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  • 7/27/2019 Tutorial Fatigue

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    FUNDAMENTALS OF MACHINE DESIGN AND DRAWING (A.Y. 2013-2014)

    TUTORIAL # 1 FATIGUE

    EXERCISE # 1

    Generate a Haigh diagram at infinite life for a steel material.Take: Rm =1180 MPa, Rp02 =880 MPa, D-1 =480 MPa - fatigue limit for alternate symmetric cycles (R= -1).

    EXERCISE # 2

    For a steel material, with fatigue limit for alternate symmetric cycles D-1=250 MPa and ultimate tensile

    strengthRm =600 MPa, compute the alternate stress level corresponding to a life to failure of 105

    cycles.

    [a =339 MPa]

    EXERCISE # 3

    For a steel material (Rm=700 MPa, D-1=300 MPa) subjected to an alternate symmetric cycle with an

    alternate stress level ofa=420 N/mm2, compute the number of cycles to failure.

    [N=6.37 10

    4cycles]

    EXERCISE # 4

    A solid circular shaft with diameter d=30 mm is subjected to a bending moment having of mean value

    Mfm=600 Nm and alternating value Mfa=200 Nm.

    The shaft is made from steel (Rm=1000 MPa, Rp02 =800 MPa, D-1 =450 MPa) with a machined surface

    finish (RA = 1.6m).

    Use the Haigh diagram to compute the factor of safety to infinite life. Consider both the case of average

    stress constant and alternate stress varying with performance (CASE A) and the case of average stress and

    alternate stress varying with performance (CASE B).

    [SF=3.8 (case A); SF= 2.3 (case B)]

    EXERCISE # 5

    A 25 x 25 mm square bar with a rough lathe finish (RA = 6.3m) is subjected to a zero to maximum (stress

    ratio R=0) tension cycle with Fmax=105

    N.

    Use the Haigh diagram (material steel: Rm=1180 MPa, Rp02=880 MPa, D-1=690 MPa) to compute the factor

    of safety to infinite life.

    [SF=4.8 (case A); SF= 3.8 (case B)]

    EXERCISE # 6

    A machined steel beam with solid circular cross section is subjected to an axial loading cycle between

    Fmax=5105

    N and Fmin=1105

    N.

    Use the Haigh diagram (Rm=1180 MPa, Rp02=880 MPa, D-1=680 MPa) to determine the diameter of the

    beam which can ensure a factor of safety SF =1.5 with respect to yielding and SF=3 with respect to infinite

    life (refer to the case of average stress and alternate stress varying with performance). Consider a machined

    surface finish (RA=1.6 m).

    For the designed beam, estimate the factor of safety to infinite life for the following axial loading cycles:

    a) Fmax=0 N and Fmin=-7105

    N;

    b) Fmax=+3.5105

    N and Fmin=-3.5105

    N;

    c) Fmax=+7105

    N and Fmin=0 N.[d = 52 mm; a)SF= 4.5; b) SF=2.7; c) SF=2.0]

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    EXERCISE # 7

    M M

    r

    F F

    D d

    A notched rotating shaft is subjected to a constant

    bending moment Mf=250 Nm and to a constant axial

    force F=30 kN. Compute the factor of safety withrespect to infinite life, considering that it is the

    bending moment that may increase during operation.

    Take: D=45 mm, d=40 mm, r=3 mm, RA= 0.8 m

    Material properties: Rm =640 MPa, Rp02=420 MPa,

    D-1=300 MPa

    [SF=3.4 (CF=1; CS= 0.83; Kf= 1.57)]

    EXERCISE # 8

    A stepped rotating shaft, loaded by an end-load F, must endure under nominal working conditions.

    Use the Haigh diagram to compute the factor of safety with respect to yielding and to infinite life.

    Take: F = 3.5 kN, D = 45 mm, d = 38 mm, r = 1.5 mm, L = 180 mm, l = 90 mm.

    Material: Rm = 900 MPa, Rp02 = 635 MPa, D-1= 450 MPa, RA= 1.6 m.

    D

    r

    F

    Notch geometry at support B

    A B

    L l

    d

    [Yielding SF= 10.7; infinite life SF= 3.4 (CF=0.95; CS= 0.85; Kf= 1.78)]