solving word problems involving quadratic equations
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Solving Word Problems Involving Quadratic Equations
Do Now: Write a “let” statement and equation for each example. Explain the difference.
A. Find two consecutive integers whose sum is 13.
Let x = first integer
x + 1 = second integer
x + x + 1 = 13
B. Find two consecutive integers whose product is 42.
Let x = first integer
x + 1 = second integer
x(x + 1) = 42
How do we solve consecutive integer problems?
Write “let” statement (if consecutive integers, use x;x+1;x+2. If consecutive even or odd, use x;x+2:x+4)
Write equation using key words from statement: sum (add), product (multiply), more than (add), less than (subtract), etc.
Solve equation
Check in original problem statement
Practice p. 774-775 10,12
10. Let x = first odd integer
x + 2 = second odd integer
x(x + 2) = 143
x2 + 2x = 143
x2 + 2x – 143 = 0
(x + 13)(x – 11) = 0
x = - 13 x = 11
Integers: -13 and – 11
11 and 13
12. Let x = first integer
x + 1 = second integer
x + 2 = third integer
(x + 1)(x + 2) = 30
x2 + 3x + 2 = 30
x2 + 3x – 28 = 0
(x + 7)(x – 4) = 0
x = - 7 x = 4
Integers: -7, - 6, - 5
4, 5, 6
How do we solve word problems?Practice p. 774 #2
Let x = the number
x2 – 9x = 36
x2 – 9x – 36 = 0
(x – 12)(x + 3) = 0
x – 12 = 0 x + 3 = 0
x = 12 x = - 3
How do we solve area problems?(what is the formula for area of a rectangle?
1. Draw diagram
2. Label information
3. Write formula
4. Substitute and solve
The length of a rectangular garden is 6 more than the width. The area is 27 sq. units. Find the dimensions of the
garden.
x(x + 6) = 27x2 + 6x = 27x2 + 6x – 27 = 0(x + 9)(x – 3) = 0x + 9 = 0 x – 3 = 0x = - 9 x = 3REJECTDimensions: 3, 9