structure strength lecturer: professor stephen t. thornton

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Structure Strength Lecturer: Professor Stephen T. Thornton

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Page 1: Structure Strength Lecturer: Professor Stephen T. Thornton

Structure Strength

Lecturer: Professor Stephen T. Thornton

Page 2: Structure Strength Lecturer: Professor Stephen T. Thornton

Reading Quiz

Stress refers to

A) a device used by policeman to catch speeders.

B) force per unit area.

C) ratio of the change in length to the original length.

D) the change in length of rod by a hanging weight.

E) stable equilibrium

Page 3: Structure Strength Lecturer: Professor Stephen T. Thornton

Reading Quiz

B) force per unit area.

Page 4: Structure Strength Lecturer: Professor Stephen T. Thornton

Last Time

Force equilibrium

Rotational equilibrium

Stability and balance

Page 5: Structure Strength Lecturer: Professor Stephen T. Thornton

Today

Elasticity, stress, and strain

Fracture: compression and tension

Trusses and bridges

Arches and domes

Page 6: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Hooke’s law: the change in length is proportional to the applied force.

Elasticity

F k= D

Page 7: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Elasticity; Stress and Strain

Stress is defined as the force per unit area.

Strain is defined as the ratio of the change in length to the original length.

The elastic modulus is equal to the stress divided by the strain:

0

/ stress

/ strain

F AE= =

D

Page 8: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

The change in length of a stretched object depends not only on the applied force, but also on its length, cross-sectional area and the material from which it is made.

The material factor, E, is called the elastic modulus or Young’s modulus, and it has been measured for many materials.

E is the Young’s modulus. A is the area of the rod.

0

1 F

E AD =

Page 9: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

This proportionality holds until the force reaches the proportional limit. Beyond that, the object will still return to its original shape up to the elastic limit. Beyond the elastic limit, the material is permanently deformed, and it breaks at the breaking point.

Do demo of breaking wire.

Page 10: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Page 11: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Elasticity; Stress and Strain

Stress is defined as the force per unit area.

Strain is defined as the ratio of the change in length to the original length.

The elastic modulus is equal to the stress divided by the strain:

0

/ stress

/ strain

F AE= =

D

Page 12: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

In tensile stress, forces tend to stretch the object.

Page 13: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Compressional stress is exactly the opposite of tensional stress. These columns are under compression.

Page 14: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

The three types of stress for rigid objects:

Page 15: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

If an object is subjected to inward forces on all sides, its volume changes depending on its bulk modulus. This is the only deformation that applies to fluids.

or

Why is the sign negative?

0

1VP

V B

D=- D

0/

PB

V V

D=-

D

Page 16: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

If the stress on an object is too great, the object will fracture. The ultimate strengths of materials under tensile stress, compressional stress, and shear stress have been measured.

When designing a structure, it is a good idea to keep anticipated stresses less than 1/3 to 1/10 of the ultimate strength.

Fracture

Page 17: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Fracture

Page 18: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

A horizontal beam will be under both tensile and compressive stress due to its own weight. Therefore, it must be made of a material that is strong under both compression and tension.

Page 19: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Fracture DisasterA tragic substitution. Kansas City Hyatt Regency bridge collapse (1981, 114 died)

Two walkways, one above the other, are suspended from vertical rods attached to the ceiling of a high hotel lobby. The original design called for single rods 14 m long, but when such long rods proved to be unwieldy to install, it was decided to replace each long rod with two shorter ones as shown. Determine the net force exerted by the rods on the supporting pin A (assumed to be the same size) for each design. Assume each vertical rod supports a mass m of each bridge.

Page 20: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Trusses and Bridges

One way to span a wide space is to use a truss—a framework of rods or struts joined at their ends into triangles.

Page 21: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

On a real bridge, the load will not, in general, be centered. The maximum load rating for a bridge must take this into account.

Page 22: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

For larger bridges, trusses are too heavy. Suspension bridges are one solution; the roadway is suspended from towers by closely spaced vertical wires.

Page 23: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

The Romans developed the semicircular arch about 2000 years ago. This allowed wider spans than could be built with stone or brick slabs.

Arches and Domes

Do demo

Page 24: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

The stones or bricks in a round arch are mainly under compression, which tends to strengthen the structure.

Page 25: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

Unfortunately, the horizontal forces required for a semicircular arch can become quite large. The pointed arch was an improvement, but still needed external supports, or “flying buttresses.”

Page 26: Structure Strength Lecturer: Professor Stephen T. Thornton

Copyright © 2009 Pearson Education, Inc.

A dome is similar to an arch, but spans a two-dimensional space.

Page 27: Structure Strength Lecturer: Professor Stephen T. Thornton

Conceptual Quiz: Five forces of the same magnitude act on a square that can rotate about point P at the midpoint of the bottom edge. Rank the forces (in increasing order) acting on the square according to the magnitude of the torque they create about point P.

2 3 4 5 1

3 4 1 2 5

5 4 3 1 2

3 1 2 4 5

4 3 2 5 1

) , , & (tie),

) , , , ,

) , , , ,

) , , , ,

) , , , ,

A F F F F F

B F F F F F

C F F F F F

D F F F F F

E F F F F F

Page 28: Structure Strength Lecturer: Professor Stephen T. Thornton

Answer: D

2 3 4 5 1

3 4 1 2 5

5 4 3 1 2

4 3 2

3 1 2 4 5

5 1

A) , , & (tie),

B) , , , ,

C) , , , ,

E) , , ,

D) , , ,

,

,

F F F F F

F F F F F

F F

F F F F F

F F F

F F F F F