

for(int i=0; i<count; i++)cout << new_arr[i] << " ";

cout << endl;}

27 | P a g e



void main(){

int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};int *front, *rear;front = a; // OR front = &a[0];rear = &a[9];while(front<=rear){

int t = *front;*front = *rear;*rear = t;rear--;front++;

}for(int i=0; i<10; i++)

cout << a[i] << " ";cout << endl;

}

Solution:

10 9 8 7 6 5 4 3 2 1

28 | P a g e

Chapter 04

RecursionPrepared By:

Dr. Murad Magableh

2013

29 | P a g e

Q1: Write a recursive function that prints the numbers between 1 to n.

Solution:


void print_numbers(int n){

if(n>1) print_numbers(n-1);cout << n << " ";

}

void main(){

int num;cout << "Please insert the number (n): ";cin >> num;print_numbers(num);cout << endl;

}

30 | P a g e

Q2: Write a recursive function that prints the numbers between 1 to n in a reverse order.

Solution:



cout << n << " ";if(n>1) print_numbers(n-1);

}

void main(){

int num;cout << "Please insert the number (n): ";cin >> num;print_numbers(num);cout << endl;

}

31 | P a g e

Q3: What is the output of the following code:



cout << n << " ";if(n>1) print_numbers(n-1);cout << n << " ";

}

void main(){

print_numbers(5);cout << endl;

}

Solution:

5 4 3 2 1 1 2 3 4 5

32 | P a g e

Q4: Write a recursive function that prints the following shape:

Solution:


void print_stars(int n){

if(n>1) print_stars(n-1);for(int i=1; i<=n; i++)

cout << "*";cout << endl;

}

void main(){

print_stars(5);cout << endl;

}

33 | P a g e

Q5: Write a recursive function that prints the following shape:

Solution:



for(int i=1; i<=n; i++)cout << "*";

cout << endl;if(n>1) print_stars(n-1);

}

void main(){


}

34 | P a g e



int global = 5;


for(int i=1; i<=(global-n); i++)cout << "*";

cout << endl;if(n>=1) print_stars(n-1);for(int i=1; i<=(global-n); i++)

cout << "*";cout << endl;

}

void main(){


}

Solution:

35 | P a g e

Q7: Write a recursive function that calculates and returns the factorial of a number x.

Solution:


int fact(int x){

if(x==1) return 1;return x*fact(x-1);

}

void main(){

cout << fact(5) << endl;}

36 | P a g e

Q8: Write a recursive function that receives a one-dimensional array and reverses the order of its elements.

Solution:


void reverse_array(int a[], int front, int rear){ if(front<(rear-1)) reverse_array(a, front+1, rear-1); int t = a[front]; a[front] = a[rear]; a[rear] = t;}

void main(){

int arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};for(int i=0; i<10; i++)


reverse_array(arr, 0, 9);

for(int i=0; i<10; i++)cout << arr[i] << " ";

cout << endl;}

37 | P a g e



void reverse_array(int a[], int front, int rear, int size){ if(front<(rear-1)) reverse_array(a,front+1,rear-1,size); int t = a[front]; a[front] = a[rear]; a[rear] = t; for(int i=0; i<size; i++) cout << a[i] << " "; cout << endl;}

void main(){

int arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};reverse_array(arr, 0, 9, 10);

}

Solution:

1 2 3 4 6 5 7 8 9 10

1 2 3 7 6 5 4 8 9 10

1 2 8 7 6 5 4 3 9 10

1 9 8 7 6 5 4 3 2 10

10 9 8 7 6 5 4 3 2 1

38 | P a g e

Q10: Write the following function in a recursive way:

int power(int x, int y){

int result = x;for(int i=1; i<y; i++)

result *= x;return result;

}

Solution:


int power(int x, int y){

if(y==1) return x;return x*power(x, y-1);

}

void main(){

cout << power(2, 3) << endl;}

39 | P a g e

Chapter 05

StringsPrepared By:

Dr. Murad Magableh

2013

40 | P a g e

Q1: Write a function that receives a string and returns its length without using the strlen function.

Solution:


int my_strlen(char *s){

int c = 0;while(s[c] != '\0') c++;return c;

}

void main(){

char *s1 = "Philadelphia University";cout << my_strlen(s1) << endl;

}

41 | P a g e

Q2: Write a function that does the same as the function strcat.

Solution:

#include<iostream>#include<cstring>using namespace std;

char* my_strcat(char *s1, char *s2){

int s2_index = 0;int len = strlen(s1)+strlen(s2);

for(int i=strlen(s1); i<len; i++)s1[i] = s2[s2_index++];

return s1;}

void main(){

char s1[100] = "Philadelphia";char s2[100] = "University";cout << my_strcat(s1, s2) << endl;

}

42 | P a g e

Q3: Write a function that does the same as the function strcpy.

Solution:


char* my_strcpy(char *s1, char *s2){

int i;for(i=0; i<strlen(s2); i++)

s1[i] = s2[i];s1[i] = '\0';return s1;

}

void main(){

char s1[100] = "Philadelphia";char s2[100] = "University";cout << my_strcpy(s1, s2) << endl;

}

43 | P a g e

Q4: Write a function that does the same as the function strcmp.

Solution:


int min(int x, int y){

if(x<y) return x;else return y; // Without "else" is OK here

}

int my_strcmp(char *s1, char *s2){

for(int i=0; i<min(strlen(s1), strlen(s2)); i++)if(s1[i]<s2[i]) return -1;else if (s1[i]>s2[i]) return 1;

if(strlen(s1)<strlen(s2)) return -1;else if(strlen(s1)>strlen(s2)) return 1;return 0;

}

void main(){ // s1 = s2

char *s1 = "ABC";char *s2 = "ABC";cout << my_strcmp(s1, s2) << endl;// s1 < s2s1 = "ABB";s2 = "ABC";cout << my_strcmp(s1, s2) << endl;// s1 > s2s1 = "ABC";s2 = "ABB";cout << my_strcmp(s1, s2) << endl;// s1 < s2s1 = "ABC";s2 = "ABCD";cout << my_strcmp(s1, s2) << endl;// s1 > s2s1 = "ABCD";s2 = "ABC";cout << my_strcmp(s1, s2) << endl;

}

44 | P a g e

Exercises:1. Write a function that does the same as the function strncat

Solution:


char* my_strncat(char *s1, char *s2, int n){

int s2_index = 0;int len = strlen(s1)+n;for(int i=strlen(s1); i<len; i++){

s1[i] = s2[s2_index++];cout <<"i="<<i<<endl;

}return s1;

}

void main(){

char s1[100] = "Philadelphia";char s2[100] = "University";

int n;cin >>n;cout << my_strncat(s1, s2, n) << endl;

}

2. Write a function that does the same as the function strncpy

Solution


char* my_strncpy(char *s1, char *s2, int n){

int i;int len = strlen (s1);

45 | P a g e

for(i=0; i<n; i++)s1[i] = s2[i];

if (n> len)s1[i] = '\0';

return s1;}

void main(){

char s1[100] = "Philadelphia";char s2[100] = "University";int n;cin >> n;cout << my_strncpy(s1, s2, n) << endl;

}

3. Write a function that does the same as the function strncmp

Solution

#include<iostream>

#include<cstring>

using namespace std;

int my_strncmp(char *s1, char *s2, int n)

{

for(int i=0; i<n; i++)

if(s1[i]<s2[i]) return -1;

else if (s1[i]>s2[i]) return 1;

return 0;

}

46 | P a g e

void main()

{ // s1 = s2

char *s1 = "ABC";

char *s2 = "ABC";

int n;

cin >> n;

cout << my_strncmp(s1, s2, n) << endl;

// s1 < s2

s1 = "ACB";

s2 = "ABC";


// s1 > s2

s1 = "CBA";

s2 = "ABB";


// s1 < s2

s1 = "ABB";

s2 = "ABBD";


// s1 > s2

s1 = "ABCD";

s2 = "ABC";


}

47 | P a g e

Chapter 06

File Processing

Prepared By:

Dr. Murad Magableh

201348 | P a g e

Q1: Write a program that copies a content of a file into a one-dimensional array. Assume that the content of the file is integers.

Solution:

#include<iostream>#include<fstream>using namespace std;

void main(){

int x, c=0;ifstream fin1("d:\\test.txt", ios::in);while(fin1>>x)

c++;

ifstream fin2("d:\\test.txt", ios::in);int *a = new int[c];for(int i=0; i<c; i++)

fin2 >> a[i];// To print the content of the arrayfor(int i=0; i<c; i++)

cout << a[i] << endl;}

49 | P a g e

Q2: Write a program that copies a content of a one file into another file. Assume that the content of the file is integers.

Solution:#include<iostream>#include<fstream>using namespace std;

void main(){

int x;ifstream fin("d:\\file_01.txt", ios::in);ofstream fout("d:\\file_02.txt", ios::out);while(fin>>x) fout << x << endl;

}

50 | P a g e

Q3: Write a program that copies a content of a one file into another file in a reverse order. Assume that the content of the file is integers.

Solution:#include<iostream>#include<fstream>using namespace std;

void main(){

int x, c=0;ifstream fin1("d:\\file_01.txt", ios::in);while(fin1>>x)

c++;// First, copy the file_01 into an array firstifstream fin2("d:\\file_01.txt", ios::in);int *a = new int[c];for(int i=0; i<c; i++)

fin2 >> a[i];// Then copy the array in reverse order into file_02ofstream fout("d:\\file_02.txt", ios::out);for(int i=c-1; i>=0; i--)

fout << a[i] << endl;}

51 | P a g e

Q4: Assuming that a file contains integer numbers, write a program that reads these values and calculates the following:

1. The maximum value2. The minimum value3. The average of all values4. How many prime numbers are in the file5. How many perfect numbers are in the file6. How many odd values are in the file7. How many even values are in the file8. How many negative values are in the file9. The summation of the positive values10. The summation of the even negative numbers

Solution:

#include<iostream>#include<fstream>using namespace std;

bool isPrime(int num){

int c = 0;for(int i=1; i<=num; i++)

if(num%i==0) c++;if(c<=2 && num>0) return true;else return false;

}

bool isPerfect(int num){

int c = 0;for(int i=1; i<num; i++)

if(num%i==0) c += i;if(c==num) return true;else return false;

}

void main(){

int x;int counter = 0;int min, max, avg, sum = 0;int prime_counter = 0, perfect_counter = 0;int odd_counter = 0, even_counter = 0, negative_counter = 0;int positive_sum = 0, even_negative_sum = 0;

52 | P a g e

ifstream fin("d:\\test.txt", ios::in);while(fin>>x){

if(counter==0){

min = x;max = x;

}else{

if(x<min) min = x;if(x>max) max = x;

}

if(isPrime(x)) prime_counter++;if(isPerfect(x)) perfect_counter++;

if(x%2==0) even_counter++;else odd_counter++;

if(x<0){

negative_counter++;if(x%2==0) even_negative_sum += x;

}else positive_sum += x;

sum += x;counter++;

}

cout << "Max is: " << max << endl;cout << "Min is: " << min << endl;cout << "AVG is: " << (float)sum/counter << endl;cout << "There is " << prime_counter << " prime number(s)" << endl;cout << "There is " << perfect_counter << " perfect number(s)" << endl;cout << "There is " << even_counter << " even number(s)" << endl;cout << "There is " << odd_counter << " odd number(s)" << endl;cout << "There is " << negative_counter << " negative number(s)" << endl;cout << "The summation of the positive number(s) is: " << positive_sum << endl;cout << "The summation of the even negative number(s) is: " << even_negative_sum << endl;

}

53 | P a g e

StructuresQuestion: Write a C++ program to do the following:

- Set up a structure/record to store products; each product has a name, a model number and a price.

- Choose appropriate types for these fields.- Your program should contain a loop which allows entry via the keyboard of

up to 10 products, to be stored in an array.- The loop can be stopped by entry of "quit" for the product name- Your program should include a function to display all the products details after

the entry loop has finished.

Solution

#include<iostream>

#include<cstring>


struct products

{

string name;

string model;

float price;

};

void printprod(products a[], int i)

{

for (int j=0; j<i; j++)

{

54 | P a g e

cout <<a[j].name;

cout <<a[j].model;

cout <<a[j].price;

}

}

void main ()

{

products p[10];

cout<<"Enter up to 10 products, when finished, enter quit"<<endl;

for (int i=0; i<10; i++)

{

cout<<"Enter name"<<endl;

cin.getline (p[i].name, 50);

if (p[i].name == "quit")

break;

cout<<"Enter model"<<endl;

cin>> p[i].model;

cout<<"Enter price"<<endl;

cin>> p[i].price;

}

printprod (p, i);

}

55 | P a g e

Philadelphia University Philadelphia University

Lecturer : Dr. Raad Alwan

Lab Instructor : Eman Alnaji

First Exam

Question1: Write a C++ program that declares a 4X4 array, and fill it as displayed in the figure below: [3 Marks]

$ # # *# $ * ## * $ #* # # $

Print the resulted array as an output, displayed row by row.

Solution

#include<iostream>

#include<cstring>


void main ()

{

char A[4][4];

for (int i=0; i<4; i++)

{

for (int j=0; j<4; j++)

{

if (i==j)

A[i][j] = '$';

else if (i+j == 3)

56 | P a g e

Faculty of Information TechnologyFaculty of Information Technology

Department of CSDepartment of CS

A[i][j] = '*';

else

A[i][j] = '#';

cout << A[i][j];

}

cout <<endl;

}

}

Question2:

Write a C++ program, that computes the area of a square, or a rectangle according to the user request. (i.e. the user inputs 's' for square or 'r' for rectangle). Pass this character to a function that accordingly ask the user for further information to complete its calculations, and returns the computed area to the main program, where the output is displayed.

Hint: Square area = width * width

Rectangle area = width * height

Solution

#include<iostream>

#include<cstring>


int area (char shape)

{

int width, height;

if (shape == 's')

{

cout << "Enter Width"<<endl;

cin >> width;

return width*width;

}

57 | P a g e

else if (shape == 'r')

{

cout << "Enter Width and Height"<< endl;

cin >> width>> height;

return width * height;

}

else

return 0;

}

void main ()

{

char shape;

cout << "Enter s for square, and r for rectangle"<<endl;

cin>> shape;

cout << "area = "<< area(shape);

}

58 | P a g e


Lecturer : Miss Hanan Hardan

Lab Instructor : Mrs. Eman Alnaji


Z Z Z Z ZZ

ZZ

Z Z Z Z ZPrint the resulted array as an output, displayed row by row.

Solution

#include<iostream>

#include<cstring>


void main ()

{

char A[5][5];

for (int i=0; i<5; i++)

{

for (int j=0; j<5; j++)

{

if ((i+j == 4)||(i==0)||(i==4))

A[i][j] = 'Z';

else

59 | P a g e



A[i][j] = ' ';

cout << A[i][j];

}

cout <<endl;

}

}

Question2: [3 Marks]

A manager of a sports equipment store has decided to apply discounts on certain items in the sale season. Write a C++ program that takes an item price, and a discount percentage, passes them to a function AfterPrice, that returns the item price after discount. As an output, print the price before and after discount.

Hint: Price After Discount = Item Price – (Item Price * Discount Percentage)

Solution:

#include<iostream>

#include<cstring>


float AfterPrice (float price, float dis)

{

return price - (price * dis);

}

void main ()

{ float p, d;

cout << "Enter Item price, and discount";

cin>>p>>d;

cout << "Price after discount = "<< AfterPrice (p, d);

60 | P a g e

}





X XX X

XX X

X XPrint the resulted array as an output, displayed row by row.

Solution

#include<iostream>

#include<cstring>


void main ()

{

char A[5][5];

for (int i=0; i<5; i++)

{

for (int j=0; j<5; j++)

{

if ((i+j == 4)||(i==j))

A[i][j] = 'X';

else

A[i][j] = ' ';

61 | P a g e



cout << A[i][j];

}

cout <<endl;

}

}

Question2: [3 Marks]

A super market arranges items into batches with certain quantity, and tags a total price on each patch. Write a C++ program that takes as input an item unit price, and batch quantity, passes this information to a function that calculates and returns back the total price to be printed and tagged on this batch.

Hint: Total Price = Item unit price * quantity.

Solution

#include<iostream>

#include<cstring>


float TotalPrice (float unitprice, float qty)

{

return unitprice * qty;

}

void main ()

{ float uprice, q;

cout << "Enter Item unit price, and its quantity";

cin>>uprice>>q;

cout << "Total Price = "<< TotalPrice (uprice, q);

}

62 | P a g e


Lecturer : Eman Alnaji

Lab Instructor : Eman Alnaji


# # # #* $ $ ** $ $ *# # # #Print the resulted array as an output, displayed row by row.

Solution

#include<iostream>

#include<cstring>


void main ()

{

char A[4][4];

for (int i=0; i<4; i++)

{

for (int j=0; j<4; j++)

{

if ((i == 0)||(i==3))

A[i][j] = '#';

else if ((j==0)||(j==3))

A[i][j] = '*';

else

63 | P a g e



A[i][j] = '$';

cout << A[i][j];

}

cout <<endl;

}

}

Question2: Write a C++ program that prompts the user to enter the basic salary, and the bonuses for an employee, and passes this information to a function that computes and returns the Net Salary, according to the following equations:

Net Salary = Income – Discount

Income = Basic Salary + Bonuses

Discount = Basic Salary * Tax

Where Tax = 0.16

Solution

#include<iostream>

#include<cstring>


float NetSalary (float basic, float bonus)

{

float Income, Discount;

const double Tax = 0.16;

Income = basic + bonus;

Discount = basic * Tax;

64 | P a g e

return Income - Discount;

}

void main ()

{ float basic, bonus;

cout << "Enter the basic salary and the bonuses";

cin>>basic>>bonus;

cout << "Net Salary = "<< NetSalary (basic, bonus);

}

65 | P a g e


Lecturer : Dr. Raad Fadel


Second Exam

Question:

Write a C++ program that reads a string, sends it to a function named "count_vowels" that counts number of vowels in the given string.

Hint: Vowels are 'a', 'A', 'e', 'E', 'o', 'O', 'i', 'I', 'u', 'U'

Examples:

Input: "Mohammad"

Output: 3

Input: "Philadelphia University"

Output: 9

Input: "Omar"

Output: 2

Solution

#include <iostream>


int count_vowels (char a[])

{ int i=0, c=0;

while (a[i] != '\0')

{

if (a[i] == 'a' ||a[i] == 'A'||a[i] == 'i'||a[i] == 'I'||a[i] == 'o'||a[i] == 'O'||a[i] == 'e'||a[i] == 'E'||a[i] == 'u'||a[i] == 'U')

c++;

i++;

}

66 | P a g e



return c;

}

void main ()

{

char s[20];

cin.getline (s, 20, '\n');

cout<<count_vowels (s);

}

67 | P a g e




Second Exam

Question:

Write a C++ program that reads a string, and a character, send them to a function called "count", which counts number of occurrences of this character in the given string, and returns it to the main program.

Examples:

Input: "Mohammad", 'm'

Output: 2 (m is repeated twice)

Input: "Philadelphia University", 'i'

Output: 4 (i is repeated 4 times)

Input: "Omar", 'e'

Output: 0 (e does not appear at all in the string)

Solution:

#include <iostream>


int count (char [], char);

void main ()

{

char s[50];

char c;

cin.getline (s, 50);

cin >> c;

cout << count (s, c);

68 | P a g e



}

int count (char st[], char ch)

{

int i=1, n=0;

while (st[i] != '\0')

{

if (st[i] == ch)

n++;

i++;

}

return n;

}

69 | P a g e




Second Exam

Question:

Write a C++ program that reads two strings, and sends them to a function called "match_count" and returns number of similar characters at the beginning of the two strings

Examples:

Input: "Mohammad", "Mohannad"

Output: 4 ("Moha" has 4 characters)

Input: "Aya", 'Ayat'

Output: 3 ("Aya" has 3 characters)

Input: "Omar", 'Ahmad'

Output: 0 (No similar characters at the beginning)

Solution

#include <iostream>


int match_count (char [], char[]);

void main ()

{

char s1[50];

char s2[50];

cin.getline (s1, 50);

cin.getline (s2, 50);

cout << match_count (s1, s2);

}

70 | P a g e



int match_count (char st1[], char st2[])

{

int i=0, n=0;

while ((st1[i] != '\0') && (st2[i] != '\0') && (st1[i] == st2[i]))

{

n++;

i++;

}

return n;

}

71 | P a g e


Lecturer : Mrs. Eman Alnaji


Second Exam

Question:

Write a C++ program that reads a string and sends it to a function named "middle", that returns the middle character in the string. Assume that number of characters in the string is always odd number.

Examples:

Input: "Ahmad"

Output: 'm'

Input: "Ali"

Output: 'l'

Solution

#include <iostream>

#include <string>


char middle (char a[])

{ int mid=strlen(a)/2;

int i=0;

while (i<mid)

{

i++;

}

return a[i];

72 | P a g e



}

void main ()

{

char s[20];

cin.getline (s, 20, '\n');

cout<< middle (s);

}

73 | P a g e



Second Exam – Makeup

Question:

Write a C++ program that reads a string and sends it to a function named "wordcount", that returns number of words in the given string.

Examples:

Input: "Ahmad Ali"

Output: 2

Input: "I like C++"

Output: 3

Solution

#include<iostream>

#include<cstring>


int wordcount (char a[])

{

int i=0;

int count=0;

while (a[i] != '\0')

{

if (a[i] == ' ')

count++;

i++;

74 | P a g e



}

if (a[i-1] != ' ')

count++; //to count the last word if not space

return count;

}

void main ()

{

char s[50];

cout<<"Enter string"<<endl;

cin.getline(s, 50);

cout << "Number of words = "<<wordcount(s);

}

75 | P a g e

+... · web viewcin>> p[i].price;} printprod (p, i);} philadelphia university . faculty of...

Documents