ssc cgl model paper 1 solution

8/17/2019 SSC CGL Model Paper 1 Solution

http://slidepdf.com/reader/full/ssc-cgl-model-paper-1-solution 1/9

Similarly.

Y

=

25 x 2 =>50

I Il.

place value

So, LADY= 24 + 2 + 8 + 50 = 84

27. (C)

LEA D E R

~~~~~~

place value

12 5 1 4 5 18

+8 +8 +8 +8 +8 +8

20 13

9"

'i213 26

0=4x2=>8

place value

place value

A = 1x2=>2

Similarly,

L = 12 x 2 =>24

place value

place value

A = lx2=>2

8 = 2x2=>4

I Il.

Maruti

is the son of

Sirnaran

and Sunil is

the son of Simran's brother/sister

~~n~iWij~¥~r:~b:re ,,:c::(;)~' -l::S~ion of Maru

ti.

II

18. (8) 9

x

2 =

lJ >

9

x

5 = 45

9x9=tl 9x6=~

19. (C)

Pritl

>

Rahul

>

Yamuna

=

Oivya

>

Manju

> Lokita

20. (A) Man Wife ~Sister-in-law

1 1

on Cous; Son

21.(0) 24+ 16-8-32

40 -

8 -

32

32 - 32

(correct)

22. (A )

Prl;/n ,BrOther SitA J.an Sister

K:th V

.is: .l;

17. (C) 5 16 51 158 481

I

('3+ I)

11

('3+3)

tI

('3+5)

tl

('3+7)

f

16. (8)

15. (A) bc cde de efg fg ghl

14.

(8)

682 => 6+8+2=16 (4)'

997 9 + 9 + 7 = 25

(5)2

1 2

(2)2

(3)2

11 (D)

12. (D) (A) 563 - 547 = 16

(8)71-55=16

(C) 523 - 517 = 6

(D) 248 - 231 = 17

13. (D) 10 => 1 + 0 = 1

13 1

+

3 = 4

234 2 + 3 + 4 = 9

Implementation

1

7. (AJb a alb b b b/ a a b b / b

8. (D) abc a b b cab c a abc a c b

9. (CJ

10. (D) Except option (D) all diseases are related

to lock of vitamins

Scheme Refinement Physical Model

6 5

Conceptual Modelling Logical Modelling

2 4

6. (Al

1 + 4 + 7 - 12

1 + 3 + 2 - 6 and

2+9+0-11

+11 1

I t

LIGHT : JJEIR

1-

2

1-2

1_2

t J

tIl ' ~

4.

(C)

MOUSE : KPSTC

1-2

1-21_2

+1

J

5. (Al

264 + 2 132

870 + 3 290

Similarly,

735+5147

+1

L :

1728

s

1

£i. (12)3 l'

12~

1. (8)

2. (D)

3. (AJ F : 216

1l

.21

£~~

+].

SSC MOCK TEST 3 (SOLUTION)

II

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1

Now'3work

in

completedbyonlyA in 2 days

.'. 1 work in completed by onlyA in

=

2

x

3

=

6 days

Work done by B alone

in

1 day

2- 1 1

=

: =

6 6

8 alone can do the same work in 6 days.

Remaining work

=

1- ~

=

1

3 3

Work done by (A + B) in 2 days

= ~

1

= -

3

2. (B) Work done by (A + B) in 1 day

1

Work done by (A + B

+

C) in 1 day

=10

Hence

A, B & C

together complete the

work in 10 days.

12 1

-=-

60 5

5+3+4

60

=-+-+-

12 20 15

WG'I'kUloneby 2(A + B + C)

in

1 day

Work done by (C + A)

in

1 day

1

=-

ork done by (B + C) in 1 day

I

=-

1. (C) Work done by (A + B) in 1 day

41. (0)

44. (0)

47. (0)

Ill.

x

39.

(0)

40.

(D)

42. (0) 43. (C)

45. (A) 46. (0)

48. (A) 49. (8)

50. (C) The numerical groups of BEST will be -

B - 00, 12, 24,31,43

E - 03,10,22,34,41

S - 58, 65,77,89,96

T - 59, 66, 78, 85, 97

1

15

20

or r.:G::::\

~

lkm

OF - OA- FA (Here,FA- 8C+OE - 2+1-3km)

- 8 km - 3 km

- 5 km

3 krn

36. (A) IHorn~__ 8_k_m~FiE- ' A

35(0)

34. (C) 4 x 9 = 36 = 6

3 x 27 = 81 = ../8l= 9

Similarly,

~=10

or,2xx=10x 10

or, 2x = 100

.'. x = 100 + 2 = 50

12426 - 2

64-2x 4 x 2 = 64

Similarly,

7 x 6 x 3 = 126

58

58

62

=> 11)(11-6-115

121-6-115

115 - 115 (correct)

31. (A) 15+24+3-6-17

15+8-6-17

23 - 6 - 17

17

5

17 (correct)

32. (0) (14 + 2) x 12 84

(18+2)x981

Similarly,

[x + 2) x 11 88

or

(88 + 11) x 2

or 8 x 2; 16

33. (0) 3 x 4 x 5 = 60 60 - 2

5 x 6 x 2 = 60 60 - 2

28. (0) According to question the new form of 37. (0)

COMMUNICATIONSwill be-

OCMMIrnUCI TAOISN 38.(0)

,.10

l tt r from right

29. (C) 8 x 20 + 5 + 9 - 3 ~ 38

=> 8 x 4 + 9 - 3 ~ 38

32

+

9 - 3 ~ 38 Conclusions: I. x

41 - 3 ~ 38 II.

38 - 38 (correct)

30. (B)33 • 11 + 3 - 6 - 115

12

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432·

100 = R

400

108 s.

SP·

100

100+ gain

P

SP (after 10% discount)

=

=

Rs.

432

61. (C) MP = Rs. 480

~ x

= 87.5

= 100 - 87.5

=

12.5%

~ 100 - x

Then,

Let x discount is given on the MP of

the table.

12000(100-x)

=

10500

100

MP = Rs. 12000

SP

=

Rs. 10500

60. (B)

= 4 pairs

CP of

1

pair of socks

144

=Rs.1'2

= Rs. 12

.'. No. of pairs ofsocks available for Rs.

48

59. (A)CP of 12 pairs of socks

=

80% of 180

=

80 . 180

100

=

Rs.

144

H

ATQ.

4

c:

3

Volume of the sphere =

3TT ( ,2)

aJ2TT bl .

=

-3-CU IC

unit

58.

(C)

Volume of the water in conical flask

=

2. TTr2h

3

Volume of the water in cylindrical flask

= TT . (mr)2H

r

=

unit

57. (0) TSA of a sphere = 8 TT

=8TT

r

=2

unit

Let ABCO is a square of side

x

unit.

Side x unit.

Its diagonal

= .fix

A, : Area of the circle (whose diameter is

2

x

the side of the square)

= TT · 2

sq. unit

A2 : Area of the circle (whose diameter is

2

.,fix

the diagonal of the square)

=T T

2 sq.

56. (0)

55. (0)

Product of two co-prime numbers

=

117

Q

Co-prime numbers have no common

factor other than

1.

Their LCM

=

117

2 8 16

1 9 9

1 3 3

= - - -

2 4 8

and 3

8

4. (C) A rational number between

ATQ.

5x =

15

15· 4

x

= 5. 2 =

6

.'. B can do the work

in 6

hI'S.

5x

=-

=_.-

100 x

4

80 1

1

A's 1 hr. work = 80% of -

x

1

53. (B)Let B's 1 hr. work = -

x

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2 J I

= x +-2 + x

-

X X

2 1 1

Now x +x+-+2

, x x

1

X+- = 3

x

x

2 + 1

--=3

x

X2

+

1= 3x

X2 - 3x + 1

1. (D)

5000· 12· 2

100

5000· 12· 2

4000· 3

10%

=0

x

Ratio of the two speeds =

y : ~

= 4 : 1

70. (D)

Q

sr, = S12

=.£..= _2_= L

2t 2. ~ 4

Y

They do not collide

if

v, :v2

=1=4:

5 .

69. (A) Let the distance = x m

& the speed = y mls

40

=

_t_= _

50 5

No. of ball left in the box

= (100 + 50 + 50) - (25 + 25)

= 150

No. of black balls = 50

50· 100

0;(, of black balls = 150

= 332.%

3

68. (A) Suppose each car takes t sec time to

reach the crossing.

40 50

V,

= -t-

V

2 = -t-

=

25 . 100

100

= 25

Red balls withdrawn = 50% of 50

= 25

% loss

NewSP = Rs. 235

(250-235)· 100

250

15· 100 = 60/

250 10

67. (B) Blue balls withdrawn = 25% of 100

= Rs. 2506. (C) CP of the article =

300· 100

120

3. 9· 10

3(1+2+3+ ...+9J _ 2

9 - 9

· ·

10

=

9.2

=15

= 50hen,

When no discount is given,

Profit = 480 - 400 = Rs. 80

0/ .

80· 100 200/

10 gaIn

=

400

=

70

62. (B) Let the price of a school bag

=

Rs. 7x

& the price of a pair of shoes = Rs. 5x

ATQ,

7x - 5x = 200

X = 100

Price of a pair of shoes

=

5x = Rs. 500

63. (A)Let P gets Rs. x.

Share of

Q

= Rs. (x + 30)

Share of R = Rs. (x + 30) + 60

= Rs. (x

+

90)

Now, P +

Q

+ R = X + (x + 30) + (x + 90)

300 = 3x + 120

x

= Rs. 60

P : Q : R = 60 : 90 : 150

= 2: 3: 5

64. (B) Let xl' x2' .... , Xgbe nine numbers.

x

50

Time t = -secons

x, + x

2

+ ...... + X9 = 4 Y

x X2+X3+X4+XS =5x54=270 d h lfd

spee w en ha istance is

x7 + Xg+ X9= 52

x

3 = 156 I---'--~*""ef't ¬ ll in double time.

X6=

(x,

+ x

2

+ .... +

Xg) -

[(Xl+ x

2

+ ...+ xs)

+ x7 + Xg+ xgl

= 450 - [270 + 156)

= 450 - 426 = 24

65. (B)Average of 1st 9 integral multiple of 3.

3+ 6+ 9 +12+ 15+18 +21+24 +27

9

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1

art BGD) = -art ABD)--------(A)

3

Similarly we can write

1

art CGD)

= 3

ar( ACD) --------(B)

from (A)& (B)

from (i)& (ii)

ABC is a triangle and G is its centroid.

Mark an another point E on AGs.t. AE=EG

AE°EG (by assumption)

ar

=

ar ( EBG) ---------(i)

[A median of a triangle divides

it into 2 triangles of equal area]

also G is the mid pt of ED

~ ar = art BGD) -------(ii)

[same reason]

79.ICIC~

A B

LC

+

LCAD

=

90°

(Q

LADC

=

90° )

LCAD + LBAD

=

90° (Q

LA=

90°,

given)

LC + LCAD

=

LCAD + LBAD

31 4z 3

~ Iyl-zz z

A

When x = y = z

°

2

I I J

I+X+l+y+l+y

=1

=3

78. (A)x2 +y 2+ Z2 = 2x + 2y + 2z

It is possible only when

x2 = 2x y2 = 2y Z2 = 2z

~ x = 2, 0 Y= 2,0 z = 2,0

When x 0 y

=

z

=

0

7 7

Fraction

=

7- 4 3

x + 1= 8x - 48

x

= 7

75. (C) x = 289K + 18

° 17 x 17K + 17 + 1

=

17(17K+ 1)+ 1

°17xM+1

When x is divided by 17,

Remainder °1

:. y = 1

76. (B)For x = 0, y = 0, here

ax

+

by

+ C

= 0 passes through origin

77. (A)Let the denominator

=

x

the number

°

x - 4

New numerator °x - 4 - 2 °x - 6

New denominator

=

x + 1

ATQ,

x

+

1 = 8(x - 6)

1

=2-

4

1

=1+1+-

4

1

2

=(1)2+(1)2+ -

2

lt is posstble only when a= 1, b= 1,C

o

73. (A) 2./50 + J18 - J72

2JS. 5 2

+

J3. 3· 2 - J6 6· 2

2· sJ2 + 3./2- 6J2

(lO+3-6)J2

7J2 ° 7 x 1.414 = 9.898

74. (C) a

2

+ b?+4c

2

= 2(a + b - 2c) - 3

~ a

2

+ b2+4c

2 -

2a - 2b + 4c + 3 = 0

(a2

-2a

+ 1)+ f:>2-2b+ 1)+ (LJc2 +4c+ 1)= 0

(a - 1)2+ (b - 1)2+ (2c + 1)2= 0

=4

~ 12 °

=04+4+4-

=0

03

2 -

2

3 =

10

4x - 3 4y - 3 4z - 3

72.

(B)

-- -- -- =

0

x y z

x

1 2 1

x+- -2+ x+-

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In OQR,

OQ=OR

Q OP

=

OR

p

83. (C)

23+ 49 _ 72

=

lO3..cm

7 7 7

PN2 = PB2 - BN2

=

122 - (7

+ X)2 ... (ii)

72 - x2

=

122 - (7 + X)2

49 - x2 = 144- (49

+

14x

+

x2)

49-x2 = 144-49-14x-x2

14x = 144- 98

23

x =

=Tcm

NB =NO+OB

In

86. (A)Equilateral.

(Angle sum property of a triangle)

In

Also,

(Angles in the same segment of

a cirle are equal)

LAEB

+

LBEC

=

180 0

(Linear pair)

40· 12

/ 'P

I Q

~eight of the tower

=

60 m.

8S'f) A EB

I

~

... (i)

Let

ON

= x em

In

82. (C)

Chords AC BD intersect at P .

.. AP.PC= BP.PD

I

when any two chords of a circle

Q

intersect each other at a point inside

it, the rectangle so formed by the ~

segments of one chord must be equal

to the rectangle formed by the

segments of the other chords]

84. (A)

XO

+

XO

+

110

0

=

180

0

XO

= 35°

(say)

1

art

BOC)

=

3

ar(

ABC)

1

=

·48

3

c16sq.cm

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~

2

3

2

- -

3

2

3

2

= -

3

92. (A)

3

tane=-

4

4

cote =-

3

~

cosec

=

91.

m2 -1

--= 2

112 -1 cos 0

m'-

=

sin

»a =

n' cos

2a

m

2 -

(1-cos

2 0) =

n

2

cos

2

o

m

n

= -

. .fi

+ 1

= smB

---I

2-]

sinB. I

r.::--:- -

SII1 B = sin B

r.::--:- -

I

V;{.

-I

,,2 -1

Now, cosB-sinB

sine

=

Ii-I

m

n

=-

os~

coso

89.

(C)

cosB+sine

. ) B

SIO- -

(1- cosB)

(1- cos B)(sinB)

(1- cos2 B)- (1- cos B)

(1- cos B)(sinB)

(1- cose)[(1 + cos e)-11

(1- cos B)(sinB)

cote

sine 1

1- cos G sine

sinB sinB

Q

sina =m

sin

.B

cos~

mx-- =n

coso

~ =n

sinB

os

B

1 1

1

88. (A)

= -

coseca+cote

sine

4· .j3. .j3. 2

.j3 = 8../3 m

AD

2

.j3

=-

=

sin600

fn

De=MB

MB

=

24 m

AM =AB-BM

=

36 - 24

=

12 m

tana =

sino

I

sinl3 _

coso cosf - n

sin

0

cos

13

coso' sinl3 = n

90. (B)

= sin9[J2+1-1) = J2sinB

7. (A)

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100 1

-

=

11-

9 9

98. (D)Difference ofmarks between Physics &

Chemistry = 191.25 - 157.5

= 33.75

Difference of marks between Social

Science & Chemistry

= 157.5 - 123.75

= 33.75

99. (C)Marks obtained in (Maths & Chemistry)

= 360

Marks obtained in (Physics & Social

Science) = 315

Difference = 45

100. (D)Marks obtained in English = 135

Difference = 500 _400 %

9 9

= 400

9

= 500%

9

of marks in (Maths & Chemistry)

=

360. 100

810

90

= 360.810= 202.5

Marks obtained in Chemistry

70

= 360.810= 157.5

Total marks in (English, Physics and

Social Science) = 450

Total marks in (Maths Chemistry)

= 360

ofmarks in (English,Physics, Social

Science) = 450. 100

810

55

= 360' 810 = 123.75

Marks obtained in Maths

Marks obtained in Social Science

= 600-400.100

400

= 50%

96. (C) No.ofstudents in science

faculty

in 200102

= 400

Total students= 150

+

200

+

400

+

600

= 1350

% of students in science faculty

= 400.100

1350

=

29.6%

97. (D) Marks obtained in English

60

= _.

810= 135

360

Marks obtained in Physics

85

= 360.810 = 191.25

1 1

-- ---- ;

sec29 cos ec29

=

cos29+sin29 = 1

94. (8) No.of students in law faculty

in

2003-04

= 250

Total students= 250

+

250

+

600

+

500

= 1600

of students in law faculty

= 250 . 100

1600

= 15.6%

95. (A)No. of science students in 2001-02

= 400

No. of science students in 2003-04

= 600

increase in science students

1 1

93. (A) (1 + tan2 9) + (1+ cot2 9)

=

J1+ 196

=n= ~

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SSC MOCK TEST 3 ANSWER KEY

1. 8

26.

C 51. C

76.

B

101. C

126.8

151. C

176.C

2.

0

27.

C

52.

8

77.

A

102.8

127.C

152.C

177.8

3.

A

28.

0

53.

8

78.

A

103.B

128.8 153.A

178.8

4.

C

29.

C

54.

C

79.

C

104.A

129.8 154.8

179.A

5. A 30.

8

55.

0

80.

8

105.8

130.B 155.A

180.C

6. A 31.

A

56.

0

81. A

106.0

131. C 156.A

181. 0

7. A 32.

0

57.

0

82.

C

107. C

132.8 157.8

182.8

8. 0 33. 0 58.

C

83.

C

108. C

133. B 158.0

183.8

9.

C

34.

C

59. A

84. A

109. C

134. C 159.D

184.D

10. D 35. D 60. 8 85. C 110. D 135. 8 160. 8 185.8

11.

D 36. A 61.

C

86. A

Ill. A

136.8 161. C

186. D

12. D 37. D 62. 8

87. A

112. C

137. D 162.D

187.D

13. D 38. 0 63. A

88. A

113.A

138. D 163.C

188.A

14. 8 39. D 64. 8

89. C

114. C

139.C 164.C

189.8

15. A 40. 0 65. 8

90. 8

115. C

140.C 165.C

190.A

16. 8 41. 0 66. C

91. 8

116. A

141. C 166.C

191. 8

17. C 42. D 67. 8

92. A

117.8

142.C 167.A

192. D

18. 8 43. C 68. A

93. A

118. C

143.0 168.C

193. D

19. C 44. 0 69. A

94. 8

119.8

144.C 169.C

194.A

20. A 45. A 70. D

95. A

120. C

145.C 170.C

195.8

21. D 46. D 71. D 96. C 121. 8 146.C 171. D 196.C

22. A 47. D 72. 8

97. D

122. D

147.C 172.C

197.D

23. 0 48. A 73. A

98. 0

123.0

148.C 173.0

198.8

24. A 49. 8 74. C

99. C

124.0

149.C 174.C

199.C

25. B 50. C 75. C

100.0

125.8

150.8 175.8

200.0

151

(C);

'On' in place of 'in'

152 (C); 'between' in place of 'among'

153 (A); Add 'it ' before 'being'

154 (8); 'Will' in place of 'would'

155 (A);Put 'not only' before 'anxious'

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ssc cgl model paper 1 solution

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