section 3.3 dividing polynomials; remainder and factor theorems
TRANSCRIPT
- Slide 1
- Section 3.3 Dividing Polynomials; Remainder and Factor Theorems
- Slide 2
- Long Division of Polynomials and The Division Algorithm
- Slide 3
- Slide 4
- Long Division of Polynomials
- Slide 5
- Slide 6
- Long Division of Polynomials with Missing Terms You need to leave a hole when you have missing terms. This technique will help you line up like terms. See the dividend above.
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- Slide 8
- Example Divide using Long Division.
- Slide 9
- Example Divide using Long Division.
- Slide 10
- Dividing Polynomials Using Synthetic Division
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- Slide 12
- Comparison of Long Division and Synthetic Division of X 3 +4x 2 -5x+5 divided by x-3
- Slide 13
- Steps of Synthetic Division dividing 5x 3 +6x+8 by x+2 Put in a 0 for the missing term.
- Slide 14
- Using synthetic division instead of long division. Notice that the divisor has to be a binomial of degree 1 with no coefficients. Thus:
- Slide 15
- Example Divide using synthetic division.
- Slide 16
- The Remainder Theorem
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- If you are given the function f(x)=x 3 - 4x 2 +5x+3 and you want to find f(2), then the remainder of this function when divided by x-2 will give you f(2) f(2)=5
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- Slide 19
- Example Use synthetic division and the remainder theorem to find the indicated function value.
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- The Factor Theorem
- Slide 21
- Solve the equation 2x 3 -3x 2 -11x+6=0 given that 3 is a zero of f(x)=2x 3 -3x 2 -11x+6. The factor theorem tells us that x-3 is a factor of f(x). So we will use both synthetic division and long division to show this and to find another factor. Another factor
- Slide 22
- Example Solve the equation 5x 2 + 9x 2=0 given that -2 is a zero of f(x)= 5x 2 + 9x - 2
- Slide 23
- Example Solve the equation x 3 - 5x 2 + 9x - 45 = 0 given that 5 is a zero of f(x)= x 3 - 5x 2 + 9x 45. Consider all complex number solutions.
- Slide 24
- (a) (b) (c) (d)
- Slide 25
- (a) (b) (c) (d)