solutions aiats medical-2016 test-07 (code-a & b) 14-02-2016

8/18/2019 Solutions AIATS Medical-2016 Test-07 (Code-A & B) 14-02-2016

1/18

Test - 7 (Code A) (Answers & Hints) All India Aakash Test Series for Medical-2016

1/9

1. (4)2. (1)

3. (4)

4. (2)

5. (2)

6. (1)

7. (1)

8. (1)

9. (1)

10. (2)

11. (2)

12. (2)

13. (4)

14. (3)

15. (3)

16. (4)

17. (3)

18. (4)

19. (2)

20. (4)21. (2)

22. (3)

23. (1)

24. (2)

25. (3)

26. (2)

27. (1)

28. (3)

29. (2)

30. (2)31. (2)

32. (3)

33. (1)

34. (1)

35. (1)

36. (1)

37. (3)38. (2)

39. (4)

40. (1)

41. (2)

42. (1)

43. (1)

44. (3)

45. (3)

46. (4)

47. (3)

48. (4)

49. (1)

50. (3)

51. (1)

52. (2)

53. (4)

54. (2)

55. (1)

56. (3)

57. (3)

58. (4)

59. (2)

60. (2)

61. (2)

62. (1)

63. (2)

64. (4)

65. (4)

66. (4)67. (3)

68. (1)

69. (3)

70. (3)

71. (3)

72. (1)

ANSWERS

TEST - 7 (Code-A)

All India Aakash Test Series for Medical-2016

Test Date : 14-02-2016

73. (1)74. (3)

75. (1)

76. (3)

77. (1)

78. (2)

79. (2)

80. (3)

81. (4)

82. (3)

83. (4)

84. (2)

85. (4)

86. (3)

87. (2)

88. (2)

89. (1)

90. (3)

91. (4)

92. (3)

93. (2)

94. (3)

95. (2)

96. (2)

97. (3)

98. (1)

99. (3)

100. (3)

101. (2)

102. (1)103. (3)

104. (3)

105. (3)

106. (2)

107. (1)

108. (3)

109. (3)110. (4)

111. (2)

112. (3)

113. (2)

114. (2)

115. (3)

116. (2)

117. (3)

118. (4)

119. (3)

120. (3)

121. (4)

122. (1)

123. (1)

124. (3)

125. (4)

126. (2)

127. (3)

128. (1)

129. (2)

130. (4)

131. (2)

132. (3)

133. (2)

134. (2)

135. (4)

136. (3)

137. (2)

138. (4)139. (4)

140. (1)

141. (1)

142. (2)

143. (3)

144. (4)

145. (2)146. (3)

147. (1)

148. (3)

149. (1)

150. (4)

151. (2)

152. (3)

153. (1)

154. (2)

155. (4)

156. (4)

157. (3)

158. (2)

159. (2)

160. (3)

161. (2)

162. (2)

163. (2)

164. (4)

165. (3)

166. (1)

167. (2)

168. (2)

169. (2)

170. (4)

171. (3)

172. (4)

173. (1)

174. (3)175. (3)

176. (4)

177. (2)

178. (2)

179. (2)

180. (4)

click here for code-B solution


2/18

All India Aakash Test Series for Medical-2016 Test - 7 (Code A) (Answers & Hints)

2/9

Hints to Selected Questions[ PHYSICS]

1. Answer (4)

u =

v = 2R

1 1

2

n n

R R

1

2

n n

R R

n = 2n – 2

n = 2

2. Answer (1)

r + r' = Ar + r' = 60°

r + 10 + t 2 = 60°

r = 60 – (10 + t 2 )

r = 50 – t 2

3. Answer (4)

x =1

1t

= 2 55 1 3 3

There will be two shift

x =10

cm3

Position from object10

10 5 153

10 10 90 10 8015 15 30 cm

3 3 3 3 ⇒ ⇒

4. Answer (2)

sin i e =1

i e = 45°

Total angle = 2 i c = 90°

5. Answer (2)

f 1 = f 2 = f 3 = f 4 = 2f

=1 2 3 4

1 1 1 1 1 eq

f f f f f

1 1 1 1 1

2 2 2 2

eqf f f f f

2

4 2

eq

f f f

6. Answer (1)

Since image is real

u + v = 4f

20 + 20 = 4 f

40 = 4 f

f = 10 cm.

7. Answer (1)

10 y

d sin = n

y d n

D

n Dy

d

2

d n D

d

n =

2

2

d

D

8. Answer (1)

22

t

97550 10 100 mm = 1 10 m

2 2 4 4 1.38


3/18


3/9

9. Answer (1)

max

24

0.5

d n

n = 4 × 4 = 16

10. Answer (2)

y = constant

11. Answer (2)

H discharge tube means max hv = 13.6 eV

w = 4.2 V

So 13.6 4.2 9.4 VV

So required voltage is – 9.4V

12. Answer (2)

ev =hc

w

v =1hc w

e e

slopehc

e

13. Answer (4)

E = hf =hc

1 2

hc hc

E E E

14. Answer (3)

E max = 13.6 eV

E min = 13.6 21 3

1 13.62 4

max

min

4

3

E

E

15. Answer (3)

E 1 = E 2 + E 3

1 2 3

1 1 1

16. Answer (4)

1E

17. Answer (3)

2

h

18. Answer (4)

9 1

16 2

t

T

2

0

1

2

t

T N

N

2

0

1

2

t

T N

N

=9

16

0

34

N N

19. Answer (2)

0 01

64 2

n

N N

1 1

64 2

n

n = 6

6

2

T

t

6 6 2 h2

t T

= 12h


4/18


4/9

20. Answer (4)

2

2

2 4

2 216

pE

pE

21654

4

E

E

54

E E

21. Answer (2)

22. Answer (3)

100 = o o oin i i

I V R

I V R

100 =o i

i o

V R

V R

100 =V 1k

1m V 10 ko

V o =100 1 mV 10 k

1 k

= 1000 mV

= 1 V

23. Answer (1)

Z = (w + x ) ( w + y ) = w 2 + wy + wx + xy

= w 2 + w ( x + y ) + xy

= w [1 + x + y ] + xy

= w + xy

24. Answer (2)

25. Answer (3)

In forward condition PD across diode 0

26. Answer (2)

50.5A

10

27. Answer (1)

1k

1515 mA

1 kI

5 10.02A

250 50I ⇒

= 20 mA

I D = I – I 1k= 20 mA – 15 mA = 5 mA

28. Answer (3)

29. Answer (2)

NOR gate

X Y Z

. .z y x x A B = NOT + OR

= NOR

30. Answer (2)

31. Answer (2)

dapp =d

∑

1 2

1 2

...d d

4 6

4 33 2

⇒

= 3 + 4 = 7 cm

32. Answer (3)

cmu

20 cmv

1 1 2

v f

= 1 2

20 f

1 2

1f R

⇒

1 2

1.5 140 R

⇒

=0.5 2 1

R R

R = 40 cm

33. Answer (1)

Let u = x

v = y

1 1 1

x y f


5/18


5/9

1 1 1 x y f

differential w.r.t. t

2 22 2 0dx dy x y dt dt

2 22 2

i m obV v y x

V im = 2

2

ob

im

V y x V

=1 1 1 2

x y f R

2

22

R v

x R ⇒

=2

1 x x y R

21 x x

y R

2 x R

R

34. Answer (1)

1D D

t d d

1t

1t

=9

7

600 10 m1

12 10 m

= 0.5 + 1 = 1.5

35. Answer (1)36. Answer (1)

37. Answer (3)

For using wavelength

2 12

n Dy

d

2 12 2

n Dd

d

2 2 2 2

, , ...2 1 3 5 7

d d d d

n D D D D

38. Answer (2)

1

d

39. Answer (4)

sin x d n

= 10 × 6.2 × 10 –6 m

= 6.2 × 10 –5 m

40. Answer (1)

1 1 1

v u f

1 1 1 u f

v f u uf

1

uf f v

f u f u

41. Answer (2)

X

24 cm15 cms

1 1 1

24 15 10 x

1 1 1 5

24 10 15 150 x

x + 24 = 30

x = 6 cm

42. Answer (1)


6/18


6/9

43. Answer (1)

0 02

1 0 0 0

V f h

h u u f

=2 1

2000 2 1000

2 11 50 100 cm

1000 1000h h

= 5 cm

46. Answer (4)

RMgx reacts with acidic hydrogen to form alkane.

47. Answer (3)

Chromyl chloride used in etards reaction

48. Answer (4)

49. Answer (1)

Nucleophile which form strong conjugate acid isbetter leaving group.

50. Answer (3)

51. Answer (1)

52. Answer (2)

Libermann nitroso test used to identify 2° amine.

53. Answer (4)

54. Answer (2)Glycerol reacts with KHSO 4 to form acrolein.

55. Answer (1)

56. Answer (3)

57. Answer (3)

Less stable alkyl halide gives S N 2 reaction.

58. Answer (4)

More stable carbocations are more reactive for S Nreaction.

59. Answer (2)

60. Answer (2)

61. Answer (2)

Br 2 gives anti addition product

62. Answer (1)

63. Answer (2)

44. Answer (3)

1RP V

1

20 1

80 4

R

R

R 1 = 2 R

45. Answer (3)

[ CHEMISTRY]64. Answer (4)

–OH and –SH have sp 3 hybridization and have bentarrangement.

65. Answer (4)

66. Answer (4)


3° alcohols are more reactive with HBr.

69. Answer (3)

Riemer Tiemann reaction

C H OH + CCl6 5 4

NaOHCOOH

OH

70. Answer (3)

Oxidation of ketone by peroxide compound.

71. Answer (3)

72. Answer (1)

CC

CH 3

Ph

H

CH 3

will show geometrical isomerism.

73. Answer (1)

-D-glucose and -D-glucose are anomer.

74. Answer (3)

Fructose is sweetest sugar.

75. Answer (1)

76. Answer (3)

Less substituted carbon atoms are more reactive.

77. Answer (1)


7/18


7/9

78. Answer (2)

Less electron density, less withdrawing group havemore bond length.

79. Answer (2)

(CH COO) Ca3 2dry dist.

CH COCH + CaCO3 3 3

80. Answer (3)

Formic acid gives Tollen’s test.

81. Answer (4)

82. Answer (3)

83. Answer (4)

NO2

NHOHvery dil. acid

91. Answer (4)

Temperature, precipitation and solar radiation play arole in formation of biome.

92. Answer (3)

Ecological Niche represents functional role andstatus of a species in environment.

93. Answer (2)

Regulators have fixed osmotic concentrations of body fluids.

94. Answer (3)

Grassland and tundra are treeless.

95. Answer (2)Warm-blooded animals have larger body size in coldclimate than in hotter areas.

96. Answer (2)

97. Answer (3)

Absence of competitively superior species expandsthe distributional range of a species.

98. Answer (1)

Sexual deceit is shown by Ophrys for pollination byColpa .


Age pyramid decides population growth.

101. Answer (2)

Show interactions in a community.

102. Answer (1)

Desert lizards show behavioural responses.

[ BIOLOGY ]

84. Answer (2)

85. Answer (4)

Poor leaving group present at acid derivatives areless reactive.

86. Answer (3)

87. Answer (2)

88. Answer (2)

89. Answer (1)

Terylene has ester linkage.

90. Answer (3)

Morphine is analgesic in nature.

103. Answer (3)

Darwinian fitness is high r-value.

104. Answer (3)

Anatomical features are simple.

105. Answer (3)

In commensalism one is benefitted and the other remains unaffected.

106. Answer (2)

Primary productivity is related to autotrophs.

107. Answer (1)

Fragmentation is breakdown of detritus into smaller

particles.108. Answer (3)

Pyramids show trophic levels.

109. Answer (3)

Decomposers do mineral recycling.

110. Answer (4)

Top consumer.

111. Answer (2)

Inverted or spindle shaped.

112. Answer (3)

Natality does population growth.

113. Answer (2)

114. Answer (2)

GFC is the major conduit in aquatic ecosystem.

115. Answer (3)

Climax community is in near equilibrium withenvironment.


8/18


8/9

116. Answer (2)

Reservoir of phosphorus is in Earth’s crust.

117. Answer (3)

Species richness increases with increasing area.

118. Answer (4)

Conserving and utilising the diversity.

119. Answer (3)

Bioprospecting

120. Answer (3)

121. Answer (4)

High inter-specific competition is seen at biodiversityhot spots.

122. Answer (1)

Habitat destruction

123. Answer (1)

Biosphere reserves124. Answer (3)

Support other species of community.

125. Answer (4)

It relates to what we owe to millions of plants.

126. Answer (2)

Catalytic convertor needs unleaded petrol.

127. Answer (3)

Dobson unit measures ozone thickness.

128. Answer (1)BOD indicates water pollution.

129. Answer (2)

Photochemical smog is made of PAN, O 3 and NO X .

130. Answer (4)

UV rays are mutagen.

131. Answer (2)

Ecosan toilets are Green solutions.

132. Answer (3)

Natural ageing of lakes is Eutrophication.

133. Answer (2)

Infra-red radiations (Long wave radiations)

134. Answer (2)

Thermal pollution is due to heat.

135. Answer (4)

Trees hold a lot of carbon in their biomass.

136. Answer (3)

Methamphetamine is a stimulant. Jimson’s weed isdatura, a hallucinogen.

137. Answer (2)

CO content is increased leading to formation of carboxyhaemoglobin.

138. Answer (4)

It is poppy plant from which morphine is obtained.

139. Answer (4)

140. Answer (1)

141. Answer (1)

Pap smear and mammography are also tests to detectcancer but do not involve removing tissue by scalpel.

142. Answer (2)

Cancer occurs when DNA of a cell has beentransformed and normal cell cycle cannot be regulated.

143. Answer (3)

144. Answer (4)

Alcohol suppresses ADH release

145. Answer (2)

Larger the surface area, more would be the absorption.

146. Answer (3)

Vincristime and taxol are mitotic poisons.

147. Answer (1)

148. Answer (3)

The viral genome can be detected by PCR.

149. Answer (1)

Ionizing radiations can cause mutations during division.Neurons do not divide.

150. Answer (4)

LSD from Clavicaps Purpurea (Ergot Ascomycetes)and Psilocybin from Psilocybe mexicana (Mexican

mushroom – Agaricaceas)

151. Answer (2)

152. Answer (3)

Sperm production decreases.

153. Answer (1)

154. Answer (2)


9/18


9/9

155. Answer (4)

Option (4) is inter specific hybridisation while remainingthree are cross-breeding examples.

156. Answer (4)

157. Answer (3)

Micropropagation is part of plant tissue culture.

158. Answer (2)

159. Answer (2)

Ethidum bromide intercalates in between DNA strands.

160. Answer (3)

This method is suitable for plants.

161. Answer (2)

Insertional inactivation for tetracycline resistance gene.

162. Answer (2)

PCR required DNA, of interest, DNA polymerase,dNTPs, Mg 2+ and primers.

163. Answer (2)

164. Answer (4)

165. Answer (3)

Brazzein is a protein which is 2000 times sweeter than the sugar.

166. Answer (1)

167. Answer (2)

168. Answer (2)

169. Answer (2)

Most common type of haemophilia is due to absenceof factor VIII.

170. Answer (4)

Lack of -1-antitrypsin causes emphysema insmokers.

171. Answer (3)

SV 40 and papillomavirus are used to transform animalcells and geminivirus for plant cells.

172. Answer (4)

YAC can carry a load of 1Mbp.

173. Answer (1)

174. Answer (3)

Gene therapy was given in the year 1990.

175. Answer (3)

176. Answer (4)

For blue/white screening the lac Z gene is insertionallyinactivated.

177. Answer (2)

178. Answer (2)

Cotton boll worm is Helicoperpa armigera (Order Lepidoptera)

179. Answer (2)Other three options are also herbicides but with diferentmode of action.

180. Answer (4)


10/18

Test - 7 (Code B) (Answers & Hints) All India Aakash Test Series for Medical-2016

1/9

1. (1)2. (1)

3. (3)

4. (3)

5. (4)

6. (3)

7. (2)

8. (4)

9. (1)

10. (1)

11. (3)

12. (3)

13. (3)

14. (1)

15. (4)

16. (4)

17. (4)

18. (1)

19. (3)

20. (4)21. (1)

22. (4)

23. (3)

24. (1)

25. (2)

26. (2)

27. (4)

28. (2)

29. (1)

30. (2)31. (1)

32. (1)

33. (2)

34. (4)

35. (4)

36. (4)

37. (3)38. (3)

39. (3)

40. (3)

41. (4)

42. (4)

43. (2)

44. (3)

45. (2)

46. (1)

47. (3)

48. (4)

49. (4)

50. (1)

51. (2)

52. (4)

53. (2)

54. (1)

55. (2)

56. (3)

57. (4)

58. (4)

59. (3)

60. (1)

61. (1)

62. (1)

63. (3)

64. (3)

65. (1)

66. (1)67. (1)

68. (3)

69. (1)

70. (4)

71. (4)

72. (2)

ANSWERS

TEST - 7 (Code-B)

All India Aakash Test Series for Medical-2016

Test Date : 14-02-2016

73. (2)74. (3)

75. (4)

76. (4)

77. (4)

78. (2)

79. (1)

80. (1)

81. (3)

82. (4)

83. (4)

84. (4)

85. (3)

86. (1)

87. (3)

88. (4)

89. (1)

90. (4)

91. (2)

92. (4)

93. (4)

94. (1)

95. (4)

96. (2)

97. (4)

98. (3)

99. (1)

100. (4)

101. (2)

102. (1)103. (3)

104. (3)

105. (2)

106. (1)

107. (1)

108. (4)

109. (1)110. (4)

111. (1)

112. (4)

113. (2)

114. (1)

115. (4)

116. (2)

117. (1)

118. (1)

119. (3)

120. (4)

121. (1)

122. (1)

123. (1)

124. (3)

125. (4)

126. (1)

127. (1)

128. (3)

129. (1)

130. (4)

131. (4)

132. (1)

133. (4)

134. (1)

135. (4)

136. (4)

137. (4)

138. (4)139. (4)

140. (2)

141. (1)

142. (1)

143. (3)

144. (2)

145. (1)146. (2)

147. (4)

148. (4)

149. (4)

150. (3)

151. (1)

152. (2)

153. (2)

154. (4)

155. (4)

156. (1)

157. (2)

158. (4)

159. (1)

160. (2)

161. (2)

162. (4)

163. (3)

164. (1)

165. (4)

166. (4)

167. (3)

168. (1)

169. (3)

170. (1)

171. (4)

172. (2)

173. (1)

174. (4)175. (3)

176. (3)

177. (2)

178. (2)

179. (2)

180. (1)

click here for code-A solution


11/18

All India Aakash Test Series for Medical-2016 Test - 7 (Code B) (Answers & Hints)

2/9

Hints to Selected Questions[ PHYSICS]

1. Answer (1)

2. Answer (1)

1RP V

1

20 1

80 4

R

R

R 1 = 2 R

3. Answer (3)

0 02

1 0 0 0

V f h

h u u f

= 2 12000 2 1000

2 1

1 50100 cm

1000 1000h h

= 5 cm

4. Answer (3)

5. Answer (4)

X

24 cm15 cms

1 1 1

24 15 10 x

1 1 1 5

24 10 15 150 x

x + 24 = 30

x = 6 cm

6. Answer (3)

1 1 1

v u f

1 1 1 u f

v f u uf

1uf f

v f u f

u

7. Answer (2)

sin x d n

= 10 × 6.2 × 10 –6 m

= 6.2 × 10 –5 m

8. Answer (4)

1

d

9. Answer (1)

For using wavelength

2 1

2

n Dy

d

2 12 2

n Dd

d

2 2 2 2

, , ...2 1 3 5 7

d d d d

n D D D D

10. Answer (1)

11. Answer (3)

12. Answer (3)

1D D

t d d

1t

1t

=9

7

600 10 m1

12 10 m

= 0.5 + 1 = 1.5

13. Answer (3)

Let u = x

v = y

1 1 1

x y f

1 1 1 x y f


12/18


3/9

differential w.r.t. t

2 22 2 0dx dy x y dt dt

2 22 2

i m obV v y x

V im

= 2

2

ob

im

V y

x V

=1 1 1 2

x y f R

2

22

R v

x R ⇒

=2

1 x x

y R

21 x x

y R

2 x R R

14. Answer (1)

cmu

20 cmv

1 1 2

v f

= 1 2

20 f

1 2

1f R

⇒

1 2

1.5 140 R

⇒

=0.5 2 1

R R

R = 40 cm

15. Answer (4)

dapp =

d ∑

1 2

1 2

...d d

4 6

4 33 2

⇒

= 3 + 4 = 7 cm

16. Answer (4)

17. Answer (4)

NOR gate

X Y Z

. .z y x x A B = NOT + OR

= NOR

18. Answer (1)

19. Answer (3)

1

1515 mA

1 kk

I

5 10.02A

250 50I ⇒

= 20 mAI D = I – I 1k= 20 mA – 15 mA = 5 mA

20. Answer (4)

50.5A

10

21. Answer (1)

In forward condition PD across diode 0

22. Answer (4)

23. Answer (3)

Z = (w + x ) ( w + y ) = w 2 + wy + wx + xy

= w 2 + w ( x + y ) + xy

= w [1 + x + y ] + xy

= w + xy

24. Answer (1)

100 = o o oin i i

I V R

I V R

100 =o i

i o

V R

V R

100 = 1 k1m V 10 koV

V o =100 1 mV 10 k

1 k

= 1000 mV

= 1 V

25. Answer (2)


13/18


4/9

26. Answer (2)2

2

2 4

2 216

pE

pE

21654

4

E

E

54

E E

27. Answer (4)

0 01

64 2

n

N N

1 1

64 2

n

n = 6

6

2

T

t

6 6 2h2

t T = 12 h

28. Answer (2)

9 1

16 2

t

T

2

0

1

2

t

T N

N

2

0

1

2

t T N

N

=9

16

0

3

4

N

N

29. Answer (1)

2

h

30. Answer (2)1

E

31. Answer (1)

E 1 = E 2 + E 3

1 2 3

1 1 1

32. Answer (1)

E max = 13.6 eV

E min = 13.6 21 3

1 13.62 4

max

min

4

3

E

E

33. Answer (2)

E = hf =hc

1 2

hc hc

E E E

34. Answer (4)

ev =hc

w

v =1hc w

e e

slopehc

e

35. Answer (4)

H discharge tube means max hv = 13.6 eV

w = 4.2 V

So 13.6 4.2 9.4 VV

So required voltage is – 9.4V

36. Answer (4)

y = constant

37. Answer (3)

max

24

0.5

d n

n = 4 × 4 = 16


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38. Answer (3)

22

t

97550 10 100 mm = 1 10 m

2 2 4 4 1.38

39. Answer (3)

10 y

d sin = n

y d nD

n Dy

d

2

d n D

d

n =2

2

d

D

40. Answer (3)

Since image is real

u + v = 4f

20 + 20 = 4 f

40 = 4 f

f = 10 cm.

41. Answer (4)

f 1 = f 2 = f 3 = f 4 = 2f

=1 2 3 4

1 1 1 1 1

eqf f f f f

1 1 1 1 1

2 2 2 2

eqf f f f f

2

4 2 eq

f f f

42. Answer (4)

sin i e =1

i e = 45°

Total angle = 2 i c = 90°

43. Answer (2)

x =1

1t

=2 5

5 13 3

There will be two shift

x =10

cm3

Position from object10

10 5 153

10 10 90 10 8015 15 30 cm

3 3 3 3 ⇒ ⇒

44. Answer (3)

r + r' = A

r + r' = 60°

r + 10 + t 2 = 60°

r = 60 – (10 + t 2 )

r = 50 – t 2

45. Answer (2)

u =

v = 2R

1 12n nR R

1

2

n n

R R

n = 2n – 2

n = 2


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46. Answer (1)

Morphine is analgesic in nature.

47. Answer (3)

Terylene has ester linkage.48. Answer (4)

49. Answer (4)

50. Answer (1)

51. Answer (2)

Poor leaving group present at acid derivatives areless reactive.

52. Answer (4)

53. Answer (2)

NO2

NHOHvery dil. acid

54. Answer (1)

55. Answer (2)

56. Answer (3)

Formic acid gives Tollen’s test.

57. Answer (4)

(CH COO) Ca3 2dry dist.

CH COCH + CaCO3 3 3

58. Answer (4)

Less electron density, less withdrawing group havemore bond length.

59. Answer (3)

60. Answer (1)

Less substituted carbon atoms are more reactive.

61. Answer (1)

62. Answer (1)

Fructose is sweetest sugar.

63. Answer (3)

-D-glucose and -D-glucose are anomer.

[ CHEMISTRY]

64. Answer (3)

CC

CH 3

Ph

H

CH 3

will show geometrical isomerism.

65. Answer (1)

66. Answer (1)

Oxidation of ketone by peroxide compound.

67. Answer (1)

Riemer Tiemann reaction

C H OH + CCl6 5 4NaOH

COOH

OH

68. Answer (3)

3° alcohols are more reactive with HBr.

69. Answer (1)

70. Answer (4)

71. Answer (4)

72. Answer (2)

–OH and –SH have sp3

hybridization and have bentarrangement.

73. Answer (2)

74. Answer (3)

75. Answer (4)

Br 2 gives anti addition product

76. Answer (4)

77. Answer (4)

78. Answer (2)

More stable carbocations are more reactive for S Nreaction.

79. Answer (1)

Less stable alkyl halide gives S N 2 reaction.

80. Answer (1)


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91. Answer (2)

Trees hold a lot of carbon in their biomass.

92. Answer (4)

Thermal pollution is due to heat.

93. Answer (4)

Infra-red radiations (Long wave radiations)

94. Answer (1)

Natural ageing of lakes is Eutrophication.

95. Answer (4)

Ecosan toilets are Green solutions.

96. Answer (2)

UV rays are mutagen.

97. Answer (4)

Photochemical smog is made of PAN, O 3 and NO X .

98. Answer (3)

BOD indicates water pollution.

99. Answer (1)

Dobson unit measures ozone thickness.

100. Answer (4)

Catalytic convertor needs unleaded petrol.

101. Answer (2)It relates to what we owe to millions of plants.

102. Answer (1)

Support other species of community.

103. Answer (3)

Biosphere reserves

[ BIOLOGY ]104. Answer (3)

Habitat destruction

105. Answer (2)

High inter-specific competition is seen at biodiversity

hot spots.

106. Answer (1)

107. Answer (1)

Bioprospecting

108. Answer (4)

Conserving and utilising the diversity.

109. Answer (1)

Species richness increases with increasing area.

110. Answer (4)

Reservoir of phosphorus is in Earth’s crust.

111. Answer (1)

Climax community is in near equilibrium withenvironment.

112. Answer (4)

GFC is the major conduit in aquatic ecosystem.

113. Answer (2)

114. Answer (1)Natality does population growth.

115. Answer (4)

Inverted or spindle shaped.

116. Answer (2)

Top consumer.

81. Answer (3)

82. Answer (4)

Glycerol reacts with KHSO 4 to form acrolein.

83. Answer (4)

84. Answer (4)

Libermann nitroso test used to identify 2° amine.85. Answer (3)

86. Answer (1)

87. Answer (3)

Nucleophile which form strong conjugate acid isbetter leaving group.

88. Answer (4)

89. Answer (1)

Chromyl chloride used in etards reaction90. Answer (4)

RMgX reacts with acidic hydrogen to form alkane.


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117. Answer (1)

Decomposers do mineral recycling.

118. Answer (1)

Pyramids show trophic levels.

119. Answer (3)

Fragmentation is breakdown of detritus into smaller particles.

120. Answer (4)

Primary productivity is related to autotrophs.

121. Answer (1)

In commensalism one is benefitted and the other remains unaffected.

122. Answer (1)

Anatomical features are simple.

123. Answer (1)Darwinian fitness is high r-value.

124. Answer (3)

Desert lizards show behavioural responses.

125. Answer (4)

Show interactions in a community.

126. Answer (1)

Age pyramid decides population growth.

127. Answer (1)

128. Answer (3)

Sexual deceit is shown by Ophrys for pollination byColpa .

129. Answer (1)

Absence of competitively superior species expandsthe distributional range of a species.

130. Answer (4)

131. Answer (4)

Warm-blooded animals have larger body size in coldclimate than in hotter areas.

132. Answer (1)

Grassland and tundra are treeless.

133. Answer (4)

Regulators have fixed osmotic concentrations of body fluids.

134. Answer (1)

Ecological Niche represents functional role andstatus of a species in environment.

135. Answer (4)

Temperature, precipitation and solar radiation play arole in formation of biome.

136. Answer (4)

137. Answer (4)

Other three options are also herbicides but with diferentmode of action.

138. Answer (4)

Cotton boll worm is Helicoperpa armigera (Order Lepidoptera)

139. Answer (4)

140. Answer (2)

For blue/white screening the lac Z gene is insertionallyinactivated.

141. Answer (1)

142. Answer (1)

Gene therapy was given in the year 1990.

143. Answer (3)

144. Answer (2)

YAC can carry a load of 1Mbp.

145. Answer (1)

SV 40 and papillomavirus are used to transform animalcells and geminivirus for plant cells.

146. Answer (2)

Lack of -1-antitrypsin causes emphysema insmokers.

147. Answer (4)

Most common type of haemophilia is due to absenceof factor VIII.

148. Answer (4)

149. Answer (4)

150. Answer (3)

151. Answer (1)

Brazzein is a protein which is 2000 times sweeter than the sugar.

152. Answer (2)


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153. Answer (2)

154. Answer (4)

PCR required DNA, of interest, DNA polymerase,dNTPs, Mg 2+ and primers.

155. Answer (4)

Insertional inactivation for tetracycline resistance gene.

156. Answer (1)

This method is suitable for plants.

157. Answer (2)

Ethidum bromide intercalates in between DNA strands.

158. Answer (4)

159. Answer (1)

Micropropagation is part of plant tissue culture.

160. Answer (2)

161. Answer (2)

Option (2) is inter specific hybridisation while remainingthree are cross-breeding examples.

162. Answer (4)

163. Answer (3)

164. Answer (1)

Sperm production decreases.165. Answer (4)

166. Answer (4)

LSD from Clavicaps Purpurea (Ergot Ascomycetes)and Psilocybin from Psilocybe mexicana (Mexicanmushroom – Agaricaceas)

167. Answer (3)

Ionizing radiations can cause mutations during division.Neurons do not divide.

168. Answer (1)

The viral genome can be detected by PCR.

169. Answer (3)

170. Answer (1)

Vincristime and taxol are mitotic poisons.

171. Answer (4)

Larger the surface area, more would be the absorption.

172. Answer (2)

Alcohol suppresses ADH release

173. Answer (1)

174. Answer (4)

Cancer occurs when DNA of a cell has beentransformed and normal cell cycle cannot be regulated.

175. Answer (3)

Pap smear and mammography are also tests to detectcancer but do not involve removing tissue by scalpel.

176. Answer (3)

177. Answer (2)

178. Answer (2)

It is poppy plant from which morphine is obtained.

179. Answer (2)CO content is increased leading to formation of carboxyhaemoglobin.

180. Answer (1)

Methamphetamine is a stimulant. Jimson’s weed isdatura, a hallucinogen.

solutions aiats medical-2016 test-07 (code-a & b) 14-02-2016

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