Review :Review :Surface Area Surface Area

Of Of Solids And NetsSolids And Nets

Problem 1 Surface Area

Storage Chest

You are painting a storage chest with the given dimensions. Find the surface area to be painted.

Problem 2 Finding the Surface Area of a Cylinder

Find the surface area of the canof sloppy joe sauce.

Problem 3

Find the surface area.

Problem 4

Find the surface area of the net.

Problem 5

Find the surface area of the net.

You want to paint a jewelry box You want to paint a jewelry box that is 13 inches by 4 inches by 5 that is 13 inches by 4 inches by 5 inches. The label on the bottle of inches. The label on the bottle of paint says the paint covers a paint says the paint covers a total area of 230 square inches. total area of 230 square inches. Do you have enough paint to Do you have enough paint to cover the entire box?cover the entire box?

Problem 6

Problem 1

SOLUTION

Using a Net to Find Surface Area

You can use a net to find the area of the toy chest as shown above.

Add the area of all the faces of the net.

The surface area of the storage chest is 2250 square inches.

Problem 2 Finding the Surface Area of a Cylinder

SOLUTION

The radius is one half the diameter, so r = 4 cm.

S = 2πr2+ 2πrh= 2π(4)2 + 2π(4)(10.7)≈ 369.264

Write formula for surface area.

Substitute 3.14 for π, 4 for r and 10.7 for h.

ANSWER

The surface area of the can is 369.264 square centimeters.

Problem 3

Find the surface area.

The area of each side face is 5 ft · 3 ft = 15 ft2

The area of the front and back faces is 3 ft · 12 ft = 36 ft2

The area of the bottom and top faces is 5 ft · 12 ft = 60 ft2

The surface area is 15 ft2 + 36 ft2 + 60 ft2 x 2 = 222 ft2

Problem 4

ANSWER

The area of each triangle is 6 m · 8 m = 24 m2

The area of the large rectangle is 10m · 14m = 140m2

The area of the small rectangle is 6 m · 14 m = 84 m2

The area of the middle rectangle is 8 m · 14 m = 112 m2

The total surface area is (2 · 24m2) + 140m2 + 84m2 + 112m2= 384 m2

12

Find the surface area of the net.

Problem 5

ANSWER

The area of each circular base is 82π = 200.96 in.2

The area of the rectangle is 20 in. · 16π in. = 1004.8 in2

The total area is 2 · 200.96 in.2 + 1004.8 in.2 = 1406.7 ft2

Find the surface area of the net

Find the surface area of the jewelry Find the surface area of the jewelry box and compare it to the area the box and compare it to the area the paint will cover.paint will cover.

Surface Area= (96 + 64 + 24) x 2 Surface Area= (96 + 64 + 24) x 2

The surface area of the box is 368 The surface area of the box is 368 square inches. You do have enough square inches. You do have enough paint.paint.

Problem 6