sensitivity analysis-case ii

Upload: atg11121

Post on 03-Jun-2018

227 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/11/2019 Sensitivity Analysis-Case II

    1/15

    Case 2

    Knitting Department

    Submitted to- Dr. Hitesh Arora

    By-

    Abhijeet Agarwal 231005

    Abhinav Joshi 231007

    Atin Garg 231036

  • 8/11/2019 Sensitivity Analysis-Case II

    2/15

    X1= Units of Product 1

    X2 = Units of Product 2

    X3 = Units of Product 3

    Maximize Z= 7x1 + 3x2 + 9x3 (Profit)

    S.t.

    Labour 4x1 + 5x2 + 6x3

  • 8/11/2019 Sensitivity Analysis-Case II

    3/15

    7 3 9 0 0 0

    B.V Cb X1 X2 X3 S1 S2 S3 Sol. Ratio

    S1 0 4 5 6 1 0 0 360 60

    S2 0 2 4 6 0 1 0 300 50

    S3 0 9 5 6 0 0 1 600 100

    Cj-Zj 7 3 9 0 0 0

    B.V Cb X1 X2 X3 S1 S2 S3 Sol. Ratio

    S1 0 2 1 0 1 -1 0 60 30

    X3 9 1/3 2/3 1 0 1/6 0 50 150

    S3 0 7 1 0 0 -1 1 300 300/7

    Cj-Zj 4 -3 0 0 -3/2 0

  • 8/11/2019 Sensitivity Analysis-Case II

    4/15

    7 3 9 0 0 0

    B.V Cb X1 X2 X3 S1 S2 S3 Sol. Ratio

    X1 7 1 0 -1/2 0 30 -

    X3 9 0 1 -1/6 1/3 0 40 120

    S3 0 0 -5/2 0 -7/2 5/2 1 90 36

    Cj-Zj 0 -5 0 -2 0

    B.V Cb X1 X2 X3 S1 S2 S3 Sol.

    X1 7 1 0 0 -1/5 0 1/5 48

    X3 9 0 5/6 1 3/10 0 -2/15 28

    S2 0 0 -1 0 -7/5 -1 2/5 36

    Cj-Zj 0 -9/2 0 -13/10 0 -1/5

  • 8/11/2019 Sensitivity Analysis-Case II

    5/15

    Maximize Z 588

    Units of Product I 48

    Units of Product II 0

    Units of Product III 28

    Labor Usage 360

  • 8/11/2019 Sensitivity Analysis-Case II

    6/15

  • 8/11/2019 Sensitivity Analysis-Case II

    7/15

    Adjustable Cells

    Final Reduced Objective Allowable Allowable

    Cell Name Value Cost Coefficient Increase Decrease

    $E$4 x1 48 0 7 6.5 1

    $E$5 x2 0 -4.5 3 4.5 1E+30

    $E$6 x3 28 0 9 1.5 4.333333333

    Constraints

    Final Shadow Constraint Allowable Allowable

    Cell Name Value Price R.H. Side Increase Decrease

    $D$8 Labor Usage x3 360 1.3 360 25.71428571 93.33333333

    $D$9

    Machine Usage

    x3 264 0 300 1E+30 36

    $D$10

    Material Usage

    x3 600 0.2 600 210 90

  • 8/11/2019 Sensitivity Analysis-Case II

    8/15

  • 8/11/2019 Sensitivity Analysis-Case II

    9/15

  • 8/11/2019 Sensitivity Analysis-Case II

    10/15

    As P1 is a basic variable,so for basic variable

    Maxykj>0{Cj-Zj /ykj}

  • 8/11/2019 Sensitivity Analysis-Case II

    11/15

    As allowable increase is 6.5 so increasing by 3would not impact the optimal solution

    But as coefficient of x1 will change

    Hence new Z=732

    Which is shown by excel solver.

    Q4-What would the values in the optimal solution be if

    the objective coefficient of x1 were to increased by 3?

  • 8/11/2019 Sensitivity Analysis-Case II

    12/15

    For labour constraint

    Maxbik>0{-Xbi / bik}

  • 8/11/2019 Sensitivity Analysis-Case II

    13/15

    Q6- What would the values in the optimal solution be if

    the amount of labor available decreased by 10 hours?

    From the excel solver solution

    Z= 575

    x1=50x2=0

    X3=25

  • 8/11/2019 Sensitivity Analysis-Case II

    14/15

    For material constraint

    Max bik>0{-Xbi / bik}

  • 8/11/2019 Sensitivity Analysis-Case II

    15/15