sev 454-design project 1.pdf
TRANSCRIPT
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SCHOOL OF SCIENCE AND TECHNOLOGY SEV454 - ADVANCED STRUCTURAL DESIGN
Design Project 1
Student Name: Busiku Silenga
Student ID: 210037589
Supervisor Name: Dr Riyadh Al-Ameri
Submission Date: 28th April 2014
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Contents
Chapter 1.Group Work .......................................................................................................................... 5
1.0 INTRODUCTION ................................................................................................................... 5
2.0 - SCOPE .......................................................................................................................................... 5
3.0 DESIGN CONCEPT ...................................................................................................................... 6
4.0 ASSUMPTIONS ........................................................................................................................... 7
5.0 MATERIAL PROPERTIES ............................................................................................................. 8
5.1- General Requirements ............................................................................................................ 8
5.2 - Hardened Concrete ................................................................................................................ 8
5.3 Concrete Mix.......................................................................................................................... 9
5.4 Reinforced steel ..................................................................................................................... 9
6.0 Structural Layouts ................................................................................................................... 10
7.0 LOADS & COMBINATION LOAD CASES ................................................................................... 16
7.1 live loads .............................................................................................................................. 17
7.2 Dead loads ........................................................................................................................... 17
7.3 Area Calculations ................................................................................................................. 18
7.4 Uniformly Distributed loading ............................................................................................ 18
7.5 Combination Loading .......................................................................................................... 20
8.0 BEAM ANALYSIS....................................................................................................................... 22
8.1 Bending moment calculations ............................................................................................ 22
9.0 COLUMN ANALYSIS ................................................................................................................. 24
9.1 Column sizes ........................................................................................................................ 24
9.2 Axial loads ............................................................................................................................ 25
9.3 Bending moment calculations ............................................................................................ 25
APPENDIXES ...................................................................................................................................... 26
Appendix A Slab Areas .............................................................................................................. 26
Appendix B Trial sections .......................................................................................................... 27
Appendix C Combination Load values ...................................................................................... 29
Appendix D Beam moment values............................................................................................ 31
Appendix E Column Moments .................................................................................................. 33
Appendix F Beam Load summary sketches + Moment Diagrams ............................................ 34
Appendix F column moment diagrams ......................................................................................... 42
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Chapter 2.Individual Work .............................................................................................................. 49
1.0 Introduction ............................................................................................................................. 49
2.0 Updates to Group Work .......................................................................................................... 50
2.1 General Requirements ........................................................................................................... 50
2.2 Loading.................................................................................................................................... 51
3.0 Column Design ......................................................................................................................... 52
3.1 Column C1-1 ......................................................................................................................... 52
3.1.1 General Requirements ................................................................................................... 52
3.1.2 Design Loads ........................................................................................................................ 53
3.1.3 Column Reinforcement Requirements ............................................................................... 54
3.1.4 Check If Column Is Short ..................................................................................................... 55
3.1.5 Moment Magnifier .............................................................................................................. 55
3.1.6 Column-Interaction diagram ............................................................................................... 56
3.1.7 Summary .............................................................................................................................. 60
3.2 Column C1-2 ......................................................................................................................... 61
3.2.1 General Requirements ................................................................................................... 61
3.2.2 Design Loads ........................................................................................................................ 62
3.2.3 Column Reinforcement Requirements ............................................................................... 63
3.2.4 Check If Column Is Short ..................................................................................................... 64
3.2.5 Column-Interaction diagram ............................................................................................... 65
3.2.6 Summary .............................................................................................................................. 69
3.3 Column C1-3 ......................................................................................................................... 70
3.3.1 General Requirements ................................................................................................... 70
3.3.2 Design Loads ........................................................................................................................ 71
3.3.3 Column Reinforcement Requirements ............................................................................... 72
3.3.4 Check If Column Is Short ..................................................................................................... 73
3.3.5 Column-Interaction diagram ............................................................................................... 74
3.2.6 Summary .............................................................................................................................. 78
3.4 Column C4 ............................................................................................................................ 79
3.4.1 General Requirements ................................................................................................... 79
3.4.2 Design Loads ........................................................................................................................ 80
3.4.3 Column Reinforcement Requirements ............................................................................... 81
+3.4.4 Check If Column Is Short ................................................................................................... 83
3.4.5 Column-Interaction diagram ............................................................................................... 83
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3.2.6 Summary .............................................................................................................................. 88
3.5 Column C1-5 ......................................................................................................................... 89
3.5.1 General Requirements ................................................................................................... 89
3.5.2 Design Loads ........................................................................................................................ 90
3.5.3 Column Reinforcement Requirements ............................................................................... 91
3.5.4 Check If Column Is Short ..................................................................................................... 92
3.5.5 Moment Magnifier .............................................................................................................. 92
3.5.6 Column-Interaction diagram ............................................................................................... 93
3.1.7 Summary .............................................................................................................................. 96
4.0 REFERENCES ............................................................................................................................. 97
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Chapter 1.Group Work
1.0 INTRODUCTION
A new reinforced concrete six storey building has been proposed in greater city of Geelong area in
Australia and therefore must adhere to Australian Design Standards. The building consists of a car
park in the ground floor, offices in the 1st 4th floors , and a fifth floor for services. Group 10 has
been engaged as the structural design team responsible for the structural design and analysis of
level 5 for the project. A full set of architectural drawings have been made available and will be the
basis of the design.
2.0 - SCOPE
Group 10 is required to perform a full reinforced concrete design and analysis for all the columns,
shear walls for the fifth floor and subsequent footings of this six storey building. There are two
projects overall, with this one being project 1. For design project 1 there will be two submissions to
be made comprising of the initial group submission were a full structural analysis will be performed
to determine the design load actions (axial loads and moments) on all the columns and the second
being an individual submission where each group member will perform a full reinforced concrete
design for five columns on floor 5. It should be noted that the moment for the bottom and top of the
column needs to be calculated, therefore a structural analysis will also be performed for the top
floor to determine moment on the top end of the columns. These two submissions comprise of the
following tasks:
Submission 1 group
Signed cover sheet
Scope and assumptions
Material properties
Loads and combinations
Floor plans and sections
Structural analysis
Submission 2 Individual
Signed cover sheet
Update to group submission
Column design
Reflection on design project
Note: A full set of architectural drawings has been provided. Also provided are detailed
engineering drawings showing dimensions of the floor, beam and column and wall placement
with details of spacings, gridlines and selected elements for simplistic analysis. Placement of
some of the structural members has been relocated ensuring it has no carry on effect on the car
parking, in order to simplify analysis.
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Figure 1.0 Braced columns
3.0 DESIGN CONCEPT
This particular building will be designed according to the framing structural system which consists of
slab on beams, columns, shear wall and isolated footings. The framing will be designed using
reinforced concrete rather than steel. This particular frame is a moment resisting frame which
means that the connections between beams and columns are rigid. Using beams will ensure longer
spans between columns ensuring there are less columns inside the building obstructing views and
space. The framing system will consists of shear walls such as the lift core. Such a design will ensure
that relative sideways between the top and bottom of the column is insignificant, making the
columns braced and more stable. Lateral loads (wind, earthquake) are also carried by combined
shear core/wall and rigid frame action. The concrete slab will behave as a horizontal diaphragm to
distribute the lateral loading to vertical structural elements (shear core/wall, columns). This type of
action can been seen in figure 1.
Design procedure:
1. Outline design process which takes place in idealizing a reinforced concrete structure
2. Simplify standard reinforced concrete building into a number of manageable idealized sub-
structures and structural elements and to construct their load paths
3. Estimate primary design loads on structural elements using appropriate standards and
handbooks.
4. Combine primary design load cases as per design standards to find critical load combinations
that govern design
5. Model building structure and analyse structural elements for design actions such as design
bending moment, shear force and deflections, etc.
6. To design reinforced concrete structural elements for design actions to satisfy strength limit
state criteria and serviceability criteria.
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4.0 ASSUMPTIONS
Building is located in the city of Geelong with a temperate climate condition.
Design life of buildings is assumed to be 50 years{Buildings and other common structures}
The building is located where it is not in contact with sea water and is not subjected to any
sulphate.
No environmental considerations were adopted for the loads and combinations as required
per the brief.
Structure members will be enclosed for its entire service life, except for a brief period during
construction.
Structure members will be waterproofed in wet areas, such as steam rooms, sauna,
bathrooms, etc.
Building was not factored for fire safety.
All dimensions not supplied on the floor plan have been scaled off the plans to gain
necessary information.
Our trial design has considered that the slab thickness will be equal to the top flange
thickness of the beam.
Constant cross sectional dimensions for the continuous beams and slabs have been adopted
for the entire floor, since it will make construction of form work easier.
Constant cross section dimensions of columns have been adopted for the entire height of
the building, since it will make construction of form work easier.
Torsion in our design we have deemed as negligible as the structure will consist of two-way
slab construction which will interlock the structure together therefore any torsion affects
would be considered minimal.
Loads and design actions from the above floor have been considered, which will be used to
determine the moment actions on the top end of the columns.
N40 concrete strength has been adopted for our initial column analysis; however this will be
reviewed at the individual design stage to confirm its adequacy.
D500N reinforcement steel was adopted for our column analysis; however this will be
reviewed at the individual design stage to confirm adequacy.
Any columns that are shifted from their original positions will still have the same design axial
loads provided. It will also be assumed that shifting these columns wont have any effect on
the original design of the building.
Floor system is designed for gravity loads only
The floor above us will have the same structural member layout as level five and also have the same member cross sections.
AS codes will be crossed checked in order to ensure that any specific requirements are taken
into account, after the regulations are verified other factors such as safety, cost and
aesthetics may then be taken into account.
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Table 5.1 Concrete cover
5.0 MATERIAL PROPERTIES
5.1- General Requirements
Exposure classification
Based on our location and building type we select a exposure class of A2, also assuming sealed
tiles for waterproofing {Non- residential, temperate climate [refer to table 4.3 AS3600-2009]}
Cover
Based on selected characteristic strength of our concrete (fc), which is selected as 40MPa, a
exposure class of A2, the required concrete cover will be 20mm {refer to table 4.10.3.2
AS3600.2009}.
5.2 - Hardened Concrete
Values are based on 28 Days of curing. All values are taken from AS3600-2009, unless stated
otherwise.
Property value Reference
Compressive strength fc (MPa) 40 Table 4.4
Minimum Compressive Strength -
Required for Exposure A2
25 Table 4.4
Mean in-situ compressive strength fc.mi (Mpa) 43 Table 3.1.2
Modulus of elasticity Ec *(MPa) 32800 Table 3.1.2
Uniaxial tensile strength fct (MPa) 2.27 Section 3.1.1.3
Coefficient of thermal expansion /oc 10*10-6 Section 3.1.6
Table 5.2- Properties of 40 MPa standard grade concrete
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5.3 Concrete Mix
All properties for the coarse and fine aggregate have been take from Mamlouk M. & Zaniewski J.
(2002) Portland Cement Concrete. In Material for Civil and Construction Engineers, 3rd ed., pp. 246
314. USA: Pearson Education. P17. Unless stated otherwise.
Cement Type I GP Cement
Admixtures N/A
Air entrainer N/A
Coarse aggregate Gravel with crushed particles Bulk oven dry specific gravity = 2.621 Absorption=0.4% Oven dry-rodded density = 1652 kg/m3 Moisture content =1.5%
Fine aggregate Natural sand Bulk oven dry specific gravity = 2.572 Absorption=0.85% Fineness modulus = 2.6 Moisture content =4%
Table 5.3- Properties concrete materials
5.4 Reinforced steel
All values are taken from AS3600 2009, unless stated otherwise
Min Yield strength (Mpa) 500 Table 3.2.1
Shear modulus (MPa) 77000
Youngs modulus (MPa) 200000 Section 3.2.2
Min Tensile Strength (MPa)
675MPa AS4671:2001
Elongation at maximum force
5% AS4671:2001
Coefficient of thermal expansion
12*10^-6/oc
Poisons ratio 0.3
Ductility class N Table 3.2.1
Minimum cover 20mm Table 4.10.3.2
Table 5.4- Properties of reinforced steel
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Table 6.0- Column allocation (Refer to column allocation figure below)
6.0 Structural Layouts
Notes on each drawing:
Fifth Floor (service) Column Layout -
Our structural layout of columns was kept relatively the same from the architectural drawings. There
were a few columns that had to be shifted slightly so structural analysis were easier, as a full
structural analysis is out of our scope for this project. The original design for this project is to have
slab straight on columns however for our concrete design; beams are placed over the columns
followed by the slab on top. This is why some columns were shifted as it made structural analysis
easier.
Fifth Floor (service) Beam Layout-
Lift is to be the structural core of the building, incorporating load bearing walls. The floor connects to the structural core.
Fifth Floor (service) Slab area Layout 2
Some of the rooms contain different superimposed loads. Therefore some of the area slabs were
split into two to acount for different loads. It is not exact but a rough lay out as a full structural
analysis is out of our scope.
Note1: Purple is the colour used to distinguish shear walls
Note2: Many columns will be designed by multiple students, since each student has to design five columns.
Student Column
Busiku Silenga [210037589] Red-C1-1, C1-2, C1-3, C1-5, C4
Saliba Adrian [211261419] Orange- C1-2, C1-3, C1-4, C4, C1-6
Alexander Karl Schmid [210689597] Grey- C1-6, C2-1, C2-2, C1-7, C1-9
Thisara Indula Siriwardena [210057207] Blue- C3-1, C3-2, C3-3, C3-4, C3-5
Syed Adil Amzar Syed Amerrudin [211178813] Brown C2-1, C1-8, C1-9, C1-10, C3-1
Qingyu Zhu [211178878] Green- C1-10, C3-1, C3-2, C1-11, C3-4
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Fifth Floor (service) Column Layout
Scale: 1:150
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Fifth Floor (service) Beam Layout
Scale: 1:150
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Fifth Floor (service) Slab area Layout
Scale: 1:150
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Fifth Floor (service) Slab area Layout 2
Scale: 1:150
A1-1 A1-2
A1-1
A1-1
A1-1
A1-1
A4-2
A1-1
A1-1
A1-1
A1-1
A8-1
A1-1
A1-1
A1-1
A1-1
A4-1
A1-1
A1-1
A1-1
A1-1
A3-1
A1-1
A1-1
A1-1
A1-1
A3-2
A1-1
A1-1
A1-1
A1-1
A2-1
A1-1
A1-1
A1-1
A1-1
A2-2
A1-1
A1-1
A1-1
A1-1 A8-2
A1-1
A7-1
A1-1 A7-2
-2
A8-2
A1-1
A1-1
A31-2
-2
A8-2
A1-1
A1-1
A31-1
-2
A8-2
A1-1
A1-1
A34-1
-1
-2
A31-1
-A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
A34-2
-1
-2
A31-1
-A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
A13-1
A1-1
A1-1
A1-1
A1-1
A13-2
A1-1
A1-1
A1-1
A1-1
A36-2
-2
A8-2
A1-1
A1-1
A36-1
-2
A36.2
-2A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
A39-1
.1
-2
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1 A36.2
-2A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
A39-2
.1
-2
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1 A36.2
-2A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
A37.1
-2
A8-2
A1-1
A1-1
A37-2
-2
A8-2
A1-1
A1-1
A38-1
.1
-2
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1 A36.2
-2A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
A38-2
.1
-2
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1
A36.1A36.2
-2A8-2 A1-1
A1-1 A8-2
A1-1
A1-1 A36.2
-2A8-2 A1-1
A1-1
A8-2
A1-1
A1-1
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Fifth Floor (service) column allocation
Scale: 1:150
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Figure 7.0.1 load paths
Figure 7.0.2 Vertical Load paths in a typical frame
7.0 LOADS & COMBINATION LOAD CASES Assuming only gravity loads are considered for the floor system. The following sketch shows gravity
load paths;
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7.1 live loads [AS1170.1, clause 3.4.1, table 3.1]
Q = 5.0 kN/m2
Note: largest possible live loading is selected due to amenities like the gym located on our floor
{areas with possible physical activities}
Note 2: 5.0 kN/m2 will be used for both level five and roof area.
7.2 Dead loads [AS1170.1, Appendix A, table A1, A2]
a) Superimposed
Ceiling G (kN/m2)
Gypsum plaster 0.13
Flooring G (kN/m2)
Ceramic tiles 0.27
Granite flooring (15mm thick) 0.40
Terrazzo paving (16mm Thick) 0.43
Jacuzzi 3.27
Note: Jacuzzi load 3kN/m2 for water based on 7-10 people Jacuzzi, + 0.27kN/m2 for ceramic tiles
Note 2: The Terrazzo paving will only be used when calculating loadings for the roof.
b) Self weight
Outside walls G (kN/m2)
Double glazed glass curtain wall
25.5 (kN/m3)
Brick masonry (110mm wide) 0.19 per 10mm thickness
Note: it will be assumed that the Brick masonry is not loaded on the roof and will have no effect
.
[AS1170.1, Appendix A, table A1]
Reinforced concrete and assuming 0.5kN/m3 for steel reinforcement 1% by volume
Pw (density) = 24 +0.5 *1 = 24.5KN/m3
G = 24.5 kN/m3
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7.3 Area Calculations
a) Floor distributions
A10 = (6.9*5.6)/2 5.62/4 = 11.48m2
A24 = 42/4 = 4m2
A37 = (6.28*5.6)/2 5.62/4 = 9.74
Note: These calculations are for a few areas only, all area values were calculated the same as
these samples. For a full list of area values refer to Appendix A
b) T Beam cross section
Area cross section = 0.64*0.3 = 0.192m2
Note: the area of the stem was only calculated due as the self-weight of the slab will
account for the flanges. The trial size used for the self-weight is calculated in Appendix B
7.4 Uniformly Distributed loading
Beam 8
a) live Loads
B8-1
B8-2
B8-3
b) Dead loads
i) Superimposed
B8-1
B8-2
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B8-3
(
) (
)
ii)Self - weight
T-Beam
0.192m2 *24.5kN/m3 = 4.70kN/m
Slab
B8-1
B8-2
B8-2
Glass curtain wall
c) Total Loading
B8-1
Q = 8.32 kN/m
G = 0.67kN/m + 4.70kN/m+6.52kN/m + 1.10kN/m = 12.99kN/m
B8-2
Q = 5.00 kN/m
G = 0.40kN/m + 4.70kN/m+3.92kN/m + 1.10kN/m = 10.12kN/m
B8-3
Q = 7.75 kN/m
G = 4.52kN/m + 4.70kN/m+6.08N/m + 1.10kN/m = 16.40kN/m
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7.5 Combination Loading
[AS 1170.0 2002]
Beam 8
a) Ultimate strength
w* = max [1.35G; 1.2G +1.5Q] [Clause 4.2.2]
B8-1
w* = 1.35*12.99kN/m = 17.54kN/m
w* = 1.20*12.99kN/m + 1.5*8.32kN/m = 28.07kN/m
Therefore w1* = 28.07kN/m
B8-2
w* = 1.35*10.12kN/m = 13.66kN/m
w* = 1.20*10.12kN/m + 1.5*5.00kN/m = 19.64kN/m
Therefore w1* = 19.64kN/m
B8-3
w* = 1.35*16.40kN/m = 22.14kN/m
w* = 1.20*16.40kN/m + 1.5*7.75kN/m = 31.31kN/m
Therefore w1* = 31.31kN/m
b) Maximum Serviceability loading
ws = max [G;G+sQ; G+ylQ]
s = 0.7 (table 4.1) [Clause 4.3]
l = 0.4
0.7 gives higher value so calculate for short term.
B8-1
ws = 12.99kN/m
ws = 12.99kN/m + 0.7*8.32kN/m = 18.81kN/m
Therefore ws1 = 18.81kN/m
B8-2
ws = 10.12kN/m
ws = 10.12kN/m + 0.7*5.00kN/m = 13.62kN/m
Therefore ws1 = 13.62kN/m
B8-3
ws = 16.40kN/m
ws = 16.40kN/m + 0.7*7.75kN/m = 21.83kN/m
Therefore ws1 = 21.83kN/m
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In all spans the ultimate strength loads were the highest and should be used to determine bending moments.
Note 1: The fifth floor contained many different rooms all for specific purposes. Each room had
relatively the same superimposed dead loads except the Jacuzzi and walkways which had were larger.
Depending were the areas fell on the architectural plans determined which superimposed load it
carried. Also the outer beams are carrying dead loads from the double glazed glass curtain wall and
brick masonry.
Note 2: These calculations are for Beam 1 only, all other uniformly distributed loading for live and
dead loads for the other beam members and combination loading were all calculated in the same way
with just the values different. All values for uniformly distributed loadings and combination loadings
can be found in Appendix C
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8.0 BEAM ANALYSIS
8.1 Bending moment calculations [AS 3600-2009, clause 6.10]
Moment Calculations may be used from clause 6.10.2.2 provided that clause 6.10.2.1 is satisfied.
a) Negative moments
Beam 8
B8-1
Left
M* = -FdLn2/16 = - 28.07kN/m*(6.1m) 2/16 = -65.28kNm
Middle
M* = FdLn2/11 = 28.07kN/m*(6.1m) 2/11 = 94.81kNm
Right
M* = -FdLn2/10 = - 28.07kN/m*(6.1m)2/10 = -104.45kNm
B8-2
Left
M* = -FdLn2/10 = - 19.65kN/m*(3.7m) 2/10 = -26.9kNm
Middle
M* = FdLn2/16 = 19.65kN/m*(3.7m) 2/16= 16.81kNm
Right
M* = -FdLn2/10 = - 19.65kN/m*(3.7m)2/10 = -26.9kNm
B8-3
Left
M* = -FdLn2/10 = - 31.32kN/m*(6.1m) 2/10 = -116.53kNm
Middle 11
M* = FdLn2/11 = 31.32kN/m*(6.1m) 2/11= 105.93kNm
Right
M* = -FdLn2/16 =- 31.32kN/m*(6.1m) 2/16 = -72.83kNm
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Note1: Only negative moments were needed to be calculated for the design of the columns. Shear
forces were not needed as the design axial loads were supplied to us, as a full structural analysis is out
of the scope for this project.
Note2: It is stated that clause 6.10.2.1 needs to be satisfied to use the simplified method. This is not
for all beam members. The simplified method is still used for all calculations for simplicity as a full
detailed structural analysis is out of our scope.
Note 3: Ln is clear length which is the distance between the faces of the columns.
Note4: The rest of the moment values can be found in Appendix D
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9.0 COLUMN ANALYSIS
9.1 Column sizes
Preliminary sizes were based from the architectural drawings provided and will be subject to review
in individual design of columns.
Column Trial Sizes:
Column 1 with 800mm length and 300mm width
Column 2 with 1000mm length and 300mm width
Column 3 with Diameter of 500mm
Column 4 with Diameter of 600mm
C1
C2
C3
C4
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9.2 Axial loads
Design axial loads are given to us as a full structural analysis is out of our scope and are provided in
the following table.
Column ID Axial Load (kN) Column ID Axial Load (kN)
C1-1 2,954 C2-1 3,643
C1-2 3,509 C2-2 4,094
C1-3 3,412 C3-1 3,080
C1-4 2,645 C3-2 3,216
C1-5 2,915 C3-3 3,366
C1-6 3,313 C3-4 3,249
C1-7 2,768 C3-5 3.039
C1-8 1,877 C4 3,823
C1-9 3,090
C1-10 2,338
C1-11 2,183
9.3 Bending moment calculations
C3-1
X Direction
Right moment B5-1 left moment B5-2
= -138.979 kNm - -80.358kNm = -58.621kNm
Y-direction
Right moment B12-3 left moment BB12-4
= -46.088 kNm - -102.242 kNm = 56.154kNm
Note: All column moment values can be found in Appendix E
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Page 26 of 98
APPENDIXES
Appendix A Slab Areas
Slab Sections Area (m2) Slab Sections Area (m2) Slab Sections Area (m2)
A1 9 A14 7.2 A36-1 0.96
A1-1 7 A15 2.52 A36-2 6.88
A1-2 2 A16 0.9 A37 9.74
A2 11.7 A17 1.26 A37-1 8.16
A2-1 2.9 A18 1.26 A37-2 1.58
A2-2 2.7 A19 6.2 A38 7.84
A3 9 A20 4.9 A38-1 1.41
A3-1 1 A21 6.2 A38-2 6.43
A3-2 8 A22 4 A39 9.74
A4 11.7 A23 7.2 A39-1 2.56
A4-1 2 A24 4 A39-2 7.18
A4-2 9.7 A25 7.2 A40 8.94
A5 6.5 A26 4 A41 7.62
A6 11.09 A27 7.6 A42 8.94
A7 6.5 A28 3.29 A43 7.62
A7-1 3.25 A29 7.6 A44 6.5
A7-2 3.25 A30 3.29 A45 7.58
A8 11.09 A31 6.5 A46 6.5
A8-1 5.545 A31-1 3.25 A47 7.58
A8-2 5.545 A31-2 3.25 A48 5.15
A9 7.84 A32 9.51 A49 5.15
A10 11.48 A33 6.5 A50 5.15
A11 7.84 A34 6.13 A51 3.6
A12 11.48 A34-1 3.75 A52 3.6
A13 6.3 A34-2 2.38 A53 3.06
A13-1 2.52 A35 3.38 A54 2.46
A13-2 3.78 A36 7.84
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Appendix B Trial sections
Foster S.J., Kilpatrick A.E. & Warner R.F (2010) Beams. In Reinforced Concrete Basics, 2nd ed., pp.77-
188. Sydney: Pearson Education Australia. Unless stated otherwise.
bw = 300 [p178]
bef = bw + 0.2a ; a = 0.7L [209]
Designing for longest span, L = 6900mm
bef = 300 + 0.2 x 0.7 x 6900 = 986.00mm
Adopt 1300mm
tf [Appendix C, Table C.3]
Depth of flange = depth of two way slab.
Designing for total deflection, heavy super imposed load and for largest slab;
Ly = 6900mm
Lx = 6000mm
Ly/Lx = 6900/6000 = 1.15 1
Lnx/50 =6000/38 = 157.89mm
Adopt 160mm
D [Appendix C, Table C.1]
Design for heavy superimposed load, one end continuous and for longest span.
D = Ln/9; Ln = clear span = 6100mm
D = 6100/ 9 = 677.77 mm
Adopt 800mm
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Page 28 of 98
Summary
bw 300mm
bef 1300mm
tf 160mm
D 800mm
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Page 29 of 98
Appendix C Combination Load values
Level 5 (services)
Uniform distribution Loading Combination loading
Beam
Total dead load (kN/m)
Total live load (kN/m)
Length (m)
1.35g (kN/m)
1.2g+1.5Q (kN/m)
g (kN/m)
g+Q (kN/m)
Biggest (kN/m)
B1-1 22.208 7.500 6.000 29.981 37.900 22.208 27.458 37.900
B1-2 16.634 6.373 5.100 22.456 29.520 16.634 21.095 29.520
B1-3 18.276 7.000 5.600 24.673 32.431 18.276 23.176 32.431
B2-1 16.220 12.750 6.000 21.897 38.589 16.220 25.145 38.589
B2-2 10.293 12.451 5.100 13.895 31.028 10.293 19.008 31.028
B2-3 16.306 13.429 5.600 22.013 39.710 16.306 25.706 39.710
B3-1 6.518 2.100 6.000 8.800 10.972 6.518 7.988 10.972
B3-2 15.703 12.451 5.100 21.198 37.520 15.703 24.418 37.520
B3-3 19.992 13.429 5.600 26.989 44.133 19.992 29.392 44.133
B4-1 10.176 6.333 6.000 13.738 21.711 10.176 14.609 21.711
B5-1 16.613 13.783 6.000 22.427 40.610 16.613 26.261 40.610
B5-2 15.716 12.745 5.100 21.216 37.977 15.716 24.637 37.977
B5-3 15.480 11.598 5.600 20.898 35.974 15.480 23.599 35.974
B6-1 13.733 10.450 6.000 18.539 32.154 13.733 21.048 32.154
B6-2 12.802 9.373 5.100 17.283 29.421 12.802 19.363 29.421
B7-1 27.358 3.000 6.000 36.933 37.329 27.358 29.458 37.329
B7-2 7.889 2.412 5.100 10.651 13.085 7.889 9.578 13.085
B8-1 12.993 8.319 6.900 17.541 28.070 12.993 18.816 28.070
B8-2 10.126 5.000 4.000 13.670 19.651 10.126 13.626 19.651
B8-3 16.404 7.755 6.280 22.145 31.317 16.404 21.832 31.317
B9-1 8.658 3.301 7.800 11.688 15.341 8.658 10.969 15.341
B9-2 4.704 0.000 1.700 6.350 5.645 4.704 4.704 6.350
B10-1 18.835 16.355 6.900 25.427 47.134 18.835 30.283 47.134
B10-2 14.475 11.125 4.000 19.542 34.058 14.475 22.263 34.058
B10-3 21.376 15.326 6.280 28.858 48.641 21.376 32.104 48.641
B10-4 14.667 11.531 5.520 19.800 34.896 14.667 22.738 34.896
B11-1 16.519 16.514 6.900 22.300 44.594 16.519 28.079 44.594
B12-1 16.930 14.000 4.000 22.856 41.316 16.930 26.730 41.316
B12-2 10.380 6.377 2.650 14.013 22.022 10.380 14.844 22.022
B12-3 16.049 12.975 3.630 21.666 38.721 16.049 25.132 38.721
B12-4 16.600 13.768 5.520 22.410 40.572 16.600 26.237 40.572
B12-5 4.704 0.000 1.350 6.350 5.645 4.704 4.704 6.350
B13-1 15.338 3.600 1.250 20.707 23.806 15.338 17.858 23.806
B14-1 16.247 8.478 6.900 21.933 32.213 16.247 22.181 32.213
B14-2 14.820 3.000 2.100 20.007 22.284 14.820 16.920 22.284
B15-1 12.228 0.000 2.650 16.508 14.674 12.228 12.228 16.508
B15-2 16.143 4.532 3.630 21.794 26.170 16.143 19.316 26.170
B15-3 18.191 6.902 5.520 24.558 32.183 18.191 23.023 32.183
B15-4 12.228 0.000 1.350 16.508 14.674 12.228 12.228 16.508
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Roof
Uniform distribution Loading Combination loading
Beam
Total dead load (kN/m)
Total live load (kN/m)
Length (m)
1.35g (kN/m)
1.2g+1.5Q (kN/m)
g (kN/m)
g+Q (kN/m)
Biggest (kN/m)
B1-1 11.229 7.500 6.000 15.159 24.725 11.229 16.479 24.725
B1-2 9.141 6.373 5.100 12.340 20.528 9.141 13.602 20.528
B1-3 10.794 7.000 5.600 14.572 23.453 10.794 15.694 23.453
B2-1 15.797 12.750 6.000 21.325 38.081 15.797 24.722 38.081
B2-2 10.248 12.451 5.100 13.835 30.974 10.248 18.964 30.974
B2-3 16.387 13.429 5.600 22.122 39.807 16.387 25.787 39.807
B3-1 6.531 2.100 6.000 8.817 10.987 6.531 8.001 10.987
B3-2 15.536 12.451 5.100 20.974 37.320 15.536 24.252 37.320
B3-3 16.387 13.429 5.600 22.122 39.807 16.387 25.787 39.807
B4-1 10.214 6.333 6.000 13.789 21.757 10.214 14.647 21.757
B5-1 16.696 13.783 6.000 22.539 40.710 16.696 26.344 40.710
B5-2 15.792 12.745 5.100 21.320 38.068 15.792 24.714 38.068
B5-3 14.794 11.598 5.600 19.973 35.151 14.794 22.913 35.151
B6-1 13.796 10.450 6.000 18.624 32.230 13.796 21.111 32.230
B6-2 12.858 9.373 5.100 17.358 29.489 12.858 19.419 29.489
B7-1 27.466 3.000 6.000 37.079 37.459 27.466 29.566 37.459
B7-2 7.904 2.412 5.100 10.670 13.102 7.904 9.592 13.102
B8-1 13.043 8.319 6.900 17.608 28.130 13.043 18.866 28.130
B8-2 10.156 5.000 4.000 13.710 19.687 10.156 13.656 19.687
B8-3 12.552 7.755 6.280 16.946 26.695 12.552 17.981 26.695
B9-1 8.678 3.301 7.800 11.715 15.365 8.678 10.989 15.365
B9-2 4.704 0.000 1.700 6.350 5.645 4.704 4.704 6.350
B10-1 18.933 16.355 6.900 25.559 47.252 18.933 30.381 47.252
B10-2 14.383 11.125 4.000 19.417 33.947 14.383 22.170 33.947
B10-3 18.038 15.326 6.280 24.351 44.635 18.038 28.767 44.635
B10-4 14.736 11.531 5.520 19.893 34.979 14.736 22.807 34.979
B11-1 15.226 16.514 6.900 20.555 43.043 15.226 26.786 43.043
B12-1 16.884 14.000 4.000 22.793 41.261 16.884 26.684 41.261
B12-2 10.252 6.377 2.650 13.841 21.869 10.252 14.716 21.869
B12-3 15.992 12.975 3.630 21.590 38.654 15.992 25.075 38.654
B12-4 16.682 13.768 5.520 22.521 40.671 16.682 26.320 40.671
B12-5 4.704 0.000 1.350 6.350 5.645 4.704 4.704 6.350
B13-1 15.360 3.600 1.250 20.736 23.832 15.360 17.880 23.832
B14-1 12.080 8.478 6.900 16.308 27.213 12.080 18.015 27.213
B14-2 14.838 3.000 2.100 20.031 22.306 14.838 16.938 22.306
B15-1 12.228 0.000 2.650 16.508 14.674 12.228 12.228 16.508
B15-2 8.647 4.532 3.630 11.673 17.173 8.647 11.819 17.173
B15-3 10.709 6.902 5.520 14.457 23.204 10.709 15.540 23.204
B15-4 4.704 0.000 1.350 6.350 5.645 4.704 4.704 6.350
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Appendix D Beam moment values Level 5 (service room)
Beam Clear Length (m) Left Moment (kNm)
Middle Moment (kNm)
Right Moment (kNm)
B1-1 5.700 -76.960 111.942 -123.136
B1-2 4.800 -68.014 42.509 -68.014
B1-3 5.300 -91.099 82.817 -56.937
B2-1 5.230 -65.970 95.956 -105.552
B2-2 4.970 -76.641 47.901 -76.641
B2-3 4.950 -97.300 88.455 -60.813
B3-1 3.600 -8.887 12.927 -14.220
B3-2 4.400 -72.638 45.399 -72.638
B3-3 4.500 -89.370 81.245 -55.856
B4-1 4.700 -29.975 43.600 -263.935
B5-1 5.850 -86.862 126.344 -138.979
B5-2 4.600 -80.358 50.224 -80.358
B5-3 5.100 -93.567 85.061 -58.480
B6-1 5.600 -63.023 91.669 -112.040
B6-2 4.600 -69.172 56.595 -38.909
B7-1 5.700 -50.534 110.257 -134.758
B7-2 3.520 -18.014 14.739 -6.755
B8-1 6.100 -65.280 94.953 -104.448
B8-2 3.700 -26.902 16.814 -26.902
B8-3 6.100 -116.530 105.936 -72.831
B9-1 7.375 -52.152 75.857 -52.152
B9-2 1.570 52.385 1.423 0.000
B10-1 5.950 -104.292 151.698 -166.867
B10-2 3.550 -42.921 26.826 -39.019
B10-3 6.100 -164.539 113.120 -180.992
B10-4 5.020 -87.940 79.945 -54.962
B11-1 6.000 -100.337 145.945 -100.337
B12-1 2.300 -13.660 19.869 -21.856
B12-2 1.650 -5.995 3.747 -5.450
B12-3 3.450 -41.898 28.805 -46.088
B12-4 5.020 -102.242 63.902 -63.902
B12-5 0.800 138.681 0.369 -0.169
B13-1 1.250 -2.325 3.382 -0.422
B14-1 6.100 -74.916 108.969 -133.184
B14-2 1.800 -8.022 6.564 -4.513
B15-1 2.350 -5.698 8.288 -9.116
B15-2 3.000 -23.553 14.720 -23.553
B15-3 4.750 -72.613 45.383 -45.383
B15-4 0.700 78.897 0.735 -0.337
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Roof
Beam Clear Length (m) Left Moment (kNm)
Middle Moment (kNm)
Right Moment (kNm)
B1-1 5.700 -50.207 73.028 -80.331
B1-2 4.800 -47.297 29.560 -47.297
B1-3 5.300 -65.879 59.890 -41.174
B2-1 5.230 -65.101 94.693 -104.162
B2-2 4.970 -76.509 47.818 -76.509
B2-3 4.950 -97.537 88.670 -60.961
B3-1 3.600 -8.900 12.945 -14.239
B3-2 4.400 -72.252 45.157 -72.252
B3-3 4.500 -80.609 73.281 -50.381
B4-1 4.700 -30.038 43.692 -265.045
B5-1 5.850 -87.074 126.653 -139.318
B5-2 4.600 -80.553 50.345 -80.553
B5-3 5.100 -91.427 83.115 -57.142
B6-1 5.600 -63.170 91.884 -112.302
B6-2 4.600 -69.331 56.725 -38.999
B7-1 5.700 -50.710 110.639 -135.226
B7-2 3.520 -18.038 14.758 -6.764
B8-1 6.100 -65.419 95.156 -104.671
B8-2 3.700 -26.951 16.844 -26.951
B8-3 6.100 -99.332 90.301 -62.082
B9-1 7.375 -52.233 75.975 -52.233
B9-2 1.570 52.455 1.423 0.000
B10-1 5.950 -104.553 152.077 -167.284
B10-2 3.550 -42.781 26.738 -38.892
B10-3 6.100 -150.989 103.805 -166.088
B10-4 5.020 -88.149 80.135 -55.093
B11-1 6.000 -96.846 140.868 -96.846
B12-1 2.300 -13.642 19.843 -21.827
B12-2 1.650 -5.954 3.721 -5.413
B12-3 3.450 -41.825 28.755 -46.008
B12-4 5.020 -102.492 64.058 -64.058
B12-5 0.800 139.105 0.369 -0.169
B13-1 1.250 -2.327 3.385 -0.423
B14-1 6.100 -63.288 92.056 -112.513
B14-2 1.800 -8.030 6.570 -4.517
B15-1 2.350 -5.698 8.288 -9.116
B15-2 3.000 -15.456 9.660 -15.456
B15-3 4.750 -52.354 32.721 -32.721
B15-4 0.700 78.858 0.283 -0.130
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Appendix E Column Moments
x -direction y -direction
columns bottom moment top moment
bottom moment top moment
C1-1 76.96 50.21 74.92 63.29
C1-2 -55.12 -33.03 100.34 96.85
C1-3 23.08 18.58 104.29 104.55
C1-4 -56.94 -41.17 65.28 65.42
C1-5 65.97 65.10 -125.16 -104.48
C1-6 -60.81 -60.96 -77.55 -77.72
C1-7 -55.86 -50.38 89.63 72.38
C1-8 29.98 30.04 14.44 6.34
C1-9 -263.94 -265.04 36.45 36.41
C1-10 86.86 87.07 49.06 36.90
C1-11 63.02 63.17 -124.28 -111.58
C2-1 58.42 58.01 -15.86 -15.87
C2-2 16.73 8.36 125.52 112.10
C3-1 -58.62 -58.77 56.15 56.48
C3-2 13.21 10.87 -93.05 -77.94
C3-3 -95.35 -91.07 -35.96 -25.152
C3-4 -42.87 -42.97 -202.58 -203.16
C3-5 50.28 35.02 -144.15 -129.11
C4 20.66 21.03 -123.95 -124.50
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-76.96
111.94
-123.14
-68.01
42.51
-68.01
-91.10
82.82
-56.94
Appendix F Beam Load summary sketches + Moment Diagrams Level 5 (service room)
Beam 1
37.90 kN/m 32.43 kN/m
29.52 kN/m
L = 6.00 m L = 5.60 m L = 5.10 m
Ln = 5.30 m
Ln = 4.80 m
Ln = 5.70 m
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-65.97
95.96
-105.55
-76.64
47.90
-76.64
-97.30
88.45
-60.81
-8.89
12.93
-14.22
-72.64
45.40
-72.64
-89.37
81.25
-55.86
Beam 2
Beam 3
38.59 kN/m
31.03 kN/m
39.71 kN/m
L = 6.00 m L = 5.60 m L = 5.10 m
Ln = 5.23 m Ln = 4.97 m
Ln = 4.95 m
10.97 kN/m
37.52 kN/m 41.13 kN/m
L = 6.00 m L = 5.60 m L = 5.10 m Ln = 3.60 m Ln = 4.40 m Ln = 4.50 m
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-29.98
43.60
-263.94
-86.86
126.34
-138.98
-80.36
50.22
-80.36 -93.57
85.06
-58.48
Beam 4
Beam 5
21.71 kN/m
40.61 kN/m
35.97 kN/m
37.98 kN/m
L = 6.00 m
L = 5.60 m L = 5.10 m L = 6.00 m
Ln = 4.70 m
Ln = 5.85 m Ln = 4.60 m Ln = 5.10 m
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-63.02
91.67
-112.04
-69.17
56.60
-38.91
-50.53
110.26
-134.76
-18.01
14.74
-6.76
Beam 6
Beam 7
32.14 kN/m 29.42 kN/m
37.33 kN/m 13.09 kN/m
L = 5.10 m L = 6.00 m
L = 5.10 m L = 6.00 m
Ln = 5.60 m Ln = 4.60 m
Ln = 5.70 m Ln = 3.52 m
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-65.28
94.95
-104.45
-26.90
16.81
-26.90
-116.53
105.94
-72.83
-52.15
75.86
-52.15
52.39
1.42 0.00
Beam 8
Beam 9
28.07 kN/m
19.65 kN/m
31.32 kN/m
15.34 kN/m 6.35 kN/m
L = 6.90 m L = 4.00 m L = 6.28 m
L = 1.70 m L = 7.80 m
Ln = 6.10 m Ln = 3.70 m Ln = 6.10 m
Ln = 2.57 m Ln = 7.38 m
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-104.29
151.70
-166.87
-42.92
26.83
-39.02
-164.54
113.12
-180.99
-87.94
79.95
-54.96
-100.34
145.94
-100.34
Beam 10
Beam 11
47.13 kN/m 48.64 kN/m
34.06 kN/m 34.90 kN/m
44.59 kN/m
L = 6.90 m L = 4.00 m L = 6.28 m L = 5.52 m
L = 6.90 m
Ln =6.10 m Ln = 5.02 m Ln = 3.55 m Ln = 5.95 m
Ln = 6.00 m
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-13.66
19.87
-21.86 -6.00
3.75 -5.45
-41.90
28.81
-46.09
-102.24
63.90
-63.90
138.68
0.37 -0.17
-2.32
3.38
-0.42
Beam 12
Beam 13
22.02 kN/m 41.32 kN/m 38.72 kN/m
6.35 kN/m
40.57 kN/m
23.81 kN/m
L = 4.00 m L = 1.35 m L = 2.65 m L = 3.63 m L = 5.52 m
L = 1.25 m
Ln = 2.30 m Ln = 1.65 m Ln = 5.02 m Ln = 0.8 m Ln = 3.45 m
Ln = 1.25 m
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-74.92
108.97
-133.18
-8.02 6.56
-4.51
-5.70
8.29
-9.12 -23.55
14.72
-23.55
-72.61
45.38
-45.38
78.90
0.74 -0.34
Beam 14
Beam 15
32.21 kN/m 22.28 kN/m
26.17 kN/m 32.18 kN/m
16.51 kN/m 16.51 kN/m
L = 6.00 m L = 6.90 m
L = 2.65 m L = 3.63 m L = 1.35 m L = 5.52 m
Ln = 2.10 m Ln = 1.80 m
Ln =2.35 m Ln = 3.00 m Ln = 4.75 m Ln = 0.70 m
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Appendix F column moment diagrams
Column X direction Y direction
C1-1
C1-2
C1-3
C1-4
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C1-5
C1-6
C1-7
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C1-8
C1-9
C1-10
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C1-11
C2-1
C2-2
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C3-1
C3-2
C3-3
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C3-4
C3-5
C4
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Page 49 of 98
Chapter 2.Individual Work
1.0 Introduction
Following the proposal of a new 6 floor building development in the Greater Geelong area, our
design team has been engaged as the structural design team responsible for the design and
analysis of a reinforced concrete design package that includes a detailed concrete columns,
shear wall and footing analysis and design for the 5th floor service space of the building. This
assignment will include a full reinforced concrete design of the selected 5 columns (four
rectangular and one circular) located on the fifth floor of the building as shown in the figure
below. The group assignment which includes design concept and assumptions, Loads &
Combination load cases, floor plans and sections, structural analysis and structural analysis has
been included.
A full set of architectural drawings has been provided. Also provided are detailed engineering
drawings showing dimensions of the floor, beam and column and wall placement with details of
spacings, gridlines and selected elements for simplistic analysis. Placement of some of the structural
members has been relocated ensuring it has no carry on effect on the car parking, in order to
simplify analysis. All designs delivered to the client will meet all relevant Australian Standards for
Reinforced Concrete Design. Also factors such as safety, strength, ductility, cost and aesthetics are all
considered during the design.
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2.0 Updates to Group Work
2.1 General Requirements
2.1.1 Exposure classification
Based on our location and building type we select a exposure class of A2, also assuming sealed tiles
for waterproofing {Non- residential, temperate climate [refer to table 4.3 AS3600-2009]}
2.1.2 Fire resistance
Assumption is that the building is designed for a fire resistance period of 90 minutes.
2.1.3 Cover
Based on selected characteristic strength of our concrete (fc), which is selected as 40MPa, a
exposure class of A2, the required concrete cover for corrosion protection will be 20mm {refer to
table 4.10.3.2 AS3600.2009}.
Cover as (axis distance)
2.1.4 Slab Thickness
Slab thickness is assumed to be 150mm thick. Since minimum thickness for fire resistance
protection is 90mm {table 5.5.1, AS3600.2009}
Therefore since D=150mm > 90mm, assumption is ok.
2.1.5 Material Properties
Concrete characteristics;
- Assuming fc = 40MPa
- Checking minimum strength requirements for concrete, minimum fc required for the
exposure A2 is 20MPa.
- Since fc = 40MPa >20MPaconcrete strength is ok
- Ec = 32800 MPa {table 3.2.1, AS3600.2009}
-
Reinforcement characteristics;
- Use N12 reinforcement
- Yield strength, fsy =500MPa
-
Page 51 of 98
2.2 Loading
Live loads
Q = 5.0 kN/m2 [AS1170.1, clause 3.4.1, table 3.1]
Note: largest possible live loading is selected due to amenities like the gym located on our floor
{areas with possible physical activities}
Note 2: 5.0 kN/m2 will be used for both level five and roof area.
Dead Loads
a) Superimposed [AS1170.1, Appendix A, table A1, A2]
Ceiling G (kN/m2)
Gypsum plaster 0.13
Flooring G (kN/m2)
Ceramic tiles 0.27
Granite flooring (15mm thick) 0.40
Terrazzo paving (16mm Thick) 0.43
Jacuzzi 3.27
Note: Jacuzzi load 3kN/m2 for water based on 7-10 people Jacuzzi, + 0.27kN/m2 for ceramic tiles
Note 2: The Terrazzo paving will only be used when calculating loadings for the roof.
b) Self weight
Outside walls G (kN/m2)
Double glazed glass curtain wall
25.5 (kN/m3)
Brick masonry (110mm wide) 0.19 per 10mm thickness
Note: it will be assumed that the Brick masonry is not loaded on the roof and will have no effect
Reinforced concrete and assuming 0.5kN/m3 for steel reinforcement 1% by volume
[AS1170.1, Appendix A, table A1]
Pw (density) = 24 +0.5 *1 = 24.5KN/m3
G = 24.5 kN/m3
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3.0 Column Design
3.1 Column C1-1
3.1.1 General Requirements
3.1.1.1 Exposure Classification & fire Resistance
-The column is designed for exposure classification A2 and a fire resistance of 90 minutes.
3.1.1.2 Material Properties & Section
-Concrete: fc = 40MPa
-Reinforcement: Fsy = 500MPa, N28 bars for longitudinal reinforcement and N10 for ligatures
-Trial Section;
The cross sectional area Ag, and hence diameter D, of the rectangular column can be estimated from
(Refer to lecture notes) ;
Ag = N* / 0.6(2* fc + fsy * P);
Where fc =40MPa and 2 =0.85 and fsy =500MPa
Assume a total steel ratio of 2% which is within the recommended limits of 1% - 4% {refer to clause
410.7.1 AS3600.2009}.
Therefore; 350mm
Ag = 2954 * 103 / 0.6(0.85 * 40 + 500 * 0.020) = 112 *103 mm2
Because for a rectangular section Ag=b *D
Therefore; D = 335 mm
Note: In order to take into account the effect of 350mm
bending moment we will try a larger section, say, D=350mm.
-
Page 53 of 98
3.1.1.3 Concrete Cover, Axis Distance
Concrete cover for corrosion protection: The required cover (for exposure class A2 concrete with fc
=40MPa) to the ligature is 20mm {refer to table 4.10.3.2 AS3600.2009}.
Therefore, the required cover to the main bar (longitudinal reinforcement) is;
C = 20 +10 =30 mm (10mm is the diameter of the ligature).
3.1.1.4 Axis distance for Fire Resistance
- Assume N* f /Nu = 0.7, where N*f is the design axial load in fire situation and Nu is the ultimate
strength in compression. {Refer to clause 5.6.3- AS3600.2009}
-For FRP = 90 minutes and column design D=350 mm; axis distance can be sufficiently taken as
53mm {refer to table 5.6.3AS3600.2009}.
-The concrete cover to main bar corresponding to this value of axis distance is
C = as (1/2 * diameter of bar) = 53 (1/2 *28) = 39mm > 30mm (cover for corrosion protection)
Therefore we will adopt
-Cover (c) = 40mm (to the face of main bar)
-Axis distance (as) = 55mm (to the centre of main bar)
Therefore, the ratio of distance between outer reinforcement to the overall diameter is:
g = g *D /D = (D- 2*as)/D = (350 - (2*53))/ 350 = 0.7
3.1.2 Design Loads
-Because the full structural analysis of the building is out of the scope of this project, the design axial
load for the column under consideration will be taken from the information provided to us in the
architectural and engineering drawings.
Therefore; N* =2954 KN {refer to pp 26; group work}
-Assume that a minimum bending moment of 0.05 * D * N* will be considered {refer to table
4.10.3.2 AS3600.2009}.
M*x = M*y = 0.05 * 0.35 * 2954 = 52KNm
Therefore the resultant bending moment
M* = (M*x)2 + (M*y)2 = (52)2 + (52)2 = 74KNm
-
Page 54 of 98
3.1.3 Biaxial Bending and compression
(Refer to clause 10.6.4 AS.3600-2009)
(M*x/Mux)n + (M*y/Muy)n 1.0
n = 0.7 + (1.7 N*) / (0.6 Nuo)within the limits 1 n 2
Therefore
Nuo= 1* fc *Ag + As* Fsy = 0.85 * 40 *112*103 +1232 *500 = 4424
n = 0.7 + (1.7 N*) / (0.6 Nuo) = 0.7 + (1.7*2954) / (0.6 * 5313.2) =2.0 2.0...therefore ok.
For P=0.01; Mux =450; Muy = 300
(52/450)2 + (52/300)2 = 0.03 1.0.Therefore design is ok.
3.1.4 Column Reinforcement Requirements
- Minimum Reinforcement: 0.01 * Ag
- Maximum Reinforcement: 0.04 * Ag
Where gross column area;
Ag = 2954 * 103 / 0.6(0.85 * 40 + 500 * 0.020) = 112 *103 mm2
Stresses due to design loading
-N*/Ag = 2954 *103 / (112 *103) mm2= 26 Mpa
- M*/Ag*D = 74 *106 / (112 *103) *350 = 1.9 MPa
-Assuming that the column is a short column (assumption to be verified)
As a trial we use 4N28 Bars as reinforcement
Therefore;
As = 282 * *2 /4 = 1232mm2
Therefore
P = As / Ag = 1232/ 112*103 = 0.011
Min Reinforcement = 0.01 * 112 *103 = 1120 mm2
Maximum Reinforcement = 0.04 * 112*103= 4480mm2
Therefore, since
1120 mm2 < As (1232mm2 )
-
Page 55 of 98
The steel ratio adopted is 1.1 % which is within the recommended limits of 1% to 4% {refer to clause
10.7.1, AS 3600-2009}
Diameter and spacing of fitments and helices
The minimum bar diameter of fitment and helices =10 for bars 24-28mm {refer to clause 10.7.4.3, AS
3600-2009}
S {D, 15* db} = {350, 15*28=420} = 350mm.
Therefore adopt N10 @150mm tie
3.1.5 Check If Column Is Short
-Unsupported length of column: Lu = 3600 -350 = 3250mm
Icolumn = b * d3 /12 = 350 *3503 /12 =1.25 * 109 mm4
Ibeam= b * d3 /12 = 640 * 3003 /12 = 1.4 * 109 mm4
= 1.0 for fixity factor {refer to table 10.5.4. AS 3600.2009}
1 = 2 = (1.25 * 109 / 3250)/ ((1*1.4*109)/6000) = 1.7
-assume the column is braced (as there are shear walls and shear core in the building), the effective
length of the column is;
Le= K*Lu = 0.9 * Lu = 0.9 * 3250 = 2925mm {Refer to clause 10.3.1, AS 3600-2009}.
-Radius of gyration of cross section {Refer to clause 10.5.2, AS 3600-2009}.:
r= 0.3 *D = 0.3*350 = 105mm
-Therefore, a column shall be deemed short where Le/r 25 {Refer to clause 10.3.1, AS 3600-2009}.
Slenderness ratio;
Le/r = 2925 /105 = 28 < 120, Therefore slenderness ratio is ok.
Le/r = 2925 /105 = 28 >25, Column is not short.
Since column is not short, work out moment magnification.
3.1.6 Moment Magnifier
-assume the column is braced (as there are shear walls and shear core in the building),
Km = 0.6-0.4(M*1 / M*2) 0.4
=0.6-0.4(52 / 52) 0.4
=0.2 0.4; therefore ok.
d= NG/NG+NQ = 24.5/24.5+5 = 0.8
-
Page 56 of 98
Nc= (2/le2)*(182*do ** Mub/ 1+ d)=(2/2.9252) *( (182 *(350*0.8*10-3)*(495*106))/ 1+ 0.8 )=
16200KN
For braced condition:
b = Km / 1 (N*/Nc) = 0.2 / 1-(2954/ 16200) = 0.24
For unbraced condition:
b = 1 / 1 (N*/Nc) = 1 / 1-(2954/16200) =1.2
Therefore; Max (0.24; 1.2). Therefore the moment magnification factor = 1.2
M*max = * M*2 = 1.2 * 1.9 =2.28 MPa
3.1.7 Column-Interaction diagram
Point 1
Assume uniform compression, no bending moment: Mu =0
Asc= Ast = 282 * *2 /4 = 1232mm2
Ac = 3502 2*1232 =120036 mm2
For Fc= 40MPa, the coefficient 1= 1.0-0.003 *40 =0.88, therefore 1=0.85
Nuo = 0.85 * fc *Ac + fsy *(Asc + Ast) = (0.85 *40 * 120036 + 500 *(1232+1232)) /103 =5313.2KN
Therefore coordinate of point 1 = (0, 5313.2)
Point 2
*Ku =1.0; Neutral axis dn =d
sy (yield strain) = fsy / Es = 500 /200000 = 0.0025
- Cover = 40mm
- Tie = 10mm
- Rebar = 28mm
-
Page 57 of 98
- dsc = 40 + 10 + 28/2 = 64mm.
- d=350-64 = 286mm
sc = u (knd dsc/ kud) = 0.003 * (d-dsc/d) = 0.003* (286-64/286) =0.0023
=1.05-0.007*fc =0.77 within limits of 0.670.770.85.therefore ok.
Therefore since sc =0.0023 < sy =0.0025, Therefore bars have not yielded yet.
sc = Es * sc = 200000 * 0.0023 =460 N/mm2
Cs = sc * Asc = 460 * 1232 = 566720 /1000 = 567KN.
T = 0, because neutral axis lies on d
Cc = compression of concrete = 0.85 * fc* *ku *d*b = (0.85 * 40 *0.77 *1 *286 *350)/1000
=2620.6KN
Nu = Cc + Cs T (Force equilibrium) = 2620.6 + 567 -0 = 3187.6KN
Zc = d-0.5**Ku*d = 286 -0.5 * 0.77 * 1 * 286 =175.89mm
Zsc = d-dsc = 286 64 =222mm
Nu*h = Cc*Zc + Cs * Zsc (Moment equilibrium)
h = (2797.6 * 175.89 + 567 *222)/3187.6= 194mm
e = h-(d-dg)=194-(286 350/2) =83mm
Mu = Nu *e = 3187.6 * 0.083 =264.5 KN.m
Therefore coordinate of point 2 (264.5, 3187.6)
Point 3
*Ku =0.545
sc / kud dsc = u / kud
sc /( 0.545 *28)5= 0.003/ 0.545 *28
Therefore; sc =0.0020
Therefore; sc = 0.0020 < y = 0.0025 Therefore compression bar not yielded yet.
sc = Es * sc = 200000 * 0.0020 =400 N/mm2 > 500N/mm2...therefore ok.
Cs = sc * Asc = 400 * 1232 = 566720 /1000 = 493KN.
-
Page 58 of 98
Cc = compression of concrete = 0.85 * fc* *ku *d*b = (0.85 * 40 *0.77 *0.545 *286 *350)/1000
=1428.2KN
T = fsy * Asc = (500 * 1232)/1000= 616KN
Nu = Cc + Cs T (Force equilibrium) = 1428.2 + 493 -616 = 1305.2 KN
Zc = d-0.5**Ku*d = 286 -0.5 * 0.77 * 0.545 * 286 = 226mm
Zsc = d-dsc = 286 64 =222mm
Nu*h = Cc*Zc + Cs * Zsc (Moment equilibrium)
h = (1428.52 * 222 + 493 *222)/1305.2 = 327mm
e = h-(d-dg) =327- (286 350/2) = 216mm
Mu = Nu *e = 1305.2 * 0.216 =281.9 KN.m
Therefore coordinate of point 3 (281.9, 1305.2)
Point 4
*Ku =Not known, must be calculated iteratively
*Zero compression, strain in compression steel smaller than sy.
sy (yield strain) = fsy / Es = 500 /200000 = 0.0025
- Cover = 40mm
- Tie = 10mm
- Rebar = 28mm
- dsc = 40 + 10 + 28/2 = 64mm.
- d=350-64 = 286mm
Ast = Asc = 2 *282 * /4 =1232mm2
Nu = 0 = Cc + Cs T
0 =0.85 * fc* *ku *d*b + sc*Asc fsy*Ast
Therefore by similar triangle;
sc / kud dsc = u / kud
sc = (u/ kud) * (kud dsc)
sc = sc * Es = (u * Es /Ku*d) * (Kud dsc) where Es= 200,000MPa
Therefore;
-
Page 59 of 98
0 = 0.85*fc* *ku *d*b + ((u * Es /Ku*d) * (Kud dsc))*Asc fsy *Ast
0= 0.85 *40 *0.077 * 286 *350 *Ku + (0.003*200000/286*Ku)*((286*Ku)-64)* 1232 -500*1232
0= 279759.48 *Ku2 -171568.32 *ku +123200
Therefore Ku = 0.28
Therefore;
0=0.85 * fc* *ku *d*b + sc*Asc fsy*Ast
0 =0.85 * 40 * 0.77 * 0.28 *286 *350 +1232 * sc -500*1232
sc = 95.5 N/mm2
Cc = 0.85 * fc* *ku *d*b
=0.85 * 40* 0.77 *0.28 * 286*350 = 733.7 KN
Cs= Es * sc * Asc = 200000 * 0.0003 *1232 =148 KN.
Zc = d -0.5 * *ku *d = 286 -0.5 *0.77 *0.28 *28 = 283mm
Zsc = d dsc = 286-64 =222mm
Mu = Cc*Zc + Cs * Zsc = ((733.7/1000) * 283) + ((148/1000) * 222) = 240.5KN.m
Therefore; the coordinate of point 4- (240.5, 0)
Column-Interaction Diagram
N
M
1 (0, 5313.2)
2 (264.5, 3187.6)
3 (281.9, 1305.2)
4 (240.5, 0)
M
-
Page 60 of 98
3.1.8 Summary
Summary Column C1-1
- Rectangular column
- D= 350mm
- Longitudinal Reinforcement = 4N28
- Tie (Ligature) = N10@150mm.
350mm
N10@150
350mm
4N28
N* =2954 KN
-
Page 61 of 98
3.2 Column C1-2
3.2.1 General Requirements
3.2.1.1 Exposure Classification & fire Resistance
-The column is designed for exposure classification A2 and a fire resistance of 90 minutes.
3.2.1.2 Material Properties & Section
-Concrete: fc = 40MPa
-Reinforcement: Fsy = 500MPa, N32 bars for longitudinal reinforcement and N12 for ligatures
-Trial Section;
The cross sectional area Ag, and hence diameter D, of the rectangular column can be estimated from
(Refer to lecture notes) ;
Ag = N* / 0.6(2* fc + fsy * P);
Where fc =40MPa and 2 =0.85 and fsy =500MPa
Assume a total steel ratio of 2% which is within the recommended limits of 1% - 4% {refer to clause
410.7.1 AS3600.2009}.
Therefore;
Ag = 3509 * 103 / 0.6(0.85 * 40 + 500 * 0.020) = 133 *103 mm2
Because for a rectangular section Ag=b *D (Assuming b=350mm)
Therefore; D = 380 mm
Note: In order to take into account the effect of bending moment we will try a larger section, say,
D= 450mm.
-
Page 62 of 98
3.2.1.3 Concrete Cover, Axis Distance
Concrete cover for corrosion protection: The required cover (for exposure class A2 concrete with fc
=40MPa) to the ligature is 20mm {refer to table 4.10.3.2 AS3600.2009}.
Therefore, the required cover to the main bar (longitudinal reinforcement) is;
C = 20 +12 =32 mm (12mm is the diameter of the ligature).
3.2.1.4 Axis distance for Fire Resistance
- Assume N* f /Nu = 0.7, where N*f is the design axial load in fire situation and Nu is the ultimate
strength in compression. {Refer to clause 5.6.3- AS3600.2009}
-For FRP = 90 minutes and column design D=450 mm can be sufficiently taken as 50mm {refer to
table 5.6.3AS3600.2009}.
-The concrete cover to main bar corresponding to this value of axis distance is
C = as (1/2 * diameter of bar) = 50 (1/2 *32) = 32mm > 30mm (cover for corrosion protection)
Therefore we will adopt
-Cover (c) = 32mm (to the face of main bar)
-Axis distance (as) = 50mm (to the centre of main bar)
Therefore, the ratio of distance between outer reinforcement to the overall diameter is:
g = g *D /D = (D- 2*as)/D = (450 - (2*50))/ 450 = 0.78
3.2.2 Design Loads
-Because the full structural analysis of the building is out of the scope of this project, the design axial
load for the column under consideration will be taken from the information provided to us in the
architectural and engineering drawings.
Therefore; N* =3509KN {refer to pp 26; Group work}
-Assume that a minimum bending moment of 0.05 * D * N* will be considered {refer to table
4.10.3.2 AS3600.2009}.
M*x = 0.05 * 0.35 * 3509= 61.4KNm
M*y= 0.05 * 0.45 * 3509 = 79KNm
Therefore the resultant bending moment
M* = (M*x)2 + (M*y)2 = (61.4)2 + (79)2 = 100.05KNm
-
Page 63 of 98
3.2.3 Biaxial Bending and compression
(Refer to clause 10.6.4 AS.3600-2009)
(M*x/Mux)n + (M*y/Muy)n 1.0
n = 0.7 + (1.7 N*) / (0.6 Nuo)within the limits 1 n 2
Therefore
Nuo = 0.85 * fc *Ac + fsy *(Asc + Ast) = (0.85 *40 * 199284 + 500 *(1608+1608)) /103 =8384KN
n = 0.7 + (1.7 N*) / (0.6 Nuo) = 0.7 + (1.7*3509) / (0.6 * 8384) =1.89 2.0...therefore ok.
For P=0.01; Mux =400; Muy = 280
(61.4/400)1.89 + (79/280)1.89 = 0.08 1.0.Therefore design is ok.
3.2.4 Column Reinforcement Requirements
- Minimum Reinforcement: 0.01 * Ag
- Maximum Reinforcement: 0.04 * Ag
Where gross column area;
Ag = 3509 * 103 / 0.6(0.85 * 40 + 500 * 0.020) = 133 *103 mm2
Stresses due to design loading
-N*/Ag = 3509 *103 / (133 *103) mm2= 26.4 Mpa
- M*/Ag*D = 100.05 *106 / (133 *103) *450 = 1.88 MPa
-Assuming that the column is a short column (assumption to be verified)
As a trial we use 4N32 Bars as reinforcement
Therefore;
As = 322 * *2 /4 = 1609mm2
Therefore
P = As / Ag = 1609/ 133*103 = 0.012
Min Reinforcement = 0.01 * 133 *103 = 1330 mm2
Maximum Reinforcement = 0.04 * 133*103= 5320mm2
Therefore, since
1330 mm2 < As (1609mm2 )
-
Page 64 of 98
The steel ratio adopted is 1.2 % which is within the recommended limits of 1% to 4% {refer to clause
10.7.1, AS 3600-2009}
Diameter and spacing of fitments and helices
The minimum bar diameter of fitment and helices =12 for bars 28-32mm.{refer to clause 10.7.4.3, AS
3600-2009}
S { D, 15* db} = {450 , 15*32=480 } = 480mm.
Therefore adopt N12 @150mm tie
3.2.5 Check If Column Is Short
-Unsupported length of column: Lu = 3600 -450 = 3150mm
Icolumn = b * d3 /12 = 350 *4503 /12 = 2.7 * 109 mm4
Ibeam= b * d3 /12 = 640 * 3003 /12 = 1.4 * 109 mm4
= 1.0 for fixity factor {refer to table 10.5.4. AS 3600.2009}
1 = 2 = (2.7 * 109 / 3150)/ ((1*1.4*109)/5100) = 1.3
-assume the column is braced (as there are shear walls and shear core in the building), the effective
length of the column is;
Le= K*Lu = 0.9 * Lu = 0.9 * 3150 = 2835mm {Refer to clause 10.3.1, AS 3600-2009}.
-Radius of gyration of cross section {Refer to clause 10.5.2, AS 3600-2009}.:
r= 0.3 *D = 0.3*450 = 135mm
-Therefore, a column shall be deemed short where Le/r 25 {Refer to clause 10.3.1, AS 3600-2009}.
Slenderness ratio;
Le/r = 2835 /135 = 21 < 120, Therefore slenderness ratio is ok.
Le/r = 2835 /135 = 21 25
-
Page 65 of 98
Therefore it can be seen that the slenderness ratio of the column under consideration is less than
the slenderness ratio limit:
Le/r = 21 < c*(38 fc/15)*(1+M*1/M*2) =43.9.
Therefore, the column can be designed as a short column which does not require moment
magnification.
3.2.6 Column-Interaction diagram
Point 1
Assume uniform compression, no bending moment: Mu =0
Asc= Ast = 322 * *2 /4 = 1608mm2
Ac = 4502 2*1608 =199284 mm2
For Fc= 40MPa, the coefficient 1= 1.0-0.003 *40 =0.88; therefore 1=0.85
Nuo = 0.85 * fc *Ac + fsy *(Asc + Ast) = (0.85 *40 * 199284 + 500 *(1608+1608)) /103 =8384KN
Therefore coordinate of point 1 = (0, 8384)
Point 2
*Ku =1.0; Neutral axis dn =d
sy (yield strain) = fsy / Es = 500 /200000 = 0.0025
- Cover = 32mm
- Tie = 12mm
- Rebar = 32mm
- dsc = 32 + 12 + 32/2 = 60mm.
- d=450-60 = 390mm
sc = u (knd dsc/ kud) = 0.003 * (d-dsc/d) = 0.003* (390-60/390) =0.0024
=1.05-0.007*fc =0.77 within limits of 0.670.770.85.therefore ok.
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Page 66 of 98
Therefore since sc =0.0024 < sy =0.0025, Therefore bars have not yielded yet.
sc = Es * sc = 200000 * 0.0024 =480 N/mm2
Cs = sc * Asc = 480 * 1608 = 771840/1000 = 772KN.
T = 0, because neutral axis lies on d
Cc = compression of concrete = 0.85 * fc* *ku *d*b = (0.85 * 40 *0.77 *1 *390 *350)/1000
=3573.6KN
Nu = Cc + Cs T (Force equilibrium) = 3573.6 + 772 -0 = 4345.6KN
Zc = d-0.5**Ku*d = 390 -0.5 * 0.77 * 1 * 389 =240mm
Zsc = d-dsc = 390 60 = 330mm
Nu*h = Cc*Zc + Cs * Zsc (Moment equilibrium)
h = (3573.6 * 240 + 772 *330)/4345.6 = 256mm
e = h-(d-dg)= 256 - (390 450/2) =91mm
Mu = Nu *e = 4345.6 * 0.091 =395.4 KN.m
Therefore coordinate of point 2 (395.4, 4345.6)
Point 3
*Ku =0.545
sc / kud dsc = u / kud
sc /( 0.545 *32)5= 0.003/ 0.545 *32
Therefore; sc =0.0021
Therefore; sc = 0.0021 < y = 0.0025 Therefore compression bar not yielded yet.
sc = Es * sc = 200000 * 0.0021 =420 N/mm2
Cs = sc * Asc = 420 * 1608 = 675360 /1000 = 675.36KN.
Cc = compression of concrete = 0.85 * fc* *ku *d*b = (0.85 * 40 *0.77 *0.545 *390 *350)/1000
=1947.6KN
T = fsy * Asc = (500 * 1608)/1000= 804KN
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Page 67 of 98
Nu = Cc + Cs T (Force equilibrium) = 1947.6+ 675.36 -804 = 1818.9 KN
Zc = d-0.5**Ku*d = 390 -0.5 * 0.77 * 1 * 390 = 240mm
Zsc = d-dsc = 390 60 =330mm
Nu*h = Cc*Zc + Cs * Zsc (Moment equilibrium)
h = (1947.6 * 240 + 675.36 *330)/1818.9 = 380mm
e = h-(d-dg) =380- (390 450/2) = 215mm
Mu = Nu *e = 2400.7 * 0.215 = 516.2 KN.m
Therefore coordinate of point 3 (516.2, 1818.9)
Point 4
*Ku =Not known, must be calculated iteratively
*Zero compression, strain in compression steel smaller than sy.
sy (yield strain) = fsy / Es = 500 /200000 = 0.0025
- Cover = 32mm
- Tie = 12mm
- Rebar = 32mm
- dsc = 32 + 12 + 32/2 = 60mm.
- d=450-60 = 390mm
Ast = Asc = 2 *322 * /4 = 1608mm2
Nu = 0 = Cc + Cs T
0 =0.85 * fc* *ku *d*b + sc*Asc fsy*Ast
Therefore by similar triangle;
sc / kud dsc = u / kud
sc = (u/ kud) * (kud dsc)
sc = sc * Es = (u * Es /Ku*d) * (Kud dsc) where Es= 200,000MPa
Therefore;
0 = 0.85*fc* *ku *d*b + ((u * Es /Ku*d) * (Kud dsc))*Asc fsy *Ast
0= 0.85 *40 *0.077 * 390 *350 *Ku + (0.003*200000/389*Ku)*((389*Ku)-61)* 1608 -500*1608
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Page 68 of 98
0= 381490.2 *Ku2 -171568.32 *ku +123200
Therefore Ku = 0.24
Therefore;
0=0.85 * fc* *ku *d*b + sc*Asc fsy*Ast
0 =0.85 * 40 * 0.77 * 0.24 *390 *350 + sc *1608 -500*1608
sc = 33.4 N/mm2
Cc = 0.85 * fc* *ku *d*b
=0.85 * 40* 0.77 *0.24 * 390*350 = 857.7 KN
Cs= Es * sc * Asc = 200000 * 0.0003 *1608 = 96.5 KN.
Zc = d -0.5 * *ku *d = 390 -0.5 *0.822 *0.24 *32 = 387mm
Zsc = d dsc = 390-60 =330mm
Mu = Cc*Zc + Cs * Zsc = ((857.7/1000) * 387) + (96.5/1000) * 330) = 363.8KN.m
Therefore; the coordinate of point 4- (363.8, 0)
Column-Interaction Diagram
N
1 (0, 8384)
2 (395.4, 4345.6)
3 (516.2, 1818.9)
4 (363.8, 0)
M
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Page 69 of 98
3.2.7 Summary
Summary
- Rectangular column
- D= 450mm
- Longitudinal Reinforcement = 4N32
- Tie (Ligature) = N12@150mm.
350mm
N12@150
450mm
4N32
N* =3509KN
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Page 70 of 98
3.3 Column C1-3
3.3.1 General Requirements
3.3.1.1 Exposure Classification & fire Resistance
-The column is designed for exposure classification A2 and a fire resistance of 90 minutes.
3.3.1.2 Material Properties & Section
-Concrete: fc = 40MPa
-Reinforcement: Fsy = 500MPa, N32 bars for longitudinal reinforcement and N12 for ligatures
-Trial Section;
The cross sectional area Ag, and hence diameter D, of the rectangular column can be estimated from
(Refer to lecture notes) ;
Ag = N* / 0.6(2* fc + fsy * P);
Where fc =40MPa and 2 =0.85 and fsy =500MPa
Assume a total steel ratio of 2% which is within the recommended limits of 1% - 4% {refer to clause
410.7.1 AS3600.2009}.
Therefore;
Ag = 3412 * 103 / 0.6(0.85 * 40 + 500 * 0.020) = 129 *103 mm2
Because for a rectangular section Ag=b *D (Assuming b=350mm)
Therefore; D = 369 mm
Note: In order to take into account the effect of bending moment we will try a larger section, say,
D= 450mm.
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Page 71 of 98
3.3.1.3 Concrete Cover, Axis Distance
Concrete cover for corrosion protection: The required cover (for exposure class A2 concrete with fc
=40MPa) to the ligature is 20mm {refer to table 4.10.3.2 AS3600.2009}.
Therefore, the required cover to the main bar (longitudinal reinforcement) is;
C = 20 +12 =32 mm (12mm is the diameter of the ligature).
3.3.1.4 Axis distance for Fire Resistance
- Assume N* f /Nu = 0.7, where N*f is the design axial load in fire situation and Nu is the ultimate
strength in compression. {Refer to clause 5.6.3- AS3600.2009}
-For FRP = 90 minutes and column design D=450 mm can be sufficiently taken as 50mm {refer to
table 5.6.3AS3600.2009}.
-The concrete cover to main bar corresponding to this value of axis distance is
C = as (1/2 * diameter of bar) = 50 (1/2 *32) = 34mm > 30mm (cover for corrosion protection)
Therefore we will adopt
-Cover (c) = 35mm (to the face of main bar)
-Axis distance (as) = 53mm (to the centre of main bar)
Therefore, the ratio of distance between outer reinforcement to the overall diameter is:
g = g *D /D = (D- 2*as)/D = (450 - (2*50))/ 450 = 0.78
3.3.2 Design Loads
-Because the full structural analysis of the building is out of the scope of this project, the design axial
load for the column under consideration will be taken from the information provided to us in the
architectural and engineering drawings.
Therefore; N* =3412KN {refer to pp 26; Group work}
-Assume that a minimum bending moment of 0.05 * D * N* will be considered {refer to table
4.10.3.2 AS3600.2009}.
M*x = 0.05 * 0.35 * 3412= 59.71KNm
M*y= 0.05 * 0.45 * 3412 = 76.8KNm
Therefore the resultant bending moment
M* = (M*x)2 + (M*y)2 = (59.71)2 + (76.8)2 = 97.3KNm
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Page 72 of 98
3.3.3 Biaxial Bending and compression
(Refer to clause 10.6.4 AS.3600-2009)
(M*x/Mux)n + (M*y/Muy)n 1.0
n = 0.7 + (1.7 N*) / (0.6 Nuo)within the limits 1 n 2
Therefore
Nuo = 0.88 * fc *Ac + fsy *(Asc + Ast) = (0.85 *40 * 199284 + 500 *(1608+1608)) /103 =8384KN
n = 0.7 + (1.7 N*) / (0.6 Nuo) = 0.7 + (1.7*3412) / (0.6 * 8384) =1.85 2.0...therefore ok.
For P=0.01; Mux =430; Muy = 320
(59.71/430)1.85 + (76.8/320)1.85 = 0.1 1.0.Therefore design is ok.
3.3.4 Column Reinforcement Requirements
- Minimum Reinforcement: 0.01 * Ag
- Maximum Reinforcement: 0.04 * Ag
Where gross column area;
Ag = 3412 * 103 / 0.6(0.85 * 40 + 500 * 0.020) = 129 *103 mm2
Stresses due to design loading
-N*/Ag = 3412 *103 / (129 *103) mm2= 26.4 Mpa
- M*/Ag*D = 97.3 *106 / (129 *103) *450 = 1.7 MPa
-Assuming that the column is a short column (assumption to be verified)
As a trial we use 4N32 Bars as reinforcement
Therefore;
As = 322 * *2 /4 = 1609mm2
Therefore
P = As / Ag = 1609/ 129*103 = 0.013
Min Reinforcement = 0.01 * 129 *103 = 1290 mm2
Maximum Reinforcement = 0.04 * 129*103= 5160mm2
Therefore, since
1290 mm2 < As (1609mm2 )
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Page 73 of 98
Therefore the assumption here is adequate, adopt 4N32 bars.
The steel ratio adopted is 1.3 % which is within the recommended limits of 1% to 4% {refer to clause
10.7.1, AS 3600-2009}
Diameter and spacing of fitments and helices
The minimum bar diameter of fitment and helices =12 for bars 28-32mm.{refer to clause 10.7.4.3, AS
3600-2009}
S { D, 15* db} = {450 , 15*32=480 } = 450mm.
Therefore adopt N12 @150mm tie
3.3.5 Check If Column Is Short
-Unsupported length of column: Lu = 3600 -450 = 3150mm
Icolumn = b * d3 /12 = 350 *4503 /12 = 2.7 * 109 mm4
Ibeam= b * d3 /12 = 640 * 3003 /12 = 1.4 * 109 mm4
= 1.0 for fixity factor {refer to table 10.5.4. AS 3600.2009}
1 = 2 = (2.7 * 109 / 3150)/ ((1*1.4*109)/5100) = 1.3
-assume the column is braced (as there are shear walls and shear core in the building), the effective
length of the column is;
Le= K*Lu = 0.9 * Lu = 0.9 * 3150 = 2835mm {Refer to clause 10.3.1, AS 3600-2009}.
-Radius of gyration of cross section {Refer to clause 10.5.2, AS 3600-2009}.:
r= 0.3 *D = 0.3*450 = 135mm
-Therefore, a column shall be deemed short where Le/r 25 {Refer to clause 10.3.1, AS 3600-2009}.
Slenderness ratio;
Le/r = 2835 /135 = 21 < 120, Therefore slenderness ratio is ok.
Le/r = 2835 /135 = 21 25
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Page 74 of 98
Therefore it can be seen that the slenderness ratio of the column under consideration is less than
the slenderness ratio limit:
Le/r = 21 < c*(38 fc/15)*(1+M*1/M*2) =44
Therefore, the column can be designed as a short column which does not require moment
magnification.
3.3.6 Column-Interaction diagram
Point 1
Assume uniform compression, no bending moment: Mu =0
Asc= Ast = 322 * *2 /4 = 1608mm2
Ac = 4502 2*1608 =199284 mm2
For Fc= 40MPa, the coefficient 1= 1.0-0.003 *40 =0.88; therefore 1=0.85
Nuo = 0.88 * fc *Ac + fsy *(Asc + Ast) = (0.85 *40 * 199284 + 500 *(1608+1608)) /103 =8384KN
Therefore coordinate of point 1 = (0, 8384)
Point 2
*Ku =1.0; Neutral axis dn =d
sy (yield strain) = fsy / Es = 500 /200000 = 0.0025
- Cover = 34mm
- Tie = 12mm
- Rebar = 32mm
- dsc = 32 + 12 + 32/2 = 60mm.
- d=450-60 = 390mm
sc = u (knd dsc/ kud) = 0.003 * (d-dsc/d) = 0.003* (390-60/390) =0.0024
=1.05-0.007*fc =0.77 within limits of 0.670.770.85.therefore ok.
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Page 75 of 98
Therefore since sc =0.0024 < sy =0.0025, Therefore bars have not yielded yet.
sc = Es * sc = 200000 * 0.0024 =480 N/mm2 > fsy=500N/mm2..therefore ok.
Cs = sc * Asc = 480 * 1608 = 771840/1000 = 772KN.
T = 0, because neutral axis lies on d
Cc = compression of concrete = 0.85 * fc* *ku *d*b = (0.85 * 40 *0.77 *1 *390 *350)/1000
=3573.6KN
Nu = Cc + Cs T (Force equilibrium) = 3573.2 + 772 -0 = 4295.2KN
Zc = d-0.5**Ku*d = 390 -0.5 * 0.77 * 1 * 390 =240mm
Zsc = d-dsc = 390 60 = 330mm
Nu*h = Cc*Zc + Cs * Zsc (Moment equilibrium)
h = (3573.6* 230 + 772 *330)/4295.2 = 247mm
e = h-(d-dg) = 247 - (390 450/2) =82mm
Mu = Nu *e = 4295.2 * 0.082 =352.2 KN.m
Therefore coordinate of point 2 (352.2, 4295.2)
Point 3
*Ku =0.545
sc / kud dsc = u / kud
sc /( 0.545 *32)5= 0.003/ 0.545 *32
Therefore; sc =0.0021
Therefore; sc = 0.0021 < y = 0.0025 Therefore compression bar not yielded yet.
sc = Es * sc = 200000 * 0.0021 =420 N/mm2
Cs = sc * Asc = 420 * 1608 = 675360 /1000 = 675.36KN.
Cc = compression of concrete = 0.85 * fc* *ku *d*b = (0.85 * 40 *0.77 *0.545 *390 *350)/1000
=1947.6KN
T = fsy * Asc = (500 * 1608)/1000= 804KN
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Page 76 of 98
Nu = Cc + Cs T (Force equilibrium) = 1947.6+ 675.36 -804 = 1818.96 KN
Zc = d-0.5**Ku*d = 390 -0.5 * 0.77 * 1 * 390 = 195mm
Zsc = d-dsc = 390 60 =330mm
Nu*h = Cc*Zc + Cs * Zsc (Moment equilibrium)
h = (2529.3 * 195 + 675.36 *330)/1947.6 = 368mm
e = h-(d-dg) =368- (390 450/2) = 203mm
Mu = Nu *e = 1818.96 * 0.203 =369.2 KN.m
Therefore coordinate of point 3 (369.2, 1818.96)
Point 4
*Ku =Not known, must be calculated iteratively
*Zero compression, strain in compression steel smaller than sy.
sy (yield strain) = fsy / Es = 500 /200000 = 0.0025
- Cover = 32mm
- Tie = 12mm
- Rebar = 32mm
- dsc = 32 + 12 + 32/2 = 60mm.
- d=450-60 = 390mm
Ast = Asc = 2 *322 * /4 = 1608mm2
Nu = 0 = Cc + Cs T
0 =0.85 * fc* *ku *d*b + sc*Asc fsy*Ast
Therefore by similar triangle;
sc / kud dsc = u / kud
sc = (u/ kud) * (kud dsc)
sc = sc * Es = (u * Es /Ku*d) * (Kud dsc) where Es= 200,000MPa
Therefore;
0 = 0.85*fc* *ku *d*b + ((u * Es /Ku*d) * (Kud dsc))*Asc fsy *Ast
0= 0.85 *40 *0.77 * 390 *350 *Ku + (0.003*200000/389*Ku)*((389*Ku)-61)* 1608 -500*1608
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Page 77 of 98
0= 381490.2 *Ku2 -171568.32 *ku +123200
Therefore Ku = 0.24
Therefore;
0=0.85 * fc* *ku *d*b + sc*Asc fsy*Ast
0 =0.85 * 40 * 0.77 * 0.24 *390 *350 + sc *1608 -500*1608
sc = 33.4 N/mm2
Cc = 0.85 * fc* *ku *d*b
=0.85 * 40* 0.77 *0.24 * 390*350 = 857.7 KN
Cs= Es * sc * Asc = 200000 * 0.0003 *1608 =96.5 KN.
Zc = d -0.5 * *ku *d = 390 -0.5 *0.77 *0.24 *32 = 387mm
Zsc = d dsc = 390-60 =330mm
Mu = Cc*Zc + Cs * Zsc = ((857.7/1000) * 387) + (96.5/1000) * 330) = 363.8KN.m
Therefore; the coordinate of point 4- (363.8, 0)
Column-Interaction Diagram
N
M
1 (0, 8384)
2 (352.2, 4295.2)
3 (369.2, 1818.96)
4 (363.8, 0) M
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Page 78 of 98
3.3.7 Summary
Summary
- Rectangular column
- D= 450mm
- Longitudinal Reinforcement = 4N32
- Tie (Ligature) = N12@150mm.
350mm
N12@150
450mm
4N32
N* =3412KN
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Page 79 of 98
3.4 Column C4
3.4.1 General Requirements
3.4.1.1 Exposure Classification & fire Resistance
-The column is designed for exposure classification A2 and a fire resistance of 90 minutes.
3.4.1.2 Material Properties & Section
-Concrete: fc = 40MPa
-Reinforcement: Fsy = 500MPa, N24 bars for longitudinal reinforcement and N10 for ligatures
-Trial Section;
The cross sectional area Ag, and hence diameter D, of the rectangular column can be estimated from
(Refer to lecture notes) ;
Ag = N* / 0.6(2* fc + fsy * P);
Where fc =40MPa and 2 =0.85 and fsy =500MPa
Assume a total stee