voltage regulation formulas and reactance of conductors - okonite electrical wire & cable

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  • 7/24/2019 Voltage Regulation Formulas and Reactance of Conductors - Okonite Electrical Wire & Cable

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    onite.com/engineering/voltage-regulation.html

    Voltage RegulationEngineering Technical Center

    Okonite Home Page

    Contact Okonite

    .

    Voltage regulation is often the limiting factor in the choice of either conductor or type of insulation.

    While the heat loss in the cable determines the maximum current it can safely carry without

    excessive deterioration, many circuits will be limited to currents lower than this in order to keep the

    voltage drop within permissible values. In this connection it should be remembered that the high

    voltage circuit should be carried as far as possible so that the secondary runs, where most of the

    voltage drop occurs, will be small.

    The voltage drop of a feeder may be calculated from the following formulae:

    V = 100 (VSVL) / VL

    V = Voltage regulation in percent

    VL= Voltage across loadVS= Voltage at source

    VS=

    = is the angle by which the load current lags the voltage across the

    load

    Cos =Power factor of load

    R = Total a-c resistance of feeder

    X = Total reactance of feeder

    I= Load current

    Approximate formula for voltage drop:

    (VSVL) = RI cos + XI sin

    This above formula is satisfactory where the power factor angle is nearly the same as the

    impedance angle. It is exact when they are equal.

    That is: tan = X / R

    Above values apply directly for single phase lines when resistance and reactance are loop values

    and voltage is voltage between lines.

    For 3-phase circuits, use voltage to neutral and resistance and reactance of each conductor to

    neutral. This gives voltage drop to neutral. To obtain voltage drop line-to-line, multiply voltage drop by

    . (The percent voltage drop is of course the same between conductors as from conductor to

    ground and should not be multiplied by ).

    Example: 3 s ingle coated copper conductors 600 volt cables in non-metallic conduit.

    Size conductor =4/0, Awg Copper .080 insulation, .045 jacket.

    O.D. = .810

    Voltage = VS= 440 volts 3 phase

    Current = I= 250 amperes

    Power Factor = cos = 0.8

    Length = 750 ft.

    Resistance

    Per conductor = R

    = .0525 ohms 1000 feet at 25C

    = .047 ohms for 750 feet at 75C

    Reactance

    Per conductor = X

    = .031 ohms 1000 feet (see table)

    = .028 ohms for 750 feet

    (including 20% for random lay)

    VS=

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    Solving for VL; VL= 240.4

    Line-to-line voltage = 240.4 = 417

    Voltage drop = 440 417 = 23 volts

    Approximate Formula:

    Voltage drop = line to neutral

    = Rl cos + Xl sin

    = 0.047 X 250 X .08 + 0.028 X 250 X 0.6

    = 9.4 + 4.2 = 13.6Line-to-line voltage drop = 13.6 = 23.5 volts

    Conductor ReactanceThe following table shows a nomogram for determining the reactance of any solid or concentric

    stranded conductor. This covers spacings encountered for conduit wiring as well as for open wire

    circuits. Various modifications necessary for use under special conditions are covered in notes on

    the nomogram. The reactances shown are for 60-Hertz operation.

    Where regulation is an important consideration several factors should be kept in mind in order to

    obtain the best operating conditions.

    Open wire lines have a high reactance. This may be improved by using parallel circuits but is much

    further reduced by using insulated cable. Three conductors in the same conduit have a lower

    reactance than conductors in separate conduits.

    Single conductors should not be installed in individual magnetic conduit because of the excessive

    reactance.

    Three conductors in magnetic conduit will have a somewhat higher reactance than cables in non-

    magnetic conduit.

    Reactance of conductors at 60Hz(Series inductive reactance to neutral)

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