table of contents parabola - graphing recall that the equations for a parabola are given by......
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Table of Contents
Parabola - Graphing
• Recall that the equations for a parabola are given by ...
)ky(p4)hx( 2 Vertical Axis of Symmetry
0p
0p
Horizontal Axis of Symmetry
0p
0p
)hx(p4)ky( 2
Table of Contents Slide 2
Parabola - Graphing
• The vertex of the parabola is located at the point (h, k).
• Example 1: Determine the vertex of the parabola given by ...
)2x(4)3y( 2
The vertex is at V(2, -3).
• Geometrically, the vertex is the midpoint of the line segment joining the focus and the directrix.
Table of Contents Slide 3
Parabola - Graphing
• Note that when the squared term is in x, the axis of symmetry is vertical, and the parabola is facing up or down.
)ky(p4)hx( 2 Vertical Axis of Symmetry Horizontal Axis of Symmetry
)hx(p4)ky( 2
• When the squared term is in y, the axis of symmetry is horizontal, and the parabola is facing left or right.
Table of Contents Slide 4
Parabola - Graphing
• The value of p is the directed distance from the vertex to the focus.
• Example 2: Consider the parabola at the right.
• Since the parabola is facing down, the axis of symmetry is vertical and the equation is of the form ...
)ky(p4)hx( 2 • The distance from the vertex to the focus moves in a negative direction, implying that p 0.
Table of Contents Slide 5
Parabola - Graphing
• Since the vertex is equidistant from the focus and the directrix (as are all points on the parabola by the definition), the distance from the vertex to the directix is | p | units.
• To determine the basic shape of the parabola, it is a good idea to plot one or more points other than the vertex.
Table of Contents
V (1, - 2)
Slide 6
Parabola - Graphing
• Example 3: Sketch the graph of the parabola whose equation is given at the right.
)1x(12)2y( 2
• The vertex is at V(1, -2).
4
4
- 4
• Since the square is on the y, the axis of symmetry is horizontal, with the parabola facing left or right ...
axis of symmetry y = - 2
Table of Contents Slide 7
Parabola - Graphing
4
4
- 4
• Find the value of p ... )1x(12)2y( 2
3p
12p4
• Since p is negative, the parabola is facing left.
• Plot another point. Letting y = 4 yields x = -2, or the point (-2, 4) ...
Table of Contents Slide 8
Parabola - Graphing
4
4
- 4
• Sketch the graph using the points and the axis of symmetry ...
• Using p = -3 the focus is three units to the left of the vertex ...
F (- 2, - 2)
• The directrix is a vertical line 3 units on the other side of the vertex.
directrix x = 4
Table of Contents
Parabola - Graphing