VOLUME

NOTEBOOK PAGE 9

Grading the Volume Lab:

SCORE /90RB#____NAME _____________ PERIOD _____

STEPS POINTS

SKETCH THE OBJECT/LABEL THE OBJECT WITH THE MEASUREMENTS

3

WRITE THE FORMULA 3

PLUG IN THE FORMULA WITH THE CORRECT MEASUREMENTS

3

CIRCLE YOUR FINAL ANSWER WITH cm3 or mLs 1

A. MEASURE THE DIMENSIONS OF THE OBJECT…

1. USE A RULER;2. A CALIPHER;3. A GRADUATED CYLINDER.

Calipher

Ruler

Graduated cylinder

Measuring Tape

NOTEBOOK PAGE 9Volume of a rectangular prism

Volume of a Sphere

Volume of a Cylinder

Circumference of a Sphere

Volume of a rectangular prism

Volume of a Sphere

Volume of a Cylinder

Circumference of a Sphere

NOTEBOOK PAGE 9Volume of a rectangular prism

Volume of a Sphere

Volume of a Cylinder

Circumference of a Sphere

V=LW H V= 4/3 r3

V= r2h C= 2r

Volume of an irregularly-shaped object using a graduated cylinder:

V = V2 – V1.The Greek

Letter Delta, Means to subtract

1. Volume of a rectangular prism

Rectangular PrismV= LENGTH WIDTH HEIGHT

2. Volume of a sphere =

2. Volume of a sphere =

4/3 r3

SOMETIMES THE ONLY WAY TO FIND THE RADIUS OF A SPHERE IS TO MEASURE

THE CIRCUMFERENCE WITH A STRING…….

Wrap a string around the fastest part of the sphere……..

CIRCUMFERENCE of a SPHEREwill lead you to the radius of

the sphere…

NEXT USE THE CIRCUMFERENCE FORMULA AND SOLVE FOR THE RADIUS

CIRCUMFERENCE is the distance around the outside of a ball

C = 2 r

r = C 2

3. Volume of a cylinder =

r2 h

CylinderV = r2 h

Volume of an irregularly-shaped object using a graduated cylinder:

VOLUME of DISPLACEMENT of WATER

HIPPO the HOUSEPAINTER

Volume of an irregularly-shaped object using a graduated cylinder:

V = V2 – V1.The Greek

Letter, Means to subtract

Volume of an irregularly-shaped object using a graduated cylinder:

V = V2 – V1.9 mLs – 7 mLs = 2mLs

Help! I can’t swim!

VOLUME VIA the DISPLACEMENT of WATER

Problem #1

The largest ruby in the world is 10.9cm long, 4.10 cm wide, and 5.80 cm high. Find its volume.

sketch

Problem #1

The largest ruby in the world is 10.9cm long, 4.10 cm wide, and 5.80 cm high. Find its volume.

sketch

Problem #1

The largest ruby in the world is 10.9cm long, 4.10 cm wide, and 5.80 cm high. Find its volume.

V = lwh.

Problem #1

The largest ruby in the world is 10.9cm long, 4.10 cm wide, and 5.80 cm high. Find its volume.

V = lwh. =(10.9cm)(4.10cm)(5.80cm)

259 cm3

Problem #2

A metallic sphere has a radius of 1.24 cm. Find its volume.

sketch

Problem #2

A metallic sphere has a radius of 1.24 cm. Find its volume.

sketch

Problem #2

A metallic sphere has a radius of 1.24 cm. Find its volume.

r=1.24cm

V sphere = 4/3 r3

(4/3)(3.14)(1.24cm) (1.24cm) (1.24cm)

=

7.98 cm3

Problem #2

A metallic sphere has a radius of 1.24 cm. Find its volume.

Problem #3 A certain metal is submerged in a graduated cylinder that initially had 20.8 mLs of water and after it was submerged the final volume was 29.9mLs of water.

SKETCH

Problem #3 A certain metal is submerged in a graduated cylinder that initially had 20.8 mLs of water and after it was submerged the final volume was 29.9mLs of water.

SKETCH

Problem #3 A certain metal is submerged in a graduated cylinder that initially had 20.8 mLs of water and after it was submerged the final volume was 29.9mLs of water.

FINAL VOLUME

STARTING VOLUME

Problem #3 A certain metal is submerged in a graduated cylinder that initially had 20.8 mLs of water and after it was submerged the final volume was 29.9mLs of water.

FINAL VOLUME

STARTING VOLUME V = V2 – V1

= 29.9 -20.8= 9.1mLs

Problem #3 A certain metal is submerged in a graduated cylinder that initially had 20.8 mLs of water and after it was submerged the final volume was 29.9mLs of water.sketch

Problem #3 A certain metal is submerged in a graduated cylinder that initially had 20.8 mLs of water and after it was submerged the final volume was 29.9mLs of water.sketch

Problem #4 A cube of gold has 2.04 meter sides. Find the volume.

Problem #4 A cube of gold has 2.04 meter sides. Find the volume.

Problem #4

A cube of gold has 2.04 meter sides. Find the volume.

By definition a cube has sides of equal length.

So………….

V=lwhV=(2.04m) (2.04m) (2.04m)= 8.489 rounds to

8.49m3

Problem #4

A cube of gold has 2.04 meter sides. Find the volume.

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

The circumference is the distance around a sphere.

The radius is the distance from the center of the sphere to the outer edge of the sphere.

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

CIRCUMFERENCE = 2(C = 2(Solve for r r = C = 2()

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

CIRCUMFERENCE = 2(C = 2(Solve for r r = C = 4.62cm 2() (2)(3.14)

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

CIRCUMFERENCE = 2(C = 2(Solve for r r = C = 4.62cm = 0.736cm 2() (2)(3.14)

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

Now find the volume V= 4/3 r3

V=(____)(____)(_____)(_____)(______)

Problem #5

A RUBBER sphere has a CIRCUMFERENCE of 4.62cm. Find its volume.

Now find the volume V= 4/3 r3

V=(4/3)(3.14)(0.736cm)(0.736cm)(0.736cm)

V= 1.669 -or- 1.67cm3

Problem #6. Find the volume of a cylinder

that has a radius of 2.53 cm and a height of 5.62

cm.

r2 h

Problem #6. Find the volume of a cylinder

with the following dimensions:

h = 5.62 cm

r= 2.53 cm