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The Design of Fiber Reinforced Polymers for Structural
StrengtheningAn Overview of ACI 440
Guidelines
Sarah WittFyfe Company
November 7, 2008
1
2
GUIDE FOR THE DESIGN AND CONSTRUCTION OF EXTERNALLY
BONDED FRP SYSTEMS FOR STRENGTHENING CONCRETE
STRUCTURES
ACI Document 440.2R-08Printed July 2008
3
OutlineStrengthening Concrete Structures
Reasons for strengtheningTypes of FRP strengthening systemsMaterials and properties of FRP strengthening systems
Substrate Preparation/FRP ApplicationRepairProper detailing and installation methodsQuality control
Design PrinciplesStrengthening limitsFlexural strengtheningShear strengtheningAxial strengthening
Reinforcement DetailsBond and delaminationDetailing of laps and splices
Design Examples and Case Studies
4
Reasons for Strengthening
Change in useConstruction or design defectsCode changesSeismic retrofitDeterioration
5
Excessive Loading
6
Flexural Cracking
7
Overloading
8
Seismic Loads
9
Improper Steel Placement
10
Impact Damage
11
Typical FRP Systems forStrengthening Structures
Wet lay-up systemsUnidirectional fiber sheetsMultidirectional fiber sheetsMechanically applied fiber tows
Prepreg systemsUnidirectional fiber sheetsMultidirectional fiber sheetsMechanically applied fiber tows
Precured systemsUnidirectional laminatesMultidirectional gridsShell elements
Other forms not covered
Section 3.2, Guide:
12
Typical FRP Systems forStrengthening Structures
13
Typical FRP Systems forStrengthening Structures
14
Typical Fiber Properties
Carbon
Aramid
E-Glass
Substrate Preparation / RepairBond vs. Contact Critical
Contact CriticalRequires intimate contact between the FRP System and the concrete
Confinement of columns
Bond CriticalRequires an adhesive bond between the FRP system and the concrete
Beam, slab and wall strengthening
15
16
Substrate Preparation / Repair
Removal / replacement of unsound concrete
Substrate issues:ACI 503ICRI 03730
200 psi (1.4 MPa) minimum tensile strength2500 psi minimum compressive strength of concrete
Section 6.4, Guide:
17
Substrate Preparation
Preparation of concrete surface
Section 6.4, Guide:
Minimum ICRI CSP 3
18
Epoxy Injection
Cracks wider than 0.010 in (0.3 mm) should be injected prior to application of the FRP system.
ACI 224.1
Smaller cracks in aggressive environments may require sealing
Section 6.4, Guide:
19
Quality Control & Assurance
Bond testingACI 503RASTM D4541Tension adhesion strengths should exceed 200 psi (1.4 MPa), exhibit failure of the concrete substrate.
Cured thicknessExtract small core samples less than 0.5 in (13 mm) diameterAvoid sampling in high stress areas if possibleRepair using overlapping sheets on filled core.
During-construction:
20
Quality Control & Assurance
General Acceptance Criteria for DelaminationsWet Layup
Delaminations less than 2 in2 (1300 mm2) each are permissible:No more than 10 delaminations per 10 ft2 of laminate areaTotal delamination area less than 5% of total laminate area
Delaminations less than 25 in2 (16,000 mm2) may be repaired by resin injection or ply replacement, depending upon the size, number and location of delaminations.Delaminations greater than 25 in2 (16,000 mm2) should be repaired by selectively cutting away the affected sheet and applying an overlapping sheet patch of equivalent plies.
Precured systemsEach delamination must be inspected and repaired in accordance with the engineer’s direction
Post-construction:
21
Design Guidelines
22
FRP Strengthening Applications
Flexural StrengtheningBeams, Slabs, Walls, etc.
Shear StrengtheningBeams, Columns, Walls, etc.
Axial EnhancementColumn Wrapping, Pressure Vessels
2323
Strengthening Limits
Limited by strength of other structural componentsColumns, footings, etc.
Limited by other failure mechanismsPunching shear
Loss of FRP should not result in immediate collapse
( ) ( )newLLDLexistingn SSR 75.01.1 +≥φ (9-1)
Section 9.2, Guide:
2424
Structural Fire Endurance
Glass Transition Temperatures of most FRP systems is typically in the range of 140 - 180oF (60 - 80oC)Use of an insulation system can improve the overall fire rating of the strengthened reinforced concrete memberInsulation system can delay strength degradation of concrete and steel, increasing the fire rating of the memberThe contribution of the FRP system can be considered if it is demonstrated that the FRP temperature remains below a critical temperature
25
Rational Fire Endurance Check
Given cover and fire endurance requirementFind the temperature of the steel & concreteFind a reduced steel & concrete material strengthFind the associated reduced section strengthReduced strength > Unfactored demandNo phi factors or load factors
ACI 216R:
26
Rational Fire Endurance Check
From ACI 216R - Reduce material strengths at elevated temperature:
( ) ( )LLDLexistingn SSR +≥
Steel: θyy ff →
Concrete: θcc ff '' →
FRP: *0→fuf
Section 9.2.1, Guide:
(9-2)
2727
Maximum Service Temperature
Typical glass transition temperature (Tg) for epoxy 140 -
180oF (60 - 80oC)
Above Tg mechanical properties start to degrade
Service temperature should not exceed Tg - 27°F (Tg – 15°C)
Section 1.3.3, Guide:
28
Flexural StrengtheningChapter 10, Guide
Typical flexural strength increases up to 40%This limit is based on the Guide’s requirements
Positive and negative moment strengtheningAdd strength to RC and PC membersReduce crack widthsSeismic loadings not covered
un MM >φ (10-1)
29
Assumptions
Design calculations are based on actual dimensions and material properties.Plane sections remain plane (including FRP).Maximum compressive strainTensile strength of concrete is ignored.FRP has linear-elastic relation to failure.Perfect bond between FRP and concrete (no slip).The shear deformation within the adhesive layer is neglected.
003.0=cuε
Section 10.2.1, Guide:
30
Verification of Shear Capacity
Section shear capacity must be sufficient to handle shear forces associated with increased flexural capacity.
Section 10.2.1, Guide:
31
Failure Modes
1. crushing of concrete prior to steel yield2. yield of steel followed by concrete crushing3. yield of steel followed by FRP failure4. shear / tension delamination in concrete cover5. FRP debonding from substrate
The desired mode of failure is usually mode 2 or 3.
Section 10.1.1, Guide:
32
Effective Strain in FRP
0
100
200
300
400
500
600
0 0.005 0.01 0.015 0.02Strain (in/in)
Stre
ss (k
si)
Effective Strain
Rupture Strain
33
Limitation on Strain in FRP
fuff
cfd tnE
f εε 9.0083.0'
≤= (10-2) US
To prevent debonding in regions away from FRP Termination
(10-2) SI
fdbicufe cch εεεε ≤−⎟⎠⎞
⎜⎝⎛ −
= (10-3)
fuff
cfd tnE
f εε 9.041.0'
≤=
34
Calculation Procedure
Estimated c = c for Equilibrium?
Estimate neutral axis, c
Determine initial strain in substrate
Determine failure mode
Calculate material strain
Calculate stresses and forces
Check Equilibrium (Calculate c)
Compute Moment Capacity
Check service conditions
YesNo
35
Estimate the Neutral Axis DepthNo closed form solution existsMust find depth to the neutral axis by trial and errorAs a starting point, a good rule of thumb is 20% of the effective section depth
dc 20.0≈
c
εs
εfe εbiεb
εc
36
Determine Mode of Failure
Concrete Crushing Controls
FRP Rupture Controls
(10-3)fdbicufe cch εεεε ≤−⎟⎠⎞
⎜⎝⎛ −
=
fdbicufe cch εεεε ≤−⎟⎠⎞
⎜⎝⎛ −
=
fdbicufe cch εεεε ≥−⎟⎠⎞
⎜⎝⎛ −
=
37
Concrete Stress Block
Whitney stress block is valid only when concrete crushing governs failure (i.e., εc=0.003)If FRP rupture controls, a stress block appropriate for the concrete strain level should be used
ActualStress
Distribution
EquivalentStress
Distribution
γf 'c
β1cc
38
Concrete Stress Block
( ) ( )[ ]( ) ( )22
1
1 1ln tan42
cccc
cccc
εεεεεεεεβ′+′′−′
−=−
( )cc1
2c
2c1900
ε′εβε′ε+
=γ ln.
c
cc E
f711 ′=ε′
.
εc < 0.003
γf'c
β1c
39
Calculation of Flexural StrainAssume strain compatibilityBased on failure modeCalculate the strain in each material by similar triangles
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛
−−
+=cdcd
fbifes εεε (10-10)
c
εs
εfe εbiεb
εc
40
Calculation Of Stress
ysss fEf ≤= ε
Steel – Elastic / Plastic:
fesfe Ef ε=FRP – Elastic:
(10-11)
(10-9)
StrainSt
ress FRP
Steel
41
Check Force EquilibriumSum forces in the horizontal directionIf forces do not equilibrate, revise “c”Repeat previous steps
bffAfA
cc
fefssest ′
+=
11αβ Asfs
α1f'cβ1c
Afff
42
Ultimate Strength Model
εfe εbiAf = n tf wfffe = Ef εfe
fsεs
εc
c
⎟⎠⎞
⎜⎝⎛ −+⎟
⎠⎞
⎜⎝⎛ −=
2211 chfAcdfAM feffssnβψβ
(10-13)
43
Loss in Ductility
( )
⎪⎪⎩
⎪⎪⎨
⎧
≤
<<−
−+
≥
=
syt
tsysy
syt
t
for
for
for
εε
εεεεε
ε
φ
65.0
005.0005.0
25.065.0
005.090.0
ACI 318 :A section with lower ductility should compensate with a higher reserve of strength
(10-5)
0.90
0.65
φ
Steel Strain at Ultimate
εsy 0.005
ρb
≈0.75ρb
44
Design Flexural Strength
⎥⎦
⎤⎢⎣
⎡⎟⎠⎞
⎜⎝⎛ −+⎟
⎠⎞
⎜⎝⎛ −=
2211 chfAcdfAM fefssnβψβφφ
Reduction factor for FRP contribution: 85.0=ψ
(10-13)
(10-1)un MM >φ
45
ServiceabilityAt service, stress in steel should be limited to 80% of yield strength:
yss ff 80., ≤ (10-6)
Curvature
Mom
ent
Unstrengthened
FRP Strengthened
Ms
My
Mu
46
Prestressed Concrete MembersAssumptions
Assumptions for concrete members applystrain compatibility for strain or change in strain in the prestressing steel prestressing steel rupture mode should be investigatedwhere prestressing steel is draped several sections should be evaluated
47
Prestressed Concrete MembersFailure Modes
1. Strain level in FRP governed by strain limitations due:1. concrete crushing2. FRP rupture3. FRP debonding4. Prestressing steel failure
48
To maintain a sufficient ductility the nominal strain in the prestressing steel should be higher than 0.013. If this strain is not achieved a lower strength factor should be used
Prestressed Concrete MembersStrength Reduction Factor
( )( )
⎪⎪⎩
⎪⎪⎨
⎧
≤
<<−
−+
≥
=
010.065.0
013.0010.0010.0013.0010.025.0
65.0
013.090.0
ps
psps
ps
for
for
for
ε
εε
ε
φ (10-19)
49
In service stress in the prestressing steel should be prevented from yielding:
Prestressed Concrete MembersServiceability
pysps ff 82.0, ≤
pusps ff 74.0, ≤
(10-20a)
(10-20b)
50
•The calculation procedure for nominal strength:• satisfy should strain compatibility•satisfy force equilibrium•consider mode of failure•similar to method for reinforced members
Prestressed Concrete MembersNominal Strength
51
For a given value of the neutral axis, c:
Prestressed Concrete MembersNominal Strength
feffe Ef ε=
035.01 2
2
≤+⎟⎟⎠
⎞⎜⎜⎝
⎛++= pnet
cc
epeps r
eEA
P εεε
Stress level in the FRP
Strain in the tendon
(10-21)
(10-22)
52
The value of enet depends on the mode of failure
Prestressed Concrete MembersNominal Strength
⎟⎟⎠
⎞⎜⎜⎝
⎛ −≤
ccd p
pnet 003.0εconcrete crushing
FRP rupture or debonding ( ) ⎟
⎟⎠
⎞⎜⎜⎝
⎛
−−
+≤cdcd
f
Pbifepnet εεε
(10-23a)
(10-23b)
53
Force equilibrium can be checked by satisfying:
Prestressed Concrete MembersNominal Strength
bffAfA
cc
fefpsp
1'
1 βα+
= (10-25)
54
Case Study – Slab Upgrade
P/T flat slab live load increase:
50 – 100 psf
55
Case Study – Slab Upgrade
Positive moment upgrade to column strip
56
Shear StrengtheningChapter 11, Guide
un VV >φ
Increase shear capacity of beams or columnsAmount of increase depends on section geometry, existing reinforcement, and a variety of additional factors.
Change failure mode to flexuralTypically results in a more ductile failure
(11-1)
57
Wrapping Schemes
Fully Wrapped “U-wrap” Two sides bonded
Overlap
58
Effective Strain in FRP
Maximum strain that can be achieved in the FRP system at the ultimate load stageGoverned by the failure mode of the FRP system and the strengthened member.
memberswrappedcompletelyforfufe εε 75.0004.0 ≤=
pliesfaceorwrapsUbondedforfuvfe −≤= 004.0εκε
(11-6a)
(11-6b)
59
Effective Strain Limitations for FRPDetermination of bond-reduction coefficient κv:
75.0468
Lkk
fu
e21v ≤
ε=κ (11-7) US
75.0900,11
21 ≤=fu
ev
Lkkε
κ
3/2'c
1 4000f
k ⎟⎟⎠
⎞⎜⎜⎝
⎛= (11-9) US
3/2'c
1 27f
k ⎟⎟⎠
⎞⎜⎜⎝
⎛=
⎪⎪⎩
⎪⎪⎨
⎧
−−
−
=bondedsidestwofor
dLd
wrapsUford
Ld
k
f
ef
f
ef
22
(11-7) SI(11-9) SI
(11-10)
60
Effective Strain Limitations for FRPDetermination of active bond length Le:
(11-8) US( ) 58.0ff
e Etn2500L = ( ) 58.0
ffe
Etn300,23L = (11-8) SI
Le
61
Effective Strain Limitations for FRPDetermination of bond-reduction coefficient κv:
75.0468
Lkk
fu
e21v ≤
ε=κ (11-7) US
75.0900,11
21 ≤=fu
ev
Lkkε
κ
3/2'c
1 4000f
k ⎟⎟⎠
⎞⎜⎜⎝
⎛= (11-9) US
3/2'c
1 27f
k ⎟⎟⎠
⎞⎜⎜⎝
⎛=
⎪⎪⎩
⎪⎪⎨
⎧
−−
−
=bondedsidestwofor
dLd
wrapsUford
Ld
k
f
ef
f
ef
22
(11-7) SI(11-9) SI
(11-10)004.0≤= fuvfe εκε
62
Pertinent Shear Dimensions
df
wf
sf
wf
sf
β
( )f
ffefvf s
dcossinfAV
α+α=
fffv wnt2A =
ffefe Ef ε=
(11-3)
(11-4)
(11-5)
α
63
Design Shear Capacity
( )ffscn VVVV ψφφ ++=
( )
)(85.0
)(95.0)318(85.0
pliesfaceorwrapsUbonded
wrappedfullyACI
VVVV
f
f
fscn
−=
==
++=
ψ
ψφ
ψφφ
(11-2)
64
Spacing, Reinforcing Limits
4max,dws ff +=
dbfVV wcfs '8≤+
bdf66.0VV cfs ′≤+
(11-11) US
Section 11.1, Guide:
Based on ACI 318-05, Section 11.5.6.9:
(11-11) SI
65
Case Study – Precast Garage
Installed FRP “U” Wraps
66
ConfinementChapter 12, Guide
Increase in member axial compressive strengthEnhance the ductility of members subjected to combined axial and bending forcesIncrease the strength of members subjected to combined axial and bending forces
67
Axial Compression
Fibers oriented transverse to the longitudinal axis of the member
Contribution of any longitudinal fibers to axial strength is negligible
Results in an increase in the apparent strength of the concrete and in the maximum usable compressive strain in the concretePassive confinement
Intimate contact between FRP system and member is critical
Confinement
Confining Pressure
69
FRP Confined Concrete Behavior
ccf ′
ccuε
cf ′
Longitudinal StrainTransverse Strain (Dilation)
Stre
ss
Unconfined Concrete
FRP Confined Concrete
εL
εT
Longitudinal Strain
Transverse Strain
cf ′85.0
cε ′ 003.0=cuεfuε feε
70
FRP Confined Concrete
Strain Limitation
fufe εκε ε≤= 004.0
Longitudinal StrainTransverse Strain (Dilation)
fufe εκε ε= (12-5)
(12-12)
For pure axial loading:
For combined axial + bending:
55.0=εκ Recommended value (accounts for premature failure strain of FRP)
Limit to maintain shear integrity of concrete
71
FRP Confinement Model
ccu
ccc ffEε
′−′=2
( )
⎪⎩
⎪⎨⎧
≤≤′+′
′≤≤′
−−=
ccuctcc
tccc
ccc
c
forEf
forfEEEf
εεεε
εεεε
2
22
2 04
2
2EE
f
c
ct −
′=′ε
Longitudinal StrainTransverse Strain (Dilation)
Where,
Stre
ss
Unconfined Concrete
FRP Confined Concrete
Ec
E2
Strain
ccf ′
cf ′
tε ′cε ′ ccuε
(12-2a)
(12-2b)
(12-2c)
72
FRP Confinement Model
⎟⎟
⎠
⎞
⎜⎜
⎝
⎛⎟⎟⎠
⎞⎜⎜⎝
⎛′′
+′=45.0
1250.1c
fe
c
lbcccu f
fεε
κεε
lafccc fff κψ 3.3+′=′
Longitudinal StrainTransverse Strain (Dilation)
Where,
fl is the confining pressure exerted by the FRP jacket
κa and κb are shape factors
Stre
ss
Unconfined Concrete
FRP Confined Concrete
Ec
E2
Strain
ccf ′
cf ′
tε ′cε ′ ccuε
(12-3)
(12-6)
73
Circular Sections
Ef εfe
FRP Jacket
fl
flEf εfe
fl
Concrete0.1== ba κκ
Shape factors:
DtnE
f feffl
ε2= (12-4)
Confining pressure:
74
Rectangular Sections
b
h
D 22 hbD +=
DtnE
f feffl
ε2= (12-4)
Confining pressure:
Equivalent circular column
75
Rectangular Sections
2
⎟⎠⎞
⎜⎝⎛=
hb
AA
c
eaκ
b
h
Effective confinement area, Ae
5.0
⎟⎠⎞
⎜⎝⎛=
bh
AA
c
ebκ
Shape factors:
(12-9)
(12-10)
Confining stress concentrated at corners
76
Rectangular Sections
Ratio of effective confinement area to total area of concrete
( ) ( )
g
gg
cc
c
e A
rbbhrh
hb
AA
ρ
ρ
−
−⎥⎦
⎤⎢⎣
⎡−⎟
⎠⎞
⎜⎝⎛+−⎟
⎠⎞
⎜⎝⎛
−=
13
221
22
(12-11)
77
Using the Confinement Model
( )[ ]stystgccn AfAAfP +−= '85.085.0 φφ
with existing steel spiral reinforcing
with existing steel-tie reinforcing:
( )[ ]stystgccn AfAAfP +−= '85.080.0 φφ
Compressive Strength:
(12-1a)
(12-1b)
Use the confined concrete compressive strength in ACI 318 equations
78
Serviceability Considerations-Axial Compression
To ensure radial cracking will not occur under service loads,
'65.0 cc ff ≤
To avoid plastic deformation under sustained or cyclic loads,
ys ff 60.0≤
Section 12.1.3, Guide:
79
Reinforcement DetailsChapter 13, Guide
General Guidelines:Do not turn inside corners;Provide a minimum 1/2 in. (13 mm) radius when the sheet is wrapped around outside cornersProvide adequate development length
Provide sufficient overlap when splicing FRP plies.
80
Allowable Termination Points –Simply Supported Beams
Plies should extend a distance equal at least to ldfpast the point along the span corresponding to the cracking moment, Mcr, If Vu > 0.67Vc at the termination point the FRP laminate should be anchored with transverse (“clamping”) reinforcement
Section 13.1.2, Guide
81
Bond and DelaminationTransverse (“clamping”) reinfocement
Area of transverse (“clamping”) FRP U-Wrap reinforcement to prevent concrete cover layer from splitting:
( )( )
anchorfuvf
allongitudinfufanchorf E
fAA
εκ= (13-1)
82
Development Length
The bond capacity of FRP is developed over a critical length:
'057.0
c
ffdf
f
tEnl =
(13-2)
'c
ffdf
f
tEnl =
in in.-lb units
in SI units
83
Detailing of NSM bars
groove dimensions shall be at least 1.5 times the diameter of the barFor a rectangular bar the minimum groove size shall be 3ab x 1.5bb
84
Development Length of NSM bars
Development length of NSM bar:
( ) fdb
db fdlmax5.04 τ
=
( )( ) fdbb
bbdb f
badal
max5.02 τ+=
Development length of NSM bar:
for rectangular bars
for circular bars (13-3)
(13-4)
QUESTIONS?
Thank You
85
86
Design Example
Flexural Strengthening of Interior Beam
87
Manufacturer’s reported FRP-system properties
24’-0”
w
DL,wLL
ELEVATION SECTION
12”
21.5”
24”f’c=5000 psi
3-#9 barsfy=60 ksi
FRP
2-12”x 23’-0” FRP pliesφMn=266 k-ft
(w/o FRP)
Thickness per ply, 0.040 in. 1.016 mm
Ultimate tensile strength 90 ksi 0.62 kN/mm2
Rupture strain, 0.015 0.015
Modulus of elasticity of FRP laminates, 5360 ksi 37 kN/mm2
Design Example: Flexural Strengthening of an Interior Beam
88
Loadings and corresponding moments
Two, 12 in. wide by 23 ft. long plies are to be bonded to the soffit of the beam using the wet-lay-up technique.
Loading/Moment Existing loads Anticipated loadsDead loads, wDL 1.00 k/ft 14 N/mm 1.00 k/ft 14 N/mmLive load, wLL 1.20 k/ft 17 N/mm 1.80 k/ft 26 N/mm
Unfactored loads, (wDL + wLL) 2.20 k/ft 32.1 N/mm 2.80 k/ft 40.9 N/mm
Unstrengthened load limit (1.1wDL +0.75wLL) n/a n/a 2.45 k/ft 34.9 N/mm
Factored loads, (1.2wDL +1.6wLL) 3.12 k/ft 50.2 N/mm 4.46 k/ft 65.1 N/mm
Dead-load moment, MDL 72 k-ft 96.2 kN-m 72 k-ft 96.2 kN-mLive-load moment, MLL 86 k-ft 114.9 kN-m 130 k-ft 173.6 kN-m
Service-load moment, Ms 158 k-ft 211.1 kN-m 202 k-ft 269.8 kN-mUnstrengthened moment limit (1.1MDL +0.75MLL) n/a n/a 177 k-ft 240 kN-m
Factored moment, Mu 224 k-ft 303.6 kN-m 294.4 k-ft- 399.2 kN-m
Design Example: Flexural Strengthening of an Interior Beam
89
• Step 1 - Compute the FRP-system design material properties
*fuEfu fCf =
*fuEfu C εε =
For an interior beam, an environmental-reduction factor (CE ) of 0.95 is suggested.
85ksiksi)(0.95)(90 ==fuf
in.0.0142in./15in./in.)(0.95)(0.0 ==fuε
Design Example: Flexural Strengthening of an Interior Beam
90
• Step 2 - Preliminary calculations
Properties of the concrete:
β1 from ACI 318-05, Section 10.2.7.3.
1'1.05 0.05 0.80
1000cfβ = − =
psi4,030,000psi500057,000 ==cE
Design Example: Flexural Strengthening of an Interior Beam
91
Properties of existing reinforcing steel:
bdAs
s ≡ρ
22 in.3.00)in.3(1.00 ==sA
( )( ) 0.0116in.21.5in.12
in.3.00 2
==ρ s
Design Example: Flexural Strengthening of an Interior Beam
• Step 2 - Preliminary calculations
92
• Step 2 - Preliminary calculations
Properties of the externally bonded FRP reinforcement:
fff wntA =
bdAf
f ≡ρ
( )( )( ) 2ply
in. 0.96in.in. 120.040plies 2 ==fA
( )( ) 0.00372in. 21.5in. 12
in. 0.96 2
==fρ
Design Example: Flexural Strengthening of an Interior Beam
93
• Step 3 - Determine the existing state of the strain on the soffit
The existing state of strain is calculated assuming the beam is cracked and the only loads acting on the beam at the time of the FRP installation are dead loads. A cracked section analysis of the existing beam gives k=0.334 and Icr=5937 in.4
ccr
DLbi EI
kdhM )( −=ε
( ) ( )( )[ ]( )( )
0.00061ksi4,030in.5,937
in.21.50.334in.24in.k8644
=
−⋅=
bi
bi
ε
ε
Design Example: Flexural Strengthening of an Interior Beam
94
0128.0)0142.0(9.00113.0 =≤=fdε
• Step 4 – Determine the design strain of the FRP System
( ) ( ) fufd inpsipsi εε 9.0
04.0000536025000083.0 ≤=
Design Example: Flexural Strengthening of an Interior Beam
95
• Step 5 - Estimate c, the depth to the neutral axis
A reasonable initial estimate of c is 0.20d. The value of c is adjusted after checking equilibrium.
dc 20.0= ( )( ) in. 4.30in. 21.50.20 ==c
Design Example: Flexural Strengthening of an Interior Beam
96
• Step 6 - Determine the effective level of strain in the FRP reinforcement
fdbif
fe ccd
εεε ≤−⎟⎟⎠
⎞⎜⎜⎝
⎛ −= 003.0
009.000061.03.4
3.424003.0 ≤−⎟⎠⎞
⎜⎝⎛ −
=feε
009.00131.0 ≤=feε
009.0=feε
Design Example: Flexural Strengthening of an Interior Beam
97
Since FRP controls the section failure, the concrete strain is less than 0.003:
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛
−+=
cdc
fbiefc εεε
( ) 0021.03.424
3.400061.0009.0 =⎟⎠⎞
⎜⎝⎛
−+=cε
Design Example: Flexural Strengthening of an Interior Beam
98
• Step 7 - Calculate the strain in the existing reinforcing steel
( ) ⎟⎟⎠
⎞⎜⎜⎝
⎛
−−
+=cdcd
fbifes εεε
( ) 0084.030.42430.45.2100061.0009.0 =⎟
⎠⎞
⎜⎝⎛
−−
+=sε
Design Example: Flexural Strengthening of an Interior Beam
99
• Step 8 - Calculate the stress level in the reinforcing steel and FRP
ysss fEf ≤ε=
feffe Ef ε=
ksi60ksi348ksi60)0084.0)(ksi000,29(s
≤=≤=
sff
( )( ) ksi.2840.009ksi5,360 ==fef
Design Example: Flexural Strengthening of an Interior Beam
100
• Step 9a - Calculate the internal force resultants
Approximate stress block factors may be calculated using the parabolic stress-strain relationship of concrete as follows:
0021.010030,4
)000,5(7.17.16
'' =
×==
c
cc E
fε
Design Example: Flexural Strengthening of an Interior Beam
749.0)0021.0(2)0021.0(6
0021.0)0021.0(426
4'
'
1 =−−
=−−
=cc
cc
εεεεβ
886.0)0021.0()749.0(3)0021.0()0021.0(3
33
22'
2'
1 ==−
=c
ccc
γεεεεα
101
• Step 9b – Check equilibrium
Force equilibrium is verified by checking the initial estimate of the neutral axis, c
Design Example: Flexural Strengthening of an Interior Beam
inbcfAAfA
cc
fefss 87.5)12)(749.0)(5)(886.0()2.48)(96.0()60)(3(
1'
1
=+
=+
=βα
NGininc 30.487.5 ≠=
102
• Step 10 – Iterate on c until force equilibrium is satisfied
in.17.5=c0083.0=sε
ksi 06== ys ff
009.0=fdε
ksi 49.8=fef
( )( ) ( )( )( )( )( )( )in.120.786ksi50.928
ksi48.2in.0.96ksi60in.3.00 22 +=c
.Oin.5.17 Kc ==
The value of c selected for the final iteration is correct.
Design Example: Flexural Strengthening of an Interior Beam
0027.0=cε
786.01 =β
928.01 =α
103
• Step 11 – Calculate reinforcement and FRP contribution to strength
ftkinkcdfAM ssns −=−=⎟⎠⎞
⎜⎝⎛ −=⎟
⎠⎞
⎜⎝⎛ −= 292504,3
2)17.5(786.05.21)60)(00.3(
21β
Design Example: Flexural Strengthening of an Interior Beam
ftkinkcdfAM ffefsf −=−=⎟⎠⎞
⎜⎝⎛ −=⎟
⎠⎞
⎜⎝⎛ −= 85017,1
2)17.5(786.024)2.48)(96.0(
21β
104
• Step 11 – Calculate design flexural strength of the section
[ ] ( ) ftkMMM nfnsn −=+=+= 327)85(85.02929.0ψφφ
The strengthened section is capable of sustaining the new required moment strength
Design Example: Flexural Strengthening of an Interior Beam
The flexural strength is calculated using the reduction factor. Since εs =0.0083>0.005, the value of Ф is 0.9
ftkMftkM un −=≥−= 294327φ
105
• Step 12 – Check service stresses in the reinforcing steel and the FRP
Calculate the elastic depth to the cracked neutral axis by summing the first moment of the areas of the transformed section.
Design Example: Flexural Strengthening of an Interior Beam
106
• Step 13 – Check service stresses in the reinforcing steel and the FRP
⎟⎟⎠
⎞⎜⎜⎝
⎛+−⎟⎟
⎠
⎞⎜⎜⎝
⎛⎟⎠⎞
⎜⎝⎛++⎟⎟
⎠
⎞⎜⎜⎝
⎛+=
c
ff
c
ss
c
ff
c
ss
c
ff
c
ss E
EEE
dh
EE
EE
EE
EEk ρρρρρρ 2
2
343.0k =
( )( ) in. 7.37in. 21.50.343 ==kd
Design Example: Flexural Strengthening of an Interior Beam
107
• Step 13 – Check service stresses in the reinforcing steel and the FRP
Calculate the stress level in the reinforcing steel:
( )
( ) ( )y
ffffss
sffbis
ss fkddkddEAkddkddEA
EkddkdhEAMf 8.0
33
3, ≤
−⎟⎠⎞
⎜⎝⎛ −+−⎟
⎠⎞
⎜⎝⎛ −
−⎥⎦
⎤⎢⎣
⎡⎟⎠⎞
⎜⎝⎛ −+
=ε
( )( ) OKksi 48ksi 600.80ksi 40.4, =≤=ssf
The stress level in the reinforcing steel is within the recommended limit
Design Example: Flexural Strengthening of an Interior Beam
108
• Step 14 – Check creep rupture limit t service for the FRP
Calculate the stress level in the FRP:
fufbif
s
fsssf fE
kddkdd
EE
ff 55.0,, ≤−⎟⎟⎠
⎞⎜⎜⎝
⎛−
−⎟⎟⎠
⎞⎜⎜⎝
⎛= ε
OKksiksif sf 50)85)(55.0(60.5, =≤=
Design Example: Flexural Strengthening of an Interior Beam
109
• Step 14 – Detailing Requirements
Detail the FRP reinforcement as follow:
1. Check that shear force at termination is less than shear force that causes end-peeling (estimate as 2/3 of concrete shear strength).
2. Terminate FRP at ldf (per Eq. 12.2) past cracking moment.a) If shear force is higher extend FRP beyond and/or use
FRP U-wraps.
Design Example: Flexural Strengthening of an Interior Beam