tension problems
DESCRIPTION
Tension Problems. F ollow the same procedure as other force problems, but keep in mind: 1) Draw a free body diagram for EACH object or for each junction in a rope. How To Solve Tension Problems. F ollow the same procedure as other force problems, but keep in mind: - PowerPoint PPT PresentationTRANSCRIPT
HOW TO SOLVE TENSION PROBLEMSFollow the same procedure as other force problems, but keep in mind:
1) Draw a free body diagram for EACH object or for each junction in a rope.
HOW TO SOLVE TENSION PROBLEMSFollow the same procedure as other force problems, but keep in mind:
1) Draw a free body diagram for EACH object or for each junction in a rope.
2) Remember that the tension on opposite sides of a rope is equal and opposite.
HOW TO SOLVE TENSION PROBLEMSFollow the same procedure as other force problems, but keep in mind:
1) Draw a free body diagram for EACH object or for each junction in a rope.
2) Remember that the tension on opposite sides of a rope is equal and opposite.
3) Create a system of equations – write force equations for each object / rope and set them equal to each other.
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
FIRST: Think about what is going on in the problem.
What do you know about the system and about how the blocks will move?
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
1) There is just one rope, so the tension on each side is equal.
2) The two blocks will have the same acceleration (because they are connected), but the direction of the acceleration will be different.
3) 90g block will move up. 110 g block will move down.
What’s our next step?
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
Draw free body diagrams for each mass.
What’s next?
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
Add the forces on each mass, and set = ma.
What’s next?
1st EquationFnet = ma T – mg = ma T – 0.9 = 0.09 a
2nd EquationFnet = ma mg – T= ma 1.1 – T = 0.11a
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
Set the two Ts equal to each other to solve a.
What’s next?
1st EquationFnet = ma T – mg = ma T – 0.9 = 0.09 a
2nd EquationFnet = ma mg – T= ma 1.1 – T = 0.11a0.09a + 0.9 = 1.1 – 0.11a
a = 1 m/s2
Two blocks are connected by a string and pulley as shown. Assuming that the string and pulley are massless, find a) the magnitude of the acceleration of each block b) Tension force on the blocks
TENSION PRACTICE – WE DO
Plug a into either equation to solve T.
1st EquationFnet = ma T – mg = ma T – 0.9 = 0.09 a
2nd EquationFnet = ma mg – T= ma 1.1 – T = 0.11a0.09a + 0.9 = 1.1 – 0.11a
a = 1 m/s2T = 1.1 – 0.11a = 1.1 – 0.11(1) T = 0.99 N
A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.
a) What is the magnitude of the acceleration of the 40-kg block?b) What is the magnitude of the tension T in the rope that connects the two blocks?
TENSION PRACTICE – WE DO
FIRST: Think about what is going on in the problem.
What do you know about the system and about how the blocks will move?
A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.
a) What is the magnitude of the acceleration of the 40-kg block?b) What is the magnitude of the tension T in the rope that connects the two blocks?
TENSION PRACTICE – WE DO
FIRST: Think about what is going on in the problem.Tension is equal and opposite because they are connected by the same rope.
Acceleration is the same (b/c connected)
What’s our next step?
A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.
a) What is the magnitude of the acceleration of the 40-kg block?b) What is the magnitude of the tension T in the rope that connects the two blocks?
TENSION PRACTICE – WE DO
Next: Draw free-body diagrams for each object
What’s our next step?
A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.
a) What is the magnitude of the acceleration of the 40-kg block?b) What is the magnitude of the tension T in the rope that connects the two blocks?
TENSION PRACTICE – WE DO
Add up the forces and set = ma
What’s our next step?
1st Equation 2nd EquationFnet = ma Fnet = maT = 10a 50 – T = 40a
A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.
a) What is the magnitude of the acceleration of the 40-kg block?b) What is the magnitude of the tension T in the rope that connects the two blocks?
TENSION PRACTICE – WE DO
Set the two T s equal to each other.
What’s our next step?
1st Equation 2nd EquationFnet = ma Fnet = maT = 10a 50 – T = 40a
50 – T = 40a 50 – 10a = 40a
A 10-kg block is connected to a 40-kg block as shown in the figure. The surface on which the blocks slide is frictionless. A force of 50 N pulls the blocks to the right.
a) What is the magnitude of the acceleration of the 40-kg block?b) What is the magnitude of the tension T in the rope that connects the two blocks?
TENSION PRACTICE – WE DO
Solve for a then solve for t.
1st Equation 2nd EquationFnet = ma Fnet = maT = 10a 50 – T = 40a
50 – T = 40a 50 – 10a = 40a
a = 1 m/s2 T = 10a = 10 N
1)Find the tension in each cable.
2) Find the tension in each cable and the acceleration of the blocks. M1 = 10 kg, and M2 = 5 kg
TENSION PRACTICE – YOU DO
1)Find the tension in each cable.
TENSION PRACTICE – YOU DO
Strategy: Draw the free body diagrams for the weight and for the middle junction. Add the forces and set = 0. (no a). You will find T3 = 200NandT1X + T2X – T3 = 0T1Y + T2Y – T3 = 0 (you will need to use trig)
Then, you’ll have to solve for one of the Ts and plug into the other equation.
T1 = 148.4 NT2 = 79.0 NT3 = 200 N