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Department of Mathematics
National University of Singapore
2014/15 Sem II MA3201 Algebra II Tutorial 5
(1) Let R be a subring of an integral domain S, and suppose R is a PID. Let a 2 R
be a greatest common divisor of r1 and r2 in R (r1, r2 2 R, not both zero). Prove
that if b 2 S is a common divisor of r1 and r2 in S, then b | a in S. Show by a
counter-example that the conclusion is invalid if R is a UFD, but not a PID.
(2) Let R be a commutative ring with 1, and let R[X, Y ] denote the set of all polynomials
in two variables X and Y with coe�cients in R.
(a) Prove that R[X, Y ] = S[Y ] where S = R[X].
(b) Suppose R is a UFD. Show that R[X, Y ] is a UFD.
(c) If R is a field, is R[X, Y ] a PID/Euclidean domain?
(3) Factor x3 � y
3 into irreducibles in Q[x, y] and prove that each of the factors is irre-
ducible.
(4) Let F be a field. Prove that if f(x) 2 F [x] and f(a) = 0 for some a 2 F , then f(x)
is reducible if deg(f) > 1.
(5) Factorize x
3 + 3x2 + 3 in Z5[x] and x
4 � x
2 + 1 in Z7[x] into product of irreducibles.
(6) Prove that the following polynomials in Z[X] are irreducible in Q[X].
(a) pX
2 + aX + q, where p and q are prime integers, and a 6= ±(p+ q),±(1 + pq).
(b) aX
2 + bX + c, where a, b and c are odd integers.
(c) X
4 � 5X2 +X + 1.
(7) Let R be a UFD, and let f(X) 2 R[X] be a primitive polynomial. Prove that if
g(X) | f(X) in R[X], then g(X) is primitive.
(8) Let R be a ring. Prove that if R[X] is a UFD, then so is R.
(9) Let R be a UFD, with field of fraction F , and let f(X) = a0+a1X+· · ·+anXn 2 R[X]
with an 6= 0. Let x 2 F be a root of f(X). Show that x = rs for some r, s 2 R, s 6= 0
satisfying r | a0 and s | an in R.
(10) Prove that the following polynomials are irreducible in R[X]:
(a) f(X) =Pp�1
i=0 (�1)iX i where p is a prime integer, R = Z.(b) f(X) = X
6 +X
3 + 1, R = Q. (Hint: Try Y = X � 1.)
(c) f(X) = X
3 � 6X2 + 4iX + (1 + 3i), R = Z[i].1
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Challenging Problem
Let R be a commutative ring. Prove that R has ACCP if and only if every non-empty
collection of principal ideals of R has a maximal element.
Prove further that if R is an integral domain and has ACCP, then R[X] has ACCP.
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