supplementary material trigosub

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 University of the Philippines Los Baños College of Engineering and Agro-industrial Technology Department of Engineering Science  ENSC 21 - SUPPLEMENTARY MATERIAL COPYRIGHT © 2015 BY JSVENTURA  Supplementary Material (Week 1) Trigonometric Substitution Table of Trigonometric Substitutions Expression Substitution Identity       =  sin , 2  ≤   2  1 =     +    =  tan , 2 <  < 2  1 +  =         =  sec , 0  < 2    < 3 2   1=   Sine substitution Tangent substitution Secant substitution sin =  tan =  sec =  Example: 1. Evaluate √     . Solution: Let = 3sin , = 3cos     9 =   9 9 =   9 = 3|cos | = 3 cos  Thus, we have √ 9   =  3 cos 9 3cos   =    =  =  ( 1)  = − cot  +  = − √   − +  2. Find   √  . Solution: Let = 2 tan , =2    

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  • University of the Philippines Los Baos College of Engineering and Agro-industrial Technology

    Department of Engineering Science

    ENSC 21 - SUPPLEMENTARY MATERIAL COPYRIGHT 2015 BY JSVENTURA

    Supplementary Material (Week 1) Trigonometric Substitution Table of Trigonometric Substitutions

    Expression Substitution Identity = sin , 2 2 1 = + = tan , 2 < < 2 1 + = = sec , 0 < 2 < 32 1 =

    Sine substitution Tangent substitution Secant substitution

    sin =

    tan =

    sec =

    Example:

    1. Evaluate

    .

    Solution: Let = 3 sin , = 3 cos 9 = 9 9 = 9 = 3|cos| = 3 cos Thus, we have

    9

    = 3 cos 9 3 cos = = = ( 1)

    = cot + =

    +

    2. Find

    .

    Solution: Let = 2 tan , = 2

  • University of the Philippines Los Baos College of Engineering and Agro-industrial Technology

    Department of Engineering Science

    ENSC 21 - SUPPLEMENTARY MATERIAL COPYRIGHT 2015 BY JSVENTURA

    + 4 = 4( + 1) = 4 = 2|sec| = 2 sec Thus, we have

    1

    + 4 = 2 4 2 sec = 14 sec

    =

    =

    Let = sin

    1

    + 4 = 14 cos = 14 = 14 1 + = 14 sin + = csc 4 + = +

    +

    3. Evaluate

    , where > 0.

    Solution: Let = sec , = sec tan = ( 1) = = |tan| = tan Therefore,

    = sec tan

    tan = sec = |sec + tan| +

    =

    (see figure above)

    =

    +

    + = + ln +

    = ln

    = + +