the mandelbrot setrolfsen/ma426/mandelbrot.pdf · the mandelbrot set is connected? we outline the...
TRANSCRIPT
But What are They?
To understand Fractals, we must first understand some things
about iterated polynomials on C.
Let f : C→ C be a polynomial. Then nth iterate of f is
fn(z) = f(f(f(· · · f(z) · · · )))︸ ︷︷ ︸n times
Note: The n here is not an exponent.
The orbit launched from z0 ∈ C is the sequence
Of(z0) = fn(z0).
The Julia Set of a Polynomial f(z)
The Basin of Attraction for ∞ is the set
Af(∞) = z ∈ C | Of(z)→∞.
The Julia Set of f(z) is the the boundary of Af(∞),
J (f) = δAf(∞).
Example: Take f(z) = zm. Then J (f) is the unit circle.
The Mandelbrot Set
For the Mandelbrot set, we consider polynomials of the form
pc(z) = z2 + c,
with parameter c ∈ C. We’ll write Opc(z) = Oc(z) for the orbits
of pc.
The Mandelbrot Set is
M = c ∈ C | J (pc) is connected.
This definition appears simple enough, but Julia Sets are not
simple objects.
J (pc) Connectedness Characterization
Luckily, there is a nice characterization of J (pc) being connected.
Theorem. The Julia Set, J (pc), is connected if and only if there
is an R ∈ R such that
|pnc (0)| ≤ R for all n.
If the Julia set is disconnected, it is totally disconnected.
This characterization shows that c 6∈ M ⇔ Oc(0)→∞.
A useful Fact
Lemma. Let |pnc (0)| > 2, and |pnc (0)| ≥ |c| for some n ≥ 1.
Then Oc(0)→∞.
Proof Take n be the smallest such integer. We have that
|pn+1c (0)| = |pnc (0)2 + c| ≥ |pnc (0)|2 − |c| ≥ (|pnc (0)| − 1)|pnc (0)|.
Now, if |pn+kc (0)| ≥ (|pnc (0)| − 1)k|pnc (0)|, then
|pn+k+1c (0)| ≥ (|pn+k
c (0)| − 1)|pn+kc (0)| ≥ (|pnc (0)| − 1)k+1|pnc (0)|.
Hence, by induction, we have that |pnc (0)| → ∞.
Characterization of M
Theorem. c ∈M ⇔ |pnc (0)| ≤ 2 for all n ≥ 1.
Proof ⇐: By the J (pc) Connectedness Characterization, |pnc (0)| ≤2 for all n ≥ 1⇒ c ∈M.
⇒: Say |pkc(0)| > 2 for some k. If |c| > 2, then |pnc (0)| ≥ |c| > 2.If |c| ≤ 2, |pnc (0)| ≥ |c|.
In either case, we can apply the above Lemma for some n to getthat |pkc(0)| → ∞. Hence, c 6∈ M.
Corollary. M⊂ D2, the disc of radius 2.
Proof |pc(0)| = |c|.
This bound is sharp. J (p−2) = [−2,2] is connected, so −2 ∈M.
Compactness
Theorem. M is compact.
Proof Let Mn be the set of parameter values with |pnc (0)| ≤ 2.
Let ck ⊂Mn be a sequence in Mn, and ck → c.Then |pnck(0)| → |pnc (0)|. Since |pnck(0)| ≤ 2, |pnc (0)| ≤ 2, so foreach n, Mn is a closed set.
The Characterization of M above gives that
M =∞⋂n=1
Mn,
so M is also closed.
M is closed and bounded, so M is compact.
The Mandelbrot Set is Connected?
We outline the Proof given by Douady and Hubbard that M is
a connected subset of C.
Our first stop is a result of Bottcher’s that underlies the proof.
Theorem. Let f(z) be a polynomial of degree n ≥ 2. Then
there is an conformal change of coordinates w = ψ(z) such that
ψ f ψ−1 : w 7→ wn
on some neighbourhood of ∞. ψ is unique up to multiplication
by an n−1 root of unity.
We say that f is conformally conjugate to zn, with conjugacy ψ.
The Bottcher Coordinate for pc
The above Theorem gives that pc is conformally conjugate to the
map z 7→ z2 in some neighbourhood, Uc, of ∞ and the conjugacy
is unique.
Douady and Hubbard go further and calculate the explicit form
of the conjugacy.
Theorem. Let Bc : Uc → C \ DR be the conformal conjugacy
associated with the polynomial pc. Then
Bc(z) = lim[pnc (z)
]1/2n,
where the root on the RHS is choosen so that[pnc (z)
]1/2n∼ z.
Moreover, Bc(z) ∼ z near ∞.
Analytic Continuation of the Bottcher Coordinate for pc
It is straightforward to show that the Bottcher coordinate obeysthe following formula.
Bc[pc(z)
]=
[Bc(z)
]2.
We can see that Bc obeys the conjugacy relationship with pc.
Now, if the critical point c is not in Uc, then pc has an analyticinverse that sends Uc to the pre-image p−1
c (Uc), by the InverseFunction Theorem.
The above equation then gives us a way to conformally extendBc to the bigger domain p−1
c (Uc).
If c is not in p−1c (Uc) either, we can extend to p−2
c (Uc), and soon, until c ∈ p−kc (Uc).
Analytic Continuation of the Bottcher Coordinate for pc
These extensions give us the the conformal map
Bc : Ωc → C \ DRc,
where the new domain Ωc depends on J(pc).
If J (pc) is connected, c 6∈ A(∞), so the extending process out-lined for Bc can be repeated infinitely, so Ωc = A(∞).
If J (pc) is disconnected, c ∈ A(∞), so the extended domain willeventually contain c. The Inverse Function Theorem then failsto provide an inverse.
Though it is not obvious from this discussion, Rc = 1 when J (pc)is connected, and Rc > 1 otherwise.
The Mandelbrot IS Connected.
We now consider the function
Φ : C∗ \M → C∗ \ D1, where c 7→ Bc(c).
Φ is well defined as c ∈ Ωc ⇔ J (pc) disconnected ⇔ c 6∈ M,
and B∞(∞) =∞.
Φ is also conformal. (not proved here)
Hence, C∗ \M and C∗ \ D1 are conformally equivalent via Φ, so
C∗ \M is simply connected.
Thus, M is connected.