revised gce assessment objectives chemistry...15 25 33 47. gce chemistry . contents . introduction....

Revised GCEAssessment Objectives

GCE

ChemistryThis document contains the assessment objectives for the Specimen Assessment Materials

CCEA Exemplar Scheme of Work: GCE Chemistry

15

25

33

47

GCE Chemistry

Contents

Introduction

Unit AS 1: Assessment Objectives



Unit A2 1: Assessment Objectives

Unit A2 2: Assessment Objectives

Unit A2 3: Assessment Objectives 57

1


Introduction

CCEA has developed a new GCE Chemistry specification for first teaching in September 2016. This Assessment Grid was developed together with the Specimen Assessment Materials (SAMs) and has been designed to support you in understanding the assessment objectives.

Please remember that assessment objectives are based on the specification and the context in which the knowledge and understanding is assessed. The scheme of work should therefore be used in conjunction with the specification and the SAMs.

A Microsoft Word version of this scheme of work is available on the subject microsite on the CCEA website (www.ccea.org.uk/microsites). You will be able to use it as a foundation for training within your department to develop understanding of assessment objectives and their balance within the examination papers.

I hope you find this support useful in your teaching.

Best wishes

Elaine Lennox Subject Officer Chemistry

E-mail [email protected] Telephone 028 9026 1200 (2320)

1


http://www.ccea.org.uk/microsites

2


CCEA Assessment Grid: GCE Chemistry

3


4


GCE Chemistry Assessment Grid: Assessment Objectives (AO)

Unit AS 1

5


6


GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) AS

Uni

t 1Q

uest

ion

Spec

Ref

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

CSe

ctio

n A

11.

2.2

B1

12

1.9.

2C

11

31.

2.8

D1

14

1.8.

5A

11

51.

3.7

B1

16

1.4.

1A

11

71.

6.4

D1

18

1.2.

10A

11

91.

2.3

A1

110

1.8.

6C

11

Sect

ion

A To

tal

Tota

l for

Sec

tion

A –

10 m

arks

64

10

Sect

ion

B11

(a)

(i)1.

2.9

a re

gion

with

in a

n at

om th

at c

an h

old

up to

two

elec

trons

with

opp

osite

spi

n [1

]1

1

(ii)

1.2.

9

[1]

11

1

(iii)

1.2.

81s

2 2s2 2

p6 3s2 3

p6 3d10

4s1

[1]

11

(b)

(i)1.

2.12

all 8

ioni

satio

n en

ergi

es s

how

ing

an in

crea

se [1

]bi

gges

t inc

reas

e is

bet

wee

n 6t

h an

d 7t

h io

nisa

tion

ener

gy [1

]

22

2

7

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(ii)

1.2.

11O

+ (g

) → O

2+ (g

) + e

− [1]

11

(iii)

1.2.

13O

has

sm

alle

r nuc

lear

cha

rge/

one

less

pro

ton

[1]

oute

r ele

ctro

n is

in th

e sa

me

shel

l so

the

shie

ldin

g is

si

mila

r [1]

less

nuc

lear

attr

actio

n on

out

erm

ost e

lect

ron

in O

[1]

33

(c)

1.2.

13go

ing

dow

n th

e gr

oup

the

ioni

satio

n en

ergy

de

crea

ses

[1]

the

oute

rmos

t ele

ctro

n is

furth

er fr

om th

e nu

cleu

s [1

]th

e ou

term

ost e

lect

ron

expe

rienc

es le

ss s

hiel

ding

[1]

oute

r ele

ctro

n is

attr

acte

d m

ore

stro

ngly

to th

e nu

cleu

s [1

]

31

4

Tota

lQ

uest

ion

11 T

otal

91

313

312

(a)

1.5.

1la

yers

of p

ositi

ve io

ns [1

]se

a of

del

ocal

ised

ele

ctro

ns [1

]2

2

(b)

(i)1.

2.4

atom

s of

the

sam

e el

emen

t [1]

U23

5 has

143

neu

trons

U23

8 has

146

[1]

22

(ii)

1.2.

623

7.97

9 =

235

x +

238

(100

-x) /

100

2379

7.9

= 23

5x +

238

00 –

238

xx=

abun

danc

e of

U23

5 = 0

.7%

; U23

8 = 9

9.3%

[3]

33

3

(c)

(i)1.

1.2

UF 4 +

2M

g →

U +

2M

gF2 [

2]2

22

(ii)

1.1.

2U

O2 +

4H

F →

UF 4 +

2H

2O [2

]2

22

(iii)

1.7.

1+6

[1]

+6 [1

]+4

[1]

33

(d)

(i)1.

7.6

nitro

gen(

IV) o

xide

[1]

11

(ii)

1.10

.1re

light

s gl

owin

g sp

lint [

1]1

1To

tal

Que

stio

n 12

Tot

al3

1316

7

8

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

13(a

)1.

5.2

wea

k fo

rces

/van

der

Waa

ls’ f

orce

s be

twee

n la

yers

[1]

laye

rs c

an s

lide/

slip

off

[1]

22

(b)

1.5.

2st

rong

cov

alen

t bon

ds [1

]3d

/gia

nt te

trahe

dron

[1]

22

(c)

1.5.

2no

free

cha

rge

carr

iers

/free

ele

ctro

ns/a

ll el

ectro

ns in

co

vale

nt b

onds

[1]

11

Tota

lQ

uest

ion

13 T

otal

55

14(a

)(i)

1.1.

6m

oles

= 0

.287

/ 143

.4 =

0.0

02ra

tio 1

:1

0.00

2 x

107.

9 =

0.21

6ger

ror -

1

22

2

(ii)

1.7.

5A

g+ + e

− → A

g [1

] 1

11

(b)

1.1.

2C

u+ + C

l → C

u2+ +

Cl−

[1]

11

1(c

)(i)

1.7.

4ox

idat

ion

num

ber o

f cop

per c

hang

es fr

om +

2 to

+1

= re

duct

ion

[1]

oxid

atio

n nu

mbe

r of c

oppe

r cha

nges

from

0 to

+1

= ox

idat

ion

[1]

oxid

atio

n an

d re

duct

ion

of th

e sa

me

spec

ies

(cop

per)

in

the

sam

e re

actio

n [1

]

33

(ii)

1.10

it is

inso

lubl

e [1

]1

1(d

)1.

9.6

mol

es o

f cop

per c

hlor

ide

= 2.

0/13

4.5

= 0.

0148

7ra

tio 2

HC

l : 1

CuC

l 20.

0297

47 =

vol

x 1

.0 /1

000

volu

me

= 29

.7cm

3 = 3

0 cm

3 to

2 si

g fig

ures

er

ror -

1

33

3

Tota

lQ

uest

ion

14 T

otal

18

211

7

9

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

15(a

)(i)

1.1.

2C

l 2 + 3

F 2 → 2

ClF

3 [1]

11

1(ii

)1.

3.3

the

elec

trost

atic

attr

actio

n be

twee

n a

shar

ed p

air o

f el

ectro

ns a

nd th

e nu

clei

of t

he b

onde

d at

oms

[2]

22

(iii)

1.3.

6

[2]

22

(b)

(i)1.

6.2

[1]

AsF

F FF

F[1

]

Cl

FF

+

trigo

nal b

ipyr

amid

[1]

bent

/v/n

onlin

ear [

1]fiv

e bo

ndin

g pa

irs o

f ele

ctro

ns re

pel e

ach

othe

r eq

ually

[1]

two

bond

ing

pairs

of e

lect

rons

and

two

lone

pai

rs o

f el

ectro

ns; t

he lo

ne p

airs

of e

lect

rons

repe

l mor

e th

an

bond

ing

pairs

[1]

22

26

2

(ii)

1.6.

210

4.5°

[1]

11

1(c

)(i)

1.3.

9 Idd

Cld–

[1

]ch

lorin

e is

mor

e el

ectro

nega

tive

than

iodi

ne [1

]1

12

F Cl F

Fx

xxxxx

x

10

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(ii)

1.4.

2ch

lorin

e ha

s va

n de

r Waa

ls’ f

orce

s be

twee

n m

olec

ules

[1]

iodi

ne m

onoc

hlor

ide

has

perm

anen

t dip

ole-

dipo

le

attra

ctio

ns b

etw

een

mol

ecul

es [1

]pe

rman

ent d

ipol

e-di

pole

attr

actio

ns a

re s

trong

er/

inte

rmol

ecul

ar fo

rces

stro

nger

in IC

l [1]

mor

e en

ergy

nee

ded

to b

reak

the

stro

nger

in

term

olec

ular

forc

es [1

]

22

4

Tota

lQ

uest

ion

15 T

otal

79

218

416

(a)

1.10.2

-1.10

.4ad

d di

lute

aci

d an

d ef

ferv

esce

nce

for c

arbo

nate

[1]

flam

e te

st y

ello

w/o

rang

e fo

r sod

ium

ions

[1]

add

silv

er n

itrat

e so

lutio

n an

d pp

t for

ms

for h

alid

e [1

]di

ssol

ve in

wat

er [1

]

44

(b)

(i)1.

5.2

Indi

cativ

e C

onte

nt•

in s

odiu

m s

trong

attr

actio

n be

twee

n po

sitiv

e io

nsan

d de

loca

lised

ele

ctro

ns•

in s

odiu

m m

etal

lic b

ondi

ng•

in s

odiu

m c

hlor

ide

stro

ng a

ttrac

tion

betw

een

posi

tive

and

nega

tive

ion

•io

nic

bond

ing

•in

iodi

ne w

eak

van

der W

aals

forc

es b

etw

een

mol

ecul

es•

ioni

c bo

ndin

g is

stro

nger

than

met

allic

bon

ding

whi

ch is

stro

nger

than

van

der

Waa

ls

51

66

11

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(b)

(i)(c

ont.)

Ban

dR

espo

nse

Mar

k

A

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

fully

exp

lain

the

diffe

renc

e in

mel

ting

poin

t usi

ng a

m

inim

um o

f 6 p

oint

s of

indi

cativ

e co

nten

t. Th

ey m

ust u

se g

ood

spel

ling,

pun

ctua

tion

and

gram

mar

an

d th

e fo

rm a

nd s

tyle

are

of a

n ex

celle

nt s

tand

ard.

[5]–

[6]

B

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

the

diffe

renc

e in

mel

ting

poin

t usi

ng a

m

inim

um o

f 4 p

oint

s of

indi

cativ

e co

nten

t. Th

ey m

ust u

se s

atis

fact

ory

spel

ling,

pun

ctua

tion

and

gram

mar

an

d th

e fo

rm a

nd s

tyle

are

of a

goo

d st

anda

rd.

[3]–

[4]

C

Can

dida

tes

expl

ain

parti

ally

the

diffe

renc

e in

mel

ting

poin

t usi

ng a

m

inim

um o

f 2 p

oint

s of

indi

cativ

e co

nten

t. Th

ey u

se li

mite

d co

rrec

t sp

ellin

g, p

unct

uatio

n an

d gr

amm

ar

and

the

form

and

sty

le is

of a

bas

ic

stan

dard

.

[1]–

[2]

DR

espo

nse

not w

orth

y of

cre

dit.

[0]

(ii)

1.8.

6gr

ey –

bla

ck [1

]w

hite

[1]

22

(c)

1.8.

33I

2 + 6

NaO

H →

NaI

O3 +

5NaI

+3

H2O

[2]

22

2

12

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(d)

(i)1.

9.6

46 x

40

= 18

40g

1840

/ 149

.9 =

12.

3 M

[2]

22

2

(ii)

1.8.

5fro

m c

olou

rless

to y

ello

w/b

row

n [1

]1

1To

tal

Que

stio

n 16

Tot

al10

25

174

6

Pape

r Tot

als

4137

1290

226

13

14



Unit AS 2

15


16


GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) AS

Uni

t 2

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

Sect

ion

A1

2.8.

5C

11

12

2.2.

3A

11

32.

3.9

A1

14

2.6.

1B

11

52.

6.6

B1

16

2.11

.6A

11

72.

1.3

C1

11

82.

4.10

C1

19

2.8.

2D

11

102.

11.2

+

2.11

.3B

11

Sect

ion

A To

tal

Tota

l for

Sec

tion

A –

10 m

arks

55

102

Sect

ion

B11

2.1.

2el

emen

tm

oles

ratio

C22

.2 ÷

12

= 1.

852

H3.

7 ÷

1 =

3.70

4B

r74

.1 ÷

80

= 0.

931

mol

es [1

]em

piric

al F

orm

ula

= C

2H4B

r [1]

216

÷ 10

8 =

2m

olec

ular

For

mul

a =

C4H

8Br 2

[1]

33

3

Tota

lQ

uest

ion

11 T

otal

33

3

17

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

12(a

)2.

2.3

CH

3CH

(CH

3)CH

2CH

3 [1]

2-m

ethy

lbut

ane

[1]

CH

3C(C

H3) 2C

H3 [

1]2,

2 - d

imet

hylp

ropa

ne [1

]

44

(b)

2.2.

1m

olec

ules

whi

ch h

ave

the

sam

e m

olec

ular

form

ula

but a

diff

eren

t st

ruct

ural

form

ula.

22

(c)

2.3.

3ne

open

tane

[1]

incr

ease

d br

anch

ing

[1]

wea

ker v

an d

er W

aals

forc

es [1

]

33

(d)

2.3.

4C

5H12

+ 8

O2 →

5C

O2 +

6H2O

[1]u

nbal

ance

d[1

]bal

ance

d

22

2

(e)

2.3.

10in

itiat

ion

Cl 2 →

2C

l• [1

]pr

opag

atio

n C

l• +

C5H

12 →

C5H

11• +

HC

l [1]

C5H

11• +

Cl 2 →

C5H

11C

l + C

l• [1

]te

rmin

atio

n C

l• +

Cl•

→ C

l 2 [1]

or C

5H11

• + C

5H11

• → C

10H

22or

C5H

11• +

Cl•

→ C

5H11

Cl

44

Tota

lQ

uest

ion

12 T

otal

411

152

13(a

)(i)

2.8.

8en

thal

py c

hang

e(s)

[1]

is/a

re in

depe

nden

t of t

he ro

ute

take

n [1

]2

2

(ii)

2.8.

5en

thal

py c

hang

e w

hich

occ

urs

whe

n 1

mol

e of

a s

ubst

ance

[1]

unde

rgoe

s co

mpl

ete

com

bust

ion

in o

xyge

n [1

] und

er s

tand

ard

cond

ition

s. [1

]

33

(iii)

2.8.

10(–

394)

+ (–

286

× 2)

+ (+

75) [

1]–8

91 k

J m

o1-1 [1

]2

22

(b)

(i)2.

8.13

aver

age

bond

ent

halp

ies

are

used

[1]

11

(ii)

2.8.

11–6

98 =

4(C

–H) –

234

64(

C–H

) = 1

648

412

kJm

ol–1

erro

r -1

33

3

18

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(c)

(i)2.

8.6

Indi

cativ

e C

onte

nt•

mea

sure

mas

s of

spi

rit b

urne

r con

tain

ing

etha

nol b

efor

ean

d af

ter b

urni

ng•

mea

sure

out

kno

wn

volu

me

of w

ater

into

a c

alor

imet

erus

ing

a bu

rette

•bu

rn th

e et

hano

l in

the

spiri

t bur

ner a

nd u

se th

e he

atev

olve

d to

hea

t the

wat

er in

the

calo

rimet

er•

mea

sure

initi

al a

nd fi

nal t

empe

ratu

re o

f wat

er (a

fter

heat

ing)

usi

ng a

ther

mom

eter

•ca

lcul

ate

the

heat

evo

lved

usi

ng th

e eq

uatio

n q

= m

c∆T

•ca

lcul

ate

the

num

ber o

f mol

es o

f eth

anol

use

d fro

m th

em

ass

of e

than

ol b

urne

d•

divi

de th

e he

at e

volv

ed b

y th

e m

oles

of e

than

ol u

sed

toca

lcul

ate

the

enth

alpy

of c

ombu

stio

n

Ban

dR

espo

nse

Mar

k

A

Can

dida

tes

mus

t use

app

ropr

iate

spe

cial

ist

term

s to

exp

lain

fully

the

proc

ess

of d

eter

min

ing

the

enth

alpy

of c

ombu

stio

n (u

sing

a m

inim

um o

f 6

poin

ts o

f ind

icat

ive

cont

ent).

The

y us

e go

od

spel

ling,

pun

ctua

tion

and

gram

mar

and

the

form

an

d st

yle

are

of a

n ex

celle

nt s

tand

ard.

[5]–

[6]

B

Can

dida

tes

mus

t use

app

ropr

iate

spe

cial

ist t

erm

s to

exp

lain

the

proc

ess

of n

mr (

usin

g a

min

imum

of

5 p

oint

s of

indi

cativ

e co

nten

t). T

hey

use

good

sp

ellin

g, p

unct

uatio

n an

d gr

amm

ar a

nd th

e fo

rm

and

styl

e ar

e of

a g

ood

stan

dard

.

[3]–

[4]

66

6

19

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

Ban

dR

espo

nse

Mar

k

C

Can

dida

tes

expl

ain

brie

fly a

nd p

artia

lly

the

proc

ess

of d

eter

min

ing

the

enth

alpy

of

com

bust

ion

(usi

ng a

min

imum

of 4

poi

nts

of

indi

cativ

e co

nten

t). T

hey

use

limite

d sp

ellin

g,

punc

tuat

ion

and

gram

mar

and

the

form

and

st

yle

are

of a

bas

ic s

tand

ard.

[1]–

[2]

DR

espo

nse

not w

orth

y of

cre

dit.

[0]

(c)

(ii)

2.8.

6in

com

plet

e co

mbu

stio

n [1

]he

at lo

ss to

sur

roun

ding

s [1

]2

2

Tota

lQ

uest

ion

13 T

otal

55

919

56

14(a

)2.

9.3

peak

shi

fts to

righ

t and

pea

k is

low

er [2

]ot

her d

raw

ing

erro

rs [–

1]2

2

(b)

2.9.

3nu

mbe

r of m

olec

ules

with

ene

rgy

grea

ter t

han

Ea [

1] in

crea

ses

[1]

22

(c)

2.9.

2ca

taly

st p

rovi

des

an a

ltern

ativ

e ro

ute

[1]

of lo

wer

act

ivat

ion

ener

gy E

a [1]

mor

e m

olec

ules

hav

e en

ergy

gre

ater

than

Ea [1

]nu

mbe

r/fre

quen

cy o

f suc

cess

ful c

ollis

ions

(bet

wee

n S

O2 a

nd O

2 m

olec

ules

) inc

reas

es [1

]

44

Tota

lQ

uest

ion

14 T

otal

62

8

Num

ber o

fm

olec

ules

with

agi

ven

ener

gy

Ene

rgy

Ea

20

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

15(a

)(i)

2.4.

7th

e H

ato

m in

HB

r has

a δ

+ ch

arge

[1]

whi

ch is

attr

acte

d to

are

a of

hig

h el

ectro

n de

nsity

(in

doub

le b

ond)

[1

]

11

2

(ii)

2.4.

8

[3

]cu

rly a

rrow

s dr

awn

corr

ectly

[1]

erro

r –1

13

4

(b)

(i)2.

2.6

CH

3 – C

H2

CH

3

CH

3 H

CC

Z is

omer

[1]

CH

3 – C

H2

H

CH

3C

H3

CC

E is

omer

[1]

22

(ii)

2.4.

9C

H3

Br

CH

3CH

2CC

H2C

H3

maj

or [1

] CH

3 Br

CH

3CH

2CH

CH

CH

3

min

or [1

]

22

CH

2 =

CH

2 C

H2 –

CH

2C

H2 –

CH

2

H+

H..+

H

Br

−B

r −

Br

21

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(iii)

2.4.

9ca

rboc

atio

n in

term

edia

tes

prod

uced

[1]

terti

ary

carb

ocat

ion

mor

e st

able

than

sec

onda

ry c

arbo

catio

n [1

]te

rtiar

y ca

rboc

atio

n le

ads

to fo

rmat

ion

of m

ajor

pro

duct

[1]

33

(c)

(i)2.

5.5

C4H

9Br +

NaO

H →

C4H

9OH

+ H

Br [

2]2

22

(ii)

2.6.

2se

cond

ary

[1]

carb

on b

onde

d to

–O

H is

bon

ded

to tw

o ot

her c

arbo

n at

oms

[1]

11

2

(d)

(i)2.

5.8

C4H

9Br +

NaO

H →

C4H

8 + N

aBr +

H2O

[2]

22

2

(ii)

2.5.

8in

eth

anol

[

1]1

1(ii

i)2.

5.8

elim

inat

ion

[1

]1

1

(iv)

2.5.

8bu

t-2-e

ne

[1

]1

1To

tal

Que

stio

n 15

Tot

al12

1022

4

16(a

)2.

10.1

rate

of f

orw

ard

reac

tion

= R

ate

of re

vers

e re

actio

n [1

]th

e am

ount

of a

ny g

iven

reac

tant

or p

rodu

ct re

mai

ns

cons

tant

[1]

22

(b)

2.10

.2in

crea

se [1

]3

mol

es (g

) LH

S 2

mol

es (g

) RH

Seq

uilib

rium

shi

fts to

RH

S to

opp

ose

the

chan

ge [1

]

22

(c)

2.10

.2de

crea

se [1

](fo

rwar

d) re

actio

n is

exo

ther

mic

equi

libriu

m s

hifts

to L

HS

to o

ppos

e th

e ch

ange

/coo

l the

sy

stem

[1]

22

(d)

2.10

.2no

effe

ct o

n yi

eld

[1]

incr

ease

s th

e ra

te o

f the

forw

ard

and

reve

rse

reac

tions

eq

ually

[1]

22

22

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(e)

(i)2.

10.3

Kc=

[NO

2]2 /[N

O]2 [O

2] [1

]m

ol-1dm

3 [1

]2

22

(ii)

2.10

.4K

c >

1 [1

]1

11

(f)2.

1.6

4×46

2×14

8 =

184/

296

= 62

.2%

erro

r –1

22

2

Tota

lQ

uest

ion

16 T

otal

310

135

Pape

r Tot

als

3544

1190

216

23

24



Unit AS 3

25


26


GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) AS

Uni

t 3Pr

actic

al B

ookl

et A

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

1a

whi

te [1

]1

1b

two

diffe

rent

par

ticle

siz

es a

re s

een

[1]

diffe

rent

sha

des

of w

hite

[1]

22

c(i)

no c

hang

e at

the

star

t, po

ssib

le v

apou

r in

the

mid

dle,

(c

olou

rless

) liq

uid

at th

e en

d (a

ny 2

out

of 3

) [2]

22

(ii)

colo

urle

ss, g

reen

col

our (

pH 7

) [1]

11

d(i)

fizzi

ng/fr

othi

ng/fo

amin

g/ef

ferv

esce

nce

[1]

whi

te s

olid

left/

som

e so

lid d

isap

pear

s [1

]2

2

(ii)

limew

ater

goe

s m

ilky

[1]

11

e(i)

mea

surin

g cy

linde

r [1]

25 c

m3 in

dica

tes

an a

ccur

acy

of 1

cm

3 [1

]1

12

1

(ii)

titre

val

ue/c

m3 [2

]va

lue

of ti

tratio

n 20

cm

3 +

/- 2

cm3 =

[2] +

/- 4

cm3 =

[1]

corr

ect r

ecor

ding

of v

alue

s e.

g. d

ecim

al p

lace

s an

d ca

lcul

atio

n of

titre

[2]

24

61

fbr

ick

red

[1]

11

Tota

lQ

uest

ion

1 To

tal

21

1518

22

aX

: so

dium

floa

ts; n

o ga

s [1

]Y:

sod

ium

floa

ts; l

ots

of g

as p

rodu

ced

[1]

Z: s

odiu

m fl

oats

; not

muc

h ga

s [1

]

33

bY

cont

ains

eth

anol

, fas

test

reac

tion

11

Tota

lQ

uest

ion

2 To

tal

13

4

27

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

3a

subs

tanc

e m

elts

da

rken

s/go

es b

lack

bl

ack

solid

left/

(mos

t) di

sapp

ears

erro

r –1

22

bbl

ack

solid

(car

bon)

form

s1

1To

tal

Que

stio

n 3

Tota

l 1

23

Tota

l for

Boo

klet

A –

25

mar

ks2

320

252

28

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

Prac

tical

The

ory

Boo

klet

B1

ach

ange

s fro

m g

reen

to re

d [2

]2

2b

chan

ges

from

gre

en to

red

and

ther

e is

som

e br

own

(bro

min

e)

pres

ent [

2]2

2

Tota

lQ

uest

ion

1 To

tal

44

2ad

d w

ater

and

stir

to d

isso

lve

[1]

filte

r the

mix

ture

[1]

add

hydr

ochl

oric

aci

d to

the

solid

[1]

it fiz

zes

show

ing

it is

a c

arbo

nate

[1]

filte

r the

sol

utio

n an

d ad

d a

solu

ble

sulfa

te [1

]w

hite

pre

cipi

tate

pro

duce

d [1

]to

a m

axim

um o

f [4]

44

Tota

lQ

uest

ion

2 To

tal

44

3a

sket

ch o

f app

arat

us i.

e. g

as p

assi

ng th

roug

h w

ater

/alk

ali [

2]ex

plan

atio

n of

how

it w

orks

[1]

12

3

bac

ts a

s a

cata

lyst

for t

he re

actio

n [1

]1

1c

the

spee

d of

dro

ps o

f liq

uid

retu

rnin

g to

the

flask

wou

ld in

crea

se

with

vig

orou

s re

fluxi

ng [1

]1

1

da

sim

ilar b

oilin

g po

int t

o th

e 1-

chlo

robu

tane

[1]

11

ew

ater

[1]

11

fpl

ace

in s

epar

atin

g fu

nnel

with

e.g

. wat

er [1

]st

oppe

r the

funn

el [1

]in

vert

the

funn

el [1

]sh

ake

and

allo

w th

e liq

uids

to s

epar

ate

and

rem

ove

the

low

er

one

[1]

44

gus

ed to

dry

the

1-ch

loro

buta

ne [1

]an

hydr

ous

sodi

um s

ulfa

te [1

]2

2

29

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

h(i)

gcm

-3 [1

]0.

81 x

23

= 18

.63

g [1

]2

22

(ii)

18.6

3/74

= 0

.25

mol

; 0.

25 m

ol o

f C4H

9C1

= 0.

25 x

92.

5 =

23.1

g

[2]

22

2

ibo

iling

poi

nts

are

usua

lly m

easu

red

in ra

nges

[1]

a ra

nge

of 1

/2 d

egre

es is

the

usua

l ran

ge [1

]th

e ra

nge

is in

crea

sed

to c

olle

ct a

s m

uch

as p

ossi

ble

(if th

ere

are

no in

terfe

ring

com

poun

ds) [

1]

21

3

jco

mpa

re th

e pu

re a

nd “i

mpu

re” s

pect

ra [1

]th

e “im

pure

” spe

ctru

m w

ill h

ave

extra

pea

ks [1

]2

2

Tota

lQ

uest

ion

3 To

tal

39

1022

44

aM

(s) +

H2O

(g) →

MO

(s) +

H2(g

)eq

uatio

n [1

]st

ate

sym

bols

[1]

22

2

bsa

me

mas

s [1

]sa

me

parti

cle

size

[1]

100%

pur

ity [1

]

33

c(i)

stea

m is

dilu

ted

wat

er [1

]1

1(ii

)bu

bble

s/fiz

zing

effe

rves

cenc

e [1

]w

hite

sol

id [1

]ca

lciu

m m

oves

up

and

dow

n [1

]he

at p

rodu

ced

[1]

stea

m p

rodu

ced

[1]

calc

ium

dis

olve

s/di

sapp

ears

[1]

to a

max

imum

of [

3]

33

d(i)

time/

seco

nds

or m

inut

es [1

]vo

lum

e of

hyd

roge

n ga

s/cm

3 [1

]2

2

(ii)

stee

per a

t the

sta

rt [1

]ea

rlier

hor

izon

tal fi

nish

[1]

22

30

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(iii)

allo

w g

as to

go

into

a te

st tu

be [1

]lig

hted

spl

int [

1]po

p no

ise

[1]

21

3

e3.

4 g

of C

a =

3.4/

40 =

0.0

85 m

ol; 0

.085

x 2

4 dm

3 =

2.04

=

2.0

dm3 [4

]er

ror –

1

44

4

fth

e G

roup

two

met

als

are

very

reac

tive

with

oxy

gen

[1]

henc

e th

e ex

perim

ent w

ould

be

over

ver

y qu

ickl

y [1

]ne

ed to

slo

w d

own

the

reac

tion

[1]

only

way

is to

dilu

te th

e ox

ygen

[1]

e.g.

by

mix

ing

it w

ith n

itrog

en/n

oble

gas

[1]

colle

ct th

e ox

ygen

ove

r wat

er/in

a s

yrin

ge [1

]co

mpa

re th

e ra

tes

of o

xyge

n co

llect

ion

and

rela

te to

reac

tivity

[1]

to a

max

imum

of [

5]

55

Tota

lQ

uest

ion

4 To

tal

64

1525

6To

tal f

or B

ookl

et B

– 5

5 m

arks

913

3355

10

Pape

r Tot

als

1116

5380

12

31

32



Unit A2 1

33


34


GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) A2

Uni

t 1

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

14.

3.7

B1

12

4.2

D1

13

4.4.

1/4.

4.2

C1

11

44.

3.4

A1

11

54.

4.2

B1

11

64.

8.1

C1

17

4.7.

6D

11

84.

9.4

D1

19

2.1.

4B

11

110

4.5.

8D

11

Sect

ion

A To

tal

Tota

l for

Sec

tion

A –

10 m

arks

35

210

4 11

(a)

(i)Sy

nopt

ic4.

2.4

4.2.

54.

2.6

DH⦵

= ∑

D fH⦵

(pro

duct

s) –

∑D fH

⦵ (r

eact

ants

)=

[3 ×

−39

3.5]

– [2

× −

824.

2]=

467.

9 kJ

mol

−1[2

]

DS⦵

= ∑

S⦵

(pro

duct

s) −

∑ S

⦵ (r

eact

ants

)=

[(4 ×

27.

3) +

(3 ×

213

.6)]

− [(2

× 8

7.4)

+ (3

× 5

.7)]

= 55

8.1

J K

−1 m

ol-1

[2]

DG⦵

= DH

⦵ −

TDS

⦵

= 46

7.9

− (2

98 ×

0.5

581)

= 30

1.6

kJ m

ol−1

[1

]

2 2 1

5

2 2 1

(ii)

4.2.

6DG

⦵ is

pos

itive

[1]

11

35

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(b)

4.2.

7T

= (DH

⦵ ÷

DS⦵

)=

(467

.9 ÷

0.5

581)

= 83

8K[2

]

22

2

Tota

lQ

uest

ion

11 T

otal

1

78

712

(a)

4.1.

1th

e en

ergy

requ

ired

to c

onve

rt 1

mol

e of

an

ioni

c so

lid in

to g

aseo

us

ions

[2

]2

2

(b)

(i)4.

1.2

Mg+ (

g) +

e− +

F2(g

)

Mg2+

(g) +

2F− (

g)

Mg(

s) +

F2(g

)

MgF

2(s)

↑ ↑ ↑ ↑↑↑

↓

[1]

[1]

[1]

[1] [4

]

44

(ii)

4.1.

2LE

= (+

1123

) + (1

50) +

(736

) + (1

450)

+ (2

x 7

9) +

(2

x −

348)

= 2

921

kJ m

ol-1

[2

]2

22

36

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(c)

(i)4.

1.3

H

Mg2+

[1]

[1]

F−

OO

O

OH

H

HH

H

HH

[2]

22

(ii)

4.1.

3LE

= (–

155)

– [(

–192

0) +

(2 x

–36

4)] =

249

3 kJ

mol

-1 [2]

22

2

Tota

lQ

uest

ion

12 T

otal

48

124

13(a

)(i)

4.7.

42-

hydr

oxy-

2-m

ethy

lbut

anen

itrile

[2]

22

(ii)

4.6.

2op

tical

[1]

11

(iii)

4.6.

3

CCH

3

CN

HO

H5C

2

CH

3

C

NC

OHC

2H5

corr

ect 3

D re

pres

enta

tion

[1]

mirr

or im

age

[1]

22

2

(iv)

4.7.

5nu

cleo

phili

c ad

ditio

n[1

]1

1

37

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(v)

4.7.

5

erro

r −1

[4]

44

(vi)

4.7.

6th

e ca

rbon

yl g

roup

is p

lana

r [1]

the

nucl

eoph

ile a

ttack

s fro

m b

oth

side

s to

an

equa

l ex

tent

[1]

equa

l am

ount

s of

eac

h op

tical

isom

er fo

rmed

[1]

21

3

(b)

4.7.

9he

at [1

] with

eith

er a

cidi

fied

pota

ssiu

m d

ichr

omat

e,

Tolle

n’s

reag

ent o

r Feh

ling’

s so

lutio

n [1

]co

rrec

t pos

itive

resu

lt w

ith b

utan

al, n

o ch

ange

with

bu

tano

ne [1

][3

]

33

(c)

(i)4.

7.7

[2]

22

O

OH

H+

− OC CC

C2H

5

C2H

5

CH

3C

H3

CH

3C

H3

C2H

5

C2H

5

CN

CN

CN

CN

−

C− O

HH

CC

CH

3C

H3

+H2O

CH

3CH

2C

H3C

H2

NO

2

NO

2N

NN

O2

NO

2

O +

NH

2N

38

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(ii)

4.7.

7/4.

7.8

Indi

cativ

e C

onte

nt

•ye

llow

/ora

nge

•so

lid•

capi

llary

tube

•he

at s

low

ly•

reco

rd th

e te

mpe

ratu

re w

hen

the

solid

mel

ts•

com

pare

to ta

bles

of d

ata

66

6

Tota

lQ

uest

ion

13 T

otal

105

924

26

Ban

dR

espo

nse

Mar

k

A

Can

dida

tes

mus

t use

app

ropr

iate

spe

cial

ist

term

s to

exp

lain

fully

the

proc

ess

of id

entif

ying

th

e ke

tone

(usi

ng a

min

imum

of 6

poi

nts

of

indi

cativ

e co

nten

t). T

hey

use

good

spe

lling

, pu

nctu

atio

n an

d gr

amm

ar a

nd th

e fo

rm a

nd

styl

e ar

e of

an

exce

llent

sta

ndar

d.

[5]–

[6]

B

Can

dida

tes

mus

t use

app

ropr

iate

spe

cial

ist

term

s to

exp

lain

the

proc

ess

of id

entif

ying

th

e ke

tone

(usi

ng a

min

imum

of 5

poi

nts

of

indi

cativ

e co

nten

t). T

hey

use

good

spe

lling

, pu

nctu

atio

n an

d gr

amm

ar a

nd th

e fo

rm a

nd

styl

e ar

e of

a g

ood

stan

dard

.

[3]–

[4]

C

Can

dida

tes

expl

ain

brie

fly a

nd p

artia

lly th

e pr

oces

s of

iden

tifyi

ng th

e ke

tone

(usi

ng a

m

inim

um o

f 4 p

oint

s of

indi

cativ

e co

nten

t).

They

use

lim

ited

spel

ling,

pun

ctua

tion

and

gram

mar

and

the

form

and

sty

le a

re o

f a b

asic

st

anda

rd.

[1]–

[2]

DR

espo

nse

not w

orth

y of

cre

dit.

[0]

39

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

14(a

)(i)

4.5.

2K

a = [C

H3C

H2C

OO

− ][H

+ ]

[C

H3C

H2C

OO

H]

[1]

11

1

(ii)

4.5.

3K

a =

[H+ ]2

÷ [C

H3C

H2C

OO

H]

[1]

[H+ ]

= 0.

0018

4 [

1]pH

= 2

.74

[1

]

33

3

(iii)

4.5.

4a

solu

tion

whi

ch m

inim

ises

cha

nges

in p

H o

n ad

ditio

n of

sm

all a

mou

nts

of a

cid

or a

lkal

i

[2

]2

2

(iv)

4.5.

5m

oles

of a

cid

0.25

x 0

.3 =

0.0

75m

oles

of s

alt 0

.15

x 0.

2 =

0.03

(con

cent

ratio

n of

aci

d =

0.15

mol

dm-3)

(con

cent

ratio

n of

sal

t = 0

.06

mol

dm-3)

[H+ ]

= K

a x ([

acid

]/[sa

lt]) =

3.3

8 x

10-5 m

oldm

-3

pH =

4.4

7

[4]

44

4

(b)

(i)4.

8.5

CH

3CH

2CO

OH

+ N

aOH

→ C

H3C

H2C

OO

Na

+ H

2O [

1]1

11

(ii)

4.5.

7ph

enol

phth

alei

n

[1

]co

lour

less

to p

ink

[2]

rang

e m

atch

es th

e ve

rtica

l por

tion

of th

e tit

ratio

n cu

rve

[1]

44

(iii)

1.9.

6m

oles

of N

aOH

= 0

.20

x (1

8.5/

1000

) = 0

.003

7m

oles

of C

H3C

H2C

OO

H =

0.0

037

conc

entra

tion

of C

H3C

H2C

OO

H =

0.1

48 m

oldm

-3

[3]

33

3

(iv)

4.5.

3[H

+ ] =

KW ÷

[OH

– ] =

5 x

10-1

4 mol

dm-3

[1]

pH =

13.

30[1

]2

22

Tota

lQ

uest

ion

14 T

otal

49

720

14

40

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

15(a

)4.

10.1

22

(b)

(i)4.

10.3

HN

O3 +

2H

2SO

4 → N

O2+ +

H3O

+ + 2

HS

O4–

22

2

(ii)

4.10

.4ni

troni

um io

n[1

]1

1(ii

i)4.

10.3

Ele

ctro

phili

c su

bstit

utio

n

erro

r −1

[5]

55

(iv)

4.10

.5m

ethy

l 3-n

itrob

enzo

ate

[1]

11

(v)

4.10

.5cr

eam

sol

id [1

]1

1To

tal

Que

stio

n 15

Tot

al7

512

2

OC

H3

OC

H3

OC

H3

OC

H3

+

CC

C

H

H

C

+H

+N

O2

NO

2NO

2N

O2

OO

OO

befo

reaf

ter

[2]

41

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

16(a

)4.

3.3

first

[1]

valid

exp

lana

tion

[1]

[2]

22

2

(b)

4.3.

3ze

ro [1

]va

lid e

xpla

natio

n [1

][2

]2

22

(c)

4.3.

3ra

te =

k [C

4H0B

r][1

]1

12

(d)

4.3.

120

00 [1

]s-1

[1]

[2]

11

21

(e)

4.3.

5/4.

3.6

[5]

erro

r −1

23

5

Tota

lQ

uest

ion

16 T

otal

39

127

CH

3C

H3

CH

3C

H3

CH

3C

H3

CH

3C

H3

H3C

H3C

H3C

H3C

RD

S

OH

−

OH

Br −

Br

C

CC

+

C+

42

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

17(a

)(i)

4.9.

6

OH

OH

OH

H

HHH

H C C C

[1]

11

(ii)

4.9.

6pr

opan

e-1,

2,3-

triol

[1]

11

(iii)

4.9.

6

(CH

2) 7 ─ C

H =

CH

CH

2CH

= C

H(C

H2) 4C

H3

(CH

2) 7 ─ C

H =

CH

CH

2CH

= C

H(C

H2) 4C

H3

(CH

2) 7 ─ C

H =

CH

CH

2CH

= C

H(C

H2) 4C

H3

O

O O

O O

O

H

H H H

HC C CCCC

[1]

11

(b)

(i)4.

9.4

+ 4.

8.1

3-m

ethy

lbut

anoi

c ac

idm

etha

nol

[1]

11

43

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(ii)

4.9.

4

[2]

22

(iii)

4.9.

5In

dica

tive

Con

tent

•ac

id a

nd a

lcoh

ol in

to ro

und-

botto

med

flas

k an

dad

d co

ncen

trate

d su

lphu

ric a

cid

slow

ly•

add

anti-

bum

ping

gra

nule

s•

heat

und

er re

flux

•di

stil

and

colle

ct a

t boi

ling

poin

t of e

ster

•sh

ake

with

aqu

eous

sod

ium

car

bona

te a

ndre

leas

e pr

essu

re•

sepa

rate

est

er la

yer u

sing

sep

arat

ing

funn

el•

add

a na

med

dry

ing

agen

t•

deca

nt/fi

lter

66

6

CH

3 ─ C

─ C

H2C

OO

H +

CH

3OH

C

H3 ─

C ─

CH

2CO

OC

H3 +

H2O

CH

3 H

CH

3

H

44

Que

stio

nSp

ec R

efM

ark

Sche

me

AO

1A

O2

AO

3To

tal

Mat

hsQ

WC

(iii)

4.9.

5 (c

ont.)

Que

stio

n 17

Tot

al2

46

126

Pape

r Tot

als

3452

2411

040

12

Ban

dR

espo

nse

Mar

k

A

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

fully

the

prep

arat

ion

of th

e es

ter (

usin

g a

min

imum

of 6

poi

nts

of in

dica

tive

cont

ent).

The

y us

e go

od s

pelli

ng,

punc

tuat

ion

and

gram

mar

and

the

form

and

sty

le a

re o

f an

exce

llent

st

anda

rd.

[5]–

[6]

B

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

the

prep

arat

ion

of th

e es

ter (

usin

g a

min

imum

of 5

poi

nts

of in

dica

tive

cont

ent).

The

y us

e go

od s

pelli

ng,

punc

tuat

ion

and

gram

mar

and

th

e fo

rm a

nd s

tyle

are

of a

goo

d st

anda

rd.

[3]–

[4]

C

Can

dida

tes

expl

ain

brie

fly a

nd

parti

ally

the

prep

arat

ion

of th

e es

ter (

usin

g a

min

imum

of 4

po

ints

of i

ndic

ativ

e co

nten

t). T

hey

use

limite

d sp

ellin

g, p

unct

uatio

n an

d gr

amm

ar a

nd th

e fo

rm a

nd

styl

e ar

e of

a b

asic

sta

ndar

d.

[1]–

[2]

DR

espo

nse

not w

orth

y of

cre

dit.

[0]

45

46



Unit A2 2

47


48


GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) A2

Uni

t 2

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

15.

2.3

D1

12

5.6.

5A

11

35.

9.6

C1

14

5.5.

5/6

C1

15

5.5.

11D

11

65.

6.2

C1

17

5.10

.1 +

2.4.

10B

11

85.

5.6

C1

19

5.7.

3 +

2.5.

5D

11

105.

9.3

B1

1Se

ctio

n A

Tota

lSe

ctio

n A

Tota

l – 1

0 m

arks

26

210

11a

5.6.

7an

ode

2H

2 +

4O

H-

→ 4

H2O

+ 4

e- [1]

cath

ode

O2

+ 2

H2O

+ 4

e- →

4O

H-

[1]

22

2

b5.

6.7

2H2(g

) +

O2(g

) →

2H

2O(I)

[2

]2

22

c5.

6.8

adva

ntag

es:

rene

wab

le s

ourc

e of

ele

ctric

ity/d

oes

not

prod

uce

pollu

tion/

sile

nt [2

]2

2

Tota

lQ

uest

ion

11 to

tal

42

64

49

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

12a

5.9.

4di

pola

r ion

s [1

]st

rong

attr

actio

n be

twee

n op

posi

te c

harg

es [1

]2

2

b5.

9.5

2H2N

CH

(CH

2SeH

)CO

OH

+ N

a 2CO

3 →

2H2N

CH

(CH

2SeH

)CO

ON

a +

H2O

+ C

O2

[2]

22

2

c(i)

5.10

.1H

2N-C

H(C

H2S

eH)-

CO

-NH

-CH

(CH

2SeH

)-C

OO

H [

3]1

23

(ii)

5.9.

7in

duce

d fit

mec

hani

sm lo

wer

s ac

tivat

ion

ener

gy [1

]1

1(ii

i)5.

9.10

bell

shap

ed c

urve

and

labe

lled

axes

[2]

22

Tota

lQ

uest

ion

12 to

tal

46

102

13a

(i)1.

1.12

Zn +

2Fe

3+

2Fe

2+ +

Zn2+

[1]

11

1(ii

)5.

6.2

E⦵

= +

0.3

2V s

o re

actio

n sh

ould

pro

ceed

[1]

11

b(i)

5.3.

2M

nO4- +

5Fe

2+ +

8H

+ → M

n2+ +

4H

2O +

5Fe

3+ [1

]1

11

(ii)

5.3.

2m

oles

MnO

4- =

26.

0 x

10-3 x

0.0

2 =

0.52

x 1

0-3

mol

es F

e =

5 x

0.52

x 1

0-3 =

2.6

x 1

0-3 in

25c

m3

= 2.

6 x

10-2 in

250

cm3

mas

s Fe

= 2

.6 x

10-2

x 5

6 =

1.45

6 g

% F

e =

1.45

6 x

100

= 9

1%[4

]1.

60

erro

r − [1

]

44

4

(iii)

5.3.

2co

lour

less

to p

ink

[2]

22

Tota

lQ

uest

ion

13 to

tal

25

29

614

ai

5.7.

3nu

cleo

phili

c su

bstit

utio

n [1

]1

1ii

5.7.

3C

4H9B

r + N

H3 →

C4H

9NH

2 +

HB

r [1

]1

1iii

5.7.

3 +

2.5.

6 d+

d−

C –

Br

pol

aris

edd+

lone

pai

r on

N/N

H3 a

ttrac

ted

to C

C-N

bon

d fo

rmed

, C-B

r bon

d br

oken

[3]

33

bi

5.7.

3lit

hal

[1]

11

50

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

ii5.

7.3

C3H

7CN

+ 4

[H] →

C3H

7CH

2NH

2 [2

]2

22

c5.

7.4

C6H

5NO

2 + 6

[H]

→ C

6H5N

H2 +2

H2O

[2]

22

2d

i5.

7.6

less

bas

ic th

an th

e ot

hers

[1]

11

ii5.

7.5

C6H

5NH

2 +

HC

l →

C6H

5NH

3Cl-

[1]

11

iii5.

7.1

phen

ylet

hyl g

roup

atta

ched

to N

ato

m w

hich

has

two

hydr

ogen

s [1

]1

1

ei

5.7.

8C

6H5-N

+ ≡N

[2]

22

ii5.

7.8

sodi

um n

itrite

and

dilu

te h

ydro

chlo

ric a

cid

[1]

11

iii4.

7.8

5.7.

35.

9.5

2.6.

5

A H

Cl/H

2SO

4 or N

aOH

[

1]B

lit

hal

[1]

C

HN

O2/N

aNO

2 + H

Cl

[1

]D

P

Cl 5/H

Cl

[1]

1 1 1 1

4

Tota

lQ

uest

ion

14 to

tal

182

204

15a

5.5.

1tra

nsiti

on m

etal

ions

hav

e an

inco

mpl

ete

d sh

ell [

1]1

1b

i5.

5.11

VO

2+(a

q)

blu

e

[1]

V3+

(aq)

gre

en

[1]

22

ii5.

6.2

3VO

2+ + C

r + 6

H+ →

3V

O2+

+ C

r3+ +

3H

2O [2

]em

f = 1

.74

V [

1]3

33

ci

5.5.

9bl

ue

[1

]ye

llow

[1

] 2

2

ii5.

5.9

octa

hedr

al [

1]1

1iii

2.10

.2hy

droc

hlor

ic a

cid/

sodi

um c

hlor

ide

[1]

11

di

5.5.

7H

2N-C

H2-C

H2-N

H2

[1]

11

ii5.

5.7

two

coor

dina

te b

onds

/poi

nts

of a

ttach

men

t [1]

11

iii5.

5.7

[Ni(e

n)3]2+

[2

]2

2

+

51

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

ei

5.5.

3C

o(C

H3C

OO

) 2.4H

2O [

2]2

2ii

5.5.

6to

oxi

dise

cob

alt(I

I) to

cob

alt(I

II) [

2]2

2iii

5.5.

9oc

tahe

dral

[1]

11

iv5.

5.5

six

[1]

11

v2.

1.3

1 dm

3 of H

2O2 p

rodu

ces

20 d

m3 o

f oxy

gen

20/2

4 m

ole

of o

xyge

n =0

.833

i.e. 0

.833

mol

dm

-3

2:1

ratio

th

eref

ore

1.67

mol

dm

-3 [

3]

33

3

Tota

lQ

uest

ion

15 to

tal

912

223

616

a(i)

4.6.

1sa

me

mol

ecul

ar fo

rmul

a bu

t diff

eren

t stru

ctur

al

form

ula

[2]

22

(ii)

4.8.

6H

CO

OH

+ C

2H5O

H ⇆

HC

OO

C2H

5 + H

2O [2

]2

2(ii

i)2.

10.2

add

conc

. H2S

O4/m

etha

noic

aci

d/et

hano

l [1

]re

mov

e w

ater

[1]

22

b(i)

5.2.

2Te

tram

ethy

lsila

ne,

Si(C

H3) 4

[2]

22

(ii)

5.2.

65.

2.5

5.2.

4

Indi

cativ

e co

nten

t•

HC

OO

- s

ingl

et -

nex

t to

O•

CH

2 - q

uarte

t -

next

to 3

H•

CH

3 -

tripl

et -

nex

t to

2H•

ratio

1:2

:3•

area

und

er c

urve

is p

ropo

rtion

al to

the

num

ber o

fH

in e

ach

envi

ronm

ent

•gr

eate

st d

eshi

eldi

ng•

H n

ext t

o O

66

6

52

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

b(ii

)(c

ont.)

c5.

1.2

28

C2H

4+ or

CO

+ [1

]45

H

CO

O+

or C

2H5O

+ [1

]2

2

Ban

dR

espo

nse

Mar

k

A

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

fully

the

proc

ess

of n

mr (

usin

g a

min

imum

of

6 po

ints

of i

ndic

ativ

e co

nten

t). T

hey

use

good

spe

lling

, pun

ctua

tion

and

gram

mar

and

the

form

and

sty

le a

re

of a

n ex

celle

nt s

tand

ard.

[5]–

[6]

B

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

the

proc

ess

of n

mr (

usin

g a

min

imum

of

5 po

ints

of i

ndic

ativ

e co

nten

t). T

hey

use

good

spe

lling

, pun

ctua

tion

and

gram

mar

and

the

form

and

sty

le a

re

of a

goo

d st

anda

rd.

[3]–

[4]

C

Can

dida

tes

expl

ain

brie

fly a

nd

parti

ally

the

proc

ess

of n

mr (

usin

g a

min

imum

of 4

poi

nts

of in

dica

tive

cont

ent).

The

y us

e lim

ited

spel

ling,

pu

nctu

atio

n an

d gr

amm

ar a

nd

the

form

and

sty

le a

re o

f a b

asic

st

anda

rd.

[1]–

[2]

DR

espo

nse

not w

orth

y of

cre

dit.

[0]

53

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

d(i)

2.7.

1bo

nds

in m

olec

ules

vib

rate

abso

rb e

nerg

y of

a c

erta

in fr

eque

ncy

depe

nden

t on

the

atom

s m

ass

in th

e bo

nd-O

H a

bsor

ptio

n pe

ak fo

r pro

pano

ic a

cid

diffe

rent

pos

ition

s fo

r C=O

and

C=O

||

OH

O

[4

]

allo

w a

ny 4

from

the

abov

e 5

stat

emen

ts

22

41

(ii)

4.8.

5so

dium

car

bona

te[1

]ef

ferv

esce

nce

with

the

acid

[1

]2

2

Tota

lQ

uest

ion

16 to

tal

414

422

16

17a

5.11

.7C

7H6O

3 +

C4H

6O3

→

C

9H8O

4 +

C2H

4O2

[2]

22

b5.

11.7

aspi

rin is

not

ver

y so

lubl

e in

wat

er. [

1]1

1c

5.4.

1In

dica

tive

Con

tent

•TL

C p

late

, pen

cil l

ine,

mar

k 3

spot

s•

diss

olve

sm

all a

mou

nts

of ‘c

rude

’ asp

irin,

‘pur

ified

’ asp

irin

and

‘pur

e’(c

omm

erci

al) a

spiri

nin

sep

arat

e te

st tu

bes

in a

sui

tabl

e so

lven

t eg

etha

nol

•sp

ot e

ach

sam

ple

on to

the

TLC

pla

te•

plac

e in

dev

elop

ing

tank

with

a s

uita

ble

solv

ent

eg e

thyl

eth

anoa

te•

rem

ove

plat

e an

d m

ark

the

posi

tion

of s

olve

ntfro

nt•

use

UV

ligh

t or a

loca

ting

reag

ent

6

54

Que

stio

nSp

ecR

ef.

Mar

k Sc

hem

eA

O1

AO

2A

O3

Tota

lM

aths

QW

C

c(c

ont.)

66

d5.

4.3

cost

or v

olat

ility

[1]

11

Tota

lQ

uest

ion

17 to

tal

46

106

Pape

r Tot

al43

4918

110

2312

Ban

dR

espo

nse

Mar

k

A

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

fully

the

proc

ess

of T

LC (u

sing

a m

inim

um o

f 5

poin

ts o

f ind

icat

ive

cont

ent).

The

y us

e go

od s

pelli

ng, p

unct

uatio

n an

d gr

amm

ar a

nd th

e fo

rm a

nd s

tyle

are

of

an e

xcel

lent

sta

ndar

d.

[5]–

[6]

B

Can

dida

tes

mus

t use

app

ropr

iate

sp

ecia

list t

erm

s to

exp

lain

the

proc

ess

of T

LC (u

sing

a m

inim

um o

f 4 p

oint

s of

indi

cativ

e co

nten

t). T

hey

use

good

sp

ellin

g, p

unct

uatio

n an

d gr

amm

ar

and

the

form

and

sty

le a

re o

f a g

ood

stan

dard

.

[3]–

[4]

C

Can

dida

tes

expl

ain

brie

fly a

nd

parti

ally

the

proc

ess

of T

LC (u

sing

a

min

imum

of 3

poi

nts

of in

dica

tive

cont

ent).

The

y us

e lim

ited

spel

ling,

pu

nctu

atio

n an

d gr

amm

ar a

nd th

e fo

rm a

nd s

tyle

are

of a

bas

ic s

tand

ard.

[1]–

[2]

DR

espo

nse

not w

orth

y of

cre

dit.

[0]

55

56



Unit A2 3

57


58


GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) A2

Uni

t 3

Prac

tical

Boo

klet

A

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3Q

uest

ion

Tota

lM

aths

QW

C

1a

use

of s

tarti

ng v

alue

s to

one

dec

imal

pla

ce [1

]co

rrec

t cal

cula

tion

of a

vera

ge ti

tre [2

]ro

ugh

valu

e be

twee

n 23

.4 a

nd 2

5.2

[1]

accu

racy

of t

itrat

ion

valu

e +/

- 0.2

cm

3 of 2

3.2

cm3

slid

ing

scal

e fo

r [2]

66

2

bre

ad th

e bo

ttom

of t

he m

enis

cus

or a

llow

a m

etho

d ta

king

into

ac

coun

t the

col

our o

f the

pot

assi

um m

anga

nate

(VII)

[2]

22

cco

lour

less

to p

ink

[2]

22

Tota

lQ

uest

ion

1 To

tal

28

102

2a

gree

n [1

]1

1b

gree

n so

lutio

n [1

]1

1c

gree

n pr

ecip

itate

[1]

11

dgr

een

prec

ipita

te [1

]1

1e

whi

te p

reci

pita

te [1

]1

1f

no re

actio

n [1

]1

1g

iron(

II) s

ulfa

te [1

]1

1

Tota

lQ

uest

ion

2 To

tal

16

7

59

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3Q

uest

ion

Tota

lM

aths

QW

C

3a

the

com

paris

on o

f col

ours

wou

ld b

e m

ade

by p

laci

ng te

st tu

bes

of th

e so

lutio

ns s

ide

by s

ide

until

one

col

our e

xact

ly m

atch

ed

the

othe

r col

our i

n in

tens

ity/d

epth

[2]

expl

anat

ion/

desc

riptio

n of

how

the

5M s

olut

ion

wou

ld h

ave

to b

e ap

prop

riate

ly d

ilute

d w

ith th

e co

rrec

t use

of s

uita

ble

appa

ratu

s e.

g. m

easu

ring

cylin

ders

[2]

44

b2M

[1]

11

Tota

lQ

uest

ion

3 To

tal

14

54

aco

rrec

t lab

ellin

g of

sol

vent

fron

t and

sta

rting

poi

nt [1

]tw

o sp

ots

labe

lled

with

app

ropr

iate

siz

es a

t app

roxi

mat

ely

corr

ect p

lace

s [1

]so

lven

t fro

nt n

ear t

he to

p of

the

TLC

slid

e [1

]

12

3

btw

o su

bsta

nces

[1]

11

Tota

lQ

uest

ion

4 To

tal

13

45

ligan

d 1

is a

mm

onia

sol

utio

n lig

and

2 is

eth

ylen

e di

amin

e so

lutio

n lig

and

3 is

edt

a so

lutio

n al

l of t

he li

gand

s w

ill fo

rm a

bl

ue c

ompl

ex; l

igan

d 3

will

dis

plac

e lig

and

2 w

hich

will

dis

plac

e lig

and

1. I

n ea

ch c

ase

for a

pos

itive

resu

lt th

ere

shou

ld b

e an

ap

prop

riate

col

our c

hang

e. F

or a

neg

ativ

e re

sult

ther

e is

no

chan

ge b

ased

on

the

orig

inal

col

our o

f the

sol

utio

ns.

Hen

ce 3

po

sitiv

e re

sults

and

3 n

egat

ive

resu

lts;

-[1] f

or e

ach

inco

rrec

t res

ult [

4]

44

Tota

lQ

uest

ion

5 To

tal

44

Tota

l for

Boo

klet

A –

30

mar

ks3

225

302

60

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3Q

uest

ion

Tota

lM

aths

QW

C

1a

rete

ntio

n tim

e [1

]e.

g. d

etec

tor r

eadi

ng [1

]2

2

b4

[1]

11

15/2

8 x

100

= 53

.6%

22

2To

tal

Que

stio

n 1

Tota

l2

35

22

agr

een

[1] a

nd b

lue

[1] s

olid

s2

2b

iiro

n(II)

hyd

roxi

de [1

] gr

een

[1]

22

iiC

u(N

H3) 42+

[1]

deep

blu

e [1

]2

2

cad

d a

solu

tion

of b

ariu

m c

hlor

ide

[1]

whi

te p

reci

pita

te p

rodu

ced

[1]

22

Tota

lQ

uest

ion

2 To

tal

26

83

ait

form

s th

e hy

droc

hlor

ide/

salt

[1]

whi

ch is

ioni

c an

d th

us m

ore

solu

ble

[1]

22

bth

e ph

enyl

dia

zoni

um io

n [1

]is

uns

tabl

e at

hig

her t

empe

ratu

res

[1]

22

cio

dine

reac

ts w

ith th

e st

arch

[1]

to p

rodu

ce a

blu

e-bl

ack

colo

ur [1

]2

2

GC

E C

hem

istr

y A

sses

smen

t Grid

Ass

essm

ent O

bjec

tives

(AO

) A2

Uni

t 3

Prac

tical

The

ory

Boo

klet

B

61

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3Q

uest

ion

Tota

lM

aths

QW

C

dit

cont

ains

an

ioni

c gr

oup

[1]

whi

ch is

sol

vate

d by

wat

er [1

]th

e be

nzen

e rin

g is

onl

y a

rela

tivel

y sm

all p

art o

f the

stru

ctur

e [1

] an

y 2

from

3

22

etu

rn d

own

[1]

the

amou

nt o

f wat

er fl

owin

g th

roug

h th

e w

ater

pum

p [1

]2

2

fit

rem

oves

the

etha

noic

aci

d [1

]w

hich

has

a h

igh/

high

er b

oilin

g po

int/m

ore

diffi

cult

to e

vapo

rate

[1

]

22

g(s

eal)

a ca

pilla

ry tu

be a

t one

end

and

put

in s

ome

azo

com

poun

d [1

]pl

ace

in a

n oi

l bat

h/m

eltin

g po

int a

ppar

atus

[1]

heat

slo

wly

[1]

note

whe

n th

e so

lid s

tarts

to m

elt [

1]no

te w

hen

the

solid

sto

ps m

eltin

g [1

]

55

h5

g of

phe

nyla

min

e =

5/93

= 0

.054

mol

7 g

of n

apht

hol =

7/1

44 =

0.0

486

= 0.

049

mol

R

MM

of d

iazo

com

poun

d is

200

.5

0.04

9 m

ol =

0.0

49 x

200

.5 =

9.8

2g%

yie

ld =

3/9

.82

x 10

0 =

30.5

498

= 30

.5 d

epen

ding

on

the

num

bers

pre

sent

ed in

the

calc

ulat

ion

[5]

erro

r −[1

]de

cim

al p

lace

inco

rrec

t –[1

]us

e of

phe

nyla

min

e –[

1]

55

5

Tota

lQ

uest

ion

3 To

tal

67

922

5

62

Que

stio

nM

ark

Sche

me

AO

1A

O2

AO

3Q

uest

ion

Tota

lM

aths

QW

C

4a

ifla

sk c

onta

inin

g w

ater

+ n

itram

ide

[1]

poss

ible

mec

hani

sm fo

r add

ing

the

wat

er/n

itram

ide

[1]

mea

ns o

f col

lect

ing

the

nitro

us o

xide

[1]

poss

ible

wat

er b

ath

for c

onst

ant t

empe

ratu

re [1

]ex

plan

atio

n ho

w th

e ex

perim

ent i

s ca

rrie

d ou

t i.e

. mea

surin

g vo

lum

e pe

r uni

t tim

e [2

]to

a m

axim

um o

f 5 m

arks

55

iite

mpe

ratu

re [1

]1

1iii

e.g.

ther

e ar

e to

o m

any

bubb

les

to c

ount

/not

all

the

bubb

les

are

the

sam

e si

ze [1

]1

1

ivlo

ne p

air o

n th

e ni

troge

n (o

r oxy

gen)

[1]

form

s hy

drog

en b

onds

[1]

22

bi

the

poin

t at 1

500

seco

nds

[1]

the

volu

me

shou

ld b

e 16

.8 c

m3 [

1]1

12

1

ii11

.2/2

4000

= 0

.000

47 =

0.0

005

mol

of N

2O; h

ence

%

deco

mpo

sed

= 0.

0005

/0.0

5 x

100

= 1%

[3]

33

3

iii5

x 10

-6 m

ol d

m-3 s

-1 =

k x

0.5

mol

dm

-3

k =

10-5 [1

] s-1

[1]

22

2c

ist

ep o

ne in

volv

es th

e se

para

tion

of a

pos

itive

cha

rge

from

a

nega

tive

char

ge w

hich

take

s en

ergy

; a n

egat

ive

ion

prod

uced

fro

m a

neg

ativ

e io

n in

volv

es re

puls

ion.

Hen

ce s

tep

one

is ra

te

dete

rmin

ing

[2]

or n

itram

ide

is th

e on

ly re

acta

nt in

the

rate

equ

atio

n

22

iith

e re

activ

e in

term

edia

te is

NO

2NH

- [1]

11

iiith

e re

activ

e in

term

edia

te n

eeds

to b

e fo

rmed

in s

tep

1 [1

]th

en it

nee

ds to

be

used

up

in s

tep

2 [1

]2

2

di

heat

with

sod

ium

hyd

roxi

de s

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revised gce assessment objectives chemistry...15 25 33 47. gce chemistry . contents . introduction....

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