v2+g level+fybch16 19,+20nvco08+electricity+and+magnetism+published
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8/3/2019 V2+G Level+FyBCh16 19,+20NVCO08+Electricity+and+Magnetism+Published
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FyBCh20; 16-19NVC08 Electricity and Magnetic Field NV-College
Physics B: FyBNVC08G-level test on Electricity and Magnetism Ch 16-19 & Ch 20
Instructions:
The Test Warning! There are more than one version of the test.
At the end of each problem a maximum point which one may get for a correct solution
of the problem is given.
Tools Approved formula sheets, ruler, and graphic calculator. You may use your green
personalized summary-formula-booklet which has your name on it. This should be
submitted along with the test.
Time: 8:00-10:00
The multi-choice problems must be answered on the original test paper.
Limits: This tests gives at maximum 36 points.
Pass (G): minimum 18 points
Qualified For a higher than G: minimum 24 points.
VG/MVG Qualified in this test, and filling the requirements in the
higher level test.
Please answer in this paper and as clear as possible. Do not forget the UNITS!Enjoy it! Behzad
Name:
16-20 C E PE E, B B C Q, B Q, B FB FB FB FB
P 1 2 3 4 5 6 7a 7b 7c 7d 7e 7d
G 2 2 1 2 2 2 2 2 2 2 2 2
G
16-20 C, E C, V C RC C, Q B, τ B, I Q, B Ch 16-20 Ch 16-20
P 8a 8b 8c 8d 8e 9 10 11 Total
G 1 2 2 2 2 1 3 2 38
G Q, B
Grade:
Teacher’s Comments
Student’s Comments
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1. Ten identical capacitors of capacitance F 1. Ten identical capacitors of capacitance F .10 are connected in series. The equivalent
capacitance of the combination is:
a) F 100
b) F μ 0.1
c) F 10.0
d) F μ .10
Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [1/0]
2. In the Bohr’s model of the hydrogen atom, an electron circles a proton at a distance
m1110 . The electric field that acts on the electron is3.5 −
×
a) m
V 11101.5 ×
b) m
V 32101.5 −
×
c) m
V 27
d) m
V 10−
82.8 ×
e) None above. It is: ______________________ Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [1/0]
3. The potential energy of a system of two charges decreases as the charges are moved
closer to each other.a) The two charges are both negative.
b) The two charges are both positive.
c) The two charges both have the same sign.
d) The two charges have different signs.
Answer: Alternative:______________ [1/0]
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FyBCh20; 16-19NVC08 Electricity and Magnetic Field NV-College
4. A moving electric charge produces4. A moving electric charge produces
a) only an electric field.a) only an electric field.
b) both an electric field and a magnetic field. b) both an electric field and a magnetic field.
c) only a magnetic field.c) only a magnetic field.
d) sometimes an electric field and sometimes a magnetic depending the direction of
its velocity.
d) sometimes an electric field and sometimes a magnetic depending the direction of
its velocity.Answer: Alternative ______________ [1/0]Answer: Alternative ______________ [1/0]
5. A proton enters a magnetic field parallel to5. A proton enters a magnetic field parallel to B .
a) The proton’s velocity remains the same, but its direction of motion is changed.
b) The proton’s velocity is changed, but its direction of motion remains the same.
c) Both proton’s velocity and its direction of motion remain the same.
d) Both proton’s velocity and its direction of motion are changed.
Answer: Alternative:______________ [1/0]
Why? Explain. [1/0]
6. Doubling the distance between the plates of a parallel plate capacitor of capacitance C
changes its capacitance to
a) 2
C
b) 4
C
c) C 2 d) C 4
Answer: Alternative:______________ [1/0]
Why? Explain. [1/0]
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7. An electron is shot into the region between the poles of a magnet. The initial velocity of
the electron is
7. An electron is shot into the region between the poles of a magnet. The initial velocity of
the electron is sm /1000.3 6× perpendicular to the direction of the magnetic field. The
magnetic field is uniform and its magnitude is
T 400.0 as illustrated in the figure.
Data: C eQ
19
1060.1
−×−=−=
,kgm
e
311011.9 −×=
C eQ19106.1 −
×−=−=
T B 40.0=
smv /100.3 6⋅=
a) The electron will
i) move straight and will not be deflected
by the magnetic field.
ii) will be deflected toward the left.
iii) will be effected toward the right.
iv) will be effected into the page.
v) will be effected out of the page.
vi) None above.
Answer: Alternative:______________ [1/0]
Why? Explain in a sufficient detail. [1/0]
b) The magnitude of the magnetic force on the electron is:
i) N 19 1092.1 −
×
ii) N 14102.1
−×
iii) N 13 1092.1 −
×
iv) J 13
10 92.1 −×
v) None. It is __________
Answer: Alternative:______________ [1/0]
Why? Explain and show your calculations in the space available below. [1/0]
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c) The electron in the uniform magnetic field will:c) The electron in the uniform magnetic field will:
i) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius m.42
i) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius m.42 7
ii) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius cm7
ii) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius cm7 .42
iii) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius mm.
iii) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius mm. 742
7
.42
742
iv) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius m
iv) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius m7.42
v) None above. See the calculation below.
Answer: Alternative:______________ [1/0]
Why? Explain and show your calculations in the space available below. [1/0]
d) If the polarity of the magnet is reversed, i.e. if the direction of the magnetic field is
changed,
i) the magnitude and the direction of the force remains the same.
ii) the magnitude of the force remains the same, but the direction of the force is
reversed.
iii) the magnitude of the force is reversed, but the direction of the force remains
the same.
iv) the magnitude of the force decreases, and the direction of the force is reversed.
v) the magnitude of the force increases, and the direction of the force is reversed.
vi) None above. It is ____________________________________
Answer: Alternative:______________ [1/0]
Why? Explain and show your calculations in the space available below. [1/0]
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e) If the electron is replaced by an alpha-particle, i.e. the nucleus of Helium, with the
charge e2+
e) If the electron is replaced by an alpha-particle, i.e. the nucleus of Helium, with the
charge e2+QQ =α
, and mass kgm 271065.6 −×=
α , keeping everything else the
same, compare the magnitude and the direction of the force on the electron, to the
magnitude and the direction of the force on the on the proton [1/0]
i) the magnitude and the direction of the force remains the same.
ii) the magnitude of the force is doubled, but the direction of the force remains thesame.
iii) the magnitude of the force is doubled, while the direction of the force is
reversed.
iv) the magnitude of the force is decreased by a factor of two, but the direction of
the force remains the same.
v) the magnitude of the force is decreased by a factor of two, while the direction
of the force is reversed.
vi) None above. It is _________________________________________________
Answer: Alternative ____________
Why? Explain. [1/0]
f) The α -particle in the uniform magnetic field will: [1/0]
i) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius m 6.15
ii) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius cm6.15
iii) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius mm6.15
iv) experience a centripetal acceleration, and as a result it will rotate in a circular
path of radius m6.15
v) None above. See the calculation below.
Answer: Alternative:______________
Why? Explain and show your calculations in the space available below. [1/0]
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8. A parallel plate capacitor, a resistor and a battery are connected as illustrated in the
figure below. The two parallel plates of the capacitor are
8. A parallel plate capacitor, a resistor and a battery are connected as illustrated in the
figure below. The two parallel plates of the capacitor are mm500.0 apart. The plates
are connected through a Ω M .100 resistor to a battery. When the plates are fully
charged, the electric field between the plates is mkV / ..200
a) Draw the electric filed lines as clear as possible on the figure. [1/0]
b) The electric potential difference between the plates is:
i) kV 0.10
ii) kV 00.1
iii) kV 100.0
iv) V 0.10
v) None above it is: ______________ Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [1/0]
c)
If the parallel capacitor has an area of
2
00. and a plate separation of 5 cmmm500.0 . Its capacitance is:
i. pF 85. 8
ii. nF 85. 8
iii. F 85. 8
iv. None. It is: _____________
Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [1/0]
R
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d) The time constant of the circuit isd) The time constant of the circuit is
i) 885 i) 885 ms.0
885
ms.0
ms885
.0
ii) . ii) . ms
iii) s.885 iii) s.885
iv) None. It is: _____________ iv) None. It is: _____________ Answer: Alternative:______________ [1/0]Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [1/0]Why? Show your calculations in the space available below. [1/0]
e) The total charge on the positive plate of the capacitor, when the capacitor is fully
charged is
e) The total charge on the positive plate of the capacitor, when the capacitor is fully
charged isi) nC 885 i) nC 885 .0
ii) nC 885 ii) nC 885
iii) C iii) C 5.88
iv) pC 85. 8
v) mC 85. 8
vi) None. It is: _____________
Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [1/0]
9. The physical reason for the electric motor is
a) the torque exerted on a current loop by an electric field.
b) the torque exerted on a current loop by an electromagnetic field.
c) the torque exerted on a current loop by a magnetic field.
d) the torque exerted on a current loop by first an electric field and then a magneticfield.
e) the torque exerted on a moving charge by a magnetic field.
f) the torque exerted on a moving charge by an electric field.
Answer: Alternative:______________ [1/0]
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10. A straight wire carrying a10. A straight wire carrying a A0.25 current has a
length cm0.10 between the poles of a magnet at
an angle °.30 as illustrated in the figure below.
The magnetic field is fairly uniform at T 00.4 .
The magnitude and direction of the force on thewire.°.30
A0.25
T 00.4
i) N .500 out of the page of the paper towards
the reader.
ii) N 00.5 out of the page of the paper towards the reader.
iii) N 00.5 into the page of the paper away from the reader.
iv) N .500 into the page of the paper away from the reader.
v) None. It is: _____________
Answer: Alternative:______________ [1/0]
Why? Show your calculations in the space available below. [2/0]
11. A charged particle moves in a circular path of radius r in a magnetic field B . The
velocity of the charged particle is doubled. The radius of the circular path of the charged
particle will be
a) r 4
b) r 2
c) r
d) 2
r
e) 4
r
Answer: Alternative:______________ [1/0]Why? Explain. [1/0]
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