tech reservoir pete310 wet gases sp gr zfact
TRANSCRIPT
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PETE 310
Lecture # 14
Wet GasSpecific Gravity & Z-factor
(Chapter 7: pages 195-205)
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Learning Objectives
Calculate the specific gravity of a wet gasmixture, given producing GOR (at separator(s)and stock tank and:
compositions liquid and gas from stock tankand separator gas
or, separator compositions (gas & liquid)
or, properties of the separator gas and stockvent gas
Define the two-phase z-factor and understand the
uses of this in reservoir engineering
Explain the shape of a typical two-phase z-factorisotherm.
Calculate values of two-phase z-factor using
Rayes etal. correlation (SPE paper).
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Separators
iSTx
)STB/scf(GORand
yiST
)STB/scf(GORand
yiSP
iSTx
Wellhead
iSPx
SToilgasSTgas
v
SToilgasSPoil
SPoilgas
SPgas
v
molelbmolelb
molelbf
molelbmolelbmolelb
molelbmolelb
molelb
f
ST
SP
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Key Points
What matters is the molar ratio of gas to oil
so lets assume one barrel of oil produced
Methods to evaluate oil density will be
discussed in Chapter 11 (here it will beprovided)
To convert oAPI to oil density
w
o
o
o
o5.131
5.141API
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Key Points
The expression [=] means has the units of Forexample
You are responsible for reading the material thatcannot be covered in this lecture
Rework ALL the example problems in the book Procedure 1 - explained in detail here - is simpler
and takes less time to solve than the methodexplained in the book
3o ftlb
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Recombination procedure when
separator gas yiSP and tock tank
compositions (xiSTO, yiST) areknown
(Procedure 1.)
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Procedure 1.
Calculate molecular weight of stock tank
liquid
Calculate lb-moles of separator gas produced
per barrel of STO from separator
Nc
1iwiiwo MxM
volume)molargas(idealmole-b380.7scf/lV
/STOmole-lbmole-scf/lb
scf/STB
V
GOR
id
m
gasid
m
SP
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Procedure 1.
Calculate lb-moles of stock gas vented per
STO
Calculate moles of oil in 1 barrel of stock tank
(need to use molar density)
/STOmole-lb
bbl
ft615.5
ft
mole-lb
ft
mole-lb
mole-lb/lb
lb/ft
M
oil
3
3
oil
3
oil3
wo
oil
/STOmole-lbmole-scf/lb
scf/STBV
GORgasid
m
ST
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Procedure 1.
STO
molelbmolelbSTO
molelb
f
molelbmolelbmolelb
STO
molelbmolelbSTO
molelb
f
SToilgas
STgas
v
SToilgasSPoil
SPoilgas
SPgas
v
ST
SP
iST
x
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Procedure 1.
Determine reservoir gas composition fromfundamental mole balance
Once reservoir composition is known determine z-factor and specific gravity
STSTSTSP
STST
SPSP
vvSTivSTivSPii
vSTivSTiSPi
vSPivSPii
f1f1xfyfyz
f1xfyx
f1xfyz
iST
x
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Example for Procedure 1.
Yi SEP Yi STOX i STO
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Recombination procedure when
separator gas yiSP and liquid
compositions xiSP are known
(Procedure 2.)
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Example for Procedure 2.
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Procedure 2.
Additional information given is the separator/stocktank volume ratio as
Use this to convert from scf/STO scf/ST
Proceed as in procedure 1.
Rework example 7.2 in textbook
)conditionsstandardat(STBbbl
separator)ofP(T,atiloSPbbl
f1xfyzSPSP vSPivSPii
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Recombination procedure when
only separator gas and stock vent
gas properties are known
(Procedure 3.)
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Procedure 3.
For two-stage separators
For three-stage separators derive
expressions
STSP
gSTSTgSPSP
gRR
RR
STSP RRR
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Procedure 3.
Moles in one stock tank barrel
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Procedure 3.
Mass of one stock tank barrel
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Procedure 3.
And the gas gravity at reservoir conditions
is
An approximation for Mo (when not given is)
oo
og
gRM/300,133R
600,4R
STO
STO
oo 008.1
43.42
8.8API
954,5M
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Procedure 3.
For two-stage separators
For three-stage separators deriveexpressions
STSP
gSTSTgSPSP
g RR
RR
STSP
RRR
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Once Gas Specific Gravity is
Known
Evaluate Tpc and Ppc (previous paperusing K and J and including correctionsfor impurities N2, CO2, H2S)
If dew-point pressure is not knownUse dry-gas z-factor when C7+ < 4%
Or when wellstream gravity < 0.911
If pdis known
if reservoir p is lower than pdevaluate z-2phase using equation from SPE 20055 paper
If reservoir p is greater than pd , evaluate z asfor a dry gas (single-phase)
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Correlation of Specific Gravities
for a wet gas
READ - SPE 20055
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Ranges of Compositions
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Single vs Two-phase z-factor
p/z-2phase vs z-2phase
0.6
0.8
1
1.2
0 1000 2000 3000 4000 5000
Pressure (psia)
z,
z-2phase
z-gas (one phase)
z-2phases
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Estimates of the Gas in Place (G)
When p/z = 0 Gp= G (PETE 323)
Exercise: verify these calculations using
information from next slide
G
G1
z
p
z
p p
i
i
From single phase z G = 644640 MMSCF
From two-phase z G = 679522 MMSCF
5.13328 % difference
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Estimates of Reserves
Gas in Place Prediction
P/z_1phase = -9.359752E-03x + 6.033670E+03
R2= 9.979569E-01
P/z_2phase = -8.405311E-03x + 5.711591E+03
R2= 9.979049E-01
0
1000
2000
3000
4000
5000
6000
7000
0 100000 200000 300000 400000 500000 600000 700000 800000
Gp (MMSCF)
p
/z
,p/z-2phase
(p
sia)
p/z-2phase
p/z-gas
Linear (p/z-gas)Linear (p/z-2phase)