unified field explained 9

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Unified Field Explained 9

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Page 1: Unified Field Explained 9
Page 2: Unified Field Explained 9

¡  All  physical    constants  are  RATIOS  

¡  Every    RATIO  is  a  RATIO  between  two  charges  

¡  These  two  charges  move  following  the  law  of  Sin  and  Cosine  

¡  The  sum  of  both  functions  represent  the  total  field.  

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LEFT RIGHT

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LET  US  BEGIN  TAKING  A  SNAP  SHOT  AT  A  WAVE  MOVING  AHEAD:  

WE  HAVE    FOUND  THE  TWO  OPPOSED  FORCES    AT  REST  

ONE  TO  THE  LEFT  :    THE  COSINE    “Y  “  at    180°    =  -­‐1  ONE  TO  THE  RIGHT:  THE  SIN  “  Y”  at  0°  =  0  

   

 

Sin  Y=  0  Cos  Y=-­‐1  

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Sin  Y=  0  H  +  

Cos  Y=-­‐1  O  -­‐  

In  Order  to  make  it  less  abstract  we  put  two  opposite  forces:  Oxygen  to  the  left  and  Hydrogen  to  the  right  

Then  let´s  observe  them  move  45°    

Magnetism:  Sin    Y  =  +  0.70711  Cos  Y  =  +  0.70711  

 H-­‐OH  

Electricity  Sin  Y  =  +  0.70711  Cos  Y=    -­‐  0.7011  

 OH-­‐H  

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Sin  Y=  0  H+  

Cos  Y=-­‐1  O-­‐  

Magnetism:  Sin    Y  =  +  0.70711  Cos  Y  =  +  0.70711    

H-­‐OH  

Electricity  Sin  Y  =  +  0.70711  Cos  Y=    -­‐  0.7011    

OH-­‐H  

Now  we  have:  ELECTRICITY  and  MAGNETISM  at  an  angle  of  90°  between  them.  

And    ionized  Water  as  Hydrogen  Hydroxide  

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Sin  Y=  0  H+  

Cos  Y=-­‐1  O-­‐  

Magnetism:  Sin    Y  =  +  0.70711  Cos  Y  =  +  0.70711    

H-­‐OH  

Electricity  Sin  Y  =  +  0.70711  Cos  Y=    -­‐  0.7011    

OH-­‐H  

GRAVITY:  Sin  90°=    1  Cos  90°=  0  

G=    Sin  Y  +  Cos  Y  =  1  +  0  =  1    And        H2O    WATER!    (MATTER)  

 G  

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• When the two polar forces oppose, at sin 0°=0, and Cos 180°= -1 ,

the resultant field is 100% an EMISSION FIELD.

• When the two polar forces oppose at an angle of 90°, the resultant field is a MAGNETIC FIELD/ ELECTRICAL

FIELD

• When the two polar forces approach Sin 90°=1 and Cos 90°=0 both vectors add, changing direction 180°, thus the resultant force will oppose the emission field

and it is called Gravity

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So  Gravity  is  the  sum:    G  =  sin  y  +  cos  y    

G  =  1  +  0    Which  means  that  the  resultant  force  will  be  

equal  to  1,  or  almost  one,  as  0.981  .  Now,  G,  the  constant,  the  gravitational  constant,  in  Newton

´s  equation:    F=G  (M1M2)/r2    

Actually  represents  the  sine  added  to  the  cosine  of  the  angle  equal  to  90°    

G  =  Sin  y  +  Cos  y  =  1  –  0  =  1  Note:  We  have  divided  G/10=0.981  

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So the Max Planck´s equation: E= hν

h = Sin y + Cos y

ν=C/λ

Becomes the equation of the Unified Field:  

E= (Sin y + Cos y)x ν  or

 E= (Sin y + Cos y)(C/λ)

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79°  Gravity  

Elec

tricity

 

Magnetism  

Earth  Gravity=  9.81  Nm    10  –  9,81  =  0.19  Sin  0.19  =  78.5°  

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78.5°  

Gravity  at  the  northen  hemisphere  

78.5°  

Gravity  at  the  southern  hemisphere  

11.5°  

Ecliptic  

Sin    23°=0.391  

The  two  vectors  of  Gravity  add,  Giving  as  the  result  the  inclination  of    axis    of  the  Earth  on    Ecliptic  

23°  

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The Pythagorean Monochord

1

1

2 =1.414….. +  

Electricity  Sin  Y  =  +  0.70711  Cos  Y=    -­‐  0.7011  

Magnetism:  Sin    Y  =  +  0.70711  Cos  Y  =  +  0.70711

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Pythagoras Monochord

Terra: Earth, Solid

Aqua: Water, Liquid

Ignis :Fire, Plasma

Aer : Air, Gas

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The eccentricity of planets´orbits it is

related to the intensity of the emission field =

Cos y

Mercury eccentricity= 0.21AC  Phase  angle  Deg.: 22.33 Cos  y  (grades) Cos  y

78.14 168.14 -­‐0.978636Gravity  (sin  y) Field  (-­‐cos  y) EM  field

Φ= 0.38 -­‐0.98 -­‐0.5987 -­‐5.99 NmVenus eccentricity= 0.01

AC  Phase  angle  Deg.: 64.16 Cos  y  (grades) Cos  y89.61 179.61 -­‐0.999977

Gravity  (sin  y) Field  (-­‐cos  y) EM  fieldΦ= 0.90 -­‐1.00 -­‐0.1000 -­‐1.00 Nm

Earth eccentricity= 0.02AC  Phase  angle  Deg.: 78.81 Cos  y  (grades) Cos  y

1.38 89.04 179.04 -­‐0.999861Gravity  (sin  y) Field  (-­‐cos  y) EM  field

Φ= 0.98 -­‐1.00 -­‐0.0189 -­‐0.19 NmMoon  (a) eccentricity= 0.03

AC  Phase  angle  Deg.: 38.46 Cos  y  (grades) Cos  y88.51 178.51 -­‐0.999662

Gravity  (sin  y) Field  (-­‐cos  y) EM  fieldΦ= 0.62 -­‐1.00 -­‐0.3777 -­‐3.78 Nm

Moon  (b) eccentricity= 0.08AC  Phase  angle  Deg.: 22.33 Cos  y  (grades) Cos  y

85.58 175.58 -­‐0.997031Gravity  (sin  y) Field  (-­‐cos  y) EM  field

Φ= 0.38 -­‐1.00 -­‐0.6170 -­‐6.17 NmMars eccentricity= 0.09

AC  Phase  angle  Deg.: 22.33 Cos  y  (grades) Cos  y84.64 174.64 -­‐0.995629

Gravity  (sin  y) Field  (-­‐cos  y) EM  fieldΦ= 0.38 -­‐1.00 -­‐0.6156 -­‐6.16 Nm

Jupiter eccentricity= 0.05AC  Phase  angle  Deg.: -­‐39.79 Cos  y  (grades) Cos  y

87.23 177.23 -­‐0.998833Gravity  (sin  y) Field  (-­‐cos  y) EM  field

Φ= 2.64 -­‐1.00 1.6412 16.41 NmSaturn eccentricity= 0.06

AC  Phase  angle  Deg.: 68.43 Cos  y  (grades) Cos  y86.79 176.79 -­‐0.998431

Gravity  (sin  y) Field  (-­‐cos  y) EM  fieldΦ= 0.93 -­‐1.00 -­‐0.0684 -­‐0.68 Nm

Uranus eccentricity= 0.05AC  Phase  angle  Deg.: 62.87 Cos  y  (grades) Cos  y

87.36 177.36 -­‐0.998937Gravity  (sin  y) Field  (-­‐cos  y) EM  field

Φ= 0.89 -­‐1.00 -­‐0.1089 -­‐1.09 NmNeptune eccentricity= 0.01

AC  Phase  angle  Deg.: -­‐6.89 Cos  y  (grades) Cos  y89.44 179.44 -­‐0.999953

Gravity  (sin  y) Field  (-­‐cos  y) EM  fieldΦ= 1.12 -­‐1.00 0.1200 1.20 Nm

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A proof of Mercury´s emission field

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It is obvious that at Sin y= 90°the Emission Field is at its Maximum and the Gravity Field, being equal to

Cos y=0 is at its Minimum, so the Emission Field is at its Minimum at

Sin y=270°=-1and the Gravity Field is at its Maximum at Cos y=270°=0

Thus: • The lesser the emission field the greater the

gravity (mass) field:

• E = (Sin y + Cos y)(C/λ)

We have adopted the notation Where the Maximum EM Field “Repulsion” be expressed as

A NEGATIVE VALUE/CHARGE

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Sin y + Cos Y إإمماامم إإمماامم √2

1 1

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The Unified field

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A wave……..

EVERYTHING IS ELECTRIC AND EVERY PHENOMENON IN NATURE IS AN ALTERNATE CURRENT”…..AT DIFFERENT

PHASE ANGLES BETWEEN THE TWO OPPOSITE FORCES

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In order to know how Energy develops following The Unified Field Law, let us do: E = ( S i n y + C o s y ) x ν E= (Sin y * ν ) + (Cos y * ν ) T h u s , l e t u s t a k e s o m e k n o w n f r e q u e n c i e s ; S o u n d f r e q u e n c i e s a n d p l o t t h e m :

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WE GET A LOGARITHM SPIRAL The perfect expression of Power from a Birkeland Current, or an Alternate Current or……

Andromeda galaxy, under IR light,

where all the Suns look connected

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SPIRAL APPEARED IN NORWAY DEC.9TH. 2009

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The FIBONACCI series The Way of Nature The Way of The Unifed Field!

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Sin  Y=  0  Cos  Y=-­‐1  

EMISSION        FIELD  

GRAVITY      FIELD  

45  °  45  °  

Sin  Y  +    Cos  Y  

180°  

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Adolfo Rios Pita Giurfa