thermal analysis engineering thermoplastics
TRANSCRIPT
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l n( a) =-E a
R
1
T -
1
To
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0 50 100 150 200 250 300 350
4
6
8
10
12
14
16
18
0
200
400
600
800
0.01
0.02
0.03
0.04
0.05
[
]TanDelta
[
]E"(MPa)
[
]E(GPa)
Temperature ( C)o
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600
1.0
4000.8
0.6
2000.4
0.2
0.0
0
300250200150100500
0
1
2
3
4
0 50 100 150 200 250 300 350 400
1
2
3
4
5
0
1
2
3
4
5
Temperature ( C)
[
]ePermitivity
[
]Log[e"]
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0 50 100 150 200 250 300 350 400
2
3
4
5
6
-4
-3
-2
-1
0
Temperature ( C)
[
]ePermittivity
[
]Log[e"
]
o
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ln (a) = E1
T-
1
T/ Ra
o
ln (a) = E1
T-
1
T/ Ra
o