solve linear equation by using this simple trick
TRANSCRIPT
8π₯ + 5π¦ = 11 β 8π₯ + 5π¦ β 11 = 0
3π₯ β 4π¦ 10 β 3π₯ 4π¦ 10 = 0
Tricks
A
Letβs solve two simultaneous equations
First write coefficients of equation in form of presentation below
Now Formula goes like this
How to remember and use this method to solve equation within 30 Seconds
π π₯ + π π¦ + π = 0
π π₯ + π π¦ + π = 0
π₯ (bβcβ β bβcβ)(aβbβ β aβbβ)
= ππ·
π¦ (cβaβ β cβaβ)(aβbβ β aβbβ)
= ππ·
π 1 π 1 π 1 π 1
π 2 π 2 π 2 π 2
8 5 β11 8
3 β4 β10 3
Visit our Blog for more SAT Helpful Insights and don't forget to share :)
Now to find x and y, letβs divide the above boxes into three compartments and cross multiply numbers. Starting from left as shown below.
π· 8 β (β4) β 5 β 3 π 1 = β5 β (β10) β (β4) β (β11) π 2 = β11 β (3) β (β10) β 8
π· β32 β 15 ==
=
β47 π 1 = β50 β 44 = β94 π 2 = β33 + 80 = 47
So π π 1π·
β94β47
=== 2 π π 2π·
β4747
== = β1
8 5 β11 8
3 β4 β10 3
8 5 β11 8
3 β4 β10 3
8 5 β11 8
3 β4 β10 3
π 1 π 1 π 1 π 1
π 2 π 2 π 2 π 2
π 1 π 1 π 1 π 1
π 2 π 2 π 2 π 2
π 1 π 1 π 1 π 1
π 2 π 2 π 2 π 2
Tricks