susy, spin chains (and aseps?) - hwdes/susy.pdf · susy, spin chains (and aseps?) des johnston...
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SUSY, Spin Chains (andASEPS?)
Des JohnstonMaxwell Institute for Mathematical Sciences
Heriot-Watt University, EdinburghCPPT, Sept 2017
Johnston SUSY 1/29
Nerses
Congratulations (and thanks)!
Symbols of Armenia
Johnston SUSY 2/29
Plan of talk
SUSY
(XXZ) Spin Chains/SUSY - Fendley, Hagendorf
The missing punchline - ASEPs (ASAPs) - Ayyer, Mallick
NOT Johnston
Johnston SUSY 3/29
SUSYOriginally.....
Q|Boson〉 = |Fermion〉
Q†|Fermion〉 = |Boson〉
Q2 = 0,(
Q†)2
= 0
In particular, Super-Poincaré algebra in 4d
{Qα, Q̄β̇} = 2(σµ)αβ̇Pµ
Getting rid of divergences in QFT
Lattice discretisation difficult (but see Catterall et.al.)
Johnston SUSY 4/29
SUSY QMHamiltonian
Hψn(x ) =
(−~2
2md 2
dx 2 +mω2
2x 2)ψn(x ) = Enψn(x )
Define
A =~√2m
ddx
+ W (x ); A† = − ~√2m
ddx
+ W (x )
Two SUSY Hamiltonians
H (1) = A†A =−~2
2md 2
dx 2 −~√2m
W ′(x ) + W 2(x )
H (2) = AA† =−~2
2md 2
dx 2 +~√2m
W ′(x ) + W 2(x )
Johnston SUSY 5/29
SUSY QM IISUSY algebra
[H ,Q] = [H ,Q†] = 0{Q,Q†} = H{Q,Q} = {Q†,Q†} = 0
H =
(H (1) 0
0 H (2)
)Q =
(0 0A 0
)Q† =
(0 A†
0 0
)
Johnston SUSY 6/29
XXZ Spin Chain
XXZ Hamiltonian acts on V⊗N where V ' C2.
H (N) = −12
N−1∑i=1
(σx
i σxi+1 + σy
i σyi+1 −
12σz
i σzi+1
)−1
4(σz
1 + σzN ) +
3N − 14
I
Write as sum of local terms, hij : V ⊗ V → V ⊗ V in bulk
H (N) =∑〈ij〉
hij + h1 + hN
Johnston SUSY 7/29
XXZ Spin Chain II
Local Hamiltonian (in the bulk)
hij = σx ⊗ σx + σy ⊗ σy − 12σz ⊗ σz +
34I
In matrix form, standard basis for C2 ⊗ C2
hij =
1 0 0 00 1
2 −1 00 −1 1
2 00 0 0 1
Johnston SUSY 8/29
XXZ Spin Chain/SUSY
Possible to define (Fendley, Yang)
Q(N) : V⊗N → V⊗N−1; Q(N)† : V (N−1) → V (N)
Properties of Q: nilpotent
Q(N−1)Q(N) = 0, Q†(N+1)Q†(N) = 0,
Hamiltonian length N
H (N) = Q†(N)Q(N) + Q(N+1)Q(N+1)†.
Johnston SUSY 9/29
XXZ Spin Chain/Supercharge I
Length-changing operator
H (N−1)Q(N) = Q(N)H (N), H (N)Q†(N) = Q†(N)H (N−1).
Local expressions (Hagendorf)
Q(N) =N−1∑i=1
(−1)i+1qi ,i+1, Q†(N) =N−1∑
i
(−1)i+1q†i
Local action - “dynamical SUSY”
q†i : V → V ⊗ V ; qi ,i+1 : V ⊗ V → V
Johnston SUSY 10/29
XXZ Spin Chain/Supercharge II
In terms of the local supercharge, nilpotency (Q†)2 = 0becomes
(q† ⊗ 1− 1⊗ q†)q† = 0
Or, more accurately - including a sort of “gauge” freedom[(q† ⊗ 1)q† − (1⊗ q†)q†
]|m〉 = |χ〉 ⊗ |m〉 − |m〉 ⊗ |χ〉
For all |m〉 ∈ V , for a particular |χ〉 ∈ V → V ⊗ V
Johnston SUSY 11/29
XXZ Spin Chain/Supercharge III
Substitute Q,Q† expression into Hamiltonian, most termsvanish:
q†i qj + qj+1q†i = 0, 1 ≤ i < j − 1 ≤ N − 1
Leaving
h = −(q ⊗ 1)(1⊗ q†)− (1⊗ q)(q† ⊗ 1) + q†q
+12
(q q† ⊗ 1 + 1⊗ q q†
)With boundary terms
hB =12
q q†
Johnston SUSY 12/29
XXZ Spin Chain/Supercharge IIIbis
The game of “does my Hamiltonian have dynamicalsupersymmetry”?
1) Pick a q† - (4× 2)
2) Construct h - (4× 4) using:
h = −(q ⊗ 1)(1⊗ q†)− (1⊗ q)(q† ⊗ 1) + q†q
+12
(q q† ⊗ 1 + 1⊗ q q†
)
Johnston SUSY 13/29
XXZ Spin Chain/Supercharge IV
q† is remarkably simple for XYZ (at combinatorial point)
q† =
0 10 00 00 0
hij =
1 0 0 00 1
2 −1 00 −1 1
2 00 0 0 1
With
|0〉 =
(10
); |1〉 =
(01
)Action
q†|0〉 = ∅ ; q†|1〉 = |00〉
Johnston SUSY 14/29
XXZ Spin Chain/Supercharge VCould start with |1〉 instead of |0〉, i.e.
q̄†|1〉 = ∅ ; q̄†|0〉 = |11〉
q̄† is still simple
q̄† =
0 00 00 01 0
hij =
1 0 0 00 1
2 −1 00 −1 1
2 00 0 0 1
Stitch together q, q̄, using “gauge” freedom
q†(y ) = x
−2y 1−y 2 −y−y 2 −yy 3 −2y 2
; x = (1 + |y |6)−1/2
Johnston SUSY 15/29
XXZ Spin Chain/Supercharge VIWith q†(y ) still true that
hij =
1 0 0 00 1
2 −1 00 −1 1
2 00 0 0 1
Boundaries become (y = ρe iθ)
hB(y ) =
(1 + 5ρ2 + ρ4
4(1− ρ2 + ρ4)
)I +
3∑j=1
λjσj ,
where
λ1 = −ρ cos θ
1 + ρ2 , λ2 = − ρ sin θ
1 + ρ2 , λ3 = −14
(1− ρ2
1 + ρ2
).
Johnston SUSY 16/29
XXZ Spin Chain/Supercharge VII
So far - SUSY for XXZ with off-diagonal BCs same at bothsends
hij = σx ⊗ σx + σy ⊗ σy − 12σz ⊗ σz +
34I
hB(y ) =
(1 + 5ρ2 + ρ4
4(1− ρ2 + ρ4)
)I +
3∑j=1
λjσj ,
Johnston SUSY 17/29
XXZ Spin Chain/Supercharge VIII
Can also arrange different BCs, take
|φ(y )〉 =1∑
m=0
φm(y )|m〉, φm(y ) = − y m+1√{m + 1}
.
|ξk (y )〉 = x (|φ(y )〉 − |φ(q2(k+1)y )〉), q = − exp(−iπ/3)
Boundary vectors
q(y )|ξk (y )〉 = |ξk (y )〉 ⊗ |ξk (y )〉, k = 0,1,2
Then
Qj ,k (y )|ψ〉 = |ξj (y )〉⊗|ψ〉+(−1)N−1|ψ〉⊗|ξk (y )〉+Q(y )|ψ〉.
Johnston SUSY 18/29
XXZ Spin Chain/Supercharge IX
Now - SUSY for XXZ with off-diagonal BCs different atboths ends
hij = σx ⊗ σx + σy ⊗ σy − 12σz ⊗ σz +
34I
hB(y ) =
(1 + 5ρ2 + ρ4
4(1− ρ2 + ρ4)
)I +
3∑j=1
λjσj ,
h(k )B (y ) = hB(q2(k+1)y )
q = − exp(−iπ/3)
Johnston SUSY 19/29
Random additional Comments
XYZ too
hij = (1− z)σx ⊗ σx + (1 + z)σy ⊗ σy − 1− z2
2σz ⊗ σz
q† in this case
q† =
0 10 00 00 −z
Hard fermion models: M2, Ml - Hagendorf, Huijse
Gl(n|m) - Meidinger, Mitev
Johnston SUSY 20/29
Story so Far
XXZ (and XYZ) spin chain has a “dynamical”supersymmetry
Relates chains of different length
Can be formulated for both open and closed chains
Can be formulated for diagonal, off-diagonal, unequal BCs
Johnston SUSY 21/29
ASEPs
Originally came from biology
Model for transport in cells
Kinesins moving along a microtubule
Johnston SUSY 22/29
The Phase Diagram (q = 0)
21
21 α
β
LD MC
HD
Roll of honour (TASEP q = 0): Derrida,Evans, Hakim PasquierRoll of honour (PASEP q 6= 0): Blythe, Evans, Colaiori, Essler
Johnston SUSY 23/29
What’s this got to do with XXZ ?Markov matrix M
ddt|P(t )〉 = M |P(t )〉,
Related to HXXZ
M =√
pqU−1µ HXXZ Uµ
Where
Uµ =L⊗
i=1
(1 00 µQ j−1
),
HXXZ = −12
L−1∑j=1
[σx
j σxj+1 + σ
yj σ
yj+1 −∆σz
j σzj+1
+h(σzj+1 − σ
zj ) + ∆
]+ B1 + BL
Johnston SUSY 24/29
What’s this got to do with XXZ ??
Various XXZ parameters related to (P)ASEP
B1 =1
2√
pq
(α + γ + (α− γ)σz
1 − 2αµeλσ−1 − 2γµ−1e−λσ+1)
BL =1
2√
pq
(β + δ − (β − δ)σz
L − 2δµQL−1σ−L
− 2βµ−1Q−L+1σ+L
)∆ = −1
2(Q + Q−1), h =
12
(Q −Q−1), Q =
√qp.
Johnston SUSY 25/29
And SUSY??Well.....“transfer matrix” symmetry (Ayyer, Mallick)
For ASEP and ASAP
TL,L+1ML = ML+1TL,L+1
Relates Ms of different length
ML =L−1∑i=1
Mi ,i+1 + R + L
Where, for ASAP
10→ 01 with rate 111→ 00 with rate λ
Johnston SUSY 26/29
And SUSY???
ASAP local Hamiltonian
hi ,i+1 = σ+i σ−i+1 + λσ+i σ
+i+1 +
1− λ4
σzi σ
zi+1 +
1 + λ
4σz
i
− 1− λ4
σzi+1 −
1 + λ
4I
L = α
(σ−1 + λσ+1 −
1− λ2
σz1 −
1 + λ
2
)R = β
(σ+L −
1− σzL
2
)
Johnston SUSY 27/29
So??
Is the transfer matrix symmetry related to SUSY?
Related spin chains have unequal, off-diagonal BCs
NOT at combinatorial point <<<<
Johnston SUSY 28/29
References
Xiao Yang and Paul Fendley, Non-local spacetimesupersymmetry on the lattice, J. Phys. A,37(38):8937–8948, 2004.
Christian Hagendorf and Jean Liénardy, Open spin chainswith dynamic lattice supersymmetry, J. Phys. A,50(18):185202, 32, 2017.
Robert Weston and Junye Yang, Lattice Supersymmetry inthe Open XXZ Model: An Algebraic Bethe Ansatz Analysis,[arXiv:1709.00442]
Johnston SUSY 29/29