unit 15 for issuu march 10 2012
DESCRIPTION
M 1 2 3 4 5 6 7 8 9 10 11 12 13 14 0 10 3 5 (NaOH Molarity)(NaOH volume) vinegar Molarity = vinegar volume molarity of known x liters of known Molarity of unknown = liters of unknown 180 g acetic acid3molesaceticacid 1 liter solution x x = = 18% Liter solution 1 mole acetic acid 1000 grams solution 1000 g solution 60 grams acetic acid TRANSCRIPT
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M
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0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
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3
5
10
10
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molarity of known x liters of knownMolarity of unknown =
liters of unknown
(NaOH Molarity)(NaOH volume) vinegar Molarity =
vinegar volume
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60 grams acetic acid 180 g acetic acid3 moles acetic acid 1 liter solution x x = = 18%
Liter solution 1 mole acetic acid 1000 grams solution 1000 g solution
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common name name formula
stomach acid hydrochloric acid HCl
hydrofluoric acid HF
hydrobromic acid HBr
hydrioidic acid HI
nitric acid HNO3
sulfuric acid H2SO4
phosphoric acid H3PO4
vinegar acetic acid CH3CO2H
lye sodium hydroxide NaOH
milk of magnesia magnesium hydroxide Mg(OH)2
calcium hydroxide Ca(OH)2
ammonia NH3
triethylamine (CH3CH2)3N
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6.0 x 10-11
[OH-]Acid
Orange juice10.221.66 x 10-43.78
Acid or base?
ExamplepOH[H+]pH
pH + pOH = 14[H+] = 10-pH
pH>7 = basepH<7 = acid
[H+][OH-] = 10-14
Use the change sign (-) button, not the subtract button
Enter 10^-14/1.66E-4
Enter 10^-3.78Enter 14-3.78
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