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Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

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Page 1: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Review Chapter 10: Theories of Bonding &

Structure

Chemistry: The Molecular Nature of Matter, 6th editionBy Jesperson, Brady, & Hyslop

Page 2: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

2

Chapter 10 Concepts

VESPR theory Predict molecular geometry & overall dipole moment

Valence Bond Theory Identify & draw hybridization of orbitals at central atom Predict molecular geometry & overall dipole moment Identify & draw σ and π bonds

Molecular Orbital Theory Draw MO Energy Diagrams to identify

Bond Order Number of Unpaired Electrons

Page 3: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Memorize

Linear

Trigonal Planaror

Planar Triangular

Tetrahedral

Trigonal Bipyramidal

Octahedral

Page 4: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Memorize

Trigonal Pyramidal

Bent

Seesaw orDistorted

Tetrahedron

T-shaped

SquarePyramid

SquarePlanar

Page 5: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Determining 3-D VESPR Stuctures

1. Draw Lewis Structure of Molecule– Don't need to compute formal charge– If several resonance structures exist, pick only one

2. Count electron pair domains– Lone pairs and bond pairs around central atom– Multiple bonds count as one set (or one effective pair)

3. Arrange electron pair domains to minimize repulsions• Lone pairs

– Require more space than bonding pairs– May slightly distort bond angles from those predicted.– In trigonal bipyramid lone pairs are equatorial – In octahedron lone pairs are axial

4. Name molecular structure by position of atoms—only bonding electrons

Page 6: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Polarity

If symmetrical polar bonds around a central atom then they cancel and there is no overall dipole moment.

Molecule is usually polar if – All atoms attached to central atom are NOT same, OR– There are one or more lone pairs on central atom

EXCEPT:

Page 7: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Valence Bond TheoryValence Bond Theory

Individual atoms, each have their own orbitals and orbitals overlap to form bonds. Extent of overlap of atomic orbitals is related to bond strength

Hybridization = mixing atomic orbitals

sp: Linear

sp2: Planar Triangular

sp3: Tetrahedral

sp3d: Trigonal Bipyramidal

sp3d2: Octahedral

Page 8: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Valence Bond Theory1) Draw lewis dot structure

2) How many lone pairs & bonded atoms will repel one another? That is the number of hybrid orbitals needed

2: sp 3: sp2 4: sp3 5: sp3d6: sp3d2

3) Convert the needed number of atomic orbitals into hybridized orbitals.

4) Fill in valence electrons. Remember that any p orbitals will be close enough in energy that they both hybrid & remaining p orbitals will fill half way with electrons before they pair.

5) Draw hybrid orbitals equally spaced around the central atom:a) Form σ bonds using hybrid orbitals with one electronb) Hybrid orbitals with two electrons are likely lone pairsc) If any lone electrons are in p orbitals π bonds will form

6) Describe molecular geometry around central atom(s).

Page 9: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Valence Bond Theory: Example N2

:NN:

Es

p p

sp

• Lone pair and atom bonded to Nitrogen will repel each other.

• Therefore, need to hybridize 2 orbitals• One hybrid orbital with one electron

will participate in a σ bond with the other nitrogen

• The other hybrid orbital contains a lone pair

• 2 p orbitals each have 1 electron so form 2 π bonds to the other nitrogen

AO of NHybrid & AO of N

Page 10: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Molecular Orbital TheoryMolecular Orbital Theory

Views molecule as collection of positively charged nuclei having a set of molecular orbitals that are filled with electrons (similar to filling atomic orbitals with electrons).

Doesn't worry about how atoms come together to form molecule

Page 11: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Molecular Orbital Theory

Li2 N2 2p Lower in energy than 2p

O2, F2 and Higher 2p Lower in energy than 2p

Can ignore filled 1s bonding & antibonding and focus on valence electrons

Page 12: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

Molecular Orbital Theory: Diagrams

E

s

p

AO of one atom AO of second atom

π

π*

σ

σ*

σ

σ*

Page 13: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

13

ProblemSet A

1. For the following molecules: a. Draw a lewis dot structure.b. Determine the molecular geometry at each central atom.c. Identify the bond angles.d. Identify all polar bonds: δ+ / δ-e. Assess the polarity of the molecule & indicate the overall

dipole moment if one exists

AsF5 AsF3 SeO2

GaH3

ICl2- SiO4-4

TeF6

Page 14: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

14

ProblemSet B

2. What is the hybridization of oxygen in OCl2? 3. For the species and XeF4O, determine the following:

a. electron domain geometry (geometry including non-bonding pairs)

b. molecular geometryc. Hybridization around central atomd. Polarity

4. How many and bonds are there in CH2CHCHCH2, and what is the hybridization around the carbon atoms?

5. Draw & list the bonding orbitals for HCN.

Page 15: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

15

ProblemSet C

6. What is the MO Energy Diagram for B2? How many unpaired electrons does B2 have?

7. What is the bond order & number of unpaired electrons in

8. Draw the MO Energy Diagram for BN.

Page 16: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

16

ProblemSet A

Page 17: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

17

ProblemSet A

Page 18: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

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ProblemSet A

Page 19: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

19

ProblemSet B

2. sp3

3. XeF4O: octahedral, square pyramid, sp3d2, polar

4. 9, 2, sp2

5. HCN: C will be create a σ bond to H and N with sp2 hybridized orbitals and use 2 p orbitals to participate in 2 π bonds with N. N will participate in the σ bond with C with an sp2 hybridized orbital, the other will hold the N lone pair, and then N will use 2 p orbitals to π bond with C.

Page 20: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

20

ProblemSet C

6. MO B2: unpaired e- = 2

7. O2: BO = 2 unpaired e- = 2O2

+: BO = 5/2 unpaired e- = 1O2

- : BO = 3/2 unpaired e- = 1

8. MO BN:

π

π*

σ

σ*

σ

σ*

π

π*

σ

σ*

σ

σ*

BNB2

Page 21: Review Chapter 10: Theories of Bonding & Structure Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop

More Practice Problems:

Analyze the following compounds: 1. Draw the lewis dot structure2. Determine the Geometry using VESPR theory3. Determine the hybridization at any central atoms using VB Theory4. Draw & Describe bonding in VB terms: ie # of sigma vs pi bonds

H2S

SO2

H2C=C=CH2

HCOCl