surface chemistry states of matter -...
TRANSCRIPT
Surface Chemistry
&
States of Matter
S. Sunil Kumar
Lecturer in Chemistry
1. Adsorption is
a. Colligative property
b. Oxidation process
c. Reduction process
d. Surface phenomenon
Ans. d
2. When adsorption of oxalic acid is
carried out on activated charcoal,
then activated charcoal is known as
a. Adsorbate
b. Adsorbent
c. Adsorber
d. Absorber
Ans. b
3. The process of removing an
adsorbed substance from a surface
on which it is adsorbed is called
a. Adsorption
b. Absorption
c. Desorption
d. Sorption
Ans. c
4. Adsorption increases when
a. Temperature increases
b. Temperature decreases
c. Temperature remains constant
d. None of these
Ans. b
Gas +Solid Adsorption + Heat
5. With the increase in critical
temperature of a gas, adsorption of
gas on solid
a. Increases
b. Decreases
c. May increase or decrease
d. First increases then decreases.
Ans. a ( greater the critical temperature
Of the gas, more the van der Waal's
force of attraction and more the adsorption )
6. Which adsorption takes place at
low temperature ?
a. Physical
b. Chemical
c. Both
d. None.
Ans. a ( Because Δ H is low )
7. For adsorption of a gas on a solid,
the plot of log x/m vs log P is linear
with slope equal to : ( n being whole
number)
a. K
b. log k
c. n
d. 1/n
Ans. d
log x/m
log P
Slope = 1/n
intercept = log k
log x/m = log k + 1/n log P
8. Which of the following statements is
correct about Langmuir adsorption?
a. It is reversible in nature
b. It occurs at low temperature
c. It forms monolayer
d. It is not specific in nature.
Ans. c
9. Which is adsorbed to maximum
amount by activated charcoal
a. N2
b. CO2
c. Cl2
d. O2
Ans. b
Because easily liquefiable gas adsorbed
to greater extent.
10. Which of the following is less than
zero during adsorption?
a. ∆ G
b. ∆ S
c. ∆ H
d. All the above.
Ans. d
11. Number of phases present in a
colloidal system is
a. 1
b. 2
c. 3
d. 4
Ans. b
12. Soap forms a colloidal solution in
water and removes the greasy matter
by
a. Absorption
b. Adsorption
c. Coagulation
d. Emulsification
Ans. d
13. Which one of the following is not a
colloid ?
a. Ruby glass
b. Chlorophyll
c. Haemoglobin
d. Smoke
Ans. b
14. Alum is used in the purification of
water, because
a. It is good disinfectant
b. It is a double salt
c. It precipitates the dissolved salt in
water
d. It coagulates the colloidal impurities
in water.
Ans. d
15. A liquid is found to scatter a beam
of light out leaves no residue when
passed through the filter paper. The
liquid can be described as
a. A suspension
b. A true solution
c. A colloidal sol
d. Oil
Ans. c
16. At the critical micelle concentration
(CMC) the surfactant molecules
a. Decompose
b. Associate
c. Dissociate
d. Becomes completely soluble
Ans. b
17. Lyophilic sols are more stable
than lyophobic sols because,
a. The colloidal particles have positive
charge
b. The colloidal particles have no
charge
c. The colloidal particles are solvated
d. Strong forces of attraction between
the negatively charged particles
Ans. c
18. Bredig arc method cannot be used
to prepare colloidal solution of which of
the following?
a. Pt
b. Fe
c. Ag
d. Au
Ans. Fe ( because Fe gets oxidised )
19. Peptisation is process of
a. Precipitation of colloidal particles
b. Purification of colloids
c. Dispersing precipitate in to colloids
d. Movement of colloidal particles in the
electric field.
Ans. c
20. The simplest way to check whether
a system is colloidal is by
a. Tyndal effect
b. Brownian movement
c. Electrodialysis
d. Finding out the particle size.
Ans. a
21. The basic principle of Cottrell
precipitator is
a. Le Chatelier's principle
b. Neutralisation of charge on colloids
c. Peptisation
d. None of the above.
Ans. b
22. Gold number of protective colloids
A, B, C and D are 0.50, 0.01, 0.10
and 0.05 respectively. The correct
order of their protective powers is ?
a. A < C < B < D
b. B < D < A < C
c. D < A < C < B
d. C < B < D < A
Ans. a
Hint: Smaller the gold number, greater
is the protective power.
D ( 0.005 ) > B ( 0.01 ) > C ( 0.50 ) > A (
0.50)
OR
A< C < B < D
23. Among the electrolytes Na2SO
4,
CaCl2, Al
2(SO
4)3 and NH
4Cl, the most
effective coagulating agent for Sb2S
3
sol is
a. Na2SO
4
b. CaCl2
c. Al2(SO
4)3
d. NH4Cl
Ans. c
24. A person is suffering from poisoning
due to arsenic then which one of the
following helpful in removing arsenic ?
a. Colloidal sulphur
b. Colloidal antimony
c. Colloidal sol of gold
d. Colloidal Fe(OH)3
Ans. d
25. The coagulation of 200 mL of a
positive colloid took place when 0.73 g
HCl was added to it without changing
the volume much. The flocculation
value of HCl for the colloid is
a. 0.365
b. 36.5
c. 100
d. 150
Ans. c
Solution:
200 mL of the sol require 0.73 g HCl
No. of moles of HCl =
26. The role of catalyst is only to
a. Decrease activation energy
b. Increases activation energy
c. Brings about equilibrium
d. None of these.
Ans. a
27. Which of the following kinds of
catalysis can be explained by the
adsorption theory ?
a. Homogeneous catalysis
b. Acid-base catalysis
c. Heterogeneous catalysis
d. Enzyme catalysis
Ans. c
28. Which of the following is an example of
homogeneous catalysis ?
a. Haber process of synthesis of ammonia.
b. Catalytic conversion of SO2
to SO 3
in
contact process
c. Catalytic conversion of water gas to
methanol
d. Acid hydrolysis of methyl acetate.
Ans. d
29. An example of autocatalysis is
a. Oxidation of NO to NO2
b. Oxidation of SO2 to SO
3
c. Decomposition of KCIO3 to KCI and
O2
d. Oxidation of oxalic acid by acidified
KMnO4
Ans. d
30. Given below, catalyst and
corresponding process or reaction are
matched. The mismatch is ?
a. Platinised asbestos – Contact
process
b. TiCl4 + Al (C
2 H
5 )
3 - Polymerisation
c. V2O
5 – Haber process
d. Nickel – Hydrogenation
Ans. c
31. Helium gas at 300 K is shifted from
a vessel of 250 Cm3 to a vessel of 1 L
capacity. The pressure of gas will
a. Becomes four times
b. Become double
c. Decrease to half of the original value
d. Decrease to ¼th of the original value.
Ans. d
Solution:
P1V
1 = P
2V
2
P1 x 250 = 1000 x P
2
32. The density of neon will be
maximum at
a. NTP
b. 0° C, 2 atm
c. 273° C, 1 atm
d. 273° C, 2 atm
Ans. b
Because d α p and p α 1/T
33. At what temperature would the
volume of a given mass of a gas at
constant pressure be twice its volume
at 0° C ?
a. 100° C
b. 273° C
c. 373° C
d. 546° C
Ans. b
Solution:
34. For an ideal gas, number of moles
per liter in terms of its pressure P, gas
constant R, and temperature T is
a. PT / R
b. PRT
c. P / RT
d. RT / P
Ans. c
Solution: PV = n RT
Number of moles per liter =
35. The densities of two gases are in
the ratio of 1 : 16. the ratio of their rate
of diffusion is
a. 16 : 1
b. 4 : 1
c. 1 : 4
d. 1 : 16
Ans. b
Solution:
Or 4 : 1
36. According to kinetic theory of
gases, in an ideal gas, between two
successive collisions, a gas molecules
travels
a. In a circular path
b. In a wavy path
c. In straight line
d. With an accelerated velocity
Ans. c
37. If the four tubes of a car are filled to
the same pressure with N2, O
2, H
2 and
He separately, then which one will be
filled first?
a. N2
b. O2
c. H2
d. He
Ans. c ( lower the density
faster the diffusion )
38. Containers A and B have same gas.
Pressure, volume and temperature of A
are all twice that of B. Then the ratio of
the number of molecules of A and B are
a. 1 : 2
b. 2 : 1
c. 1 : 4
d. 4 : 1
Ans. b
Solution:
For gas B, P1 = P , V
1 = V, T
1 = T
For gas A, P2 = 2 P, V
2 = 2 V, T
2 = 2 T
Applying ideal gas equation,
Or
39. 28 g of each of following gases are
taken at 27° c and 600 mm pressure.
Which of the these will have the least
volume ?
a. HBr
b. HCl
c. HF
d. HI
Ans. d
Solution:
PV = n RT or
Since P and T are same V α n
As , , n will we least for
which M is maximum.
40. By what factor does the average
velocity of a gaseous molecule
increase when the absolute
temperature doubled ?
a. 1.4
b. 2.0
c. 2.8
d. 4
Ans. a
Solution:
Average velocity
When the temperature is doubled,
41. A real gas most closely approaches
ideal gas behaviour at
a. 1.5 atm and 200 K
b. 1.0 atm and 273 K
c. 0.5 atm and 500 K
d. 15.0 atm and 500 K
Ans. C ( low pressure and high
temperature)
42. Molar volume of CO2 is maximum at
a. NTP
b. 0° C and 2.0 atm
c. 127° C and 1 atm
d. 273° C and 2.0 atm
Ans. c
43. Equal masses of methane and
oxygen are mixed in an empty container
at 25° C. The fraction of total pressure
exerted by oxygen is
a. 1/2
b. 2/3
c. 273/298
d. 1/3
Ans. d
Solution:
If the mass of CH4 = mass of O
2 = w gm
44. The number of atoms in 0.1 mole of
triatomic gas is: ( NA = 6.02 x 10
23 )
a. 1.806 x 1023
b. 3.600 x 1023
c. 1.800 x 1022
d. 6.026 x 1023
Ans. a
Solution:
Number of atoms = number of moles x
NA
x atomicity
= 0.1 x 6.02 x 1023
x 3
= 1. 806 x 10
23
45. When the temperature is increased,
the viscosity of the liquid decreases.
This is because,
a. Volume of the solution decreases
b. Average kinetic energy of molecules
increases which overcomes the
attractive forces
c. Decreases the hydrogen and covalent
bond
d. None of the above.
Ans. b
46. The r.m.s velocity of an ideal gas at
constant pressure varies with density (
d ) as
a. d2
b. d
c.
d. 1/
Ans. d
Solution:
47. Select the one having maximum
viscosity
a. Acetone
b. Ether
c. Alcohol
d. Glycol
Ans. d ( due to H-bonding )
48. At relatively high pressure, van der
Waal’s equation reduces to
a. PV = RT
b. PV = RT – a/V
c. PV = RT + Pb
d. PV = RT – a/V2
Ans. c
Solution:
At high pressure is negligible.
For one mole of gas
( P + 0 ) ( V – 0 ) = RT
PV = RT + Pb
49. Dalton’s law of partial pressure is
not applicable to which of the
following gaseous mixtures ?
a. Nitrogen and oxygen
b. Nitric oxide and oxygen
c. CO and H2
d. N2 and H
2
Ans. b ( Dalton’s law is applicable to
mixture of non reacting gases )
50. In the van der Waal’s equation of
state about gas laws, the constant b
is measure of ?
a. Intermolecular collisions per unit
volume
b. Intermolecular attraction
c. Volume occupied by the molecules
d. Intermolecular repulsion
Ans. c
51. If the temperature of an ideal gas in
sealed, rigid container is increased to
1.5 times the initial value ( in K ), the
density of the gas
a. Becomes 1.5 times the initial value
b. Becomes 1/1.5 times the initial value
c. Becomes 2.5 times the initial value
d. Remains constant
Ans. d ( because mass and volume
remains constant )
52. An ideal gas cannot be liquefied
because,
a. Its critical temperature is always
above 0° C-
b. Its molecules are smaller in size
c. It solidifies before becoming liquid.
d. Force of attraction between its
molecules are negligible.
Ans. d