tutormansor wordpress com latihan matematik tingkatan 4 07 probability i answer
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https://tutormansor.wordpress.com/ Latihan Matematik Tingkatan 4
Exercise Mathemtics Form 4
Bab 07 – PROBABILITY I
Chapter 07 – KEBARANGKALIAN I
JAWAPAN / ANSWER
Question: http://goo.gl/AwxcsW
EXERCISE 1
1) {1, 2, 3, 4, 5, 6}
(a) {1, 3, 5}
(b) {3, 6}
2) {N, E, R, 2, 9, 3, 8}
(a) Set P {𝑵𝑵,𝑬𝑬,𝑹𝑹}.
(b) Set Q {𝑵𝑵,𝑹𝑹,𝟗𝟗,𝟑𝟑}.
3) {𝑃𝑃,𝑅𝑅,𝑂𝑂,𝐵𝐵,𝐴𝐴,𝐵𝐵, 𝐼𝐼, 𝐿𝐿, 𝐼𝐼,𝑇𝑇,𝑌𝑌}
Elements {𝑃𝑃,𝑅𝑅,𝑂𝑂,𝐵𝐵,𝐴𝐴, 𝐼𝐼, 𝐿𝐿,𝑇𝑇,𝑌𝑌} = 9 elements
4) Coins {𝐻𝐻𝐻𝐻𝐻𝐻𝐻𝐻,𝑇𝑇𝐻𝐻𝑇𝑇𝑇𝑇}
(a) {(𝑯𝑯𝑯𝑯𝑯𝑯𝑯𝑯,𝑯𝑯𝑯𝑯𝑯𝑯𝑯𝑯), (𝑻𝑻𝑯𝑯𝑻𝑻𝑻𝑻,𝑻𝑻𝑯𝑯𝑻𝑻𝑻𝑻)}
(b) {(𝑯𝑯𝑯𝑯𝑯𝑯𝑯𝑯,𝑻𝑻𝑯𝑯𝑻𝑻𝑻𝑻), (𝑻𝑻𝑯𝑯𝑻𝑻𝑻𝑻,𝑯𝑯𝑯𝑯𝑯𝑯𝑯𝑯)}
5) _ 8𝑥𝑥
=27
𝑥𝑥 =72
× 8
𝒙𝒙 = 𝟐𝟐𝟐𝟐
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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6) _ 25
× 365 = 𝟏𝟏𝟏𝟏𝟏𝟏 𝐻𝐻𝐻𝐻𝑑𝑑𝑑𝑑
7) Hari Raya Cards
Family = 5, Relatives = 10, Friends = 15
Total = 30
(a) Send by family
530
=𝟏𝟏𝟏𝟏
(b) Not sent by her relatives
5 + 1530
=2030
=𝟐𝟐𝟑𝟑
8) Probability for red marble 120280
=𝟑𝟑𝟕𝟕
Probability of green marble 14
=𝑥𝑥
280
𝑥𝑥 =14
× 280
= 70
Probability for white marbles
1 −14−
37
=9
28
White marbles 𝑑𝑑
280=
928
𝑑𝑑 =9
28× 280
= 90
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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9) Girl = 80, Boy = 115 − 80 = 35
After, Boy = 35 + 5 = 40
Probability
40115 + 5
=𝟏𝟏𝟑𝟑
10) Red = 75, Green = 90, Blue = 𝑥𝑥.
(a) Red 14
=75
75 + 90 + 𝑥𝑥
=75
165 + 𝑥𝑥
165 + 𝑥𝑥 = 75(4)
165 + 𝑥𝑥 = 300
𝑥𝑥 = 300 − 165
= 𝟏𝟏𝟑𝟑𝟏𝟏
(b) If the number of student is small, the probability still same. Probability for green 90
75 + 90 + 135=
90300
=3
10
No of student from 100 3
10× 100 = 30 students
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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Exercise 2
1) Blue balls = 3, white balls = 4, green balls = 2
3 elements
2) {𝑂𝑂,𝐴𝐴, 𝐼𝐼}
3) All the possible outcomes
{(𝐻𝐻,𝐻𝐻,𝐻𝐻), (𝑇𝑇,𝐻𝐻,𝐻𝐻), (𝐻𝐻,𝑇𝑇,𝐻𝐻), (𝐻𝐻,𝐻𝐻,𝑇𝑇), (𝐻𝐻,𝑇𝑇,𝑇𝑇), (𝑇𝑇,𝐻𝐻,𝑇𝑇), (𝑇𝑇,𝑇𝑇,𝐻𝐻), (𝑇𝑇,𝑇𝑇,𝑇𝑇)}
Anwers : {(𝑻𝑻,𝑯𝑯,𝑯𝑯), (𝑯𝑯,𝑻𝑻,𝑯𝑯), (𝑯𝑯,𝑯𝑯,𝑻𝑻)}
4) Red = 5, Black = 7, Yellow = 3
Probability of red 5
5 + 7 + 3=
515
=13
5) 28 teams 14
× 28 = 7 teams
6) Total employees = 550 15
= 550
= 110 employees
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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7) Green = 24, Blue = 𝑥𝑥
Probability green 8
10=
2424 + 𝑥𝑥
8(24 + 𝑥𝑥) = 24(10)
192 + 8𝑥𝑥 = 240
8𝑥𝑥 = 240 − 192
= 48
𝑥𝑥 =488
= 6
8) 36 numbers card
Probability of odd number
1 −16
=56
56
× 36 = 30
9) Red = 30, Black = 50, Blue = 𝑥𝑥
Probability of black pen
516
=50
30 + 50 + 𝑥𝑥
=50
80 + 𝑥𝑥
5(80 + 𝑥𝑥) = 16(50)
400 + 5𝑥𝑥 = 800
5𝑥𝑥 = 800 − 400
= 400
𝑥𝑥 =400
5
= 𝟐𝟐𝟖𝟖
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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10) List number that can divide by 4 from 1 – 30 {4,8,12,16,20,24,28} 𝟕𝟕𝟑𝟑𝟖𝟖
Diagnostic Test
1) Girls = 35, Boys = 45 − 35 = 10
New, Boys = 10 + 5 = 15, Total students 45 + 5 = 50
Probability of boys student 1550
=𝟑𝟑𝟏𝟏𝟖𝟖
𝑨𝑨
2) Total = 270 (Orange, Lychee, Coffee), Orange = 48, Prob. lychee 13
𝑇𝑇𝑑𝑑𝑙𝑙ℎ𝐻𝐻𝐻𝐻, 13
× 270 = 90, Coffee = 270 − 48 − 90 = 𝟏𝟏𝟑𝟑𝟐𝟐 𝑩𝑩
3) Multiple of 4 {16, 28, 60, 84}
46
=𝟐𝟐𝟑𝟑
𝑨𝑨
4) Friends = 6, Relatives = 5, Brothers = 2
Probability not sent to her brothers
6 + 56 + 5 + 2
=𝟏𝟏𝟏𝟏𝟏𝟏𝟑𝟑
𝑫𝑫
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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5) Boys = 18, Girls = 𝑘𝑘
Probability of girl
47
=𝑘𝑘
18 + 𝑘𝑘
4(18 + 𝑘𝑘) = 𝑘𝑘(7)
72 + 4𝑘𝑘 = 7𝑘𝑘
72 = 7𝑘𝑘 − 4𝑘𝑘
= 3𝑘𝑘
𝑘𝑘 =723
= 𝟐𝟐𝟏𝟏 𝑩𝑩
6) Total shirt = 20
Probability of green = 15100
15100
× 20 = 𝟑𝟑 𝑨𝑨
7) Wear watches = 15, Not Wear Watches = 𝑥𝑥
Probability of wear watches = 35
35
=15
15 + 𝑥𝑥
3(15 + 𝑥𝑥) = 15(5)
45 + 3𝑥𝑥 = 75
3𝑥𝑥 = 75 − 45
= 30
𝑥𝑥 =303
= 10
New wear watches= 15 − 3 = 12, new total = (10 + 15) − 3 = 22
Probability for wearing watch 1222
=𝟏𝟏𝟏𝟏𝟏𝟏
𝑪𝑪
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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8) Red = 40, White = 𝑥𝑥
Probability of white buttons
57
=𝑥𝑥
𝑥𝑥 + 40
5(𝑥𝑥 + 40) = 𝑥𝑥(7)
5𝑥𝑥 + 200 = 7𝑥𝑥
200 = 7𝑥𝑥 − 5𝑥𝑥
= 2𝑥𝑥
𝑥𝑥 =200
2
= 𝟏𝟏𝟖𝟖𝟖𝟖 𝑩𝑩
9) Probability of Team P win 12, loss 1
2
Probability of Team Q win 27, loss 5
7
Probability for P win, Q win 12
×27
=2
14
=𝟏𝟏𝟕𝟕
𝑨𝑨
10) Total eggs = 100
Probability
𝐴𝐴 =14
,𝐵𝐵 =25
,𝐶𝐶 = 1 −14−
25
=7
20
Number of eggs of Grade C 7
20× 100 = 𝟑𝟑𝟏𝟏 𝑩𝑩
ANSWER / JAWAPAN CHAPTER 07 – PROBABILITY I (MATHEMATICS FORM 4) BAB 06 – KEBARANGKALIAN I (MATEMATIK TINGKATAN 4) © HAK CIPTA TERPELIHARA JAN 2015 https://tutormansor.wordpress.com/
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