soil mechanics i 3 – water in soils - univerzita karlovalabmz1.natur.cuni.cz/~bhc/s/sm1/sm1_3_ ·...
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SM1_3 November 28, 2017 1
Soil Mechanics I
3 – Water in Soils
1. Capillarity, swelling
2. Seepage
3. Measurement of hydraulic conductivity
4. Effective stress in the ground
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WATER IN SOIL - affects soil behaviour (e.g., consistency, consistency limits)
Adsorbed water
Mechanisms of water adsorption to clay surfaces: hydrogen bonds, ion hydration, osmosis, dipole attraction...
The effects neglected in the basic SM
'Free' water
Effect of gravity - effective stress, capillarity, seepage
Influence of Water - Basics
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WATER IN SOILS
[2]
Influence of Water - Basics
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Shrinking
w > wS – saturated soil (?)
Suppose the Terzaghi principle of effective stresses valid and u < 0:
for hC= 50 m → u = - 500 kPa → σ' = 500 kPa (+ σ)
Swelling
Due to
mineralogy (smectites)
partial saturation
unloading
Disintegration of “cohesive” soil on submerging in water
elimination of capillary forces
elimination of cementation
Capillarity
Influence of Water - Basics
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GT Practice – the role of water
Hydrostatic pressure
basis for computing effective stresses (only with no seepage, i.e. no hydraulic gradients)
Steady state seepage
the pore pressure is generally different from the hydrostatic pressure
the pressure heads does not have to correspond to phreatic water table
Laplace equation – a flow net
Consolidation
dissipation of excess pore pressures
Influence of Water - Basics
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Steady flow – H. DARCY (1856)
q = A k i
q = flow quantity (volume per time unit)
i = hydraulic gradient i = - Δh/Δx
v = k i
k = hydraulic conductivity (coefficient of permeability; coefficient of filtration)
Steady Flow – Darcy's Law
v = seepage velocity
Real velocity vreal
= q / (n A) = v / n
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Permeability Κ: a property of the porous medium, independent of the permeating fluid
Κ = k μ / γ [m2]
Κ = permeability
k = hydraulic conductivity, i.e. coefficient of Darcy's law
μ = dynamic viscosity [N×s×m-2]
(μ =kinematic viscosity × ρ)
γ = unit weight of permeating fluid
Steady Flow – Darcy's Law
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Re = v d
ef ρ
w / μ
v = seepage velocity
μ = dynamic viscosity [N×s×m-2]
Change from laminar to turbulent flow at critical velocityv
cr = R
e cr μ /(ρ
w d
ef)
Initial gradient
Steady Flow – Darcy's Law
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Hydraulic conductivity (≡ filtration coefficient ≡ coefficient of permeability)
Constant Head Permeameter
Q = A v t; Q = volume of water; v = discharge velocity; t = time
v = k i = k h / L
k = Q L / (h A t)
At low permeability (h. conductivity: k < 10-6 ms-1), the device cannot be used – insufficient readability / accuracy
→ the set-up needs to be refined:
closed system for discharge water, or
triaxial apparatus / flexible wall permeameter (+avoiding preferential flow at the rigid wall)
Another alternative – Falling Head Permeameter (accuracy not good though)
Measurement of Hydraulic Conductivity
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Hydraulic conductivity (≡ filtration coefficient ≡ coefficient of permeability)
Falling Head Permeameter
q in
= - a dh/dt
q out
= A k i
q in
= q out
- a dh/dt = A k h / L
- a ∫dh / h = k A / L ∫ dt
- a (ln h2 – ln h
1)= k A (t
2-t
1) / L
a (ln h1 – ln h
2) = k A (t
2-t
1) / L
k = a L ln(h1/h
2) / (A Δt)
Measurement of Hydraulic Conductivity
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Measurement of Hydraulic Conductivity – Lab Class
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Hydraulic conductivity (≡ filtration coefficient ≡ permeability coefficient)
In situ
For example
[ → k = q / (2π D H) ln(R / r) ]
Indirect determination
For example FOR SANDS: Hazen k [ms-1] = 0,01D10
2 [mm]
Measurement of Hydraulic Conductivity
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Typical values
Gravel 10-1 to 10-3 ms-1
Sand 10-2 to 10-4 ms-1
Fine Sand 10-5 ms-1
Silt 10-6 ms-1
Sandy Loam 10-6 to 10-8 ms-1
Clay <10-8 ms-1
Measurement of Hydraulic Conductivity
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Equation for Seepage
isotropy: kx=k
y=k
z
Δh = 0
δ2h / δx2 + δ2h / δy2 + δ2h / δz2 = 0
Seepage
Hydraulic head does not have to correspond with the phreatic surface ← seepage
.....the actual height in the piezometer ← definition of equipotential lines
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A flow net in 2D
saturated soil, GWT at the surface, steady percolation
Seepage
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A flow net in 2D
(long dam / embankment)
Seepage
Hydraulic head does not have to correspond with the phreatic surface ← seepage
.....the actual height in the piezometer ← definition of equipotential lines
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Influence of seeping water on soil grains: Seepage Forces - DRAG
v = k i
Loss of hydraulic head due to drag effect of water
Δp = γ
w Δh
Δ S = Δp × area = γw Δh Δy Δz =
= γw Δh Δy Δz Δx/Δx =
= γw i (Δx Δy Δz) =
= γw i ΔV
Force acting on the soil skeleton: S = γw i V
Force acting on the soil skeleton in the unit volume: p = γ
w i
Seepage
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Influence of seeping water on soil grains: Seepage Forces - DRAG
Bernoulli equation:
γw (z + u/γ
w + v2/(2g) + h
s) = const
v2/(2g) can be neglected (v small)
Loss of energy between two cross section (distance s):
ΔE = γw Δh
s = (z
2 +u
2/γ
w - (z
1 +u
1/γ
w))
ΔE / Δs = γw Δh
s / Δs
= γ
w i
The loss of energy: p = γw i
Seepage
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Flow net
Boundary conditions:(constant) water levels = equipotentials (GA; CF)impermeable boundaries = flow lines (AB; BC; DE; detto axis of symmetry EF)
Upward seepage → possibility of hydraulic failure - „boiling sand“; „piping“
[1])
Seepage
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hcr ... critical height, i.e. height at liquefaction
neglecting friction on sides; cross section area A
thrust = water pressure on A: u A= hcr γ
w A
equilibrium:
hcr γ
w A = A z γ
sat ( γ
sat ≡ γ)
hcr = z γ / γ
w
icr = (h
cr – z) / z = (z γ / γ
w – z) / z = γ / γ
w – 1 = (γ - γ
w)/γ
w
icr = (γ – γ
w) / γ
w
Seepage
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What is the necessary embedment depth t of the sheet pile wall?
icr = (γ – γ
w) / γ
w
icr ≈ 1
i= (H + h) / (h + t + t) < 1 = icr
H < 2 t
t > ½ H
Seepage
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Capillary height hC
Downward Force: W= ρwg V = ρ
wg h
C π d2 / 4
Upward Force: π d T cosα
“surface tension of water” T = 7×10-5kNm-1
Equilibrium:
ρw g h
C π d2 / 4 = π d T cosα
hC
= 4 T cosα / (ρw
g d)
clean water vs glass → α = 0
hC
= 4 T / (ρw
g d) = 4 T / ( γw d)
hC
[m] ≈ 3×10-5 / (d [m]) [m]
For example: d = 1μm → hC = 30m
Capillarity
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Capillary height hC
depends on PORE SIZE
Theoretical values for soils
(α = 0 a capillary tube of constant diameter d)
silt d ≈ 1mm → hC = 30 mm
fine silt d ≈ 1μm → hC = 30 m
clay d ≈ 10nm →hC = 3 km
Realistic values for soils
sand hC = 0,03 – 0,1 m
loamy sand hC = 0,5 – 2 m
loam (silt) hC = 2 – 5 ( – 10) m
clay hC = tens of metres
Capillarity
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In Capillary Fringe – soil is saturated
Principle of effective stress is valid, u < 0
hC= 50 m → u = - 500 kPa → σ' = σ + 500 kPa
Unsaturated Zone
Three Phase Medium – Terzaghi's principle QUESTIONABLE (the expression for pore pressure not clear to date?)
ua- u
w= T
(1/r
m-1/r) ”capillary suction”
r is the radius of meniscus
Bishop:
u = χ uw+ (1 - χ) u
a
σ' = σ – (χ uw+ (1 - χ) u
a)
σ' = σ – ua + χ (u
a - u
w)
χ function of S, way of loading...
Very approximate assumption: χ = Sr
Capillarity
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Capillary water in sand – unconfined compression of wet sand
Assumed: “Bishop's Effective Stress”
σ' = σ – (χ uw+(1-χ) u
a)
Pore Pressure u = χ uw+ (1 - χ) u
a
for χ = S
u = S uw+ (1 - S) u
a
If the air phase continuous (at w = 0.1 should be) then
→ pore pressure u = S uw
→ capillary suction s = - uw
Procedure:
M.C. for total stress; Failure envelope; Determination of capillary cohesion; M.C. for effective stress. From its shift the pore pressure and suction in the sand castle (assuming the Bishop's stress and χ = S)
Capillarity – Lab Class
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Sand without capillary water (dry or saturated)
Angle of repose:
continuous slope failure – ideal plasticity “critical state”
→ τmax
= σ' tg φcr'
Equilibrium:
T = W sin α = τmax
× 1 = W cos α × tg φcr
→ tg α = tg φcr
→ α = φcr
Capillarity – Lab Class
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σv
= ∑ (hi γ
i)
u = hwγ
w = (z - z
w) γ
w
σv' = σ
v – u = ∑(h
i γ
i) – h
wγ
w
detto for increments
Effective vertical stress in the ground
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Δσv' = Δσ
v – Δu
Δσv
> 0
Δu = 0 (drained event)
Δσv' = Δσ
v> 0
→ increase in effective stress
→ deformation
→ settlement under loaded area
Effective vertical stress in the ground
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Δσv' = Δσ
v – Δu
Lowering of GWT – increase of effective stress:
before:1u = hw
γw 1σ
v= h
γ
sat
after: 2u=(hw-Δh
w) γ
w 1σ
v= h
γ
sat
(soil remains saturated - capillarity)
Δu = 2u – 1u = - Δhw
γw
Δσv
= 0
Δσv' = - Δu > 0
→ increase of effective stress
→ deformation
→ settlement on lowering GWT
Effective vertical stress in the ground
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← increase in effective stress
Effective vertical stress in the ground
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σ = 18 × 1 = 18 kPau = 10 × 1 = 10 kPaσ' = 18 – 10 = 8 kPa
σ = 18 × 1 = 18 kPau = 10 × 0,5 = 5 kPaσ' = 18 – 5 = 13 kPa
σ = 18 × 1 + 10 × 100 = 1018 kPau = 10 × 101 = 1010 kPaσ' = 1018 – 1010 = 8 kPa
Effective vertical stress in the ground
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http://labmz1.natur.cuni.cz/~bhc/s/sm1/
Atkinson, J.H. (2007) The mechanics of soils and foundations. 2nd ed. Taylor & Francis.
Further reading:
Wood, D.M. (1990) Soil behaviour and critical state soil mechanics. Cambridge Univ.Press.
Mitchell, J.K. and Soga, K (2005) Fundamentals of soil behaviour. J Wiley.
Atkinson, J.H: and Bransby, P.L. (1978) The mechanics of soils. McGraw-Hill, ISBN 0-07-084077-2.
Bolton, M. (1979) A guide to soil mechanics. Macmillan Press, ISBN 0-33318931-0.
Craig, R.F. (2004) Soil mechanics. Spon Press.
Holtz, R.D. and Kovacs, E.D. (1981) An introduction to geotechnical engineering, Prentice-Hall, ISBN 0-13-484394-0
Feda, J. (1982) Mechanics of particulate materials, Academia-Elsevier.)
Literature for SM1
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[1] Atkinson, J.H. (2007) The mechanics of soils and foundations. 2nd ed. Taylor & Francis.
[2] Santamarina, J (2003) in Mitchel, J.K. and Soga, K (2005) Fundamentals of soil behaviour
References – used figures etc.