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    BASIC FLUID MECHANICS

    (ECW 211)

    NURAKMAL HAMZAHBKBA 2.15

    O13-5925330

    EXT: 2637

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    CONTENT

    PROGRAM OUTCOMES

    COURSE SYLLABUS

    COURSE OUTCOMES

    LESSON PLAN

    COURSE ASSESSMENT

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    PROGRAME OUTCOMESPO1 - Ability to acquire and apply basic knowledge of science,

    mathematics and engineering.

    PO2 - Ability to communicate effectively with technical personal

    and the public.

    PO3 - Ability to identify, formulate and solve engineering

    problems.

    PO4 - Ability to function on multi-disciplinary teams.

    PO5 - Ability to function effectively as an individual and in a

    group with leadership, managerial and entrepreneurial

    capabilities.

    PO6 - Understanding of the social, cultural, global andenvironmental responsibilities and ethics for sustainable

    development.

    PO7 - Recognising the need to undertake lifelong learning and

    possessing/acquiring the capacity to do so.

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    COURSE OUTCOMES

    CO1 - Acquire and apply basic knowledge on various fluidproperties and problems related to fluid mechanics.

    CO2 - Apply concept of hydrostatic pressure in determining forces

    exerted by fluids on plane surfaces under static condition.

    CO3 - Analyse concept of up thrust, buoyancy of objects immersedin fluids in determining the stability of floating bodies.

    CO4 - Formulate and solve problems regards to the concepts of the

    continuity, energy and momentum equations and flow

    measurement in fluid mechanics.

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    COURSE ASSESMENT

    GRADING %

    TEST 1 30%

    SOFT SKILLS 10%

    FINAL EXAMINATION 60%

    TOTAL 100%

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    COURSE ASSESMENT

    QUESTION CHAPTER5 Questions

    Question 1

    Question 2

    Question 3 Question 4

    Question 5

    Chapter 1Chapter 2Chapter 3Chapter 4Chapter 5

    REMARKSDONTWRITE USING PENCIL, PLEASE WRITE USING PEN

    PLEASE WRITE USING BALL POINT PEN RATHER THAN GEL PEN

    BRINGS YOUR CALCULATOR DURING FINAL EXAMINATION SESSION

    STANDARD MARKING ( BEWARE)

    WRITE ALL UNITS/FORMULA.

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    CH PTER ONE1.1 FLUID AS CONTINUUM

    1.2 UNITS AND DIMENSION USED IN

    ENGINEERING FLUIDS

    At the end of this topic student should:

    Be able to explainthe continuum concept of fluid. (CO1-PO1)

    Be able to identifythe units and dimensionused in engineering

    fluids.(CO1-PO3)

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    WHAT IS

    HYDRAULICS

    WHAT IS

    FLUIDMECHANICS

    ?

    Mechanics of flui sIts that branch of engineering

    science which deals with the

    behaviour of fluid under the

    conditions of rest & motion

    Greek word HUDAR, means

    WATER

    Its that branch of engineeringscience deals with water ( at rest

    or in motion)

    Or its that branch of engineering

    science which is based on

    experimental observation of

    water flow.

    INTRODUCTION

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    FLUID MECHANICS

    FLUID MECHANICS is a study of the behavior

    of liquids and gases either at rest (fluid

    statics) or in motion (fluid dynamics).

    The analysis is relate continuity of

    massand energywith forceand

    momentum.

    FLUID is a substance which deformscontinuously under the action of shearing

    force (however small it is may be)

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    IMPORTANTOF FLUID

    MECHANICSTO

    ENGINEER

    To determine the

    stability of floating andsubmerged objects

    pontoons, ships

    To determine the

    hydrostatic forces

    dams

    To determine flow and

    energy losses in pipe

    To design fluid

    machinespumps

    and turbines

    To determine flow rate,

    energy dissipation from

    spillway and flow in

    open channels such as

    rivers

    IMPORTANT OF FLUID MECHANICS

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    DIFFERENCE BETWEEN SOLID AND FLUID

    Have

    preferredshape

    Hard & noteasily

    deformed

    Cannotdeformedcontinuouslyunder shear

    force

    SOLIDDoes nothave anypreferredshape

    Soft & easilydeformed

    Deformedcontinuouslyunder shear

    force

    FLUID

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    3 CONDITIONS OF FLUIDS

    The study ofincompressible fluidunder static conditions(hydrostatics)

    That dealing with thecompressible staticgases- aerostatics

    STATICS

    Deals with thevelocities,accelerations andpattern of flow only

    Force and energycausing velocities andaccelerations are notdeal under this head.

    KINEMATICS

    Deal with therelationshipbetweenvelocities andaccelerations of fluidwith the FORCES @ENERGY causingthem.

    DYNAMICS

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    CONCEPT OF FLUID

    In FLUID:

    -The molecules can move freely but are constrained through a traction forcecalled cohesion.

    -This force is interchangeable from one molecule to another.

    For GASES:

    -It is very weak which enables the gas to disintegrate and move away from itscontainer.

    -A gasis a fluid that is easily compressed and expandsto fill its container.

    -It fills any vessel in which it is contained. There is thus no free surface.

    For LIQUIDS:

    -It is stronger which is sufficient enough to hold the molecule together and canwithstand high compression, which is suitable for application as hydraulic fluid suchas oil.

    -On the surface, the cohesion forms a resultant force directed into the liquid regionand the combination of cohesion forces between adjacent molecules from atensioned membrane known as free surface.

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    1.1 FLUID AS CONTINUUM

    Continuum mechanics and its concept

    It is a branch ofmechanicsthat deals with theanalysis of the kinematicsand mechanicalbehaviour of materials modelled as a continuum.(eg. solids and fluids), (eg. liquids and gases)

    A continuum concept assumes that the substanceof the body is distributed uniformlythroughout, andcompletely fills the space it occupies.

    Fluid properties is depends on their molecularstructure.However, engineering applications hardlyanalyses fluids at molecular level.

    It is the fluids bulk behavior of main concern in

    engineering applications.

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    CONTINUUM CONCEPTS

    Atoms are widely spaced in the

    gas phase.

    However, we can disregard the

    atomic nature of a substance.

    View it as a continuous,

    homogeneous matter with no

    holes, that is, a continuum . This allows us to treat properties

    as smoothly varying quantities.

    Continuumis valid as long as sizeof the system is large in

    comparison to distance between

    molecules.

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    Fluid as acontinuum

    A continuous substancewhere quantities such as

    velocity and pressure canbe taken as constant atany section irrespective ofthe individual fluid particle

    velocity.

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    PRESSURE

    Pressure acts

    perpendicular to the

    surface and increases

    at greater depth.

    area

    forcepressure

    Pressureis the force per unit area, where the force is perpendicular to the area.

    A measure of the amount of force exerted on a surface area

    1 2 UNITS AND DIMENSION USED IN

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    1.2 UNITS AND DIMENSION USED IN

    ENGINEERING FLUIDS

    WHAT IS

    UNITS?

    WHAT IS

    DIMENSION

    ?

    Standardized system ofmeasurements used todescribe the magnitude ofthe dimensionA properties that can bemeasured

    Measurable properties used todescribe a body/systemThe standard element, in terms ofwhich these dimensions can bedescribed quantitatively assignednumerical values.

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    VARIOUS SYSTEM OF UNIT

    Parameter SI UNITS c.g.s system of unit Imperial units ( BritishGravitational system; EnglishUnits)

    Length Meters (m) Centimeters (cm) Foot (ft)

    Mass kilogram(kg) Gramme (g) Pound ( Ib)

    Time Seconds (s) Seconds (s) Seconds (s)

    Temperature

    Degree Celcius(oC)

    Degree Fahrenheit ( oF)

    Theprimary quantitieswhich are also referred to as basic dimensions, such asLfor length, Tfor time, Mfor mass and Ffor force.

    Student also expected to be familiar with the various systems of units used inengineering. These systems include :

    As any quantity can be expressed in whatever way you like it is sometimes easy to become

    confused as to what exactly or how much is being referred to. This is particularly true in the

    field of fluid mechanics.

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    DERIVED UNIT

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    1.3 DENSITY, RELATIVE DENSITY

    SPECIFIC WEIGHT, SPECIFIC GRAVITY,

    SPECIFIC VOLUME AND VISCOSITY

    At the end of this topic student should:

    Be able to apply basic knowledge of various fluid

    properties.(CO1-PO1)Be able to acquire various fluid properties in identify and solving

    problems related to fluid engineering problem.(CO1-PO3)

    Be able to formulate the relationship between shear, stress and

    velocity gradient from the Newtonslaw of viscosity. (CO1-PO3)

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    1. DENSITY

    Regardless of form (solid, liquid,

    gas) we can define how much mass

    is squeezedinto a particular space

    Densityof a material is defined by

    the amount of matterper unit

    volume.

    Density of material may be referred

    to in many ways.

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    1.1 MASS DENSITY,

    Definition

    Density of a fluid, , is defined as the mass per unit volume It is denoted by the Greek

    symbol, .

    ==V m3kgm-3

    kgm

    water= 1000 kgm-3

    air=1.23 kgm-3

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    1.2 SPECIFIC WEIGHT,

    Definition

    Specific weight of a fluid, , is defined as the weight of the fluid per unitvolumeForce exerted by gravity, g, upon unit volume of substance

    =wV

    = g

    Units: N/m3

    = the density of the material (kgm-3)g = acceleration due to gravity (ms-2)

    Water =9.81 X 103N/m3

    1 3 RELATIVE DENSITY

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    1.3 RELATIVE DENSITY

    @ SPECIFIC GRAVITY, SG

    Definition

    A ratio of the specific weight of a substance to the specific weight ofwater at standard temperature (4C) and atmospheric pressure.

    Units: dimensionless

    Cw

    s

    Cw

    sSG

    4@4@

    Unit is none, since ratio is a pure number.SGis a dimensionless quantity

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    2. SPECIFIC VOLUME, V

    Definition

    The reciprocal of the mass density i.e. the volume per unit massor theinverse of density

    Units: m3/kg

    v = 1/ = V/m

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    Dynamic

    Kinematic

    3. VISCOSITY

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    3.1 DYNAMIC VISCOSITY,

    Definition

    Dynamic viscosity, , is defined as the Shear force per un it area(shear stress, ) needed to drag a layer of fluid with a unit velocity past

    another layer at a unit distance away from it in the fluid

    Measure of internal friction of fluid particles

    Molecular cohesiveness

    Resistance fluid has to shear (or flow)

    Units:

    Water:

    Air:

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    3.2 KINEMATIC VISCOSITY,

    Definition

    It defined as the ratio of dynamic viscosity to mass density

    v

    = dynamic viscosity= mass density

    Will be found to be important in cases

    in which significant viscous and

    gravitational forces exist.

    Typical values:

    Water = 1.14x10-6m2/s;Air = 1.46x10-5m2/s;

    Units: m2/s or stokes (10,000 St = 1m2s-1)

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    NEWTON LAW OF VISCOSITY

    When fluid moves, it generates shearing stress

    If no movement between the moving fluid particles no shearstresses developed

    Fluid particles which in contact with solid boundaries will adhere tothese boundaries will have same velocities as the solidboundaries

    Movement of a fluid over solid boundary can be visualized aslayers of a fluid moving one above the other.

    The velocity of fluid layers increases as the distance from the solidboundary increases

    y

    vFlowing passing over a solid boundary

    TEMPERATURE VS VISCOSITY

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    TEMPERATURE VS VISCOSITY(LIQUID AND GASES)

    Liquids

    Gases

    Viscosity

    Temperature

    Viscosity is caused by the cohesive

    forces between the molecules in liquidsand by the molecular collisions in

    gases, ant it varies greatly with

    temperature.

    The viscosity of liquid decreases with

    temperature, whereas the viscosity of

    gases increases with temperature. This is because in a liquid the

    molecules possess more energy at

    higher temperature and they can

    oppose the large cohesive

    intermolecular forces more strongly.

    As a result, the energized liquid

    moleculescan move more freely.

    In gases, the intermolecular activities

    are negligibleand the gas molecules at

    high temperature move randomly at

    higher velocity.

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    Viscosity in gases

    Due to intermolecular collisionbetween randomly moving particles

    For gas, temperature , amount ofintermolecular collision , viscosity

    Viscosity in liquid

    Due to intermolecular collisionbetween liquid particles

    For liquid, temperature ,intermolecular collisionis weakened,viscosity

    VISCOSITY IN GASES & LIQUIDS

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    NEWTON LAW OF VISCOSITY

    It is important to evaluate the magnitude of the shearstress generated by the moving fluid

    NewtonsLaw of viscosity: = shear stress

    = viscosity of fluid

    du/dy = shear rate, rate of strainor velocity gradient

    dy

    du (1.1)

    The viscosity is a function only of the condition of the fluid, particularly itstemperature.

    The magnitude of the velocity gradient (du/dy) has no effect on the magnitude of .

    NEWTONIAN &

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    NEWTONIAN &NON NEWTONIAN FLUID

    Fluid Newtons lawof viscosity

    Newtonian fluidsobey refer

    Example: Air, Water, Oil, Gasoline, Alcohol, Kerosene, Benzene, Glycerine

    FluidNewtons law

    of viscosity Non Newtonian fluids

    not obey refer

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    NON NEWTONIAN FLUID

    *The slope of a curve at a point is the apparent viscosity of the fluid at that point

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    EXAMPLE 1

    1. The lower plate as shown below is fixed while the upper

    one is free to move under the action of a mass of 50g.Castor oil with absolute viscosity 650 x 10-3 Ns/m2

    occupies the space between these two plates. The area

    of contact of the upper plate with the oil is 0.7m2, find the

    velocity of the upper plate when the distance separating

    the plates is 0.5cm.

    Hint:

    Answer: du = 5.4mm/s

    A

    F

    dy

    du

    = 650 x 10-3Ns/m2 y =

    0.5cm

    m=50g

    pulley

    Stationary

    EXAMPLE 2

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    2. A vertical gap 25mm wide of infinite extent contains oil

    of relative density 0.95 and viscosity 2.4Pa.s. A metalplate 1.5m x 1.5m x 1.6mm, weighing 55N is to be lifted

    through the gap at a constant speed of 0.06 m/s.

    Determine the force required.

    Hint:

    Answer: F = 110.4 N

    0.06m/s

    dydy

    F

    W

    25 mm

    A

    F

    dy

    du

    EXAMPLE 2

    EXAMPLE 3

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    EXAMPLE 3

    3. Crude oil at 20C fills the space between two concentric

    cylinders of diameters 150mm and 156mm respectively.Both cylinders are 250mm in height. If the inner cylinder is

    to be rotated at a constant speed of 12 rev/min while

    keeping the outer cylinder stationary, calculate the torque

    required. The fluid properties of the crude oil at 20C are:

    i) specific gravity = 0.86

    ii)kinematic viscosity = 8.35 x 10-6m2/s

    Hint: Linear velocity,

    Answer: T = 0.002NmrFT

    A

    F

    dy

    du

    rv

    EXAMPLE 4

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    EXAMPLE 4

    4. A vertical cylinder of diameter 180mm rotates

    concentrically inside another cylinder of diameter181.2mm. Both the cylinders are 300mm high. The

    space between the cylinders is filled with a liquid whose

    viscosity is unknown. Determine the viscosity of the fluid

    if torque of 20 Nm is required to rotate the inner cylinder

    at 120 rpm.

    Answer : =0.696 Ns/m2

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    1.4 COMPRESSIBILITY AND BULK MODULUS,

    VAPOUR PRESSURE, SURFACE TENSION,

    AND CAPILLARITY

    At the end of this topic student should:

    Be able to define thefluid parameters.(CO1-PO1)

    Be able to apply bulk modulus, surface tension and capillarity insolving fluid engineering problem.(CO1-PO1)

    Be able to use the Newtons law of viscosity which are the

    relationship of shear stress and velocity gradient in solving fluid

    engineering problems (CO1-PO3)

    4 SURFACE TENSION

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    4. SURFACE TENSION,

    Surface tension

    defined as the force acting a unit length ofa line drawn in the liquid surface

    Surface tension

    Surface tension tend to reduce the surface

    area of a body of liquid The internal pressure within the droplet, p

    and the surface tension forces,must be inequilibrium.

    p

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    Surface tension

    Taking vertical equilibrium of the forces actingon the droplet

    The magnitude of surface tension forces arevery small compared to other forces

    Normally are neglected

    22 rpr

    rp

    2

    2

    pr Units : N/m

    5 VAPOR PRESSURE P

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    5. VAPOR PRESSURE, Pv

    Vapor pressure

    defined as the pressure at which a liquidturns to vapour

    thepressure exerted by its vapor in phaseequilibrium with its liquid at a giventemperature

    Themolecules which moves above thesurface of the liquid exert pressure in theconfined surface

    Vapor pressure

    Pvapour= P saturat ion

    Units: N/m2 or Pascal

    6 CAPILLARITY

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    6. CAPILLARITY

    When a liquid comes into contact with a solid surface:

    - Adhesion forces: forces between solid and liquid- Cohesion forces:forces within liquid

    If cohesive forces > adhesive forces, the meniscus in a glass tube

    will take a shape as in figure (a) and (b).

    Figure (a) and (b)

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    Capillary effectis

    the riseor fallof a

    liquid in a small-

    diameter tube

    gdh

    cos4

    grh

    cos2

    dh

    cos4@ @

    Units= m @ mm

    where h= height of capillary rise (or depression)

    = surface tension

    = wetting (contact) angle

    = specific weight of liquid

    r= radius of tube

    7. COMPRESSIBILITY &

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    7. COMPRESSIBILITY &BULK MODULUS

    Definition

    The change of pressure corresponding to frictional changein volume of fluid where temperature remains constant

    Gases are much more compressible compared to liquids

    Liquids are considered incompressible

    The compressibility of a fluid is expressed by its bulk modulus ofelasticity, K, which describes the variation of volume withchange of pressure, i.e.

    Typical values : Water = 2.05x109N/m2; Oil = 1.62x109N/m2

    strainvolumetricpressureinchangeK

    /pK

    VdVpK/

    Units: N/m2

    EXAMPLE 6

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    6. 1 When the pressure exerted on a liquid isincreased from 550 kN/m2 to 1000 kN/m2, the

    volume is decreased by 1%. Determine the bulk

    modulus of the liquid.

    Answer: K = 45x106N/m2

    EXAMPLE 6

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    6.3 Determine the bulk modulus of a liquid if itundergoes a 0.1% decrease in volume when

    subjected to a pressure change from 100kPa to

    6.5Mpa.

    Answer: 6.4GPa

    51

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    for your ttention