se 402 3 conservation of mass
TRANSCRIPT
5.3 – To explain the law of conversation of matter in a chemical change after conducting an experiment involving a neutralization reaction
CONSERVATION OF MASS
Chemical equations consist of reactants and products
Matter can be neither created nor destroyed
Reactants Products
2 H2 + O2 2 H2O
…the mass of the reactants is always equal to the mass
of the products
2H2 + O2 2H2OReactants Products
4g + 32g = 36g 36 g = 36 g
mass of reactants = mass of products
In a chemical reaction below, how many grams of oxygen (O2) was used given the following information.
29g ? 88g 48g
29 g + O2 = 88 g + 4829 g + O2 = 136 gO2 = 107 grams
10 24 2 22 + 13 8 + 10 OC O COH H
Water (H2O) can be broken down into hydrogen and oxygen.
During a reaction you notice that 9 grams of water will produce 8 grams of oxygen (O2) and a certain amount of hydrogen (H2). How much hydrogen is produced?
9 g = ? + 8 g H2 = 1 grams
2 H2O 2 H2 +O2
2 H2O 2 H2 + O2
37 grams sulphuric acid (H2SO4) is neutralized with calcium hydroxide (Ca(OH)2).
During the reaction, calcium sulphate (CaSO4), a salt, and water are produced. If 14g of water & 51g of salt are produced, how much calcium hydroxide was initially used?
37 g + Ca(OH)2 = 51 g + 14 g
Ca(OH)2 = 28 grams
H2SO4+ Ca(OH)2 CaSO4 + 2H2O
37 g + Ca(OH)2 = 65 g
o Conservation of matter states the mass of the reactants will equal the mass of the products.
MASS OF REACTANTS = MASS OF PRODUCTS
Study guide, Module 3, page 36 Worksheet # 10