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Chapter 8 Notes Name_______________________
Ch 8.1 – Adding and Subtracting PolynomialsMonomials: Single term that is a number, a variable, or the product of a number and a variable.Examples:
Binomials:Examples:
Trinomials:Examples:
Polynomials : Either a monomial or a sum of monomials ; Each monomial is a term of the polynomial
Standard FormWhen the polynomial is in descending order with respect to the degrees of the variables
Degree of a PolynomialThe degree of a polynomial in one variable is equal to the degree of the monomial with the greatest exponent. The degree of 3x4+5x2-7x+1 is 4.
You can name a polynomial based on its degree or the number of monomials it contains
1Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
Adding and Subtracting Polynomials
Group like terms by rearranging the polynomial
Examples: Add the following polynomials
5) (3x2 – 4x + 8) + (2x – 7x2 – 5) 6) (7y2 + 2y – 3) + (2 – 4y + 5y2)
Examples: Subtract the following polynomials. (REMEMBER TO DISTRIBUTE THE “NEGATIVE” TO THE QUANTITY)
7) (3x2 – 4x + 8) - (2x – 7x2 – 5) 8) (7y2 + 2y – 3) - (2 – 4y + 5y2)
2Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
Ch 8.2 – Multiplying and Factoring
Multiplying a Polynomial by a MonomialRemember the rules for exponents….. x (x2) = x 1+2 = x3
Distributive property:
x
5(x + 3) 5 (x + 3)
5(x) + 5(3) x
= __5x + 15______
Examples: Find the product of the following.1) -2x2(3x2 – 7x + 10) 2) 4a(a2 + 9)
Examples: Simplify the following expressions.3) 4(3d2 + 5d) – d(d2 -7d + 12) 4) 3(2t2 – 4t – 15) + 6t(5t + 2)
3Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
Factors and Greatest Common Factor Prime Number – number that can only be divided by itself and one; has only 2 factors
Ex: 1, 2, 3, 5, 7, 11, 13…Composite Number- number that has more than 2 factors
Ex: 4, 6, 8, 9, 10…
Prime Factorization – when a whole number is expressed as a product of prime numbersTHINK FACTOR TREE
You must factor out a -1 when factoring negative numbers.Factored Form: expressed as a product of prime numbers and variables with degree 1Example: Factor completely: 6x3y
2(3)(x)(x)(x)(y)
Greatest Common Factor – greatest term that divides into a number or monomial - factor completely and circle like factors
WHAT DOES EVERY TERM HAVE IN COMMON????? / WHAT CAN YOU DIVIDE EVERYTHING BY????Examples: Find the GCF of the following5) 18xy + 24y2 6) 10x - 15 7) -14x3y2 - 16x4y3
Examples: Factor the polynomial. (Find the GCF and divide it out)EX: 3x2 + 6x + 9 factors into 3(x2 + 2x + 3)
8) 9x + 6 9) -15x2 – 25x 10) 5k3 + 20k2 – 15k
4Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
Ch 8.3 – Multiplying Binomials (F.O.I.L.) or BOX Method
FOIL Method
FOR USE ONLY WHEN MULTIPLYING BINOMIALS
First terms in each binomial are multiplied Example: (x + 4)(x + 3)
Outer of the four terms are multiplied F O I L
Inner of the four terms are multiplied x(x) x(3) 4(x) 4(3)
Last terms of each binomial are multiplied x2 +3x +4x +12
x2 + 7x + 12
BOX MethodCreate a 2 x 2 box and label each part with a term from each binomial
(x + 4)(x + 3)x 4
x x2 + 4x + 3x + 12
3 x2 + 7x + 12
Example: Find the product of the following
1) (x + 3)(x + 5) 2) (x + 4)(x – 3) 3) (x – 5)(x + 7)
5Mr. Keller Algebra I
x(x) (4)x
3(x) 3(4)
Chapter 8 Notes Name_______________________
4) (2n + 3g)(4n – 5g) 5) (2x – 5)(3x2 – 4x + 1)
Ch 8.4 – Multiplying Binomials - Special Cases
Square of a Sum Square of a Difference Sum and a Difference (a + b)2 = a2 + 2ab + b2 (a – b)2 = a2 – 2ab + b2 (a + b)(a – b) = a2 – b2
(x + 3)2 = x2 + 2(x)(3) + (3)2
= x2 + 6x + 9What does the expression 33 mean to do? Rewrite it: Rewrite the expression x5 without exponents: How can we rewrite (x + 2)2 without exponents:
How can knowing this trick, help you with simplifying an expression then?
Example: Simplify the following6) (x + 7)2 7) (2x - 3y)2 8) (x – 4)(x + 4) 9) (3x – 9y)(3x + 9y)
6Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
8.5 – 8.8:Factoring QuadraticsFactoring By Grouping: works for polynomials with 4 terms or more; use the method above to factor
Group terms with like variables together and factor by distributive propertySteps for Factoring:
1. Factor out any common terms first (i.e….Is there anything they all divide by)2. Mutliply the First Coefficient by the Last Term (i.e. the # in front of x2 by the number with no variable)3. Find 2 factors of that product that add to the “x” term4. Rewrite the middle term as the sum of the 2 factors5. Factor by Grouping (Split the 4 terms into 2 sets of 2)6. Write the final answer as 2 quantities (x + a)(x – b)
Example: x2 + 5x + 6 1(6) = 6Factors of 6 that add to 5 = 3 and 2Rewrite: x2 + 3x + 2x + 6Grouping: x2 + 3x + 2x + 6 x(x + 3) +2(x + 3) ---Factor out the common terms on each side
(x + 3) (x + 2) ---Take out quantity from each side and write what is left
Examples: Factor the following.1) 4ax – 5a 2) 3xy + 12y
Example: Factor3) 4ab + 8b + 3a + 6 4) 3ab – 15a + 4b – 20 5) 2xy + 7x – 4y – 14
6) 2x2 + 4x + 8x + 16 7) 3x3 + 3x2 + 12x2 + 12x
7Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
WHAT HAPPENS WHEN THERE ARE NOT 4 TERMS ALREADY????Steps for Factoring:
1. Factor out any common terms first (i.e….Is there anything they all divide by)2. Create the 2x2 box again. The x2 term goes in the upper left corner and the constant term goes in the
lower right corner.3. Multiply the coefficient of the x2 and the constant term.4. Find factors of that number that add the middle term of the quadratic.5. Place those factors in the other 2 boxes with variables. 6. Factor out the GCF and complete the sides.
Example: Factor the following8) x2 + 6x + 8 9) x2 + 5x + 4 10) x2 + 7x + 12
11) x2 – 10x + 16 12) x2 – 12x + 27 13) x2 + x – 12
14) x2 – 7x – 18 15) x2 – x – 20 16) x2 – 8x - 20
8Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
Ch 8.6 – Factoring Trinomials when a ≠ 1ALWAYS LOOK FOR A GCF TO TAKE OUT FIRST!!!
Factoring Trinomials where a ≠ 1
- must be in the form ax2 + bx + c- has a coefficient in front of x2 Steps for Factoring:1. Factor out any common terms first (i.e….Is there anything they all divide by)2. Create the 2x2 box again. The x2 term goes in the upper left corner and the constant term goes in the
lower right corner.3. Multiply the coefficient of the x2 and the constant term.4. Find factors of that number that add the middle term of the quadratic.5. Place those factors in the other 2 boxes with variables. 6. Factor out the GCF and complete the sides.
Example:
7x2 + 22x + 3 → 7(3) = 21 → →
Examples:Factor
1) 5x2 + 27x + 10 2) 10x2 - 43x + 28 3) 2x2 + 7x + 5
**4) 3x2 + 24x + 45 ***5) 12x2 + 20x - 8
9Mr. Keller Algebra I
Factors of 21 Sum of Factors1 21 223 7 10
Chapter 8 Notes Name_______________________
Ch 8.7 – Factoring Special CasesREMEMBER TO LOOK FOR GCF!!!!
Factoring a Difference of Squares Remember: (x + y)(x – y) = x2 – y2
Therefore: x2 – y2 – (x – y)(x + y
Examples: Factor the following
1) x2 – 25 2) m2 – 64 3) 4x2 – 9y2 4) 36x2 – 81y2
5) 3x3 – 27x 6) 16x2 – 16 7) 5x3 + 15x2 – 5x - 15
10Mr. Keller Algebra I
Chapter 8 Notes Name_______________________
Perfect Square Trinomials – trinomials that are a square of a binomial first and last term are prefect squares middle term is two times the root of the first term times the root of the last term
When factoring and you multiply the 1st and last terms together:
If it is a huge number, take the square root of it, that will tell you what to fill the box with.
Examples: Factor the following.
8) 16x2 – 72x + 81 9) 4x2 + 20x + 25 10) 81r2 – 90r + 25
11Mr. Keller Algebra I