series-connected multi-phase multi-motor drivesewh.ieee.org/r8/ukri/pels/synopsis4.pdf · model...
TRANSCRIPT
Series-Connected Multi-Phase Multi-Motor Drives
Prof. Emil LeviLiverpool John Moores University
School of Engineering
Standard Multi-Motor Drives with Independent Control
• Three-phase configuration of k motors with independent vector control: 3k inverter legs.• Motor/inverter sets connected in parallel, with common dc link.
• Independent control of two or more three-phase
motors supplied from one inverter is not possible.
Vector Feedback control common DC link 3-phase PWM Machine VSI 1 3-phase Machine PWM 2 VSI Vector control Feedback
Multi-phase machines versus three-phase machines
• Higher torque density: since torque production can be enhanced using injection of higher stator
current harmonics.• Greater fault tolerance, since the machine can continue to operate in the event of failure of one
(or more) inverter legs.• Reduction in the required rating per inverter leg.
• The first two advantages will not exist in the drive systems discussed here.
Modelling of an n-Phase Induction Machine• Sinusoidal distribution of MMF in the air-gap.
• Torque production: fundamental stator current harmonic only.• All the other standard assumptions apply.
• The concept is independent of the ac machine type.• Model transformation using decoupling transformation (n = odd).
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−−−
−−−
−−−
−−−
=
21
21
21...
21
21
21
21
21sin
212sin
213sin...
213sin
212sin
21sin0
21cos
212cos
213cos...
213cos
212cos
21cos1
......................................4sin8sin12sin...12sin8sin4sin0
4cos8cos12cos...12cos8cos4cos13sin6sin9sin...9sin6sin3sin0
3cos6cos9cos...9cos6cos3cos12sin4sin6sin...6sin4sin2sin0
2cos4cos6cos...6cos4cos2cos1sin2sin3sin...3sin2sinsin0
cos2cos3cos...3cos2coscos1
2
nnnnnn
nnnnnn
nC
α
αααααα
αααααααααααααααααααααααααααααααααααααααααααααααα
Modelling of an n-Phase Induction Machine (cont.)
• For even system phase numbers decoupling transformation matrix is:
−−−−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−−−
−−−
−−−
=
−
+
−
−
212121.....21212121212121.....212121212
2sin2
22sin2
23sin.....2
23sin2
22sin2
2sin0
22cos
222cos
223cos.....
223cos
222cos
22cos1
........................................3sin6sin9sin.....9sin6sin3sin0
3cos6cos9cos.....9cos6cos3cos12sin4sin6sin.....6sin4sin2sin0
2cos4cos6cos.....6cos4cos2cos1sin2sin3sin.....3sin2sinsin0
cos2cos3cos.....3cos2coscos1
00
...2
24
24
2
2
1
1
αααααα
αααααα
αααααααααααααααααααααααααααααααααααα
βα
nnnnnn
nnnnnn
y
x
yxyx
n
n
n
C
Machine Model after Transformation( ) ( )
( ) ( )
dtdi
LiRdt
diRv
dtdi
LiRdt
diRv
dtdi
LiRdt
diRv
iidtdL
dtdi
LLiRdt
diRv
iidtdL
dtdi
LLiRdt
diRv
slsss
ssss
sylssys
sysyssy
sxlssxs
sxsxssx
rrms
mlssss
sss
rrms
mlssss
sss
00
000
11
111
11
111
...........................................................................
...........................................................................
cossin
sincos
+=+=
+=+=
+=+=
++++=+=
−+++=+=
ψ
ψ
ψ
θθψ
θθψ
βαβ
ββ
ββ
βαα
αα
αα
( ) ( )
( ) ( )
dtdi
LiRdt
diRv
dtdi
LiRdt
diRv
dtdi
LiRdt
diRv
iidtdL
dtdi
LLiRdt
diRv
iidtdL
dtdi
LLiRdt
diRv
rlrrr
rrrr
rylrryr
ryryrry
rxlrrxr
rxrxrrx
ssmr
mlrrrr
rrr
ssmr
mlrrrr
rrr
00
000
11
111
11
111
0
...........................................................................
...........................................................................
0
0
cossin0
sincos0
+=+==
+=+==
+=+==
+−+++=+==
++++=+==
ψ
ψ
ψ
θθψ
θθψ
βαβ
ββ
ββ
βαα
αα
αα
( ) ( )[ ]srsrsrsrme iiiiiiiiPLT ββαααββα θθ +−−= sincos
Model Properties• The model contains one (two) zero sequence component equations, one pair of α-β component equations and (n – 3)/2 [or (n – 4)/2 for even phase numbers] pairs of x-y component
equations.• Stator to rotor coupling appears only in α-β component
equations; hence the torque is entirely governed by α-βcurrent components.
• A mechanism that would induce x-y or zero sequence components in rotor does not exist.
• CONCLUSION: Independent flux and torque control of a multi-phase machine asks for only two stator currents,
regardless of the number of phases.
The Idea• Only two currents required for the control of one machine – why
not use the remaining currents for control of other machines?• At most (n – 1)/2 [or (n – 2)/2 for even phase numbers] machine
can be controlled independently.• Why? To save in the number of required legs.
• How? By using a series connection. n-phase CC stator of stator of stator of voltage machine machine machine source 1 2 (n-1)/2 +
A 1 1 1 + B 2 Phase 2 Phase 2 + C 3 transpo- 3 transpo- 3 sition sition + N n n n
What is Phase Transposition?
• Flux/torque producing (α-β) currents of one machine must be non-flux/torque producing (x-y) currents for all the other machines, and vice versa.• Simple series connection cannot achieve this. Hence a transposition is required when connected
in series phases of stator windings.• How to establish the required rules for connection
of stator windings in series? Well, it follows directly from the decoupling (Clark’s)
transformation matrix.
Transposition Rules
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−
−−−
−−−
−−−
−−−
=
21
21
21...
21
21
21
21
21sin
212sin
213sin...
213sin
212sin
21sin0
21cos
212cos
213cos...
213cos
212cos
21cos1
......................................4sin8sin12sin...12sin8sin4sin0
4cos8cos12cos...12cos8cos4cos13sin6sin9sin...9sin6sin3sin0
3cos6cos9cos...9cos6cos3cos12sin4sin6sin...6sin4sin2sin0
2cos4cos6cos...6cos4cos2cos1sin2sin3sin...3sin2sinsin0
cos2cos3cos...3cos2coscos1
2
nnnnnn
nnnnnn
nC
α
αααααα
αααααααααααααααααααααααααααααααααααααααααααααααα
• Column 1: connect phases ‘a’ of all machines directly in series.• Column 2: connect phase ‘b’ of M1 to phase ‘c’ of M2 to phase ‘d’ of M3 etc.• Column 3: connect phase ‘c’ of M1 to phase ‘e’ of M2 to phase ‘g’ of M3 etc.• Column 4: connect phase ‘d’ of M1 to phase ‘g’ of M2 to phase ‘j’ of M3 etc.• And so on.
General Connectivity Matrix A B C D E F G H I J K L M N O
M1 a b c d e f g h I j k l m n …
M2 a b+1 c+2 d+3 e+4 f+5 g+6 h+7 i+8 j+9 k+10 l+11 m+12 n+13 … M3 a b+2 c+4 d+6 e+8 f+10 g+12 h+14 i+16 j+18 k+20 l+22 m+24 n+26 … M4 a b+3 c+6 d+9 e+12 f+15 g+18 h+21 i+24 j+27 k+30 l+33 m+36 n+39 … M5 a b+4 c+8 d+12 e+16 f+20 g+24 h+28 i+32 j+36 k+40 l+44 m+48 n+52 … M6 a b+5 c+10 d+15 e+20 f+25 g+30 h+35 i+40 j+45 k+50 l+55 m+60 n+65 … M7 a b+6 c+12 d+18 e+24 f+30 g+36 h+42 i+48 j+54 k+60 l+66 m+72 n+78 … …. … … … … … … … … … … …. … … … …
• Upper case letters: source phases.• Lower case letters: machine phases, according to the
spatial distribution around the air-gap.• Boxed: five-phase, seven-phase, eleven-phase and thirteen-
phase systems.
Two-Motor Five-Phase Drive
A B C D E
as1bs1cs1ds1es1
as2 bs2 cs2 ds2 es2
Stator ofmachine 1
Stator ofmachine 2
A B C D E M1 1 2 3 4 5 M2 1 3 5 2 4
21
21
21
21
21
dsesE
bsdsD
escsC
csbsB
asasA
vvvvvvvvvvvvvvv
+=+=+=+=+=
21
21
21
21
21
dsesE
bsdsD
escsC
csbsB
asasA
iiiiiiiiiiiiiii
==========
Three-Motor Seven-Phase Drive
7654321M1
5263741M36427531M2
GFEDCBA
A
B
C
D
E
F
G
Source
a1
b1
c1
d1
e1
f1
g1
a2
b2
c2
d2
e2
f2
g2
Machine 1 Machine 2
a3
b3
c3
d3
e3
f3
g3
Machine 3
Four-Motor Nine-Phase Drive
2
4
6
8
H IGFEDCBA
5
4
3
2
1
1
1
1
M4
M3
M2
M1
717417
842975
7
7
63849
96543
2
4
6
8
H IGFEDCBA
5
4
3
2
1
1
1
1
M4
M3
M2
M1
717417
842975
7
7
63849
96543
A
B
C
D
E
F
G
H
I
Source
a1
b1
c1
d1
e1
f1
g1
h1
i1
a2
b2
c2
d2
e2
f2
g2
h2
i2
Machine 1 Machine 2
a3
b3
c3
d3
e3
f3
g3
h3
i3
Machine 3
a4
b4
c4
Machine 4
Two-Motor Six-Phase Drive
A B C D E F M1 1 2 3 4 5 6 M2 1 3 5 1 3 5
A
B
C
D
E
F
Source
a1
b1
c1
d1
e1
f1
a2
b2
c2
Machine 1 Machine 2
Four-Motor Ten-Phase Drive A B C D E F G H I J M1 1 2 3 4 5 6 7 8 9 10 M2 1 3 5 7 9 1 3 5 7 9 M3 1 4 7 10 3 6 9 2 5 8 M4 1 5 9 3 7 1 5 9 3 7
A
B
C
D
E
F
G
H
I
J
Source
a1
b1
c1
d1
e1
f1
g1
h1
i1
j1
a2
b2
c2
d2
e2
f2
g2
h2
i2
j2
Machine 1 Machine 2
a3
b3
c3
d3
e3
Machine 3
a4
b4
c4
d4
e4
Machine 4
The Number of Connectable Machines
• All the cases illustrated so far have enabled series connection of the maximum number of machines
k = (n – 1)/2 [or k = (n – 2)/2 for even system phase numbers].
• An odd system phase number and the subsequent even number enable connection of, at best, the same number of machines. Hence odd numbers
save more inverter legs.• Machine phase numbers are all the same only if
the system phase number is a prime number.
The Number of Connectable Machines (n = odd)
n = an odd number, ≥ 5 Number of
connectable machines
Number of phases of machines in the multi-drive system
n = a prime
number
n = 5,7,11,13….. 2
1−=
nk n
n ≠ a prime
number
.....4,3,2 , == mln m
21−
=nk 12
......., , , ,−ml
nln
lnn
njnnnn ⋅⋅⋅⋅= .....3212
1−<
nk njnnnnnnn
,or ...... 3 ,or 2 ,or 1 ,
,...4,3,2
,.....21=
⋅⋅⋅⋅=m
lnjnnn m
2
1−<
nk 12
.....,or
,or ..... 2,or 1 ,
−mln
ln
ln
njnnnnn
The Number of Connectable Machines (n = even)
n = an even number, ≥ 6 Number of connectable machines Number of phases of
machines n/2 = prime
number
22−
=nk
k/2 are n-phase and k/2 are n/2-phase
n/2 ≠ prime number
.....5,4,3 , 2 == mn m 2
2−=
nk 22 2 ......., ,
2 ,
2 ,
−mnnnn
all other even numbers 2
2−<
nk n, ....4/,3/,2/ nnn
as appropriate
Vector Control of a Series-Connected Multi-Motor Drive
PI
jφr
e
2
n
i1*i2*i3*
in*
ids* = idsn
iqs*ω*
s P
θ
φr
ω
K1
1/s
• The same vector control schemes are applicable as for a three-phase machine
of the same type.• Current control in the stationary reference frame
is assumed throughout.• Figures illustrate indirect
rotor flux oriented controller for induction and
synchronous (permanent magnet and reluctance)
machines.
PI
jφr
e
2 n
i1*
i2*
i3*
in*
ids*
iqs* ω*
s P
θ
φr
ω
Creation of Phase Current References
( ) ( )
( ) ( )])1(sin)1(cos[2
------------------------------------------
]sincos[2
]sincos[2
)()(*)()(*)(*
)()(*)()(*)(*2
)()(*)()(*)(*1
αφαφ
αφαφ
φφ
−−−−−=
−−−=
−=
ninin
i
iin
i
iin
i
Mjr
Mjqs
Mjr
Mjds
Mjn
Mjr
Mjqs
Mjr
Mjds
Mj
Mjr
Mjqs
Mjr
Mjds
Mj
• Phase current references are created at first individually for each machine in the group.
• Inverter phase current references are built next, by summing the individual machine phase current references
according to the connection diagram.
Inverter Phase Current References
Three-motor seven-phase drive Two-motor six-phase drive
*3
*2
*1
*
*3
*2
*1
**3
*2
*1
*
*3
*2
*1
**3
*2
*1
*
*3
*2
*1
**3
*2
*1
*
efgG
bdfFfbeE
cgdDgecC
dcbBaaaA
iiii
iiiiiiii
iiiiiiii
iiiiiiii
++=
++=++=
++=++=
++=++=
*2
*1
**2
*1
*
*2
*1
**2
*1
*
*2
*1
**2
*1
*
5.0 5.0
5.0 5.0
5.0 5.0
cfFbeE
adDccC
bbBaaA
iiiiii
iiiiii
iiiiii
+=+=
+=+=
+=+=
Two-motor five-phase drive Four-motor nine-phase drive
*4
*3
*2
*1
*
*4
*3
*2
*1
**4
*3
*2
*1
*
*4
*3
*2
*1
**4
*3
*2
*1
*
*4
*3
*2
*1
**4
*3
*2
*1
*
*4
*3
*2
*1
**4
*3
*2
*1
*
)3/1(
)3/1( )3/1(
)3/1( )3/1(
)3/1( )3/1(
)3/1( )3/1(
cfhiI
bbfhHagdgG
ccbfFbhieE
adgdDciecC
becbBaaaaA
iiiii
iiiiiiiiii
iiiiiiiiii
iiiiiiiiii
iiiiiiiiii
+++=
+++=+++=
+++=+++=
+++=+++=
+++=+++=
*2
*1
**2
*1
*
*2
*1
*
*2
*1
**2
*1
*
dsesEbsdsD
escsC
csbsBasasA
iiiiii
iii
iiiiii
+=+=
+=
+=+=
Modelling Example: Two-Motor Five-Phase Drive
++−+
=
+++++
=
=
021
21
21
21
21
21
21
21
21
0
sys
sxs
yss
xss
de
bd
ec
cb
aa
E
D
C
B
A
INV
INVy
INVx
INV
INV
vvvvvvvv
vvvvvvvvvv
C
vvvvv
C
vvvvv
β
α
β
α
β
α
21
21
21
21
sysINVy
sxsINVx
yssINV
xssINV
iii
iii
iii
iii
β
α
ββ
αα
==
==
−==
==
Model in the stationary common reference frameInverter equations Rotor and torque equations
dtdi
Ldt
diLLiR
dtdi
LiRv
dtdi
Ldt
diLLiR
dtdi
LiRv
dtdi
LiRdt
diL
dtdi
LLiRv
dtdi
LiRdt
diL
dtdi
LLiRv
qrm
INVy
mlsINVys
INVy
lsINVys
INVy
drm
INVx
mlsINVxs
INVx
lsINVxs
INVx
INVq
lsINVqs
qrm
INVq
mlsINVqs
INVq
INVd
lsINVds
drm
INVd
mlsINVds
INVd
2222211
2222211
221
1111
221
1111
)(
)(
)(
)(
+++++=
+++++=
+++++=
+++++= ( ) ( )( )
( ) ( )( )111111
11111
111111
11111
0
0
drmlrINVdm
qrmlr
INVq
mqrr
qrmlrINVqm
drmlr
INVd
mdrr
iLLiLdt
diLL
dtdi
LiR
iLLiLdt
diLLdt
diLiR
++−+++=
++++++=
ω
ω
( ) ( )( )
( ) ( )( )222222
22222
222222
22222
0
0
drmlrINVxm
qrmlr
INVy
mqrr
qrmlrINVym
drmlr
INVx
mdrr
iLLiLdt
diLL
dtdi
LiR
iLLiLdt
diLLdt
diLiR
++−+++=
++++++=
ω
ω
[ ][ ]22222
11111
qrINVx
INVydrme
qrINVd
INVqdrme
iiiiLPT
iiiiLPT
−=
−=
Simulation Studies: Three-Motor Seven-Phase Drive
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-200
0
200
400
600
800
1000
1200
1400
1600
IM1
IM2
IM3
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.80
0.5
1
1.5
2
2.5
3
3.5
Rotor flux refe rence
Rotor flux space ve ctor ma gnitude in the ma chine
IM1,IM2 & IM3
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-5
0
5
10
15
20
25
IM1
IM2
IM3
0.3 sRated speed (1428 rpm)IM1
0.5 s1/3 of rated (476 rpm)IM3
0.4 s2/3 of rated (952 rpm)IM2
Instant of application
Speed command
0.3 sRated speed (1428 rpm)IM1
0.5 s1/3 of rated (476 rpm)IM3
0.4 s2/3 of rated (952 rpm)IM2
Instant of application
Speed command
Simulation Studies: Seven-Phase Drive (cont.)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-5
0
5
10
15
Stator phase "a" current reference (A) I
M1
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-15
-10
-5
0
5
Time (s )
Stator phase "a" current reference (A) I
M2
IM2
IM1
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-400
-200
0
200
400
600
800
Stator phase "a" voltage (V) I
M1
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-1200
-1000
-800
-600
-400
-200
0
200
400
Time (s )
Stator pase "a" voltage (V) I
M2
Stator phase current references Stator phase ‘a’ voltages
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-5
-4
-3
-2
-1
0
1
2
3
4
5
Time (s )
Stator phase "a" current reference (A) I
M3
IM3
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-150
-100
-50
0
50
100
150
200
Time (s )
Stator phase "a" voltage (V) I
M3 IM3
Simulation Studies: Seven-Phase Drive (cont.)
Inverter phase voltages
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-800
-400
0
400
800
1200
1600
2000
Source phase "a" voltage (V)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-2200
-1700
-1200
-700
-200
300
Time (s )
Source phase "b" voltage (V)pha se "b"
pha se "a "
Inverter output currents
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-10
-5
0
5
10
15
20
25
30
Source phase "a" current (A)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8-30
-25
-20
-15
-10
-5
0
5
10
Time (s )
Source phase "b" current (A)
Pha se "b"
Pha se "a "
Simulation Studies: Two-Motor Five-Phase Drive
(inverter included; hysteresis current control)
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 20
0.5
1
1.5
2
2.5
3
Time (s )
Rot
or fl
ux (W
b)
Re fe rence rotor flux for IM1 & IM2
Rotor flux in IM1 & IM2
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-10
0
10
20
Time (s )
Torq
ue IM
1 (N
m)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-1000
-500
0
500
1000
1500
2000Commanded & actual torque
S peed
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-5
0
5
10
15
20
Time (s )
Torq
ue IM
2 (N
m)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-200
0
200
400
600
800
Spe
ed IM
2 (rp
m)
Commanded & actual torque Speed
Spe
ed IM
1 (rp
m)
Currents Voltages
Simulation Studies: Five-Phase Drive (cont.)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-15
-10
-5
0
5
Time (s )
Sta
tor p
hase
'a' c
urre
nt re
fere
nce
IM1
(A)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-5
0
5
10
15
Sta
tor p
hase
'a' c
urre
nt re
fere
nce
IM2
(A)
IM1
IM2
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-2000
-1500
-1000
-500
0
500
Time (s )
Sta
tor p
hase
'a' v
olta
ge IM
1 (V
)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-600
-100
400
900
1400
1900
Sta
tor p
hase
'a' v
olta
ge IM
2 (V
)
IM1
IM2
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-1000
-800
-600
-400
-200
0
200
400
600
800
1000
Time (s )
Inve
rter p
hase
'a' v
olta
ge (V
)
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9-10
-8
-6
-4
-2
0
2
4
6
8
10
Time (s )
Inve
rter p
hase
'a' c
urre
nt (A
)
Reference current
Actual current
Simulation Studies: Five-Phase Drive (cont.)
(disturbance rejection)Machine 1
0.9 0.95 1 1.05 1.1 1.15 1.2-5
0
5
10
15
Time (s )
Torq
ue IM
1(N
m)
0.9 0.95 1 1.05 1.1 1.15 1.21200
1500
2000
Spe
ed IM
1 (rp
m)
Commanded & actua l torque Applied loadtorque
S peed
Machine 2
0.9 0.95 1 1.05 1.1 1.15 1.2-10
-5
0
5
10
Time (s )
Torq
ue IM
2 (N
m)
0.9 0.95 1 1.05 1.1 1.15 1.2650
750
800
Spe
ed IM
2 (rp
m)
Commanded & actual torque
Applied load torque
S peed
Simulation Studies: Five-Phase Drive (cont.)(reversing transients)Torque and speed responses Currents
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-20
-10
0
10
20
Time (s )
Torq
ue IM
1 (N
m)
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-2000
-1000
0
1000
2000
Spe
ed IM
1 (rp
m)
Commanded & actual torque
S peed
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-15
-10
-5
0
5
Time (s )
Sta
tor p
hase
'a' c
urre
nt re
fere
nce
IM1
(A)
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-5
0
5
10
15
Sta
tor p
hase
'a' c
urre
nt re
fere
nce
IM2
(A)
IM1
IM2
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-20
-15
-10
-5
0
5
10
15
20
Time (s )
Torq
ue IM
2 (N
m)
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-1000
-750
750
1000
Commanded & ac tua l torque
S peed
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2-10
-8
-6
-4
-2
0
2
4
6
8
10
Time (s )
Inve
rter p
hase
'a' c
urre
nt (A
)
Reference current
Actual current
Spe
ed IM
2 (rp
m)
Properties of Series-Connected Multi-Motor Drives• Advantages of the concept:
– Saving in the number of inverter legs (except in 6-phase case).– Simplicity of the control realisation within a single DSP –
execution of vector control algorithms in parallel with subsequent inverter phase current generation by summation.
– Braking energy can be directly used and does not have to circulate through the inverter.
• Disadvantages:– An increase in the stator winding losses and a much smaller
increase in the core losses.– Consequently, a somewhat worsened efficiency of the
complete drive system.
Experimental systemUtilised number of the inverter phases (maximum = 12)
5 6* 7 8* 9 10* 11**
*
12**
Number of connectable
machines
2 2 3 3 4 4 5*** 4**
** The twelve-phase supply can control at most four series-connected motors, rather than five.
***At least one machine must operate in speed sensorless mode.
• Four three-phase inverters with paralleled DC links. Each inverter with a DSP for current control and an encoder/resolver input..
• Vector control algorithm executed within a PC (C code). Communication between inverters and the PC through a dedicated FPGA board.
Experimental system (cont.)
• Six-phase two-motor drive system is in the commissioning stage.
Preliminary Experimental Results (steady states)
-6
-4
-2
0
2
4
Inve
rter p
hase
cur
rent
(A)
0 0.025 0.05 0.075 0.1 0.125 Time (seconds)
n (6phase) = 800rpm; n (3phase) = 600 rpm-4
-3
-2
-1
0
1
2
3
4
3-ph
ase
mot
or c
urre
nt (A
)
0 0.025 0.05 0.075 0.1 0.125 Time (seconds)
n (6phase) = 800rpm; n (3phase) = 600 rpm
0
0.5
1
1.5
2
Inve
rter c
urre
nt sp
ectru
m (A
rms)
0 25 50 75 100 Frequency (Hz)
n (6phase) = 800 rpmn (3phase) = 600 rpm
0
0.5
1
1.5
2
3-ph
ase
mot
or c
urre
nt sp
ectru
m (A
rms)
0 25 50 75 100 Frequency (Hz)
n (6phase) = 800 rpmn (3phase) = 600 rpm
Preliminary Experimental Results (cont.)
-6
-4
-2
0
2
4
6
Inve
rter p
hase
cur
rent
(A)
0 0.025 0.05 0.075 0.1 0.125 Time (seconds)
f (IM1) = 50 Hz; f (IM2) = 16.67
0
0.5
1
1.5
2
2.5
Inve
rter c
urre
nt sp
ectru
m (A
rms)
0 25 50 75 100 Frequency (Hz)
f (IM1) = 50 Hzf (IM2) = 16.67
Further Work• Experimental:
– Testing of the six-phase two-motor drive (transients and steady states).
– Testing of the five-phase two-motor drive (transients and steady states).
• Theoretical:– applicability of current control in the rotating reference
frame to multi-phase multi-motor drive systems.– detailed modelling (transient and steady state) for the
six-phase two-motor drive.– evaluation of the efficiency loss due to series
connection.
Thank You for Your Attention!