tugas analisa 3_d121_ ip2

REPORT OF ANALYSIS ASSIGNMENT 3

LAB WORK OF COMPUTER SIMULATION

Arranged by:

Wildan Adiwena (12522107)

Imam Mukhri (12522276)

Group IP-02

ASSISTANT CODE : D – 121

INDUSTRIAL ENGINEERING DEPARTMENT

FACULTY OF INDUSTRIAL TECHNOLOGY

UNIVERSITAS ISLAM INDONESIA

YOGYAKARTA

2015

1. CASE STUDY 1

a. Printscreen Layout

Figure 1.1 Layout Case Study 1

b. Description of Case Study

In this Post Office, there are queuing systems, the researcher make a queuing

model using Flexsim software. The location of this post office is contain from

door, exit 1, queue, teller, exit 2. The probability of arrival customer is one

customer come every 60 seconds, so the researcher type exponential (0.60.1)

in source. The new customer will directly go if see in queue there are more

than 20 customers waiting, then that new customer will indicated “unsatisfied

customer”. Then the time of customer when come in and process in teller is

lognormal2 (31,3.1,0.5).

c. Analysis of Report based on question

Tabel 1.1 Summary Report Study Case 1

Object Classstats_

content

stats_

content

min

stats_

content

max

stats_

content

avg

stats_

input

stats_

output

stats_

stay

time

min

stats_

stay

time

max

stats_

stay

time

avg

state_

current

state_

since

Exit 2 Sink 0 0 0 0 0 0 0 0 0 7 0

Queue Queue 0 0 3 0.22 104 104 0 102.84 14.90 6 7118.81

TellerProcesso

r0 0 1 0.50 104 104 32.10 43.44 34.55 1 7151.97

Exit 2 Sink 1 1 1 0 104 0 0 0 0 7 0

Source5 Source 0 0 0 1 0 104 0 0 0 5 7318.81

Table 1.2 State Report Study Case 1

Object Class idle processing Busy Blocked generating empty collecting releasing

Waiting

for

operator

Waiting

for

transporter

breakdown

Exit 2 Sink

Queue Queue 0.00% 0.00% 0.00% 0.00% 0.00% 83.74% 0.00% 16.26% 0.00% 0.00% 0.00%

Teller Processor 49.75% 50.25% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Exit 2 Sink

Source5 Source 0.00% 0.00% 0.00% 0.00% 100.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Object Classscheduled

downconveying

travel

empty

travel

loaded

offset

travel

empty

offset

travel

loaded

loading unloading down setup utilize

Exit 2 Sink

Queue Queue0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

0.00

% 0.00% 0.00% 0.00%

Teller Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00 0.00% 0.00% 0.00%

%

Exit 2 Sink

Source5 Source0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

0.00

% 0.00% 0.00% 0.00%

1. How much customers who aren’t satisfied and is served until finish?

Answer: Based on summary report, there is no unsatisfied customer because the

number in queue never reach more than 20 customers. This conclusion get from

object queue, class queue in stat_contentmax only get 3 and this argument

supported also by object Exit 2 in class sink which stats_input 0 in summary

report. It means that there is no customer aren’t satisfied before processing by

teller then there are 104 satisfy customer until finish.

2. How much customer was served by the post office? (teller)

Answer: Based on summary report in object Teller, class processor in stat_output

are 104. It means that there are 104 customer was served by the post office.

3. How is the performance of server (teller)?

Answer: We can see the performance of server based on state report from idle and

processing the server, which are idle 49.75%, and processing 50.25%. It can be

concluded that the performance of the server (teller) into the less well because the

server has a large idle.

4. What is the queue condition in the system?

Answer: From the state report, the percentage of allowing customer from queue to

teller is 16.26%, then percentage queue empty is 83.74% because customer wait in

queue not reached 20 customers and not busy.

d. Summary

In this model, there is no unsatisfied customer; 104 customers are the total

customers that can be served until finish. In the teller there are idle time is

49.75%, and processing time 50.25%. The process of queue is smoothly because

customer wait in queue not reached 20 customers and not busy.

2. CASE STUDY 2




In this Post Office, there are queuing systems, the researcher make a queuing

model using Flexsim software. The location of this post office is contain

from door, exit 1, queue, teller, exit 2. The probability of arrival customer is

one customer come every 60 seconds, so the researcher type exponential

(0.60.1) in source. The new customer will directly go if see in queue there are

more than 20 customers waiting, then that new customer will indicated

“unsatisfied customer”. Then the time of customer when come in and process

in teller is lognormal2 (31,3.1,0.5).and there are additional teller in this

model, so after queue, the model set the 40% customer will go to Teller 1 and

60% customer will go to Teller 2.


Table 2.1 Summary Report Case 2

Object Classstats_

content

stats_

content

min

stats_

content

max

stats_

content

avg

stats_

input

stats_

output

stats_

stay

time

min

stats_

stay

time

max

stats_

stay

time

avg

state_

current

state_

since

Exit 2 Sink 0 0 0 0 0 0 0 0 0 7 0

Queue Queue 0 0 2 0.031517 112 112 0 33.038128 1.985143 6 7054.554144

Teller 1 Processor 0 0 1 0.216634 44 44 31.971191 39.37447 34.902947 1 7089.036798

Exit 1 Sink 1 1 1 0 112 0 0 0 0 7 0

Source5 Source 0 0 0 1 0 112 0 0 0 5 7054.554144

Teller 2 Processor 0 0 1 0.101788 68 68 10 10 10 1 6680.541074

Table 2.2 State Report Case 2

Object Class idleprocessin

gbusy blocked

Generatin

gEmpty

collectin

greleasing

waiting

for

operato

r

Waiting

for

transporter

Break

down

scheduled

down

Exit 2 Sink

Queue Queue 0.00% 0.00% 0.00% 0.00% 0.00% 96.85% 0.00% 3.15% 0.00% 0.00% 0.00% 0.00%

Teller 1 Processor 78.34% 21.66% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Exit 1 Sink

Source

5 Source 0.00% 0.00% 0.00% 0.00% 100.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Teller 2 Processor 89.82% 10.18% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Object Class conveying travel emptytravel

loaded

offset travel

empty

offset

travel

loaded

loading Unloading down setup utilize

Exit 2 Sink

Queue Queue 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Teller 1 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Exit 1 Sink

Source5 Source 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Teller 2 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

1. What is the performance difference after added on server? (compare with

case study 1)

Answer: The different is, in case study 2, there are 2 teller that can make

services process more optimal, with total customer served is 112 customer,

which teller 1 are services 44 customers, and teller 2 services 68 customers.

2. How much costumer type 2 was served?

Answer: To determine the number of customer that can be served on type

2, can be seen from the comparison object, and then select a total of two

outs and teller to see its results. From the chart picture, it is known to result

in type 2 28 people that can be served by tellers 1, and 37 people can be

served by tellers 2.

Figure 3.2 Comparison Objective Step

Figure 3.3 Comparison Objective customer type 2 diagram in teller 1

and 2

3. How much is the minimal and maximal wait time in the server?

Answer: Based on summary report, the stats_staytimemin is 0 and

stats_staytimemax is 33.038128.

4. What will happen when the queue capacity is reduced to 1?

Answer: If the queue capacity reduced to 1, it will make disappoint the

customer because based on summary report in object queue, class queue in

stat_contentmax are 2. It means that since the simulation occurs with 2

teller there are probability that there are 2 customer will wait in queue.

d. Summary

from all of the answer above in case study 2, additional Teller can make services

and queuing process more optimal, with total customer served is 112 customer,

which teller 1 are services 44 customers, and teller 2 services 68 customers. And

the stats_staytimemax in case study 2 is more decrease than stats_staytimemax

in case study 1.

3. CASE STUDY 4




The component of electonic will be testing firstly after manufacturing

process. There are 2 type component arrived in Queue randomly where

40% type 1 and 60% type others. The time between arrival from

component is exponential(0,30,0). There are 2 inspection machine for

component 1, 3 inspection machine for component 2. The component

will go to machine that firstavailable. The all inspection time between

120 until 150 seconds and uniform distribution.


Object Classstats_

content

stats_

content

min

stats_

content

max

stats_

content

avg

stats_

input

stats_

output

stats_

stay

time

min

stats_

stay

time

max

stats_

stay

time

avg

state_

current

state_

since

Source1 Source 0 0 0 1 0 253 0 0 0 5 7128.256977

Queue2 Queue 8 0 19 9.202494 253 245 0 997.155334 258.960789 8 7128.256977

Processor3 Processor 1 0 1 0.977671 53 52 120.193741 149.608994 134.693596 2 7164.034762





Sink8 Sink 1 1 1 0 240 0 0 0 0 7 0



Object Class idleprocessin

gbusy

blocked

generating

emptycollectin

greleasin

g

Waitingfor

operator

waitingfor

transporter

Breakdown

scheduled

down

Source1 Source 0.00% 0.00% 0.00% 0.00% 100.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Queue2 Queue 0.00% 0.00% 0.00% 0.00% 0.00% 1.56% 0.00% 98.44% 0.00% 0.00% 0.00% 0.00%

Processor3

Processor 2.23% 97.77% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Processor4

Processor 2.45% 97.55% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Processor5

Processor 10.50% 89.50% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Processor6

Processor 11.32% 88.68% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Processor7

Processor 16.15% 83.85% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Sink8 Sink

Object Class conveying

travel empty

travel loaded

offset travel empty offset travel loaded loading Unloading down setup utilize

Source1 Source 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Queue2 Queue 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Processor3 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor4 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor5 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Processor6 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor7 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%

Sink8 Sink

1. Are the three inspection machines for component 2 working in

balance?

Answer: Yes, because in state report processing percentage for the

second component inspection machine doesn’t show significant

difference (89.5%; 88.68%; 83.85%). This is also supported by the

summary report which is also show there is no significant difference

for input (49; 47; 45) and output (48; 46; 44) of the second

component inspection machines.

2. How is the last condition of inspection machine when the simulation

ended?

Answer:

Object state_current Condition

Processor3 2 Processing





3. How much item type 1 and 2 has been inspected? Is there a

significant difference?

Answer: Item type 1 has been processed is 102 item while item type

2 is 138. It gets based on summary report in class processor which

are for type 1 the objective is processor 3 and 4 with stats_output 52

and 50 and type 2 the objective is processor 5, 6, and with

stats_output 48, 46, and 44 . There is a quite significant difference

because the comparison of type 1:type 2 is 40:60.

4. How is the system performance based on total items in and out of

the system?

Answer: Based on the total input and output of system there is a

slightly difference where total input are 253 and total output are 240.

It gets from summary report in the objective Source1, class Source

in stats_output that are 253 and the objective Sink8, class Sink in

stats_input are 240. It means that the performance of the system

based on total items in and out is not quite optimal yet.

d. Summary

It can be inferred that the process is running quite smoothly and the

process is still running after 2 hours with quite proportional input and

output. The allocation of burden in 3 inspection machine in component

type 2 is quite balance. The last 2 hours still remain process in every

inspection machine.

5. CASE STUDY 5




3 kinds of product (uniform distribution) enter to 5 work station cell.

Product will be porcess at station that have determined as:

a. Product 1 will be processing at station 1,3, and 2

b. Product 2 will be processing at station 1,2, and 4

c. Product 3 will be processing at station 2,4,3, and 5


Object Classstats_content

stats_contentmin

stats_contentmax

stats_contentavg

stats_input

stats_output

stats_staytimemin

stats_staytimemax

stats_staytimeavg

state_current

state_since

Source1 Source 0 0 0 1 0 718 0 0 0 5 7197.953489

Queue2 Queue 6 0 12 4.601184 3088 3082 085.72810

4 10.687929 8 7197.953489Processor3 Processor 1 0 1 0.663253 478 477 10 10 10 2 7191.826516Processor4 Processor 1 0 1 0.985172 710 709 10 10 10 2 7196.712723Processor5 Processor 1 0 1 0.666034 480 479 10 10 10 2 7191.826516Processor6 Processor 0 0 1 0.650297 468 468 10 10 10 1 7196.712723Processor7 Processor 0 0 1 0.329317 237 237 10 10 10 1 7196.712723Sink8 Sink 1 1 1 0 709 0 0 0 0 7 0



Object Class conveyingtravel empty

travel loaded

offset travel empty

offset travel loaded loading unloading down setup utilize

Source1 Source 0.00% 0.00% 0.00% 0.00% 100.00% 0.00% 0.00% 0.00% 0.00% 0.00%Queue2 Queue 0.00% 0.00% 0.00% 0.00% 0.00% 2.65% 0.00% 97.35% 0.00% 0.00%Processor3 Processor 33.67% 66.33% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor4 Processor 1.48% 98.52% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor5 Processor 33.40% 66.60% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor6 Processor 34.97% 65.03% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor7 Processor 67.07% 32.93% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Sink8 Sink

Object Class conveyingtravel empty

travel loaded

offset travel empty

offset travel loaded loading unloading down setup utilize

Source1 Source 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Queue2 Queue 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor3 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor4 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor5 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor6 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Processor7 Processor 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00% 0.00%Sink8 Sink

1. Why stat_input dan stat_output on queue is not proportional to

total flowitem entering the system?

Answer:

Because there is a global time in this model where the sequence of

every type routing should enter queue before going to another

sequence. Hence, There are double input enter to the queue.

2. How is the final condition of each location?

Answer:

Object

state_curr

ent

Conditio

n

Source1 5

Generati

ng

Queue2 6 Empty

Processo

r3 1

Idle

Processo

r4 2

Processi

ng

Processo

r5 2

Processi

ng

Processo

r6 2

Processi

ng

Processo

r7 2

Processi

ng

Sink8 7

Collecti

ng

3. Why station 2 has higher percentage than other stations?

Answer: Because station 2 must process all types of items while the

other station only process 2 types of items. It means that from 3

different routing of this production process, station 2 include in all

type routing while other station not include in all type routing.

4. Why total flowitem coming into the system is not proportional with

the flowitem going out? How to overcome this problem?

Answer: Because capacity in all station is limited (only 1 item for

each process). It can get from summary report in class Processor

which is the stats_contentmax only 1. Solution for this problem is

increasing capacity of workstation 2 because in workstation 2 has

high processing time and low idle time that is 98.52% and 1.48%

respectively. Hence, it can give chance to another routing to join in

that station to accelerate the process production with reducing

stats_contentmax, stat_timemax in objective Queue2 class Queue.

d. Summary

There is a bias information in summary report in objective queue in

stats_input because of the routing that made in global table. And other

consequences from this global table is the station 2 has higher

percentage than other stations because of station 2 include in all type

routing. For the flowitem that going out and in is not proportional

because the processor only have one capacity therefore there is a state

where every type routing should wait other routing finish their process.

Hence, it needs to add the capacity worksation especially in worksation

2 because of the idle that 1.48% and processing 98.52%/

tugas analisa 3_d121_ ip2

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