Current Score : 19 / 19 Due : Wednesday, February 26 2014 11:59 PM EST

1. 1/1 points | Previous Answers SCalcET7 3.1.004.

Differentiate the function.

f '(x) =

2. 1/1 points | Previous Answers SCalcET7 3.1.005.

Differentiate the function.

f '(t) =

3. 1/1 points | Previous Answers SCalcET7 3.1.007.

Differentiate the function.

Section 3.1 HW (Homework)Frances CoronelMAT 151 Calculus I, Spring 2014, section 01, Spring 2014Instructor: Ira Walker

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f(x) = e6

f(t) = 7 − t23

f(x) = x5 − 4x + 3

f '(x) =

4. 1/1 points | Previous Answers SCalcET7 3.1.009.

Differentiate the function.

g'(x) =

5. 1/1 points | Previous Answers SCalcET7 3.1.011.

Differentiate the function.

g'(t) =

6. 1/1 points | Previous Answers SCalcET7 3.1.013.

Differentiate the function.

7. 1/1 points | Previous Answers SCalcET7 3.1.015.

Differentiate the function.

g(x) = x2(1 − 6x)

g(t) = 2t−1/4

A(s) = − 13s6

A'(s) =

R(a) = (5a + 1)2

R'(a) =

8. 1/1 points | Previous Answers SCalcET7 3.1.019.

Differentiate the function.

y' =

9. 1/1 points | Previous Answers SCalcET7 3.1.023.MI.

Differentiate the function.

y' = Master ItDifferentiate the function.

Part 1 of 3

The function is a quotient. It is important to remember that the derivative of a quotient is not the

quotient of the derivatives Instead, we find the derivative by first simplifying the quotient. We can re-write it asfollows.

Remembering that and that we will get the following.

y = 3ex + 4x3

y = 6x2 + 4x + 4x

y = 3x2 + 3x + 9x

y = 3x2 + 3x + 9x

f(x)/g(x)

f '(x)/g'(x).

y = = + + 3x2 + 3x + 9x

3x2

x

3xx

9x

= x1/2x = xn − m,xn

xm

= 3x

= 3x

= 9x

3x2

x(No Response)

3xx

(No Response)

9x

(No Response)

10.1/1 points | Previous Answers SCalcET7 3.1.024.

Differentiate the function.

11.1/1 points | Previous Answers SCalcET7 3.1.027.

Differentiate the function.

12.1/1 points | Previous Answers SCalcET7 3.1.029.

Differentiate the function.

13.1/1 points | Previous Answers SCalcET7 3.1.031.

Differentiate the function.

g(u) = u + 7 10u

g'(u) =

H(x) = (x + x−1)3

H'(x) =

u = + 6t7t7

u' =

z = + BeyAy13

z' =

14.1/1 points | Previous Answers SCalcET7 3.1.032.

Differentiate the function.

15.1/1 points | Previous Answers SCalcET7 3.1.034.

Find an equation of the tangent line to the curve at the given point.

16.2/2 points | Previous Answers SCalcET7 3.1.035.

Find equations of the tangent line and normal line to the curve at the given point.

y = ex + 5 + 8

y' =

y = x4 + 7x2 − x, (1, 7)

y =

y = x4 + 3ex, (0, 3)

tangent line y =

normal line y =

17.2/2 points | Previous Answers SCalcET7 3.1.037.

Find an equation of the tangent line to the curve at the given point.

y =

Illustrate by graphing the curve and the tangent line on the same screen.

y = 4x2 − x3, (1, 3)