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Test - 09 (Code E) (Answers) All India Aakash Test Series for Medical-2018

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35. (1)

36. (2)

Test Date : 08/04/2018

TEST - 09 (Code E)

All India Aakash Test Series for Medical - 2018

ANSWERS

37. (2)

38. (4)

39. (4)

40. (4)

41. (1)

42. (2)

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150. (2)

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153. (4)

154. (3)

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156. (3)

157. (2)

158. (4)

159. (3)

160. (2)

161. (2)

162. (3)

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164. (4)

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167. (3)

168. (4)

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171. (2)

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173. (3)

174. (4)

175. (1)

176. (3)

177. (3)

178. (2)

179. (1)

180. (3)

All India Aakash Test Series for Medical-2018 Test - 09 (Code E) (Hints)

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PHYSICS

1. According to principle of homogeneity,

6 2 2 6 8 2

6

AE A Er ML T L ML T

r

⇒

12 2 2 12 14 2

12

BE B Er ML T L ML T

r

⇒

2.1 2

1 2

t tt

t t

t1 = 90 s

t = 36 s

t2 = ?

2

2

9036

90

t

t

36 × 90 + 36t2 = 90t

2

36 × 90 = 54t2

2

36 9060 s

54t

3.1 2

cot cot 602 3

u u u u

tg g g

4.

mgcosmg

mgsin

f

h

r-h

RO

f = N

mgsin = mgcos = tanBut, h = r(1 – cos)

2

11

1

⎛ ⎞ ⎜ ⎟⎜ ⎟ ⎝ ⎠

h r

5. m1u

1 + m

2u

2 = m

1v

1 + m

2v

2From, u

1 – u

2 = v

2 – v

1

3 3 3

1 2 2 20r u r u r v 2u = v

2 – 0

3 3 3

1 2 2(2 )r u r u r u v

2 = 2u

3 3

1 23r u r u

HINTS

3

3 1

23

rr

1

2 1/3 1/33 3

r rr

6.

L

4

C1

C2

C

O

/2x

From OCC1,

cos2

4

x

L

cos4 2

Lx

7.21(1 )

2mgh mv

2

(1 )2

vgh

5 11

2 2

gRgh

⎛ ⎞ ⎜ ⎟⎝ ⎠

5 3 15

2 2 4

R Rh

8. u = uf – u

i

2 21 1( )

2 2k a b ka

2 2 21[( 2 )]

2k a b ab a

21[ 2 ]

2k b ab

1( 2 )

2kb b a

9. Acceleration of block is 6 2

3 3= = =

Fa

m m m

For block 2m, N 2m

N = 2ma

22 4 N= ⇒N m

m

Test - 09 (Code E) (Hints) All India Aakash Test Series for Medical-2018

3/9

10.Δ ρ

= =⎛ ⎞Δ Δ ⎟⎜ ⎟⎜ ⎟⎜⎝ ⎠

P ghB

V V

V V

11. F1 = Force due to complete sphere

24

GMm

R

F2 = Force due to removed portion of sphere

2 2

8

9 18

4

⎛ ⎞⎜ ⎟⎝ ⎠

MG m

GMm

R R

Fnet

= Force due to remaining part of sphere

1 2 2

1 1

4 18

GMmF F

R

⎛ ⎞ ⎜ ⎟⎝ ⎠

2 2

9 2 7 7

36 9 94

GMm GMm F

R R

⎛ ⎞ ⎛ ⎞ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠

12. Compare with equation, x = acost

In 3 s, its distance is 3a

2

24 s

2

⇒ TT

13. Conceptual

14. Let h be the height will the ball jump out of water.

Using work energy theorem,

WB + W

gravity = KE

FBh

– W(h + h) = 0

1⎛ ⎞⎟⎜′ = − ⎟⎜ ⎟⎟⎜⎝ ⎠

BF

h hW

water

body

1

⎛ ⎞ρ ⎟⎜ ⎟⎜′ = − ⎟⎜ ⎟⎜ ρ ⎟⎜⎝ ⎠h h

900

1000

⎛ ⎞⎟⎜′ = −⎟⎜ ⎟⎟⎜⎝ ⎠h h

2 cm9

′ = ⇒h

h

15. 2= πE

E

LT

g, 2= π

M

m

LT

g

2

2

E

m E

M

Tg g

T

⎛ ⎞⎟⎜ ⎟⎜= ⎟⎜ ⎟⎜ ⎟⎝ ⎠

16. 1

2

T

T 1 15

2 30

t

t

15 ( 15)

2t 30 – t = 2t – 30

110 (30 )

2t 60 = 3t t = 20°C

17.1

1dw

dQ r

75 3 11

4 4dQ dQ = 300 J

18.

2 2half half

2complete complete

(Area) 2 3

(Area) 44

E R R

E R

19. xLice

= msx × 80 = 40 × 1 × 60

x = 30 g

Mass of ice = 50 – 30 = 20 g

Mass of water = 40 + 30 = 70 g

20.90°

( )TA

BCT

C = ?

L

2 L

2 )T(

L

Using, KA

HL

HBC

= HCA

2 ( )

2

c C

KA T T KA T T

L L

2 2C C

T T T T

33 2 1

2 1C C

TT T T ⇒

21. n w

2 2

1 1

n w

n w

1 2

1 1

2n w

n w

w2 = 4w

1= 4 × 4

w2 = 16 kg wt.


4/9

22. Temp.n

1

2

n T

n T

10000 1 10016.67 Hz

2 2 300 6

n Tn

T

23. Conceptual

24. kr2 = constant

25.a a

–q –qQ

u12

+ u23

+ u13

= 0

2

02

Qq Qq q

a a a

22

1 : 42

⇒ Qq q Q

a a q

26. ts = t

1 + t

2 = 45 min

tp =

1 2

1 2

15 3010 min

45

t t

t t

45 9

10 2

s

p

t

t

27.

2

volume

L LR

A

2 3 3

RVL

3

L

28.1

2

lx

R l

1

2

20 11

80 4

lx R

l

2 21 2

4 4 1 2

l r r

A

⇒

6

64 102 10 ohm-m.

2

29. = BA 0

MH A

V

⎛ ⎞ ⎜ ⎟⎝ ⎠ 0

pm

H AA

⎛ ⎞ ⎜ ⎟⎝ ⎠

= 0(AH + m

p)

30. F = Bqv

2VqF Bq

m

as, 21

2mv Vq

F V

2 2

1 1

F V

F V

2

2

22

F VF F

F V ⇒

31. A

B

C

D

E

F

Mnet

= 2 M 2 i A

10 102 3

100 100 23

1.4 0.042 Am100

32.1

wC

2 1

1 1

w C

w KC

100 1

125 K

51.25

4K K = 1.56

33. Conceptual

34. Momentum, 2 2E IAt

pC C

4

8

2 24 3.5 3.5 10 60 60

3 10

= 2.2×10–6

35.2

n

nhJ mvr

2n

nhp

r

...(i)

Again, de Broglie’s wavelength

2

2

n n

h h r

nhp n

r

⇒ ⎛ ⎞⎜ ⎟⎝ ⎠

...(ii)


5/9

2 2

2

2 2 2

(i)( )

(ii) 2 2 4 4⇒

n

n

J nh n h n h nr n

r r n

constant

n

n n

n

JJ ⇒

36. U r2, dU

Fdr

F r,

2mv

r

r

v r ...(i)

From angular momentum,

2

nhmvr

nr

v

...(ii)

From (i) & (ii), r n37. A = A

0e–t

90

03

II e

9 1

3e

Later, 18

0A I e

29

0I e

2

0

1

3I⎛ ⎞ ⎜ ⎟⎝ ⎠

0

9

IA

38. dNN

dt

AmNdN

dt M

39.5 216

K.E220

d

d

Qm

m m = 4.9 MeV.

40.1 2

1 1 1

F f f

1 1 1 5 8 3

40 25 200 200

F

200 cm

3F

Power = 100 100 3

1.5 Din cm 200

F

41.

u = 20 cm

O

Power of system, P = 2PL + P

m

1 2 2

15

L

F f

F = –7.5 cm

From mirror formula,

1 1 1 1 1 1

75 20F v u v

⇒

1 1 1012 cm

20 75v

v

⇒

42.1 11

tan cot cot ⎛ ⎞ ⎛ ⎞ ⇒ ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠

v

c

43. ⇒ d

d

i iv n

neA v

7 4 4.

5 7 5 e e n

h h e

n i v

n i v

44. Apply the truth table, verify with .A B A

45.

98

10049

2

100

C

B

I

I

CHEMISTRY

46.2 3 2 2

X O 3H 2X 3H O

1 mol 3 mol

(2a 48)g 6 g

∵ 0.006 g H2 is required by 0.3192 g oxide

6 g H2 will be required by 319.2 g oxide.

2a + 48 = 319.2

a = 135.6 amu

47. Magnetic quantum number (m) represents the

orientation to atomic orbitals in three-dimensional

space.

48. Cr (Z = 24) = 1s22s22p6 3s23p63d54s1

n + l = 4 is for orbitals 4s and 3p

Hence the number of electrons in orbitals having

n + l = 4 is equal to 7.


6/9

49. On Pauling scale,

Electronegativity of an atom = I.P E.A

2 2.8

,

where I.P. and E.A are in eV.

50. H– = 208 pm, I– = 216 pm.

51. H – O – BO – H

O – H,2Na

+

HO – BO

O

B

B

B – OH 8H O2

O

O

OH

1 2

4

3

OH

1 & 2 3 = sp2

3 & 4 4 = sp3

3 = sp2

O

2–

52. Solubility of salts depend on hydration enthalpy and

lattice ethalpy. If hydration enthalpy decreases and

lattice enthalpy increases, the solubility of salt will

decrease.

53.

A

3 NK.E R 150 x

2 N ...(i)

A

3 yK.E R 300 2x

2 N ...(ii)

Dividing 1 by 2, y = N molecules.

54. The fraction of molecules with most probable speed

decreases on increasing temperature.

55. For the process, H2O(�) H

2O(g)

ng = 1 – 0 = 1

We know, H = U + ngRT

40.66 × 1000 = U + 1 × 8.314 × 373

U = 37559 J mol–1

U = 8.98 kcal mol–1 (∵ 1 kcal = 4.18 kJ)

56. 3 2Ag Fe Ag Fe

3 2cell Fe /Fe Ag /AgE E E

= 0.77 – 0.80 V = –0.03 V

cell

oE 0

Hence not fesible.

57.i

2 4 4H SO H HSO

Cathode : 2

2H 2e H

Anode : 4 2 2 8

2HSO H S O 2e

58. pKa = –log

1010–6

= 6

a

[Salt]pH pK log

[Acid]

(1/ 3)6 log

(2 / 3)

6 log2

5.7

59.

2 2H I 2HI

Initial mole 15 5.2 0

eq. mole 15 5 5.2 5 10

+

− −

��⇀↽��

2

c p2 2

[HI] 100K or K 50

[H ][I ] 10 0.2

G = G° + RT lnQ

At eq., G = 0

G°= –8.314 × 800 × 2.303 log10

50

= –26040 J

= –26 kJ

60. *1s, *2pz and 2p

x have one nodal plane each

whereas *2py has two nodal plane.

61.

CH3

CH3

CH3

Reductive3

Ozonolysis3CH C CHO

||O

62. p = pA + p

B

2 3120 80

5 5 = 96 torr.

mole fraction of B in the vapour phase,

YB = B

total

380

p 15

p 96 2

63. As A Ahas higher activation energy hence it will

be slowest and rate determining step.

64. Order of reaction may by fractional.

65. % Packing = Area of one circle

100Area of square

2

2

r100 25

(2r)

66. C.N. of Fe in ferrocene is = 10

C.N. of Pt in zeise’s salt is = 4

Fe

Pt

(CN) 10 5

(CN) 4 2

67. en forms chelate.


7/9

68.

base

Acid acid

V1.4 M n V

n%N

W

⎛ ⎞ ⎜ ⎟⎝ ⎠

W = Weight of organic compound

n = n factor of acid used

3

1.4 0.2 1(30 20)

200 10 g

31.4 2 10

14%200

69. Cell reaction, Ni(s) + 2H+(aq) Ni2+(aq) + H2(g)

22

o o ocell H |H Ni |Ni

E E E 0.236

2

2

Ho

cell cell 10 2

[p ][Ni ]0.0591E E log

n [H ]

10 2

0.0591 1 10 0.236 log

2 [H ]

0.05910.236 2 pH

2 10

1log pH

[H ]

⎛ ⎞⎜ ⎟⎜ ⎟

⎝ ⎠∵

0.236

pH 40.0591

70. Geometrical isomers = 22 = 4

71. U.I. = (H N)

(C 1)2

(91 3)(50 1) 51 44 7

2

72. [Fe(ox)3]3– is optically active.

E.A.N. in both = 26 – 3 + 6 × 2 = 35, hence do

not follow EAN rule.

Fe3+ 3d 5, due to one unpaired electron both

are paramagnetic.

73. NO2 is EWG and when present at para position

increases acidic strength of phenols.

74. Species b, c, d are antiaromatic compounds.

75. H

3 2 3CH CH CH CH CH

3 2 2 3CH CH CH CH CH

or 3 2 2 3

CH CH CH CH CH

both are secondary carbocation.

76. O

CH MgBr3 CH

3

OMgBr

HOH CH3

OH

+ MgBrOH

77.+ HC – C H

6 5

O

OH/

O

CH – C H6 5

O

78. Since reaction intermediate is a carbanion, therefore

E.W.G stabilize the carbanion.

79.H /

6 5 2Glucose 3C H NH NH

Osazone of glucose + C6H

5NH

2 + NH

3

80.

CH = CH2

H+

CH – CH3

CH – CH – CH2

CH3

Intramolecular Friedel

craft reaction.

CH3

CH = CH2

+ H+

82. PbS is black colour.

83. Emulsification of micelles takes place.

84. KF + AlF3 3K+ + [AlF

6]3–

85. Number of unpaired electrons, Mn2+ = 5, Cr2+ = 4,

V2+ = 3.

Magnetic moment is proportional to the number of

unpaired electrons.

86.2 4 2

ZnS 4NaCN Na [Zn(CN) ] Na S.

87.

OO

O O

O

P

P

P = OO = P O

O

O

All P atoms are sp3 hybridised.

1% s-character 100 25%

4

88. Lattice energy depends on charge and size of the

ions.

89. As2S

3 is a negatively charged sol therefore according

to Hardy schulze rule higher the valency of cation

good is flocculating agent.

90. All these species have acidic hydrogen.


8/9

BIOLOGY

91. Zoospore are flagellated motile spores.

Conidia are non motile asexual spore found in

fungi (Penicillium).

Rhizome is underground stem modification

found in ginger, turmeric, banana.

Bulbils are large fleshy bud present in Agave.

92. Epidermis, endothecium and middle layer perform

function of protection.

Tapetum is the innermost layer of anther wall.

Each lobe of anther has two microsporangia.

93. Family and genus are taxonomic category.

94. Only recessive trait can be expressed in

homozygous state.

(i) Yellow pod colour

(ii) Constricted pod shape

(iii) Wrinkled seed shape

(iv) Terminal flower position

95. Meiocyte is 2n(diploid) = 20 chromosome

Tube nucleus – (n) – 10 chromosome

PEC – (3n) – 30 chromosome

Nucellus – (2n) – 20 chromosome

Synergid – (n) – 10 chromosome

96. Zostera is marine plant which show hydrophily.

97. Hybrid produced in garden pea are fertile.

98. G = 14%

Guanine = cytosine C = 14%

Thymine = adenine where remaining 72% are A & T

So A = 36%, T = 36%

99. Three biodiversity hot spots present in India are

Western Ghats and Sri Lanka

Indo – Burma

Himalaya

100. Immunosuppressive agent Cyclosporin-A is obtained

from Trichoderma polysporum.

103. Clown fish and sea anemone show

commensalism.

Barnacles Balanus and Chathamalus show

competition.

Tiger and deer show predation.

Fig (Ficus) and Fig wastes show mutualism.

104. Eltonian pyramids are ecological pyramid.

These pyramids assume simple food chain and can

not accommodate food web.

107. Life cycle of Drosophila is two weeks.

Male and female are easily distinguishable.

108. UTRs are present at both end at 5 end before start

codon and at 3 end after stop codon.

111. Klinefelter’s syndrome have

(a) 44 + XXY Trisomy

(b) Sterile males with overall musculine development

(e) Testicular atrophy (small testes)

112. (Sigma) is initiation factor

(Rho) is termination factor

115. a. About 13%

b. Homofermentaive lactic acid bacteria,

(Lactobacillus lacti)

116. Allen’s rule

119. Cymose inflorescence.

120. A – Mammals

B – Reptiles

C – Fishes

123. Lema, Peru – CoP 20

125. N2O – 6%

CO2 – 60%

CFC – 14%

CH4 – 20%

127. Phloem parenchyma is present in dicot stem, but

absent in monocot stem.

128. Dichogamy

129. Inversion of C and D segment.

130. Frequency of PPQqRrSSTt is

1 1 1 1 1 1

2 2 2 2 2 32

133.uses

31 NH 4e ;4H ;8ATP

135. Coding strand is non template strand of double

stranded DNA.

mRNA

5 AUCGGCUACGA 3

Sequence on template strand

3 TAGCCGATGCT 3


9/9

Sequence on non template or coding strand

5 ATCGGCTACGA 3

This can be written as

3 AGCATCGGCTA 5

136. Dope test is done to estimate alcohol and other

drugs level in blood by blood sampling not through

breath analysis.

137. Cellular oncogenes are growth promoter genes

that upon undergoing mutations lead to overgrowth.

139. Coxal is hip bone formed by fusion of ilium, ischium

and pubis. At the point of fusion of all these three

bones, a cavity called acetabulum is present.

140. Adrenaline increases heart rate.

141. Glossopharyngeal is a mixed nerve.

142. The activity of enzymes increases with increase in

substrate conc. till they achieve steady state.

143. Cysteine is a sulphur containing amino acid.

144. Sma I produces blunt ends.

All others e.g., Bam HI, Sal I and Pst I produce

sticky ends.

145. Fact.

147. hPL is maternal growth hormone of pregnancy.

148. Ascending limb of loop of Henle being permeable to

electrolytes and impermeable to water makes the

filtrate hypo-osmotic to plasma.

149. Inhibin hormone further brings down the level of FSH.

150. The combined pills are taken for 21 days, starting

preferably within the first five days of menstrual

cycle.

151. Fact.

152. Exoskeleton is made up of four plates called

sclerites in each segment.

(i) Structures of mastication are mandibles.

(ii) Excretory product of cockroach is uric acid.

153. Flatworms are also bilaterally symmetrical and

triploblastic and show cephalisation.

154. Typhoid, pertussis, diphtheria and cholera are caused

by bacteria.

155. In ectinoderms, mouth is on ventral side and anus is

on dorsal side, e.g. Asterias.

In molluscs, organ of Bojanus is the excretory organ

and teeth of sharks are modified placoid scales.

156. They are all non-chordates having double ventral solid

nerve cord.

157. Neutrophils and monocytes perform the function of

phagocytosis.

158. Adrenaline – Emergency hormone.

159. Deposition of uric acid in joints is gout.

Autoimmune disorder of muscles is myasthenia

gravis.

Disorder of joints associated with inflammation of

joints is rheumatoid arthritis.

160. Fact.

161. A decrease in body fluid volume stimulates ADH

release.

164. Mutations are sources of variations hence bring

changes in gene frequencies.

165. Fact

166. One thick filament is composed of many meromyosin

molecules.

167. The corticoids which are involved in carbohydrate

metabolism are glucocorticoids, mainly cortisol.

168. In test tube baby programme, ova from the wife/

donor female and sperms from husband/donor male

are collected and are induced to form zygote under

simulated conditions in the laboratory.

169. Mendel established purelines by inbreeding.

170. Parasympathetic nervous system stimulates salivary

secretion and peristaltic contractions.

171. Asthma is difficulty in breathing causing wheezing

due to inflammation of bronchi and bronchioles.

172. At low pO2 carbamino haemoglobin is stable and at

high pO2 carbamino haemoglobin is unstable.

173. Fact

174. Morphine is obtained from Papaver somniferum.

175. All our blood cells develop in bone marrow.

176. ‘C’ being circular will move fastest towards anode.

177. Fact

178. Fact

179. Sponges are pore bearing animals. They have water

transport or canal system. Echinoderms have water

vascular system.

180. Units of compound eyes are ommatidia.

� � �

Test - 09 (Code F) (Answers) All India Aakash Test Series for Medical-2018

1/9

1. (4)

2. (1)

3. (3)

4. (2)

5. (1)

6. (4)

7. (4)

8. (4)

9. (2)

10. (2)

11. (1)

12. (3)

13. (3)

14. (3)

15. (1)

16. (3)

17. (4)

18. (2)

19. (2)

20. (3)

21. (1)

22. (3)

23. (4)

24. (3)

25. (2)

26. (4)

27. (1)

28. (4)

29. (3)

30. (2)

31. (1)

32. (1)

33. (1)

34. (2)

35. (4)

36. (2)

Test Date : 08/04/2018

TEST - 09 (Code F)

All India Aakash Test Series for Medical - 2018

ANSWERS

37. (3)

38. (4)

39. (1)

40. (3)

41. (2)

42. (4)

43. (3)

44. (2)

45. (1)

46. (4)

47. (2)

48. (3)

49. (4)

50. (2)

51. (1)

52. (3)

53. (2)

54. (3)

55. (3)

56. (2)

57. (4)

58. (2)

59. (1)

60. (1)

61. (2)

62. (3)

63. (2)

64. (1)

65. (3)

66. (2)

67. (1)

68. (2)

69. (3)

70. (2)

71. (4)

72. (1)

73. (3)

74. (2)

75. (3)

76. (4)

77. (1)

78. (3)

79. (2)

80. (1)

81. (4)

82. (2)

83. (1)

84. (4)

85. (1)

86. (1)

87. (3)

88. (2)

89. (2)

90. (1)

91. (2)

92. (4)

93. (3)

94. (1)

95. (4)

96. (1)

97. (4)

98. (2)

99. (1)

100. (4)

101. (1)

102. (1)

103. (2)

104. (3)

105. (4)

106. (4)

107. (1)

108. (3)

109. (2)

110. (1)

111. (4)

112. (2)

113. (2)

114. (1)

115. (1)

116. (4)

117. (2)

118. (3)

119. (2)

120. (3)

121. (4)

122. (3)

123. (4)

124. (4)

125. (4)

126. (2)

127. (3)

128. (1)

129. (2)

130. (2)

131. (3)

132. (1)

133. (2)

134. (3)

135. (3)

136. (3)

137. (1)

138. (2)

139. (3)

140. (3)

141. (1)

142. (4)

143. (3)

144. (3)

145. (2)

146. (3)

147. (3)

148. (4)

149. (3)

150. (1)

151. (2)

152. (4)

153. (3)

154. (3)

155. (2)

156. (2)

157. (3)

158. (4)

159. (2)

160. (3)

161. (3)

162. (3)

163. (4)

164. (3)

165. (3)

166. (2)

167. (3)

168. (4)

169. (4)

170. (4)

171. (3)

172. (3)

173. (3)

174. (4)

175. (4)

176. (3)

177. (3)

178. (3)

179. (3)

180. (3)

All India Aakash Test Series for Medical-2018 Test - 09 (Code F) (Hints)

2/9

PHYSICS

1.

98

10049

2

100

C

B

I

I

2. Apply the truth table, verify with .A B A

3. ⇒ d

d

i iv n

neA v

7 4 4.

5 7 5 e e n

h h e

n i v

n i v

4.1 11

tan cot cot ⎛ ⎞ ⎛ ⎞ ⇒ ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠

v

c

5.

u = 20 cm

O

Power of system, P = 2PL + P

m

1 2 2

15

L

F f

F = –7.5 cm

From mirror formula,

1 1 1 1 1 1

75 20F v u v

⇒

1 1 1012 cm

20 75v

v

⇒

6.1 2

1 1 1

F f f

1 1 1 5 8 3

40 25 200 200

F

200 cm

3F

Power = 100 100 3

1.5 Din cm 200

F

7.5 216

K.E220

d

d

Qm

m m = 4.9 MeV.

HINTS

8. dNN

dt

AmNdN

dt M

9. A = A0e–t

90

03

II e

9 1

3e

Later, 18

0A I e

29

0I e

2

0

1

3I⎛ ⎞ ⎜ ⎟⎝ ⎠

0

9

IA

10. U r2, dU

Fdr

F r,

2mv

r

r

v r ...(i)

From angular momentum,

2

nhmvr

nr

v

...(ii)

From (i) & (ii), r n

11.2

n

nhJ mvr

2n

nhp

r

...(i)

Again, de Broglie’s wavelength

2

2

n n

h h r

nhp n

r

⇒ ⎛ ⎞⎜ ⎟⎝ ⎠

...(ii)

2 2

2

2 2 2

(i)( )

(ii) 2 2 4 4⇒

n

n

J nh n h n h nr n

r r n

constant

n

n n

n

JJ ⇒

Test - 09 (Code F) (Hints) All India Aakash Test Series for Medical-2018

3/9

12. Momentum, 2 2E IAt

pC C

4

8

2 24 3.5 3.5 10 60 60

3 10

= 2.2×10–6

13. Conceptual

14.1

wC

2 1

1 1

w C

w KC

100 1

125 K

51.25

4K K = 1.56

15. A

B

C

D

E

F

Mnet

= 2 M 2 i A

10 102 3

100 100 23

1.4 0.042 Am100

16. F = Bqv

2VqF Bq

m

as, 21

2mv Vq

F V

2 2

1 1

F V

F V

2

2

22

F VF F

F V ⇒

17. = BA 0

MH A

V

⎛ ⎞ ⎜ ⎟⎝ ⎠ 0

pm

H AA

⎛ ⎞ ⎜ ⎟⎝ ⎠

= 0(AH + m

p)

18.1

2

lx

R l

1

2

20 11

80 4

lx R

l

2 21 2

4 4 1 2

l r r

A

⇒

6

64 102 10 ohm-m.

2

19.

2

volume

L LR

A

2 3 3

RVL

3

L

20. ts = t

1 + t

2 = 45 min

tp =

1 2

1 2

15 3010 min

45

t t

t t

45 9

10 2

s

p

t

t

21.a a

–q –qQ

u12

+ u23

+ u13

= 0

2

02

Qq Qq q

a a a

22

1 : 42

⇒ Qq q Q

a a q

22. kr2 = constant

23. Conceptual

24. Temp.n

1

2

n T

n T

10000 1 10016.67 Hz

2 2 300 6

n Tn

T

25. n w

2 2

1 1

n w

n w

1 2

1 1

2n w

n w

w2 = 4w

1= 4 × 4

w2 = 16 kg wt.


4/9

26.90°

( )TA

BCT

C = ?

L

2 L

2 )T(

L

Using, KA

HL

HBC

= HCA

2 ( )

2

c C

KA T T KA T T

L L

2 2C C

T T T T

33 2 1

2 1C C

TT T T ⇒

27. xL

ice = ms

x × 80 = 40 × 1 × 60

x = 30 g

Mass of ice = 50 – 30 = 20 g

Mass of water = 40 + 30 = 70 g

28.

2 2half half

2complete complete

(Area) 2 3

(Area) 44

E R R

E R

29.1

1dw

dQ r

75 3 11

4 4dQ dQ = 300 J

30. 1

2

T

T 1 15

2 30

t

t

15 ( 15)

2t 30 – t = 2t – 30

110 (30 )

2t 60 = 3t t = 20°C

31. 2= πE

E

LT

g, 2= π

M

m

LT

g

2

2

E

m E

M

Tg g

T

⎛ ⎞⎟⎜ ⎟⎜= ⎟⎜ ⎟⎜ ⎟⎝ ⎠

32. Let h be the height will the ball jump out of water.

Using work energy theorem,

WB + W

gravity = KE

FBh

– W(h + h) = 0

1⎛ ⎞⎟⎜′ = − ⎟⎜ ⎟⎟⎜⎝ ⎠

BF

h hW

water

body

1

⎛ ⎞ρ ⎟⎜ ⎟⎜′ = − ⎟⎜ ⎟⎜ ρ ⎟⎜⎝ ⎠h h

900

1000

⎛ ⎞⎟⎜′ = −⎟⎜ ⎟⎟⎜⎝ ⎠h h

2 cm9

′ = ⇒h

h

33. Conceptual

34. Compare with equation, x = acost

In 3 s, its distance is 3a

2

24 s

2

⇒ TT

35. F1 = Force due to complete sphere

24

GMm

R

F2 = Force due to removed portion of sphere

2 2

8

9 18

4

⎛ ⎞⎜ ⎟⎝ ⎠

MG m

GMm

R R

Fnet

= Force due to remaining part of sphere

1 2 2

1 1

4 18

GMmF F

R

⎛ ⎞ ⎜ ⎟⎝ ⎠

2 2

9 2 7 7

36 9 94

GMm GMm F

R R

⎛ ⎞ ⎛ ⎞ ⎜ ⎟ ⎜ ⎟⎝ ⎠ ⎝ ⎠

36.Δ ρ

= =⎛ ⎞Δ Δ ⎟⎜ ⎟⎜ ⎟⎜⎝ ⎠

P ghB

V V

V V

37. Acceleration of block is 6 2

3 3= = =

Fa

m m m

For block 2m, N 2m

N = 2ma

22 4 N= ⇒N m

m

38. u = uf – u

i


5/9

2 21 1( )

2 2k a b ka

2 2 21[( 2 )]

2k a b ab a

21[ 2 ]

2k b ab

1( 2 )

2kb b a

39.21(1 )

2mgh mv

2

(1 )2

vgh

5 11

2 2

gRgh

⎛ ⎞ ⎜ ⎟⎝ ⎠

5 3 15

2 2 4

R Rh

40.

L

4

C1

C2

C

O

/2x

From OCC1, cos

2

4

x

L

cos4 2

Lx

41. m1u

1 + m

2u

2 = m

1v

1 + m

2v

2From, u

1 – u

2 = v

2 – v

1

3 3 3

1 2 2 20r u r u r v 2u = v

2 – 0

3 3 3

1 2 2(2 )r u r u r u v

2 = 2u

3 3

1 23r u r u3

3 1

23

rr

1

2 1/3 1/33 3

r rr

42.

mgcosmg

mgsin

f

h

r-h

RO

f = N

mgsin = mgcos = tanBut, h = r(1 – cos)

2

11

1

⎛ ⎞ ⎜ ⎟⎜ ⎟ ⎝ ⎠

h r

43.1 2

cot cot 602 3

u u u u

tg g g

44.1 2

1 2

t tt

t t

t1 = 90 s, t = 36 s, t

2 = ?

2

2

9036

90

t

t

36 × 90 + 36t2 = 90t

2

36 × 90 = 54t2

2

36 9060 s

54t

45. According to principle of homogeneity,

6 2 2 6 8 2

6

AE A Er ML T L ML T

r

⇒

12 2 2 12 14 2

12

BE B Er ML T L ML T

r

⇒

CHEMISTRY

46. All these species have acidic hydrogen.

47. As2S

3 is a negatively charged sol therefore according

to Hardy schulze rule higher the valency of cation

good is flocculating agent.

48. Lattice energy depends on charge and size of the

ions.

49.

OO

O O

O

P

P

P = OO = P O

O

O

All P atoms are sp3 hybridised.

1% s-character 100 25%

4


6/9

50.2 4 2

ZnS 4NaCN Na [Zn(CN) ] Na S.

51. Number of unpaired electrons, Mn2+ = 5, Cr2+ = 4,

V2+ = 3.

Magnetic moment is proportional to the number of

unpaired electrons.

52. KF + AlF3 3K+ + [AlF

6]3–

53. Emulsification of micelles takes place.

54. PbS is black colour.

56.

CH = CH2

H+

CH – CH3

CH – CH – CH2

CH3

Intramolecular Friedel

craft reaction.

CH3

CH = CH2

+ H+

57.H /

6 5 2Glucose 3C H NH NH

Osazone of glucose + C6H

5NH

2 + NH

3

58. Since reaction intermediate is a carbanion, therefore

E.W.G stabilize the carbanion.

59.+ HC – C H

6 5

O

OH/

O

CH – C H6 5

O

60. O

CH MgBr3 CH

3

OMgBr

HOH CH3

OH

+ MgBrOH

61. H

3 2 3CH CH CH CH CH

3 2 2 3CH CH CH CH CH

or 3 2 2 3

CH CH CH CH CH

both are secondary carbocation.

62. Species b, c, d are antiaromatic compounds.

63. NO2 is EWG and when present at para position

increases acidic strength of phenols.

64. [Fe(ox)3]3– is optically active.

E.A.N. in both = 26 – 3 + 6 × 2 = 35, hence do

not follow EAN rule.

Fe3+ 3d 5, due to one unpaired electron both

are paramagnetic.

65. U.I. = (H N)

(C 1)2

(91 3)(50 1) 51 44 7

2

66. Geometrical isomers = 22 = 4

67 Cell reaction, Ni(s) + 2H+(aq) Ni2+(aq) + H2(g)

22

o o ocell H |H Ni |Ni

E E E 0.236

2

2

Ho

cell cell 10 2

[p ][Ni ]0.0591E E log

n [H ]

10 2

0.0591 1 10 0.236 log

2 [H ]

0.05910.236 2 pH

2 10

1log pH

[H ]

⎛ ⎞⎜ ⎟⎜ ⎟

⎝ ⎠∵

0.236

pH 40.0591

68.

base

Acid acid

V1.4 M n V

n%N

W

⎛ ⎞ ⎜ ⎟⎝ ⎠

W = Weight of organic compound

n = n factor of acid used

3

1.4 0.2 1(30 20)

200 10 g

31.4 2 10

14%200

69. en forms chelate.

70. C.N. of Fe in ferrocene is = 10

C.N. of Pt in Zeise’s salt is = 4

Fe

Pt

(CN) 10 5

(CN) 4 2

71. % Packing = Area of one circle

100Area of square

2

2

r100 25

(2r)

72. Order of reaction may by fractional.

73. As A Ahas higher activation energy hence it will

be slowest and rate determining step.


7/9

74. p = pA + p

B

2 3120 80

5 5 = 96 torr.

mole fraction of B in the vapour phase,

YB = B

total

380

p 15

p 96 2

75.

CH3

CH3

CH3

Reductive3

Ozonolysis3CH C CHO

||O

76. *1s, *2pz and 2p

x have one nodal plane each

whereas *2py has two nodal plane.

77.

2 2H I 2HI

Initial mole 15 5.2 0

eq. mole 15 5 5.2 5 10

+

− −

��⇀↽��

2

c p2 2

[HI] 100K or K 50

[H ][I ] 10 0.2

G = G° + RT lnQ

At eq., G = 0

G°= –8.314 × 800 × 2.303 log10

50

= –26040 J

= –26 kJ

78. pKa = –log

1010–6

= 6

a

[Salt]pH pK log

[Acid]

(1/ 3)6 log

(2 / 3)

6 log2

5.7

79.i

2 4 4H SO H HSO

Cathode : 2

2H 2e H

Anode : 4 2 2 8

2HSO H S O 2e

80. 3 2Ag Fe Ag Fe

3 2cell Fe /Fe Ag /AgE E E

= 0.77 – 0.80 V = –0.03 V

cell

oE 0

Hence not fesible.

81. For the process, H2O(�) H

2O(g)

ng = 1 – 0 = 1

We know, H = U + ngRT

40.66 × 1000 = U + 1 × 8.314 × 373

U = 37559 J mol–1

U = 8.98 kcal mol–1 (∵ 1 kcal = 4.18 kJ)

82. The fraction of molecules with most probable speed

decreases on increasing temperature.

83.

A

3 NK.E R 150 x

2 N ...(i)

A

3 yK.E R 300 2x

2 N ...(ii)

Dividing 1 by 2, y = N molecules.

84. Solubility of salts depend on hydration enthalpy and

lattice ethalpy. If hydration enthalpy decreases and

lattice enthalpy increases, the solubility of salt will

decrease.

85. H – O – BO – H

O – H,2Na

+

HO – BO

O

B

B

B – OH 8H O2

O

O

OH

1 2

4

3

OH

1 & 2 3 = sp2

3 & 4 4 = sp3

3 = sp2

O

2–

86. H– = 208 pm, I– = 216 pm.

87. On Pauling scale,

Electronegativity of an atom = I.P E.A

2 2.8

,

where I.P. and E.A are in eV.

88. Cr (Z = 24) = 1s22s22p6 3s23p63d54s1

n + l = 4 is for orbitals 4s and 3p

Hence the number of electrons in orbitals having

n + l = 4 is equal to 7.

89. Magnetic quantum number (m) represents the

orientation to atomic orbitals in three-dimensional

space.

90.2 3 2 2

X O 3H 2X 3H O

1 mol 3 mol

(2a 48)g 6 g

∵ 0.006 g H2 is required by 0.3192 g oxide

6 g H2 will be required by 319.2 g oxide.

2a + 48 = 319.2

a = 135.6 amu


8/9

BIOLOGY

91. Coding strand is non template strand of double

stranded DNA.

mRNA

5 AUCGGCUACGA 3

Sequence on template strand

3 TAGCCGATGCT 3

Sequence on non template or coding strand

5 ATCGGCTACGA 3

This can be written as

3 AGCATCGGCTA 5

93.uses

31 NH 4e ;4H ;8ATP

96. Frequency of PPQqRrSSTt is

1 1 1 1 1 1

2 2 2 2 2 32

97. Inversion of C and D segment.

98. Dichogamy

99. Phloem parenchyma is present in dicot stem, but

absent in monocot stem.

101. N2O – 6%

CO2 – 60%

CFC – 14%

CH4 – 20%

103. Lema, Peru – CoP 20

106. A – Mammals

B – Reptiles

C – Fishes

107. Cymose inflorescence.

110. Allen’s rule

111. a. About 13%

b. Homofermentaive lactic acid bacteria,

(Lactobacillus lacti)

114. (Sigma) is initiation factor

(Rho) is termination factor

115. Klinefelter’s syndrome have

(a) 44 + XXY Trisomy

(b) Sterile males with overall musculine development

(e) Testicular atrophy (small testes)

118. UTRs are present at both end at 5 end before start

codon and at 3 end after stop codon.

119. Life cycle of Drosophila is two weeks.

Male and female are easily distinguishable.

122. Eltonian pyramids are ecological pyramid.

These pyramids assume simple food chain and can

not accommodate food web.

123. Clown fish and sea anemone show

commensalism.

Barnacles Balanus and Chathamalus show

competition.

Tiger and deer show predation.

Fig (Ficus) and Fig wastes show mutualism.

126. Immunosuppressive agent Cyclosporin-A is obtained

from Trichoderma polysporum.

127. Three biodiversity hot spots present in India are

Western Ghats and Sri Lanka

Indo – Burma

Himalaya

128. G = 14%

Guanine = cytosine C = 14%

Thymine = adenine where remaining 72% are A & T

So A = 36%, T = 36%

129. Hybrid produced in garden pea are fertile.

130. Zostera is marine plant which show hydrophily.

131. Meiocyte is 2n(diploid) = 20 chromosome

Tube nucleus – (n) – 10 chromosome

PEC – (3n) – 30 chromosome

Nucellus – (2n) – 20 chromosome

Synergid – (n) – 10 chromosome

132. Only recessive trait can be expressed in

homozygous state.

(i) Yellow pod colour

(ii) Constricted pod shape

(iii) Wrinkled seed shape

(iv) Terminal flower position

133. Family and genus are taxonomic category.

134. Epidermis, endothecium and middle layer perform

function of protection.

Tapetum is the innermost layer of anther wall.

Each lobe of anther has two microsporangia.

135. Zoospore are flagellated motile spores.

Conidia are non motile asexual spore found in

fungi (Penicillium).


9/9

� � �

Rhizome is underground stem modification

found in ginger, turmeric, banana.

Bulbils are large fleshy bud present in Agave.

136. Units of compound eyes are ommatidia.

137. Sponges are pore bearing animals. They have water

transport or canal system. Echinoderms have water

vascular system.

138. Fact

139. Fact

140. ‘C’ being circular will move fastest towards anode.

141. All our blood cells develop in bone marrow.

142. Morphine is obtained from Papaver somniferum.

143. Fact

144. At low pO2 carbamino haemoglobin is stable and at

high pO2 carbamino haemoglobin is unstable.

145. Asthma is difficulty in breathing causing wheezing

due to inflammation of bronchi and bronchioles.

146. Parasympathetic nervous system stimulates salivary

secretion and peristaltic contractions.

147. Mendel established purelines by inbreeding.

148. In test tube baby programme, ova from the wife/

donor female and sperms from husband/donor male

are collected and are induced to form zygote under

simulated conditions in the laboratory.

149. The corticoids which are involved in carbohydrate

metabolism are glucocorticoids, mainly cortisol.

150. One thick filament is composed of many meromyosin

molecules.

151. Fact

152. Mutations are sources of variations hence bring

changes in gene frequencies.

155. A decrease in body fluid volume stimulates ADH

release.

156. Fact.

157. Deposition of uric acid in joints is gout.

Autoimmune disorder of muscles is myasthenia

gravis.

Disorder of joints associated with inflammation of

joints is rheumatoid arthritis.

158. Adrenaline – Emergency hormone.

159. Neutrophils and monocytes perform the function of

phagocytosis.

160. They are all non-chordates having double ventral

solid nerve cord.

161. In ectinoderms, mouth is on ventral side and

anus is on dorsal side, e.g. Asterias.

In molluscs, organ of Bojanus is the excretory

organ and teeth of sharks are modified placoid

scales.

162. Typhoid, pertussis, diphtheria and cholera are

caused by bacteria.

163. Flatworms are also bilaterally symmetrical and

triploblastic and show cephalisation.

164. Exoskeleton is made up of four plates called

sclerites in each segment.

(i) Structures of mastication are mandibles.

(ii) Excretory product of cockroach is uric acid.

165. Fact.

166. The combined pills are taken for 21 days,

starting preferably within the first five days of

menstrual cycle.

167. Inhibin hormone further brings down the level of

FSH.

168. Ascending limb of loop of Henle being

permeable to electrolytes and impermeable to

water makes the filtrate hypo-osmotic to plasma.

169. hPL is maternal growth hormone of pregnancy.

171. Fact.

172. Sma I produces blunt ends.

All others e.g., Bam HI, Sal I and Pst I produce

sticky ends.

173. Cysteine is a sulphur containing amino acid.

174. The activity of enzymes increases with increase

in substrate conc. till they achieve steady state.

175. Glossopharyngeal is a mixed nerve.

176. Adrenaline increases heart rate.

177. Coxal is hip bone formed by fusion of ilium,

ischium and pubis. At the point of fusion of all

these three bones, a cavity called acetabulum is

present.

179. Cellular oncogenes are growth promoter genes

that upon undergoing mutations lead to

overgrowth.

180. Dope test is done to estimate alcohol and other

drugs level in blood by blood sampling not

through breath analysis.

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