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Rock Properties Chandran Udumbasseri Technical Consultant Reservoir

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Page 1: Rock properties

Rock Properties Chandran Udumbasseri

Technical Consultant

Reservoir

Page 2: Rock properties

Porosity

• Porosity is a measure of the storage capacity of a reservoir. It is defined as the ratio of pore volume to bulk volume, and it may be expressed as either a percent or a fraction.

• In equation form, Porosity, φ, is given as

Page 3: Rock properties

Porosity • Total porosity and effective porosity • Total porosity is the ratio of all pore spaces to the bulk volume of rock • Effective porosity is the ratio of interconnected void spaces to the bulk volume

of the rock • Only effective porosity contains fluids that can be produced from a well • For granular rocks like sand stone the effective porosity approaches total

porosity • For some limestone and cemented rocks there is large variation from effective

to total porosity • There two types of porosity classified based on origination, the primary and

secondary. • Primary porosity is caused during the original deposition of sediment.

Secondary porosity is cause by geological process like ground stresses, water movement, other geological activities.

• For uniform grains the porosity in independent of their size. For cubic packing the porosity is 47.6%, for rhombohedral packing it is 26%

• Porosity is depending on grain size distribution, grain arrangement, cementing material quantity.

Page 4: Rock properties

Rock packing

Page 5: Rock properties

Rock porosity…..

• Petroleum explorenists sedimentary rock’s stratigraphy and sedimentology to conclude the possibility for the existence of petroleum system

• Then a decision is taken on drilling and well completion • Significant part is to estimate the possible quantity of crude oil • Reservoir characteristic is determined through a study of rock

properties • Sedimentary rocks are made up of sandstone (quartz sand),

carbonate mud or dolomite. Dolomite reservoirs are good one compared limestone as porosity is better in the former type.

• Sandstone rocks are composed of silica grains with minimal fragmented particles.

• Carbonate rocks are made up of fossils of non even size.

Page 6: Rock properties

Porosity ….

• Porosity gives the information on the capacity of reservoirs to contain fluids

• The primary porosity (formed during original sedimentation) has two types, inter and intra particle. Inter particle porosity is lost through cementing. Intra particle porosity is created by carbonate interiors

• Secondary porosity which was formed by geographical processes can lead to dissolution porosity due to carbonate dissolution and leaching. Another type of secondary porosity is from fracture of rock leading to less volume

Page 7: Rock properties

Dissolution and fracture porosity

Page 8: Rock properties

Porosity and permeability

• Morphological porosity – Caternary in which the pore open to more than one throat

passage – Cul-de-sac in which the pore open to only one throat

passage – Closed pore in which there is no connection with other

pores.

• Permeability is one ability for fluids to communicate through porous medium

• Rock can be porous without being permeable • Rock with permeability is suitable for fluid

accumulation

Page 9: Rock properties

Pores-geographical processes

• The pores created during the initial sedimentation can under go changes in the subsequent processes due to weight and dissolution.

• The weight from added top sediment can press the pores which may get closed or some may get isolated

• This secondary process alter pore space and fuid flow through pores. The fluid that was trapped in the closed pores cannot be produced.

• The brine that flow through the rock can plug the pores by cementing grain to grain contact area.

• Sometimes the cation exchange can take place. The calcium ion from lime may get replaced by Mg. this usually results in the space reduction thus increasing available pores.

Page 10: Rock properties

Calcite sediment to dolomite

Page 11: Rock properties

Pore volume –contributory factors

• Factors effecting pore volume:

– Grain size and packing pattern

– Shape of the grains: spherical grains makes good packing thus reduce pore volume.

– Size of gains: uniformity in size causes uniformity in pore volume

– Compaction causes reduction in volume. Sandstone is less compressive compared to clay

Page 12: Rock properties

Measurement-porosity

• Sample collection: core sample may be collected during drilling from known depths

• Small samples called core plugs are cut from the core sample

• Samples are then cleaned using solvents to remove oil and water present in the sample

• Bulk volume is the sum of grain volume and pore volume

• Bulk volume, Vb = Vg +Vp where Vg is grain volume and Vp is pore volume

• Absolute Porosity, φ, = Vp / Vb

Page 13: Rock properties

Porosity-bulk volume measurement

• Cylindrical core sample is cut out with cross sectional area, Ac and length, L

• Volume is Ac*L

• For irregular sample use a water displacement method

• The sample is weighed initially and coated with wax and again weighed. Note down both weights

• Take certain volume of solvent in a graduated glass cylinder. The volume of solvent should be enough to submerge the sample. Note the volume . Now hang the sample in the glass cylinder as shown in (a) so that the sample submerge in the solvent without any adhered air bubbles. Note down the volume on the cylinder. The difference in volume from the initial one gives the physical volume of the sample.

• The wax coating volume should be subtracted from above noted volume to get the bulk volume ( wax coating volume = coating weight /wax density)

Page 14: Rock properties

Bulk volume and grain volume

Page 15: Rock properties

Porosity calculation

• If the rock is made of uniform grain like quartz then grain volume is

• Vg = mass of core sample/density of the mineral (core sample)

• For core with unknown mineral, an uncoated core sample in immersed in suitable solvent as before for sufficient time so that all the pores are filled with solvent. Now note down the volume on the cylinder. The difference from initial volume gives the grain volume (Vg)

• Knowing both bulk volume and grain volume, then porosity may be calculated

Page 16: Rock properties

Pore measurement

• Measuring pore directly gives more accurate porosity value

• The cleaned and dried core sample is weighed and placed in a vacuum flask as shown for a few hours

• Now introduce water slowly until the sample is completely submerged in water.

• Now take out sample and shake the sample to remove outside water and weigh quickly.

• Increase in mass is the weight of water taken up by pores. The water weight may be converted to volume of water which is the pore volume

• Porosity, φ = pore volume/bulk volume

Page 17: Rock properties

Pore volume measurement

Page 18: Rock properties

Porosity -indirect method • Porosity can be measured indirectly using well logs. Sonic (acoustic) log is

one such method.

• The instrument sonde generates sound waves which travel in the vicinity of well bore and their return time is noted

• Travel time (generation time and return detection time) is recorded with depth of reservoir.

• Travel time is related to porosity by the equation:

Page 19: Rock properties

Formation density log

• Another logging sonde that emits gamma rays is used to compute bulk density of the reservoir.

• This bulk density value is related to porosity:

Page 20: Rock properties

Compressibility

• It is the shrinkage of a unit volume of substance per unit increase in pressure

•Minus sign is added to give a positive compressibility value • compressibility slightly vary with temperature •All minerals found in sedimentary rocks are elastic in nature

Page 21: Rock properties

Compressibility

• Reservoir rocks are subjected to overburden pressure from all rocks strata above it

• Also the fluids in the pore exert pressure on the grains. This pore pressure in independent of the overburden pressure. The pore pressure is the atmospheric pressure allowing air to move within cavities.

• An increase in overburden pressure causes compaction in pore volume.

• The porosity measured in lab is independent of this overburden pressure. So a correction is introduced to lab value while considering for reservoir:

• Porosity Correction: Δφ = - cp φlab

ΔP o b, net

• ΔP o b, net is the net overburden pressure; φlab is the porosity result from

lab test; cp is the pore volume compressibility

Page 22: Rock properties

Compressibility measurement

• Pore volume compressibility is measured in the lab by measuring variation in pore volume at different conditions of overburden pressure (Pob) and pore pressure (Pp)

• Pore volume is measured first at atmospheric pressure and reservoir temperature

• The saturated sample is loaded to a core holder which is a device where different combinations of Pob and Pp can be applied.

• The liquid that is squeezed out at each combination these two pressure values are collected and measured the volume. Use these values to compute current porosity values.

• Now plot φ against each Pob

• The graph is given below

Page 23: Rock properties

Instrument for compressibility

Page 24: Rock properties

Plot of porosity vs overburden pressure

Page 25: Rock properties

Application of rock compressibility

• Rock compressibility is used to correct the lab measured porosity

• Production rate of a well suddenly changes with pressure over a period of time. The results are interpreted using compressibility values

• Total reserves in a well is calculated using pore pressure and production data. The pore volume of the reservoir changes as Pp

decreases with production, and cp

is needed to correct the pore volume from its initial value.

Page 26: Rock properties

Fluid saturation

• The pores of the reservoir rock is partially filled with water and hydrocarbon which can be in the gas, liquid and solid state

• The saturation level of the fluid is given by:

Page 27: Rock properties

Variation in fluid saturation

• Saturation level of the fluid in the rock helps the explorers to estimate available oil in the reservoir.

• The saturation level never remains constant. When the oil is pumped out the space left is taken up by water. When pressure drops the dissolved gas get released and occupy the space. If gas is injected to the reservoir then gas saturation occurs. So it is necessary to measure the level of all fluids periodically.

• Measurement of fluid:

• The fluid in a core rock sample is extracted and individual volume determined.

• The weighed core sample is placed in the thimble of the extraction unit and heated. The solvent evaporates carries along with it the fluid in the core sample and get condensed in the receiver flask.

Page 28: Rock properties

Fluid extraction

•The mass of oil is computed using the equation:

Page 29: Rock properties

Resistivity

• Resistance of a material to the flow of electric current is the resistivity of the material

Page 30: Rock properties

Resistivity -measurement

• Rock materials are having high resistivity, also crude oil and natural gas

• Water which present along with crude oil is saline and having low resistivity

• This difference is used to study the presence of crude oil in the rock

• In the above resistivity measuring sample holder fill with saline water the resistivity will come down

• If some water is replaced with crude oil, the resistivity will go up.

• By varying water and crude oil quantity in the sample holder a series of resistivity value are determined. Plot the values against percentage of crude oil in the mixture and construct a graph. This graph is applicable to that particular sample only.

Page 31: Rock properties

Resistivity-porosity relation

• Let Rw (Ωm) is the resistivity of reservoir water, Ro (Ωm) is the resistivity of reservoir rock saturated with reservoir water and Rt (Ωm) the resistivity of reservoir rock saturated with oil and water

• Defining the formation factor as F= Ro/ R w

• F is related to porosity by the expression:

• For sand stone the value for C= 0.62 and m=2.15

• Now oil saturation expression is given by Swn = C φ –m R w

/ R t • This expression is used for the calculation of oil saturation in the reservoir

rocks

Page 32: Rock properties

Resistivity-porosity relation • When resistivity sonde is sent into a reservoir to measure the resistivity

with depth of reservoir a typical graph as shown is obtained. High oil zones show large resistivity while water zones show low resistivity.

Page 33: Rock properties

Resistivity-porosity relation

• Mathematical calculation: for the above reservoir the water resistivity is 1.2Ωm, saturation exponent m=2.2, estimating the oil saturation at the depth 4226ft where porosity is 24%

• Swn = C φ –m Rw / Rt

• Sw2.2 = 0.62 (0.24) –2.15 x 1.2 / 400 = 0.04

• S w = 0.232 = 23.2%

• So = 100-23.2 = 76.8%

• At the depth 4226ft the oil saturation is 76.8%

Page 34: Rock properties

Rock permeability • Permeability is defined as the ability of a porous medium, e.g.,

sedimentary rock, to conduct fluids. The larger the permeability, the more fluid flow can be achieved through the medium for a given set of conditions. Darcy relationship:

• K is the coefficient of permeability (called simply as Permeability), regardless of dimensions

Page 35: Rock properties

• Permeability is given a dimension with the following definition

• If 1 atmosphere of pressure drop is required to flow a liquid of 1 cp viscosity through a porous medium of 1 cm length and 1 cm2 cross-sectional area at a rate of 1 cm3 per second, then the medium has a permeability of 1 darcy.

• 1 darcy = 9.869 x 10-9 cm2.

• A more common unit of reservoir rock permeability is the millidarcy (md), which is one thousandth of a darcy. Since the petroleum industry still uses the system of field units, a conversion factor is introduced in Darcy’s law as follows

• where q, k, A, ΔP, μ and L are in bbl/day, darcy, ft2, psi, cp and ft, respectively.

Page 36: Rock properties

Rock permeability and Darcy law

• The generalized differential form of Darcy’s law is given below:

• ρ : density of the fluid, g/cm3

– g : gravitational acceleration (980 cm/s2)

– d : depth measured from a reference horizon, cm

Page 37: Rock properties

Permeability measurement

• Laboratory measurement is performed under steady-state conditions using a permeameter.

• The clean and dry core sample is mounted in the core holder and then placed under a suitable confining pressure to simulate reservoir overburden conditions.

• The sample is then placed under vacuum for a sufficient period of time to remove all air from the sample.

• The fluid – usually brine, oil or air – is then flowed through the sample until steady-state flow is established.

• The flow rate and the inlet pressure are then recorded

• the test is usually repeated at different sets of flow rate and inlet pressure and the data is plotted

• The slope of the straight line is the core sample’s permeability multiplied by A/ μL.

• To vacuum

Page 38: Rock properties

Permeability measurement

Page 39: Rock properties

Permeability computation from graph

Page 40: Rock properties

Permeability calculation • Compute the permeability of the core sample whose flow data is shown in

above graph if the sample is 5 cm in diameter and 10 cm long. The fluid used in the experiment is an oil with a viscosity of 1.6 cp.

• The cross-sectional area of the sample is , A = [π(5)2]/4 = 19.63 cm2

• The slope of the best-fit line, m, is 6.25 cm3/min/atm, or 0.1 cm3/s/atm. The core permeability is: k = m μ L / A = 0.1 x 1.6 x 10 / 19.63 = 0.0815 d

• = 81.5 md

This method of measurement needs some precautions

• If the sample is sandstone which contains some clay particles, distilled water should not be used

• The flow rate should be low as the law does not work for excessive flow

• Inlet pressure should not be closed to confining pressure otherwise the flow can bypass the sample

• If gas is used mean pressure (average of inlet and outlet) should be used for plotting

Page 41: Rock properties

Permeability and porosity

• For clean sandstone the permeability is related to porosity, k = a φ b

• If some clay particles are present in sandstone then a correction factor is added

• k = a φ b (1-Vsh)c

• For carbonate rocks (calcite, dolomite, gypsum) such correlation not found

• Mineral deposits have minor effect on permeability

• Minute fractures improve permeability but no effect on porosity

Page 42: Rock properties

Linear flow from Darcy law

• For incompressible fluid (no change in density with pressure) assume flow direction along the x direction Darcy equation changes to:

• Rearranging the pressure at any location in the x direction is given by: