section 6.2 trigonometric functions unit circle approach
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Section 6.2
Trigonometric Functions:
Unit Circle Approach
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2 2,2 2
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Make a second congruent triangle.
Use Pythagorean Theorem to find b.
This triangle is equilateral so all sides are 1. 2a = 1 so a = .
12
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Find the exact value of each expression.3 5 9(a) cos135 (b) tan (c) sin 225 (d) cos (e) sin4 4 4
2 2 2(a) The point , corresponds to 35 so cos 1352 2 2
2 2 3(b) The point , corresponds to 2 2 4
23 2so tan 14 2
2
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Find the exact value of each expression.3 5 9(a) cos135 (b) tan (c) sin 225 (d) cos (e) sin4 4 4
2 2 2(c) The point , corresponds to 225 so sin 2252 2 2
2 2 5 5 2(d) The point , corresponds to so cos2 2 4 4 2
2 2 9(e) The point , corresponds to 2 2 4
9 2so sin4 2
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4 7Find: (a) cos 150 (b) sin ( 30 ) (c) tan (d) sin3 6
5 3(a) cos 150 cos6 2
1(b) sin ( 30 ) sin6 2
34 2(c) tan 313
2
7 1(d) sin6 2
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Your calculator has buttons for sin, cos, and tan so to find values of the remaining 3 trigonometric functions we use:
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2 24 and 3 so 16 9 5a b r a b