[speed time work] three men can finish a work in x days, share in wages & other special cases -...
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men and work by murnal.orgTRANSCRIPT
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Aptitude (http://mrunal.org/category/aptitude) / 3 years Ago /18 Comments (http://mrunal.org/2012/11/speed-time-work-three-men-can-finish-work-x-days-share-wages-special-cases.html#comments)
1. Prologue2. Case: three men start the work simultaneously.3. Case: Three Men Start Working One After Another4. Case: Share in Daily Wage5. Case: Share in money after work finished?6. Case: Time equations: set of two people working7. Case: Time Ratios are given
Prologue
Speed Time workquestions routinely appears in almost every aptitude exam
A can complete a piece of work in 10 days, B can do it in 12 days, C can to it in 15 days. Now Astarts the work and continues for 2 days, then B joins and then C joins .etc.etc. how muchtime will it take?
Sometimes, Instead of character names, theyll give your three pipes. Pipe A can fill the tankin X minutes, Pipe B can do in .But the approach remains the same. (if pipe is emptyingthen use minus sign in the speed.)Such questions take very little time. Just LCM, fill in the table, and use STD formula and done.
Case: three men start the work simultaneously.
Aiyyar can paint Gokuldham society in 10 days, Bhide Master can do it in 12 days andChampaklal can do it in 15 days. If all three of them start working simultaneously from day 1,how many days will it take for them to finish the painting work?
[Speed Time Work] Three men can nish a work in x days, share inwages & other special cases
English: SP Bakshi(http://www.flipkart.com/objective-general-
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Mrunal (http://mrunal.org/)
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It is similar to the pipes and cisterns problem.so make a table
Aiyyar Bhide Champak Together
Speed
Time 10 12 15
Distance
The time for each individual character, is already given in the problem.
Now take the LCM of Time, means that factorize number into its prime numbers(2,3,5,7,11,13,17,19 etc)
10=25
12=2 3
15=35
Now take each prime number in its highest power and multiply them together.
LCM=2 3 5 =60
So LCM (10,12,15)=60. This is the total distance covered, and in this case it means total workdone. i.e. entire surface area of walls of Gokuldham is 60 square meters.Whether these characters paint the society individually or together, the area of the walls willremain one and same 60.
Aiyyar Bhide Champak Together
Speed
Time 10 12 15
Distance 60 60 60 60
2
2 1 1
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Not only empty box is of speed.
Simply write the number required to get 60 by multiplication.
Example Aiyyers time is 10 days. So to get 60 from ten, youve to multiply 10 with 6.
(Alternatively) for Aiyyers case
Speed x time = distance
Speed x 10 days = 60 ; because it is already given in the problem that Aiyyar takes 10 days.
Speed = 60/10 = 6.
Write 6, in Aiyyars speed box.
Similarly for Bhide and Champak youll get 5 and 4 respectively.
Aiyyar Bhide Champak Together
Speed 6 5 4 6+5+4=15
Time 10 12 15
Distance 60 60 60 60
When these three characters work together, their speed will increase: 6+5+4=15.
Now we have to find out the time required,
Again STD formula
Speed x time = distance
15 x time = 60
Time = 60/15= 4 days.
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Final answer: if these three characters work together, they can paint the society in only fourdays.
Case: Three Men Start Working One After Another
Same problem, but with little modification
Aiyyar can paint Gokuldham society in 10 days, Bhide Master can do it in 12 days andChampaklal can do it in 15 days. Aiyyar starts painting the society and Bhide joins him after 2days. Then Both of paint the society together for one day and then Champaklal joins the gang.In this manner, how many total days will be required to finish the paint work?
Part I: Aiyaar starts the work
The table remains seem up to this part
Characters Work
Aiyyar Bhide Champak Aiyyar starts
Speed 6 5 4 6
Time 10 12 15 x2
Distance 60 60 60 =12
It is given that For the first two days, Aiyyar works alone.
So in the last column, fill up Aiyyars speed and time accordingly.
Speed x time = distance
6 x 2 =12 ; because Aiyyars speed is 6 and he works for 2 days.
Meaning, in the first two days Aiyyar has painted 12 square meters of walls.
How much work remains?
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Total 60 minus 12 = 48.
Part II: Bhide joins
it is given that, after two days Bhide master joins and together Aiyyar and Bhide work for oneday. (and then Champak joins)
So make a new column in a table, Aiyyar +Bhide
since theyre working together, this bill will increase and we will do addition : 6 + 5 =11
Characters Work
Aiyyar Bhide Champak Aiyyar starts Bhide Joins
Speed 6 5 4 6 6+5=11
x Time 10 12 15 x2 x 1
=Distance 60 60 60 12 =11
Again
Speed x time = distance
11 x 1 =11
Meaning, in one-day Aiyyar and Bhide painted another 11 square meters.
How much work is left??
48 minus 11 =37
Part III : Champaklal joins
Now Champaklal also joins, so combine speed is 6+5+4=15
and remaining work is 37 We have to find out the time
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Characters Work Progress report
Aiyyar Bhide Champak Aiyyarstarts BhideJoins ChampakJoins
Speed 6 5 4 6 6+5=11 6+5+4=15
xTime 10 12 15 2 1 ??
Distance 60 60 60 60 11 37 remains
Again STD
Speed x Time =distance
15 x Time = 37
Time = 37/15= approx. 2.5 days
Caution : This 2.5 is not the final answer. Because theyve asked you to find total number ofdays required to finish the paint work. So total time is right from the day one when Aiyyarstarted.
2+1+2.5=5.5
Final Answer: The work will be finished in 5.5 days.
Case: Share in Daily Wage
Abdul can do a piece of work in 10 days; Bhide in 15 days. They work for 5 days. The rest of thework was finished by Champak in 2 days. If they get Rs.1500 for the whole work. Find the dailywages of Bhide and Champak.
They got Rs.1500 for the whole work, meaning the work is worth Rs.1500 so take it as ourdistance
Repharse: Abdul can do road-construction of 1500 kms in 10 days!.. and so on
Abdul Bhide
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Speed
Time 10 15
distance 1500 1500
Apply STD formula and find out speed value of each column
A B
Speed 150 100
xTime 10 15
=distance 1500 1500
Given: they (A and B) worked for five days
A B A+B
Speed 150 100 150+100=250
Time 10 15 5
distance 1500 1500 250 x 5=1250
Combined speed of A+B=250 so in two days they constructed road of 1250 kms.
Remaining work = 1500 minus 1250 = 250kms
This was done by C alone, in two days.
A B A+B C
Speed 150 100 250
Time 10 15 5 2
distance 1500 1500 1250 250
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Run STD formula on Cs column and find his speed
A B A+B C
Speed 150 100 250 125
Time 10 15 5 2
distance 1500 1500 1250 250
Their daily wage depends on how much work can they do per day?
Which is actually their speed. E.g. B can construct 100 km roads per day.
So daily wage of B=Rs.100
And daily wage of C=Rs.125
Total daily wage of B and C=100+125=225
Case: Share in money after work nished?
Q. Abdul alone can do a piece of work in 6 days and Bhide alone in 8 days. They undertook to doit for Rs.3200. With the help of Champak, they completed the work in 3 days. How much is to bepaid to Champak?
Total road construction is 3200 kms this time.
A B
Speed
Time 6 8
distance 3200 3200
Run STD formula to find speeds
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A B
Speed 3200/6 400
Time 6 8
distance 3200 3200
Given: With the help of C, they completed the work in 3 days.
We dont know the speed of C, assume it is c but construct his column and fill remaining data.
A B C A+B+C
Speed 3200/6 400 c (3200/6)+400+c
Time 6 8 ?? 3
distance 3200 3200 3200
Run STD formula on third column
[ (3200/6)+400+c ] x 3 = 3200
Solve this equation you get c=400/3
Meaning speed of c=400/3
He works for 3 days.
Speed x time = distance
(400/3) x 3 =distance
400= distance
Meaning C covered 400kms
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Which means he was paid Rs.400
Case: Time equations: set of two people working
Q. A & B can do a piece of work in 12 days , B and C in 15 , C & A in 20 days. How longwould each take separately to do the same work?
In the STD table, when people come and go, we can do addition and subtraction in the SPEEDboxes only and now in the Time boxes.
Now fill up the table.
A+B B+C C+A
SPEED
TIME 12 15 20
DISTANCE
TAKE THE LCM (12, 15, 20) =60. Based on that we can find individual speeds using STD formula.
A+B B+C C+A
SPEED 5 4 3
TIME 12 15 20
DISTANCE 60 60 60
Assume that these three entities work together
A+B B+C C+A (A+B)+(B+C)+(C+A)
SPEED 5 4 3 5+4+3=12
TIME 12 15 20 ??
DISTANCE 60 60 60 60
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Speed of A+B+C together can be derived using
(A+B)+(B+C)+(C+A)
= 2(A+B+C)=5+4+3=12
Hence speed of A+B+C together =12/2=6
Now STD formula
Speed x time = distance
6 x time = 60
Time = 10
Meaning if A+B+C work together, they can finish work in 10 days. [Although Time of A+B+C, isnot asked in the question, but Ive given it only for explanation]
Now back to the question, weve to find individual time. So far our table looks like this-
A+B B+C C+A A+B+C
SPEED 5 4 3 6
TIME 12 15 20 10
DISTANCE 60 60 60 60
Now you can solve it three unknown equation.
Because this is speed, we can do addition, subtraction and solve it as three unknown equations
Speed of A+B+C=6
Speed of A+B=5
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Hence speed of C= 6 (A+B)= 6-5=1
A+B B+C C+A A+B+C (A+B+C)-(A+B)=C
SPEED 5 4 3 6 6-5=1
TIME 12 15 20 10 ??
DISTANCE 60 60 60 60 60
Speed of C is 1 and he has to cover 60 kilometers alone,
STD formula,
1 x Time = 60
Hence itll take him 60 days.
A+B B+C C+A A+B+C (A+B+C)-(A+B)=C
SPEED 5 4 3 6 6-5=1
TIME 12 15 20 10 60
DISTANCE 60 60 60 60 60
Do similar procedure for B and A.
A+B B+C C+A A+B+C C B A
SPEED 5 4 3 6 6-5=1 6-3=3 6-4=2
TIME 12 15 20 10 60 20 30
DISTANCE 60 60 60 60 60 60 60
Final answer, time taken by A,B,C if they work individually= 30,20,60
Run a cross verification to see the answer is correct. Plug the answer values.
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A B C A+B B+C C+A
Speed 2 3 1 5 4 3
Time 30 20 60 12 15 20
Dist 60 60 60 60 60 60
Yes it satisfies the statements given in the Question.
Case: Time Ratios are given
Q. A takes twice as much time as B and thrice as much as C to finish a piece of work. Theytogether finish the work in one day. Find the time taken by each of them to finish thework.
A takes twice as much time as B,
meaning if B takes 1 day, A takes 2 days
So the ratio of time is A:B=2:1
Similarly A:C=3:1
We can write the same thing as
B:A=1:2
A:C=3:1
If we want the three terms ratio, we want mid term (A) to be same in both equation.
In the first eq. A is 2 and in second eq. A is 3. LCM (2,3)=6
Multiply something in both equations so that we get 6 in both equation.
Meaning, Multiply first eq with (2) and second equation with (3)
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B:A=3:6
A:C=6:2
Now we can make a three terms ratio
B:A:C=3:6:2
Keep in mind, this is ratio and not absolute number
So we fill Time boxes as
As time = 6x
Bs time = 3x
Cs Time = 2x
Run the STD table, fill the data
A B C A+B+C
Speed 1 2 3 6
Time 6x 3x 2x 1 day
Distance 6x 6x 6x 6x
LCM of (6x,3x,2x)= 6x
From the STD fomula, we can get the individual speeds of A,B,C,= 1,2,3
Together their speed A+B+C=1+2+3=6
For the last column
Speed x time = distance
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6 multiplied with 1 =6x
Hence x= 1
Put the value of x=1 in the table and you get individual time
A will take 6 days individually, B will take 3 days and C will take 2 days.
Cross verification (plug the answers we got)
A B C A+B+C
Speed 1 2 3 6
Time 6 3 2 1 day
Distance 6 6 6 6
From the table,
A takes twice as much time as B and thrice as much as C to finish a piece of work
Yes it satisfies the statement given in the question itself.
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aditya swaroopThanx fr the practice questions mrunal sir !!!!!!! Please give sum guidanceon preparation of science and tech. for GS (prelims) !!!!!
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 0 5 0 7 2 # R E S P O N D )
aditya swaroopPlease guide as to on which portions of technology one must focus ?????Questions frm biology and physics came in 2013 pre. but they were lessthan the technology questions !! Pls guide
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R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 1 7 8 6 5 # R E S P O N D )
sunny kumarkindly help with below question-my answer- 48.actual answer-24
twenty four men can complete a work in 16 days.thirty two women can complete the same work in 24 days.sixteen men & sixteen women started working and worked for twelvedayshow many more men are to be added to complete the remaining work in2 days?
thanks.
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E -W A G E S - S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 3 3 7 1 3 # R E S P O N D )
Ghufran AlamYou didnt take into account the work done by existing group ofpeople(16 men and women) for those two last days. Subtract theirshare of work done in those two days and calculate men requiredfor completing the work.
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 2 5 7 2 8 # R E S P O N D )
AvinashMrunal bhai..kindly tell us..what if 2 persons work alternatively or evry3rd day and that type eof questionsThank u
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R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 3 0 0 2 5 # R E S P O N D )
AmitCase 3: (short way out)assume total time taken = x ;then accordingly,total work(distance)= 60;as work = 6*x;bs work = 5*(x-2);cs work = 4*(x-3);all 3 guys working,should add up to 60; thus, x = 82/15;
It removes the redundancy of solving remainin work when other guysjoin the party.
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 4 5 1 8 3 # R E S P O N D )
NehaMrunal Sir, plz tell me how to solve this ques with your method oranybody whove mastered this method:A can do piece of work in 6 days while B can do it in 5 days. If the totalamount to be given for this work is Rs.660, whatll be the share of B ifboth do the work together?Ans: Rs. 360
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E -W A G E S - S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 4 5 4 8 7 # R E S P O N D )
Neha
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No need to post this comment. Ive solved it Thank you Mrunal Sir, Your STD method is awesome
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S -S H A R E - W A G E S - S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 6 4 1 6 8 # R E S P O N D )
devendrahow u have solved with STD method ??
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 4 9 1 2 9 # R E S P O N D )
swathigoodto give such a great explanation
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 5 1 5 5 2 # R E S P O N D )
shivangiawesome ,just loved the way u make it easier and understandable.
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 5 2 7 6 5 # R E S P O N D )
shubham tomarthnx #mrunal sir..it is really helpful
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 6 3 7 2 5 # R E S P O N D )
priya
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4men and 6 women get 1600 Rs by doing a piece of work in 5 days . 3men and 7 women get 1740 Rs by doing same piece of work in 6 days. Inhow many days, 7 men and 6 women can complete the same workgetting 3740 rs?
Can You explain this problem using STDs?
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E -W A G E S - S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 8 3 9 0 9 # R E S P O N D )
SadiqDear Sir,
Please explain Priyas question if you can. I am also having thisdoubt.
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 2 8 2 0 8 8 # R E S P O N D )
vaibhav shuklaThanx mrunal sir..
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 3 0 8 3 5 8 # R E S P O N D )
sancan someone please explain me this stepi dont know how 6 has comehere2(12)=24 right?
Speed of A+B+C together can be derived using
(A+B)+(B+C)+(C+A)
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= 2(A+B+C)=5+4+3=12
Hence speed of A+B+C together =12/2=6
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 3 1 8 4 9 8 # R E S P O N D )
LuvishSir, Please help me with this problem. (SSC CGL Tier-I 2014)
Three men A,B & C working together can do a job in 6 hours less timethan A alone, in 1 hour less time than B alone and in half the timeneeded by C when working alone. Then A and C together can do the jobin??a) 2/3 hrsb) 3/4 hrsc) 3/2 hrsd) 4/3 hrs
R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T H R E E - M E N - C A N - F I N I S H - W O R K - X - D A Y S - S H A R E - W A G E S -S P E C I A L - C A S E S . H T M L ? R E P L Y T O C O M = 3 3 1 3 1 9 # R E S P O N D )
Raj1.A can do a work in 15 days and B in 20 days. If they work on it togetherfor 4 days, then the fraction of the work that is left is :
Please show how to use ur trick in this problem?
2.A can lay railway track between two given stations in 16 days and B cando the same job in 12 days. With help of C, they did the job in 4 daysonly. Then, C alone can do
this too
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ABHISHEK { now how many lecture still remain to complete the economic lecture. sir please discuss } [Economy Lecture] GS2: UNFCCC Lima Summit, Paris Summit Post-2020...(http://mrunal.org/2015/06/economy-lecture-paris-summit-post-2020-climate-finance-framework.html/comment-page-1#comment-340641)
ISHU { THANKUUUUUU..SO MUCH SIR.. my economics was not so good and i have fear for that but after listening to ur lectures all doubts are clear.... } [Economy Lecture] GS2: UNFCCC LimaSummit, Paris Summit Post-2020... (http://mrunal.org/2015/06/economy-lecture-paris-summit-post-2020-climate-finance-framework.html/comment-page-1#comment-340627)
DWARIKA { in composition of the interior of the earth need updation in part of crust property you are mentioned potassium is lowest in earth's crust ,... } [Geography Lecture1] Longitude,Latitude, Timezones, Earth Interior, Rock types,... (http://mrunal.org/2015/02/youtube-geography-l1-longitude-latitude.html/comment-page-2#comment-340620)
ANN { Thanks for the MCQs on IYB :) } [Mock Test #3] India Yearbook Chapter 1 to 12:...(http://mrunal.org/2015/06/upsc-mock-test-paper-1-india-yearbook.html/comment-page-1#comment-340565)
RAVIRAJDODIYA { Sir, I want to appear UPSC in Gujarati.Because I think I am comfortable in that language and I can write 10 time better that any... } [Analysis] Essay topic trends in last19 years (1993-2011)... (http://mrunal.org/2011/12/analysis-essay-topic-trends-in-last-19.html/comment-page-1#comment-340560)
VIMAL { product of two number is 600.Lcm of thease number 10.What is the HCF of those two number? } [Aptitude] LCM, HCF, GCD: Basic concept, calculation, applications explained(http://mrunal.org/2013/03/aptitude-lcm-hcf-gcd-basic-concept-calculation-applications-
60 Days : CSAT-15
101 Days : IBPS-PO-15
164 : IBPS-Clerk-15
177 Days : Mains-15
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explained.html/comment-page-2#comment-340559)
HARSHADNARKAR { What is your Message? Search before asking questions & confine discussions to exams related matter only. sir,history lectures kab honge. } [Economy Lecture]GS2: UNFCCC Lima Summit, Paris Summit Post-2020... (http://mrunal.org/2015/06/economy-lecture-paris-summit-post-2020-climate-finance-framework.html/comment-page-1#comment-340552)
JOHNSSWARGIARY { ist true that double the money plz ans me } [Financial Inclusion]Kisan Vikas Patra (KVP): Features, Money Laundering,... (http://mrunal.org/2014/12/kisan-vikas-patra-kvp-features-money-laundering-black-money-tax-benefit.html/comment-page-1#comment-340548)
NAVEEN { Prateek even i got.....291 marks.....what about the reserved list??? Whts the procedure?? } [CAPF-2014] Final result out, 105 selected, marksheets in 15...(http://mrunal.org/2015/02/upsc-capf-2014-final-result-marksheet.html/comment-page-2#comment-340545)
VacanciesEntire List shifted to bottom. Scroll down
(http://www.alexa.com/siteinfo/mrunal.org)
Mega Jobs
23-Jul: IBPS Rural PO & Asst. (http://ibps.in/html/cwe_rrb.htm)
17-Aug: IGNOU PG Admission (https://onlineadmission.ignou.ac.in/Login.aspx)
17-Jul: NDA Officers (http://upsconline.nic.in/mainmenu2.php)
13-Jul: SSC 10+2 (http://www.ssconline.nic.in/)
09-Jul: APFC Provident Fund Comm.
(http://www.upsc.gov.in/recruitment/advt/2015/Spl.Advt.52-15%20Web%20Cell.pdf)
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09-Jul: Punjab Corp Engineer (http://202.164.52.147/serv1/docs/dysecyrect121017527.pdf)
09-Jul: Punjab Corp Clerks (http://202.164.52.147/serv1/docs/dysecyrect121017527.pdf)
07-Jul: RBI Assistants (504) (https://opportunities.rbi.org.in/Scripts/bs_viewcontent.aspx?
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30-Jun: LIC ADO (25k Bond,4yr) (http://www.licindia.in/careers_pop0022.htm)
24-Jun: Haryana Gramin Bank Assiatant (http://www.shgb.co.in/RecruitmentsandPromotions)
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Rural Banks
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25-Jun: MP Electricity
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20-Jul: NISER APO (http://www.niser.ac.in/drupal_new/)
15-Jul: Jammu Univ. (http://www.cujammu.ac.in//Default.aspx?
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15-Jul: MoEF Scientists (http://envfor.nic.in/advertisements)
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12-Jul: GBPUAT (http://www.gbpuat.ac.in/)
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07-Jul: NBCC Building (http://www.nbccindia.com/nbccindia/nroot/njsp/Career.jsp)
01-Jul: NIELIT Spec. (http://www.nielit.gov.in/recruitments.aspx)
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30-Jun: IIT Kanpur (http://www.iitk.ac.in/new/vacancies-in-administrative-and-technical-
cadre )
28-Jun: ONGC Rajbhasha (NET)
(http://ongcindia.ongc.co.in/wps/wcm/connect/ongcindia/home/career/recruitment+notices/recruitment-
of-olo-2015)
25-Jun: Raj. Industrial Development (http://www.riicorecruitment.org/)
25-Jun: HSCC Noida (http://www.hsccltd.com/)
24-Jun: Haryana Gramin Agro (http://www.shgb.co.in/RecruitmentsandPromotions)
24-Jun: Haryana Gramin Law Officer (http://www.shgb.co.in/RecruitmentsandPromotions)
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Medics
14-Jul: MP medical officer (http://www.mppsc.nic.in/)
30-Jun: HAL Medical officer (http://www.hal-
india.com/Common/Uploads/Resumes/144_CareerPDF1_Med-advt-AC.pdf)
ParaMedics
Not At the moment
Deskjobs
05-Aug: NBE Assistants (http://natboard.edu.in)
31-Jul: IIIT Allahabad Gr.C (http://www.iiita.ac.in/announcements.php)
20-Jul: NISER Clerks (http://www.niser.ac.in/drupal_new/)
15-Jul: Jammu Univ. (http://www.cujammu.ac.in//Default.aspx?
option=article&type=single&id=32&mnuid=734&prvtyp=site)
07-Jul: NBCC Building (http://www.nbccindia.com/nbccindia/nroot/njsp/Career.jsp)
01-Jul: NIELIT Deskjobs (http://www.nielit.gov.in/recruitments.aspx)
13-Jun: Bank Note Press (http://www.jobapply.in/bnpdewas/)
30-Jun: Lucknow Law univ. (http://rmlnlu.ac.in/recruitment-notification-process.html)
30-Jun: Rashtriya Sanskrit Sansthan (http://sanskrit.nic.in/advt_22_05_2015.pdf)
25-Jun: Pawan Hans Limited (http://pawanhans.co.in/site/Careern.aspx)
24-Jun: SJVN (PH) (http://sjvn.nic.in/careerdetail.htm?10/jobdetail)
Faculty
31-Jul: IIIT Allahabad (http://www.iiita.ac.in/announcements.php)
20-Jul: Raipur Univ. (http://www.prsu.ac.in:8010/Univ_Req.aspx)
15-Jul: NIT Puducherry (http://www.nitpy.ac.in/assets/teaching.pdf)
16-Jul: RPSC Home Science (http://rpsconline.rajasthan.gov.in/)
15-Jul: Jammu Univ. (http://www.cujammu.ac.in//Default.aspx?
option=article&type=single&id=32&mnuid=734&prvtyp=site)
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12-Jul: GBPUAT (http://www.gbpuat.ac.in/)10-Jul: NITTTR Chandigarh (http://www.nitttrchd.ac.in )
07-Jul: Palampur, Himachal asst. (http://www.ihbt.res.in/recruit/recruitNotice.php)
06-Jul: PEC Chandigarh (http://pec.ac.in/~pecac/new/jobs)
03-Jul: SKHM Government Medical College (http://www.gmcmewat.ac.in)
30-Jun: IIT Roorkee (http://www.iitr.ernet.in/administration/pages/Openings+Faculty.html)
30-Jun: Ambedkar Uni. Delhi (http://aud.ac.in/careerataud)
30-Jun: NEIGRIHMS (http://neigrihms.gov.in)
30-Jun: Lucknow Law (http://rmlnlu.ac.in/recruitment-notification-process.html)
30-Jun: AIIMS Raipur (http://www.aiimsraipur.edu.in/Career.aspx)
28-Jun: Ranchi Agro (http://www.bauranchi.org/application-for-the-post-of-teachers-2/)
22-Jun: DIATPune (http://14.139.111.180/admin.html)
22-Jun: IGIT (http://www.igitsarang.ac.in/careers.php)
22-Jun: Himachal Central Univ. (http://www.cuhimachal.ac.in/job_emp.aspx)
Uniform
19-Jul: Navy Officers (http://www.irfc-nausena.nic.in/hindi/join_indiannavy.htm)
17-Jul: NDA Officers (http://upsconline.nic.in/mainmenu2.php)
15-Jul: Army Dental (23) (http://indianarmy.nic.in)
10-Jul: Army 10+2 (http://joinindianarmy.nic.in/)
30-Jun: BSF Constable (http://bsf.nic.in/en/recruitment.html)
15-Jun: Navy Sailers (SSR) (http://nausena-bharti.nic.in/forthcomingSailor.php)
15-Jun: Daman Diu Constables (http://daman.nic.in/jobs/2015/616-12-05-2015.PDF)
B.Com,CA,HR,MBA
20-Jul: Pawan Hans Audit (http://pawanhans.co.in/site/Careern.aspx)
06-Jul: GBPUAT Accountant (http://www.gbpuat.ac.in/)
01-Jul: NIELIT Accounts (http://www.nielit.gov.in/recruitments.aspx)
25-Jun: MP Electricity Accounts
(https://www.mponline.gov.in/Portal/Services/Recruit_MPKVV/Indore/notification.aspx)
21-Jun: Lucknow Metro Accounts
-
1. Online Form Part-I stops few days before deadline, so don't wait till last date. Dont forget
reg.id & roll no.Note'em in Google Drive (https://www.google.com/drive/)
2. I usually update vacancies every Monday.Purple link= newly added,Blue= existing.Last
updated Mon. Jun 22, at 9:04PM
(https://www.digialm.com/EForms/html/form2399/index.html)
RESULT /MARKSHEET
SSC 2014 T2
NCLAT
Hotel Management
TENTATIVE NOTIFICATIONS
IAS-IPS-IFoS: 16 May
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SSC 10+2: 6 June
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CAT: Aug 2015
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IBPS PO / Clerk / RRB: ??
ACIO 2015: ??
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