theories of failure for pressure equipment...failure theories which apply for ductile materials...
TRANSCRIPT
THEORIES OF FAILURE FOR PRESSURE EQUIPMENT
Why do parts fail?
If we keep increasing the magnitude of load applied to a part, at some point it will fail. But
the important questions are: how can we predict when the failure will occur? or what level
does the stresses in the part need to reach for it to fail?
Parts fail when the induced stresses exceed their strength.
To prevent failure, we must know what kind of stresses cause the failure: Tensile, Compressive,
Shear? Essentially, it depends on material’s relative strength in tension, compression and
shear. Also, it depends on the type loading (Static, Fatigue, Impact) and presence of the
cracks in the material.
What is Failure?
Failure doesn’t have a universal definition; it depends on the type of application. In mechanical design,
a part is said to have failed, if it becomes unsuitable for performing its desired function.
There are basically three types of mechanical failure:
1. Yielding
Yielding results in excessive permanent deformation which makes the part unfit to perform
its function satisfactorily.
This mostly occurs in ductile materials.
2. Fracture
Fracture results in breaking the component into two parts.
This mostly occurs in brittle materials.
3. Excess elastic deflection/ inadequate rigidity
In some applications, where components are desired to have sufficient rigidity, excess elastic
deflection (not permanent) could be the reason for failure to perform the desired function.
Examples: Flanges must be rigid, to effectively transmit the applied bolt load on the gasket to
compress/ squeeze it uniformly; tall distillation columns have restriction for maximum tip
deflection to ensure the liquid height on trays is uniform at all points.
This mostly occurs in ductile materials.
Ductile and Brittle materials
There is no sharp line of demarcation between ductile and brittle materials. However, a rough
guideline is that if the percentage elongation is less than 5%, then the material may be
treated as brittle and if it is more than 15% then the material is ductile.
However, there are many instances when a ductile material may fail by fracture. This may
occur if a material is subjected to: cyclic loading, long term static loading at elevated
temperature, Impact loading, work hardening, and severe quenching.
In general, ductile, isotropic materials are limited by their shear strengths. Brittle materials
are limited by their tensile strengths.
Static loads are slowly applied and remain constant with time. Dynamic loads are suddenly
applied (impact), or repeatedly varied with time (fatigue), or both. In dynamic loading, the
distinction between failure mechanisms of ductile and brittle materials blurs. Ductile materials
often fail like brittle materials in dynamic loading.
Figure 1: Tensile test specimen of ductile steel (Failure along principal shear stress plane)
Figure 2: Tensile test specimen of brittle steel (Failure along principal normal stress plane)
Figure 3: Compression test specimens (a) Ductile Steel (b) Brittle Cast Iron
Figure 4: Torsion test specimens (a) Ductile Steel (b) Brittle Cast Iron
Why do we need different failure theories?
For ductile materials failure is usually considered to occur at the onset of plastic
deformation and for brittle materials it occurs at fracture. These points are easy to define
for a uniaxial stress state, like a tensile test. They occur when the normal stress in the object
reaches the yield strength for ductile materials and the ultimate strength for brittle materials.
Figure 5: Ductile Vs Brittle failure
But for a more complex case of tri-axial stress, predicting failure is not that straightforward. In
fact it's so difficult to predict that we don't have one universally applicable method. Instead,
we have to predict failure by selecting the most suitable one of a range of different failure
theories, each of which we know works relatively well under certain circumstances, based on
experimentation. Failure theories which apply for ductile materials usually aren't applicable
for brittle materials, and vice-versa.
We have material properties from a uniaxial tensile test; whereas, in real world, the loading is
not uniaxial. Failure theories help us predict the failure in a component in case of multi-axial
loading. Theories of failure are required due to the unavailability of failure stresses under
combined loading conditions.
What does a failure theory do?
Theories of failure allow us to PREDICT FAILURE of a material by comparing the stress state in
the object with material properties like yield or ultimate strengths obtained by performing
uniaxial tensile test.
The stress state at a point can be described using the three principal stresses, so most failure
theories are defined as a function of the principal stresses and the material strength.
f(σ1, σ2, σ3) = Syt, Sut
By convention principal stresses are ordered from largest to smallest as σ1 ≥ σ2 ≥ σ3
At yield point in tension test:
The maximum principal stress is equal to the yield strength of the material, and the two other
principal stresses are equal to zero.
i.e. σ1 = Syt, σ2 = σ3 = 0.
Also, the maximum shear stress will be Syt/2.
For generally used ductile metals SyTension = SyCompression.
Various Theories of Failure
Theories of failure state the governing parameter causing failure (criteria) in general tri-axial
stress state and prescribe the safe limit for design from uniaxial tension test. Some of the most
popular failure criteria are listed below.
i. Maximum principal stress reaches tensile yield strength of the material
ii. Maximum shear stress reaches shear yield strength of the material
iii. Maximum tensile strain reaches yield point strain
iv. Total strain energy per unit volume absorbed by the material reaches the strain
energy limit
v. Shear strain energy (distorsion energy) per unit volume reaches its maximum limit
In a uniaxial tensile test all parameters listed above will simultaneously reach their limiting
values. But when the loading is complex, not all of them would reach their limiting values
simultaneously. Often only one of them may reach its limiting value causing failure, even if the
other parameters are well within their safe limits.
As pressure vessels are primarily constructed of ductile materials, the scope of this article is
limited to failure theories applicable/ used for pressure equipment design. Of the many
theories developed to predict elastic failure, the three most commonly used are:
1. Maximum Principal Stress theory
2. Maximum Shear Stress theory
3. Maximum Distortion Energy theory
Hydrostatic and deviatoric stresses
Before we go to specifics of any failure theory, it is required to understand the concept of
hydrostatic and deviatoric stresses. A general tri-axial stress state can be decomposed into
stresses which cause a change in volume and stresses which cause shape distortion.
Figure 6: Decomposition of general tri-axial stress state into hydrostatic stress and deviatoric stresses
Stresses that cause a change in volume are called HYDROSTATIC stresses, because that is the
type of stress acting on an object submerged in liquid. For a hydrostatic stress
configuration, the three principal stresses are always equal, and there are no shear
stresses. i.e. σ1 = σ2 = σ3
For a tri-axial stress state we can calculate the hydrostatic component as the average of the
three principal stresses.
Hydrostatic stress = σavg = (σ1 + σ2 + σ3) / 3
The mechanism that causes yielding of ductile materials is shear deformation. Since there are
no shear stresses for a state of hydrostatic stress, this component can be very large and still
not contribute to yielding.
Yielding is only caused by the stresses which cause shape distortion. These are called
DEVIATORIC stresses. The deviatoric component is calculated by subtracting the hydrostatic
component from each of the principal stresses.
The hydrostatic and deviatoric components can be expressed in matrix form, like this.
Here we have described the stress state using the principal stresses, but we could also
describe it for an arbitrary orientation of the stress element.
Any good failure theory needs to be consistent with experimental observations we can make
about how materials fail. There is one key observation that failure theories for ductile materials
need to capture, which is the fact that hydrostatic stresses do not cause yielding in ductile
materials.
1. Maximum Principal Stress theory (also known as RANKINE’S THEORY)
This theory states:
“Failure occurs when any one of the three principal stresses reach the yield or ultimate
strengths of the material determined from a uniaxial tension or compression test.”
What is principal stress?
It is defined as the normal stress calculated at an angle when shear stress is zero.
Condition for failure
Maximum principal stress > Failure stress in Tension test
Max [ |σ1| , |σ2| , |σ3| ] > Syt or Sut
Failure Envelope
For planer (biaxial) state of stress, σ3 = 0
Max [ |σ1| , |σ2| ] > Syt
For the limiting condition of failure, the above inequality results in a square envelope when
plotted on graph with principal stresses on x-y axes.
Figure 7: Failure envelope for Maximum Principal Stress Theory
Condition for safe design
Maximum principal stress ≤ Permissible stress
Permissible stress = Failure stress in Tension test / Factor of Safety
Max [ |σ1| , |σ2| , |σ3| ] ≤ Syt/ FOS or Sut/ FOS
For planer stress state, σ3 = 0
Max[σ1, σ2] ≤ Syt/ FOS
2. Maximum Shear Stress theory (also known as Tresca- Guest theory)
This is the oldest failure theory, originally proposed by the great French scientist C. A.
Coulomb. French engineer Henri Tresca modified it in 1864, and J. J. Guest validated by
experiments around 1900. For these reasons the maximum-shear-stress theory is sometimes
called the Tresca-Guest theory.
This theory states:
“A material subjected to any combination of loads will fail by yielding when the maximum
shear stress exceeds the shear stress at yielding in a uniaxial tensile test.”
“This theory states that yielding occurs when the difference between the maximum and
minimum principal stresses is equal to the yield strength of the material.”
Condition for failure
Maximum shear stress > Yield strength in shear at yield point in tension test
Yield strength in shear in tensile test = Syt/ 2
τmax > Syt/ 2
For tri-axial state of stress,
Max [ | τ12 , τ23 , τ31 ] > Syt / 2
Max [ | (𝜎1−𝜎2)
2 | , |
(𝜎2−𝜎3)
2 | , |
(𝜎3−𝜎1)
2 | ] >
𝑆𝑦𝑡
2
Max [ | (σ1-σ2) | , | (σ2-σ3) | , | (σ3-σ1) | ] > Syt
Failure Envelope
For planer (biaxial) state of stress, σ3 = 0
Max [ | (σ1-σ2) | , | σ2 | , | σ1 | ] > Syt
For the limiting condition of failure, the above inequality results in a hexagonal envelope when
plotted on graph with principal stresses on x-y axes.
Figure 8: Failure envelope for Maximum Shear Stress Theory
Condition for safe design
Maximum shear stress ≤ Permissible shear stress (τper)
Permissible shear stress = Yield strength in shear at yield point in tension test / Factor of
safety
τper = Syt / (2*FOS)
τmax ≤ Syt / (2*FOS)
For tri-axial state of stress,
Max [ | (σ1-σ2) | , | (σ2-σ3) | , | (σ3-σ1) | ] ≤ Syt / FOS
When σ1 ≥ σ2 ≥ σ3,
|σ1- σ3| ≤ Syt / FOS
For planer (biaxial) state of stress, σ3 = 0
Max [ | (σ1-σ2) | , | σ2 | , | σ1 | ] ≤ Syt / FOS
| σ1 | ≤ Syt / FOS, when σ1 and σ2 are like in nature
| σ1 - σ2| ≤ Syt / FOS, when σ1 and σ2 are unlike in nature
3. Maximum Distortion Energy (Shear Strain Energy) theory (also known as von
Mises, Huber and Hencky’s Theory)
It was initially developed by the Austrian scientist Richard von Mises, but a number of others
were involved in refining it, so it is sometimes called the Maxwell–Huber–Hencky–von Mises
theory.
This theory states:
“It states that yielding occurs when the maximum distortion energy in a material is equal to
the distortion energy at yielding in a uniaxial tensile test.”
What is the distortion energy?
It is essentially the portion of strain energy in a stressed element corresponding to the effect
of the deviatoric/ shear stresses i.e. stress which cause shape distortion.
Condition for failure
Max. Distortion Energy per unit volume > Distortion Energy per unit volume at Yield Point in
Tension Test
Ud > Ud Y.P.T.T
The Maximum Distortion Energy per unit volume (Ud) can be derived as follows:
Total strain energy (UTotal) is the sum of strain energy corresponding to hydrostatic/ volumetric
stresses (UVol) and strain energy corresponding to deviatoric/ shear stresses (Ud).
UTotal = Uvol + Ud
Ud = UTotal - UVol
Strain energy is the area under the stress-strain curve.
Figure 9: Strain energy = Area under stress-strain curve
Strain energy = ½ * Stress * Strain
Strain energy due to principal stress σ1 = Uσ1
= 1
2 * σ1 * 1
= 1
2 ∗ 𝜎1 ∗ [
𝜎1
𝐸 −
µ∗𝜎2
𝐸 −
µ∗𝜎3
𝐸]
= [σ12 − µ∗σ1∗σ2 − µ∗σ1∗σ3])
2E
Total Strain energy due to all principal stresses = UTotal
= Uσ1 + Uσ2 + Uσ3
= [σ12 − µ∗σ1∗σ2 − µ∗σ1∗σ3])
2E +
[σ22 − µ∗σ2∗σ3 − µ∗σ2∗σ1])
2E +
[σ32 − µ∗σ3∗σ2 − µ∗σ3∗σ1])
2E
UTotal = [𝜎12 + 𝜎22 + 𝜎32 − 2µ(𝜎1∗𝜎2 + 𝜎2∗𝜎3 + 𝜎3∗𝜎1) ]
2𝐸
Uvol = ½* Volumetric stress * Volumetric strain
Uvol = 1
2 (
𝜎1 + 𝜎2 + 𝜎3
3)[(
1−2µ
𝐸)( σ1 + σ2 + σ3) ]
Uvol = (𝟏−𝟐µ
𝟔𝑬)( σ1 + σ2 + σ3)^2
As, Ud = UTotal - UVol
Ud = 𝟏+µ
𝟔𝑬 [ (σ1 – σ2)2 + (σ2 – σ3)2 + (σ3 – σ1)2 ]
To get Ud Y.P.T.T, substitute σ1 = Syt, σ2 = σ3 = 0 in equation above
Ud Y.P.T.T = [ 𝟏+µ
𝟑𝐄 ] * Syt2
For the limiting condition of failure, equating Ud and Ud Y.P.T.T we get,
[ (σ1 – σ2)2 + (σ2 – σ3)2 + (σ3 – σ1)2 ] > 2*Syt2
Failure Envelope
For planer (biaxial) state of stress, σ3 = 0
σ12 + σ2
2 – σ1*σ2 > Syt2
For the limiting condition of failure, above inequality becomes an equation of an ellipse with
Semi-major axis = √2*Syt and Semi-minor axis = √2/3*Syt
Figure 10: Failure envelope for Maximum Distorsion Energy Theory
Condition for safe design
Maximum Distortion Energy/ volume ≤ Distortion energy/ volume at yield point in tension test
[ (σ1 – σ2)2 + (σ2 – σ3)2 + (σ3 – σ1)2 ] ≤ 2*(𝑺𝒚𝒕
𝑭𝑶𝑺)𝟐
√𝟏
𝟐[ (𝛔𝟏 – 𝛔𝟐)^𝟐 + (𝛔𝟐 – 𝛔𝟑)^𝟐 + (𝛔𝟑 – 𝛔𝟏)^𝟐 ] = Syt = σeq
The term on the left is often called the equivalent von Mises stress. If it is larger than the
yield strength of the material, yielding is predicted to have occurred. The equivalent von Mises
stress is a common output from stress analysis performed using the finite element method.
Contour plots are typically generated to show the distribution of the von Mises equivalent
stress within a component, as these allow areas at risk of yielding to be identified.
For planer (biaxial) state of stress, σ3 = 0
σ12 + σ2
2 – σ1*σ2 ≤ (𝑺𝒚𝒕
𝑭𝑶𝑺)^2
Comparison of failure theories
For comparing failure theories, the failure envelope (region of safety) of each theory is plotted
on a single graph. A failure envelope is the representation of a failure theory in the principal
stress space. Yielding is considered to have occurred when the stress state reaches the
boundary of envelope.
Figure 11: Superimposed failure envelopes of three theories
Figure 12: Comparison of failure criteria with experimental results
From the above figure it is clear that the Maximum Principal Stress theory has large areas
where its use is potentially unsafe. So we will compare Tresca and von Mises. Both agree well
with experimental observations, although von Mises agrees slightly better. The Tresca yield
surface lies entirely inside the von Mises surface, meaning that Tresca is more conservative.
The difference between the Tresca and von Mises theories is largest for the three
configurations indicated in figure below. The maximum difference between the two theories
can be calculated to be 15.5%.
Theory
[Researchers]
Ease of
use
Failure
envelope
τy/ σyt
on shear
diagonal
(τ=σ1=-σ2)
Accuracy/ Experimental correlation ASME Code Sec
VIII
Max principal
stress (MPST)
[Rankine]
Simplest Square 1
Potentially unsafe, when σ1 and σ2 are unlike in nature.
Correlates well for brittle materials under all loading conditions because
brittle materials are weak in tension.
But for ductile materials, it doesn’t agree because ductile materials are
weak in shear.
This theory can be applied for ductile materials when state of stress
condition such that maximum shear stress is less than or equal to maximum
principal stress i.e.
• Uniaxial state of stress(τmax=σ2)
• Biaxial loading when principal stresses are like in nature (τmax=σ2)
• Under hydrostatic stress condition (shear stress in all planes is 0).
Adopted in Div-1
Max shear
stress (MSST)
[Henri Tresca,
Guest]
Easier to
apply than
von Mises
Hexagon 0.5
Gives safe but uneconomic design.
More conservative for ductile materials.
This theory can be applied for ductile materials when uniaxial state of stress
and biaxial state of stress when principal stresses are like in nature.
It is not suitable for hydrostatic loading.
Was adopted in
Div-2,
before edition 2007
Max distorsion
energy (MDET)
[Richard von
Mises, Maxwell,
Huber, Hencky]
Relatively
complex for
manual
calculations
Ellipse 1/√3 = 0.58
Gives safe and economic design.
Agrees better with experimental data for ductile materials.
It cannot be applied materials under hydrostatic stress condition.
Adopted in Div-2,
edition 2019