series and parallel equations

Upload: janmejaya-mishra

Post on 01-Jun-2018

216 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/9/2019 Series and Parallel Equations

    1/6

    R, L, C Circuits Prof. Townsend Page 1 of 6

    Series RC, RL, and RLC Circuits

    Parallel RC, RL, and RLC Circuitsby Prof. Townsend

    MTH 352 Fall 2005

    If you want a good description of the analysis of these circuits, go to the Wikipedia web site, for

    example http://en.wikipedia.org/wiki/RL_circuit.

    Analyses for series RC, parallel RL, and series RLC circuits were taken from class notes for

    Berkeleys EE 40, Introduction to Microelectronic Circuits. The lecture notes for this course are

    very well written. http://laser.eecs.berkeley.edu/ee40/lectures/cch-Lec09-021505-2-6p.pdf.

    General Information

    dQi

    dt= (1a) ( )

    t

    Q i d

    = (1b)

    R Rv Ri= (2a)1

    R Ri vR

    = (2b)

    ( )1 t

    C C

    Qv i d

    C C

    = = (3a) CC

    dvi C

    dt= (3b)

    LL

    div L

    dt= (4a) ( )

    1 tL Li v d

    L

    = (4b)

    Time Constants

    RL LR

    = (5a) RC RC = (5b)

    Natural frequency2

    0

    1

    LC = (6)

    Kirchhoffs voltage law (KVL): the net voltage (potential) change around a circuit is 0. You

    end up where you started.

    Kirchhoffs current law (KCL): the total current into a node = the total current leaving the node.

    The electrons have to go somewhere.

  • 8/9/2019 Series and Parallel Equations

    2/6

    R, L, C Circuits Prof. Townsend Page 2 of 6

    First Order Series RC circuit

    +

    -

    s

    C

    R

    KVL: R C sv v v+ = (7)

    Write in terms of Cv :

    From equation (2a)R R

    v Ri= (8)

    There is only one current in the loop so R Ci i i= = (9)

    From equation (3b) CR Cdv

    v Ri R C dt

    = =

    (10)

    Plug into equation (7)C

    C s

    dv

    RC v vdt + = (11a)

    Rewrite using equation (5a) CRC C sdv

    v vdt

    + = (11b)

    First Order Series RL circuit

    +

    -

    R

    L

    s

    KVL: R L sv v v+ = (12)

    Write in terms ofC

    v :

    From equation (2a) R Rv Ri= (13)

    From equation (4a) LL

    div L

    dt= (14)

    There is only one current in the loop so R Li i i= = (15)

    Plug into equation (12) sdi

    L Ri vdt

    + = (16)

    Divide by L1

    s

    di Ri v

    dt L L+ = (17a)

    Rewrite using equation (5a)1 1

    s

    RL

    dii v

    dt L+ = (17b)

  • 8/9/2019 Series and Parallel Equations

    3/6

    R, L, C Circuits Prof. Townsend Page 3 of 6

    First Order Parallel RC circuit

    s

    CR

    s

    R

    C

    KCL: C R si i i+ = (18)

    Write in terms of v :

    There is only one voltage drop so R Cv v v= = (19)

    From equation (2b)1

    Ri vR

    = (20)

    From equation (3b) Cdv

    i Cdt

    = (21)

    Plug into equation (18)1

    s

    dvC v i

    dt R+ = (22)

    Divide by C1 1

    s

    dvv i

    dt RC C + = (23a)

    Rewrite using equation (5b)1 1

    s

    RC

    dvv i

    dt C+ = (23b)

    First Order Parallel RL circuit

    s

    LR

    s

    LR

    KCL: L R si i i+ = (24)

    Write in terms of Li :

    From equation (2b)1

    R Ri vR

    = . (25)

    There is only one voltage drop so R Lv v v= = (26)

    From equation (4a)1 1 L

    R L

    dii v L

    R R dt

    = =

    (27)

    Plug into equation (24) LL sdiL

    i iR dt

    + = (28a)

    Rewrite using equation (5a) LL RL sdi

    i idt

    + = (28b)

  • 8/9/2019 Series and Parallel Equations

    4/6

    R, L, C Circuits Prof. Townsend Page 4 of 6

    Second Order Series RLC circuit

    +

    -

    C

    R

    L

    s

    KVL: L R C sv v v v+ + = (29)

    Write in terms of the loop current i , (equations (2a). (3a), (4a)).

    L

    div L

    dt= Rv Ri= ( )

    1 tCv i d

    C

    = (30)

    Plug into (29)L R C s

    v v v v+ + = :

    ( )1 t

    s

    diL Ri i d v

    dt C

    + + = (31)

    The integral is a problem so take the time derivative of every term in (31)2

    2

    1 sdvd i diL R idt dt C dt

    + + = (32)

    Divide by L2

    2

    1 1 sdvd i R di idt L dt LC L dt

    + + = (33a)

    Rewrite using equations (5a) and (6)22

    02

    1 1 s

    RL

    dvd i dii

    dt dt L dt

    + + = (33b)

  • 8/9/2019 Series and Parallel Equations

    5/6

    R, L, C Circuits Prof. Townsend Page 5 of 6

    Second Order Parallel RLC circuit

    s

    CLR

    s

    LR

    C

    LC

    KCL: LC R si i i+ = and L C LCi i i+ = Combine to give L R C si i i i+ + = (34)

    Write in terms of v , the voltage across all components (equations (2b). (3b), (4b)).

    ( )1 t

    L Li v dL

    =

    1R Ri v

    R=

    CC

    dvi C

    dt=

    (35)

    Plug into (34) L R C si i i i+ + =

    :

    ( )

    1 1t CL R s

    dv

    v d v C iL R dt

    + + = (36)

    The integral is a problem so take the time derivative of every term in (36). Reorder.2

    2

    1 1 sdid v dvC vdt R dt L dt

    + + = (37)

    Divide by C2

    2

    1 1 1 sdid v dv vdt RC dt LC C dt

    + + = (38a)

    Rewrite using equations (5b) and (6)2

    2

    02

    1 1 s

    RC

    did v dvv

    dt dt C dt

    + + = (38b)

  • 8/9/2019 Series and Parallel Equations

    6/6

    R, L, C Circuits Prof. Townsend Page 6 of 6

    Summary

    Circuit Differential Equation Form

    First Order Series RC circuit 1 1CC s

    RC RC

    dvv v

    dt + = (11b)

    First Order Series RL circuit 1 1s

    RL

    dii v

    dt L+ = (17b)

    First Order Parallel RC circuit 1 1s

    RC

    dvv i

    dt C+ = (23b)

    First Order Parallel RL circuit 1 1LL s

    RL RL

    dii i

    dt + = (28b)

    First Order General Form

    ( )

    1dxx f t

    dt + =

    Second Order Series RLC circuit 22

    02

    1 1 s

    RL

    dvd i dii

    dt dt L dt

    + + = (33b)

    Second Order Parallel RLC circuit 22

    02

    1 1 s

    RC

    did v dvv

    dt dt C dt

    + + = (38b)

    Second Order General Form

    ( )

    22

    02

    1d x dxx f t

    dt dt

    + + =

    Time ConstantsRL

    L

    R = (5a)

    RC RC = (5b)

    Natural frequency 20

    1

    LC = (6)