∆= = 0.01 v / kg

* = 1.04 v / kg

∆v= = = 9.61x10-3 ⇔ 0.01

∆v= - = 0.01 y si Rf = 100 Ω entonces Ri = 10 KΩ

∆out = = 5x10-4 A/

∆I = =

+1 =

Rf = -1 * Ri

Si Ri= 1KΩ

Rf = - 1 * 1KΩ = 49KΩ

∆out = = 1 v/kg/cm2

* = -1.42 mA/ kg/cm2

∆v = =

=

Rf = * Ri * -1

Si Ri = 1KΩ entonces:

Rf = * 1KΩ * -1 = 704.22Ω