select cust_id, reg_no, rent_date from rent where reg_no in (select reg_no from car
DESCRIPTION
SELECT cust_id, reg_no, rent_date FROM Rent WHERE reg_no IN (SELECT reg_no FROM Car WHERE model_id = 6) SELECT cust_id, reg_no FROM Rent WHERE reg_no IN (SELECT reg_no FROM Car WHERE rate = 45) SELECT reg_no, model_id FROM Car WHERE rate IN (SELECT rate FROM Car - PowerPoint PPT PresentationTRANSCRIPT
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1. SELECT cust_id, reg_no, rent_dateFROM RentWHERE reg_no IN
(SELECT reg_noFROM CarWHERE model_id = 6)
2. SELECT cust_id, reg_noFROM RentWHERE reg_no IN
(SELECT reg_noFROM CarWHERE rate = 45)
3. SELECT reg_no, model_idFROM CarWHERE rate IN
(SELECT rateFROM CarWHERE reg_no = 'BAA-441')
4. SELECT cust_id, Rent.reg_no, rent_dateFROM Rent, CarWHERE model_id = 6AND Rent.reg_no = Car.reg_no
5. SELECT cust_id, Rent.reg_noFROM Rent, Car WHERE rate = 45AND Rent.reg_no = Car.reg_no
6. SELECT C1.reg_no, C1.model_idFROM Car AS C1, Car AS C2WHERE C2.reg_no = 'BAA-441'AND C1.rate = C2.rate
Solutions (Multitable)
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7. SELECT C1.reg_no, C1.model_idFROM Car AS C1, Car AS C2WHERE C2.rate <> 65AND C1.reg_no = C2.reg_no
8. SELECT cust_id, reg_noFROM RentWHERE rent_date IN (#1-15-2005#, #1-26-2005#, #2-6-2005#)
9. SELECT reg_noFROM Car, CarTypeWHERE year = 2004AND CarType.model_id = Car.model_id
10. SELECT *FROM RentWHERE return_date IS NULL
11. SELECT rent_id, (return_date - rent_date) * rate AS ‘total price’FROM Rent, CarWHERE Rent.reg_no = Car.reg_noAND return_date IS NOT NULL
Solutions