unit v: the mole concept

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Unit V: The Mole Concept 5.1-5.2 – Atomic Mass, Avogrados Hypothesis, and the Mole (pg. 77-85, Hebden)

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Unit V: The Mole Concept. 5.1-5.2 – Atomic Mass, Avogrados Hypothesis, and the Mole (pg. 77-85, Hebden ). Today’s Objectives. Explain the significance of the mole, including: Recognize the significance of relative atomic mass, with reference to the periodic table - PowerPoint PPT Presentation

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Page 1: Unit V: The Mole Concept

Unit V: The Mole Concept

5.1-5.2 – Atomic Mass, Avogrados Hypothesis, and the Mole(pg. 77-85, Hebden)

Page 2: Unit V: The Mole Concept

Today’s Objectives Explain the significance of the mole, including:

Recognize the significance of relative atomic mass, with reference to the periodic table

Identify the mole as the unit for counting atoms, molecules, or ions

Perform calculations involving the mole, including: Determine the molar mass of an element or

compound

Page 3: Unit V: The Mole Concept

The Mole Question: how long would it take to spend a

mole of 1 Yuan coins if they were being spent at a rate of 1 billion coins per second?

Page 4: Unit V: The Mole Concept

What is a mole? Atoms are REALLY small! We can’t work with individual atoms or amu’s

(atomic mass units) in the lab Why? Because we can’t see things that small

Page 5: Unit V: The Mole Concept

The Mole Instead, we work with samples large enough for

us to see and weigh on a balance using units of grams

This creates a problem…. A pile of atoms big enough for us to see contains

billions of atoms! Billions of atoms are hard to keep track of in

calculations So, chemists made up a new unit:

THE MOLE

Page 6: Unit V: The Mole Concept

The Mole Just as a dozen eggs equals 12 eggs, a mole =

602,000,000,000,000,000,000,000 or 6.02x1023

It is equal to that number no matter what kind of particles you’re talking about

It could represent marbles, pencils, or chicken feet

Usually, the mole deals with atoms and molecules

The mole, whose abbreviation is mol, is the SI base unit for measuring amount of a pure substance

Page 7: Unit V: The Mole Concept

The Mole The mole, as a unit, is only used to count very

small items It represents a number of items, so, we can know

exactly how many items are in 1 mole The experimentally determined number a

mole is called is Avogrado’s Number, or 6.02x1023

The term representative particle refers to the species present in a substance: Atoms (most often) Molecules Formula units (ions)

Page 8: Unit V: The Mole Concept

Pop Quiz 1 dozen Mg atoms =

12 Mg atoms 1 mole Mg atoms =

6.02x1023 Mg Atoms 1 mole Mg(OH)2 =

6.02x1023 Mg(OH)2 molecules 1 mole O2 =

6.02x1023 O2 molecules

Page 9: Unit V: The Mole Concept

How big is a Mole? 1 Mole of soft drink cans is enough

to cover the surface of the earth to a depth of over 320 km

If you had Avogrado’s number of unpopped popcorn kernels, and spread them across China, the country would be covered in popcorn to a depth of over 15 km

If we were able to count atoms at the rate of 10 million per second, it would take about 2 billion years to count the atoms in one mole

Page 10: Unit V: The Mole Concept

Mollionaire Back to that question: How long would it take to

spend a mole of 1 Yuan coins if they were being spent at a rate of 1 billion per second?

Answer: ¥ 6.02 x 10^23/ ¥1 000 000 000 = 6.02 x 10^14 payments = 6.02 x 10^14 seconds 6.02 x 10^14 seconds/60 = 1.003 x 10^13 minutes 1.003 x 10^13 minutes/60 = 1.672 x 10^11 hours 1.672 x 10^11 hours/24 = 6.968 x 10^9 days 6.968 x 19^9 days/365.25 = 1.908 x 10^7 years It would take 19 million years!

Page 11: Unit V: The Mole Concept

How gases combine Early chemist John Dalton (1766-1844) wondered how

much of a given element would bond (react) with a given amount of another element

He did not assign an absolute mass for individual atoms of any given element, but rather assigned an arbitrary (relative) mass to each element

He assumed that hydrogen was the lightest and assigned hydrogen a unit mass of 1

Through experimentation, he determined that C was 6 times heavier than oxygen, so he assigned C a mass of 6

Oxygen was found to have a mass 16 times heavier than hydrogen, so he assigned O a mass of 16

Using this same process, he was able to determine the relative masses of all of the elements

Page 12: Unit V: The Mole Concept

John Dalton’s Experiment Looked at masses of gases

11.1g H2 reacted with 88.9g O2 Interpretation O2 is 8 times heavier (look at PT)

46.7g of N2 reacted with 53.3g O2 42.9g C reacted with 57.1g O2

No real pattern

Page 13: Unit V: The Mole Concept

Joseph Gay-Lussac Combined gas

1L of H2 reacts with 1L Cl2 2L of HCl 1L of N2 reacts with 3L H2 2L of NH3 2L of CO reacts with 1L O2 2L of CO2

Concluded that gases combine in simple volume ratios

But why aren’t the volumes of the reactants and products equal?

Page 14: Unit V: The Mole Concept

Avogrado’s Hypothesis Equal volumes of any gas at standard temperature and

pressure contain the same number of molecules Example:

1L of N2 reacts with 3L H2 2L of NH3 Lets say each volume contains 1 molecule, we could then

say: 1 molecule of N2 reacts with 3 molecules of H2 to form 2

molecules of NH3 Lets count the atoms to prove this: Reactants: 2 nitrogens, 6 hydrogens Products: 2 nitrogens, 6 hydrogens

Mass is always conserved in a chemical reaction, volume is not always conserved in a chemical reaction

Page 15: Unit V: The Mole Concept

Avogrado’s Hypothesis Let’s look at the other 2 examples (again

assuming each volume of gas contains 1 molecule):

1L of H2 reacts with 1L Cl2 2L of HCl Reactants: 2 hydrogen atoms, 2 Cl atoms Products: 2 hydrogen atoms, 2 Cl atoms

2L of CO reacts with 1L O2 2L of CO2 Reactants: 2 carbon atoms, 4 oxygen atoms Products: 2 carbon atoms, 4 oxygen atoms

If 2L of H2 reacts with 1L of O2, how many litres of H2O would be produced? 4 H, 2 O = 2H2O = 2L H2O

Do exercises 2-5 on p. 78

Page 16: Unit V: The Mole Concept

Who can explain this? Avogadro’s Hypothesis

Equal volumes of any gas at standard temperature and pressure contain the same number of molecules

This Explains the simple volume ratio for gases

Page 17: Unit V: The Mole Concept

Atomic Mass

The mass of 1 mole of atoms of an element. The mass of one mole of “C” atoms is 12.0g The mass of one mole of “Ca” atoms is 40.1g

Page 18: Unit V: The Mole Concept

Molar Mass (Molecular Mass)The mass of 1 mole of molecules of an element or compound

Page 19: Unit V: The Mole Concept

Diatomic Elements Some elements are naturally diatomic.

Remember the “gens” Hydrogen, nitrogen, oxygen, halogens

H2, O2, N2, F2, Cl2, Br2, I2, At2 you must remember these

Special elements Sometimes Phosphorus is P

Sometimes P4

Sometimes Sulphur is S Sometimes S8

Assume the rest of the elements are monatomic

Page 20: Unit V: The Mole Concept
Page 21: Unit V: The Mole Concept

Finding the Molar Mass of Compounds H2O = 2(1.0) + 16.0 = 18.0 g/mol Ca(NO3)2

= 40.1 + 2(14.0) + 6(16.0) = 164.1g/mol Ammonium phosphate

(NH4)3PO4

= 3(14.0) +12(1.0) + 31.0 + 4(16.0)= 149.0 g/mol

HMWK: p80 #6-7