A.I. SandaNagoya University

Nagoya Japan

FPCP2004Daegu, KOREA

A partial list of things that interested me

1

1

sin 2 0.728 0.056 0.023 Belle

sin 2 0.722 0.040 0.023 Babar

Very impressiveIt will get even better!

ψKS asymmetry

KM mechanism is correct description of CP violation at low energies!

Dramatic sign flip in sin2Φ1 with new VD 　 at Belle. While ΨKS value for sin2Φ1 is stable with bo

th VD, Monte-Carlo studies supports that there nothing wrong, it is hard for me to understand. 　（ I look forward to Hazumi’s talk. I hope we can be convinced.) 　

A partial list of things that interested me 　 p.1

Φ KS asymmetry

Belle( ) ( )

cos sin( ) ( )

t t

A Mt S Mtt t

Milky 　 Way

A partial list of things that interested me 　 p.2

Why are these different?

Very useful for NP searches

As for CPV, my gut feeling is that it must be there!

( 0.13 0.60 0.56)% Belle

N NN N

Same sign dilepton CP asymmetry

Belle+Babar

( ) ( )0.113 0.019

( ) ( )

B K B K

B K B K

0 0

0 0

( ) ( )0.04 0.04

( ) ( )

B K B K

B K B K

B→Kπ CP asymmetries

obviously Belle data must come within the circle

ππ CP asymmetries

pQCD predicted itWith correct sign! Keum, Li, AIS

Babar New!

A partial list of things that interested me 　 p.3

Lyra

Altair

July 7

0.170.160.43 0.51 BelleAsym

A partial list of things that interested me 　 p.4

Good news for isospin analysis

CP violation should be here too!

Looks promising!

Ways to unfold 4 fold ambiguities.

0 0 -6

0 0 0.44 0.22 -60.48 0.18

( ) (1.17 0.32 0.10) 10 Babar

( ) (2.32 ) 10 Belle

Br B

Br B

Observation of B→π0 π0

3*

0

+

*+

0

i

cb us

ub cs

B D K K

B D K K e

V V

V V

Observation of B→DK

Φ3

A partial list of things that interested me 　 p.5

B→VV polarization measurmentsMust for the new physics searches

0 0 0 0

Naive prediction

+10% K KC A

*B K

B→π0KS CP asymmetry

A partial list of things that interested me 　 p.6

Indication of things to expect in the future!

A partial list of things that interested me 　 p. ８

Belle

A partial list of things that interested me 　 p. ９

Not just limits. A quest for the discovery!

Foreword: kaons again?In spite of a long history the K system is still a laboratory for the flavour physics, an interferometry system, a repository of all kinds of CP violation and can be a sensitive probe for NP.. Then:

YES, kaons again!

Vincenzo Patera*LNF/INFN

1030.189.0 1047.1)(

KBr

A partial list of things that interested me 　 p.10

He does not need to apologizeIt is a good sign for FP thatK physics continues after 57 years!

KL0@E391a:Run I (2004)Expected

sensitivity

by Run I:

4÷9x10-10

Results from Run I in fall 2004

Requesting Run II in 2005

*11

2

4

3.2

110 10)5.06.2(10

Im

166

)(1048.1)(

ttt

SML GeV

mmKBR

A dream for a theorist, a

nightmare for an experimentalist. All

neutral, 2/3 invisible final state:

“Nothing to nothing”

A partial list of things that interested me 　 p.11

( , )

*

*ud ub

ucd cb

V VV V

132

*

*td tb

tcd cb

V VV V

(1,0)

SLAC notationIn honor of Bjorken

Fermilab workshop 1988

Correct a mistake in the CKM fitter figure

This solution is not allowed by ΨKS asymmetry!

AIS WIN2002, I.I. Bigi and AIS, to appear

Notation

0 01

0 02

B p B q B

B p B q B

Mass eigenstates

1 1 11 11 12 12

2 2 11 11 12 12

2 2 2

2 2 2

i i q iM M M

p

i i q iM M M

p

Mass eigenvalues

2 1 12 122Re2

q iM M M M

p

Mass difference

* *2 12 12

12 12

* *12 12

12 12

2

2

2

2

iMq

ip M

iMq

ip M

Coefficients1 2 B B

1

1

1

2*212 12

212 12

i

ii

M M eqe

p M M e

112 12

iM M e

1 12 22 1 12 122Re 2i iM M M e M e M

1212sin Im ( ) sin 2 Im ( )

iqMt f M t e f

p

112 122Resign MM M

This way -π/2< φ1 < π/2

± cancel but we need to know the sign

*122

sin Im ( ) sin Im ( )

MqMt f Mt f

p M

2. Define △M>0 H LM M M

*122

sin Im ( ) sin Im ( )Mq

Mt f Mt fp M

1. Method which cancels △M dependence

*122Mq

p M

3. Try to cancel q/p dependence

12sin Im ( ) sin Re Im ( )q q q

Mt f M t fp p p

Discussions on the marketSign of ΔM cancel but you need to know the sign

ΔM>0, but you need to know the sign

Sign of q/p cancel but you need to know the sign

2 2( ) ((1 ) )sign M sign

-

++

-

( )sign M

1 2 2

2 (1 )sin 2

(1 )

-

+

+

-

1sin 2

-+

+-

+

+ -

- 1sin sin 2M

These are allowed region for ψKS asym>0

1 1sin 2 0, cos2 0

1 1sin 2 0, cos2 0

Excluded

.)(27.0.)(72.2)cos(2β 50.079.0 syststat

CL 86.6%at excluded

68.0

)β2(sin1)cos(2β 2

Babar

Lets assume that ΔM contains NP.ε and ΔM 　 constraints are removed as they may contain effects of new physics

Constraint from ψKS asymmetryassume sin2φis given by exp.

ubV

c

t

u 132

KM parameters are not directly related to ψKS asymmetry

u c experimentally known

1Given all others are fixed

12iSMR e

2 ie

2iNPR e

12 212 12 12 2

iSM NP i

SM NPM

M M M R e R e

2

2

iMe

c

t

u 132

12 2 2 i i iSM NPR e R e e

1212 2SM i

SMM

M R e

12i

SMR e

2 ie2iNPR e

c

t1

2

u

12 2 2 i i iSM NPR e R e e

If Φ1 <0, RNP gets bigger

( 0.13 0.60 0.56)%

N NN N

1.0006 0.0030 0.0028qp

Belle hep-ex/0408012

4

4

1

1

SL

pqN N

AN N p

q

12

2

2

2 21

2

8

3 (1Im

)SLc

b

mA

M m

*12

c

* *12

In the limit 0,

=

u

ud u

td b

c cb

t

b d

m m

V

M

V

V

V V

V

1

12*

* *2Im Im

td tb

ud ub cd cbSL

V V V VA

M V V NP

NP will get in the way ofcancellation

1* *

*2

12

I n the limit 0,

is realtbt

ub cbud c

d

d

c u

V

m

M

V

V

V

m

V

V

1)ΨKS asymmetry sinφ

2) Φ ３ determination

230

( ) ( )1 2 cos cos

2 ( )CP CP

CP B B B

B D K B D KR r r

B D K

3

( ) ( )2 sin sin /

( ) ( )CP CP

CP B B CPCP CP

B D K B D KA r R

B D K B D K

Four fold ambiguity in Determining φ ３

Large φ3 solutionIs almost excluded

4 fold degeneracy

*

*

ub us

Ttb ts

T V Vr

P V V EW

TP

rP

T P EWP

Leave it to Yoshikawa to talk aboutThe importance of EW penguinsAnd other general analysis

2 2

32 22 sin sin

K K TCP T

K K

A AA r

A A

2 20 00

32 20 0\

32 sin sin2 sin sinK K T

CP

K

CT

K

C

A AA r r

A A

2 200 0000

2 200 0032 sin sinC

CK K

CP

K K

A AA

A Ar

0 0 0( ) ( ) ( ) 0Asym K Asym K Asym K

+- 00

00

CP aymmetry A - A

A +10%

CP CP

CP

CP violation in the decay amplitude

( ) ( )0.113 0.019

( ) ( )

B K B K

B K B K

Belle+Babar

0 0

0 0

( ) ( )0.04 0.04

( ) ( )

B K B K

B K B K

See Yoshikawa’s talk for details

A naïve analysisNeglect all r2

terms and annihilation just to illustrate a point

Cancellation?

0 0The role of C in B

2

2

2

2

0 0 0

0

0

( ) ( )

( ) (1 )

( ) (1 )

id

i

i

i

w

d

e

ew

P Ce

T TPC

eT

PA B T e

T

A B T

PA B T

T

eT

pi pi data => C/T = 0.70 e^{i 63^o}Substituting the above C/T into the K pi data, we obtain T/P = 0.16 e^{-25^o i}, P^{ew}/P = 0.26 e^{-70 ^o i} So, it is possible to accommodate all data by increasing only C.

See Yoshikawa’s talk for details

Charng and Li

ΦKS 　 asymmetry

2 2

* * *

4

0

tb ts cb cs ub usV V V V V V

( ) ( ) S SK K

* tb tsV V

0B

d

b c

csd

SK

*cb csV V

Standard model predicts equal CP violation for these decay modes

Im( ( ))qp f

I believe that some new physics effect might be there.

But not at the level of 50%.It is probably at 1% level.

So, precision experiments are needed!

Naïve factorizationWe expect |A00 |>> |A-- |>> |A++

|

New physics must show up in B→ ΦK*

asymmetry

f A A

fL should dominate

|f00|>>|f--|>> |f++| 1

f

f

Φ

b s

s s

A. Kagan

3 possibilities

BΦ K*0 0 No spin flip

Spin filp of s quark

Spin flip of both s quarks

00LA A

A

ACP + 00LA A

A A A+

A A A-

This is a naïve argument! Non factorizable diagrams ect.

If there is NPit should appear here

I am not surprised if so called new physics effects went away! Continued search is absolutely necessary.

Don’t say 1035 , it is not enough! SUPERB with 1043 is strongly

encouraged! Many interesting physics to do for many

years to come! Lets have fun!