reminder: angel quiz 8 due on thur 10/20 - pennsylvania ...courses.chem.psu.edu/chem110fall/lecture...
TRANSCRIPT
Jensen Chem 110 Chap 10 Page: 1
Week 8: Lectures 22 – 24
Lecture 22: W 10/12
Lecture 23: F 10/14
(Special lecture by Dr. Ben Lear)
Lecture 24: M 10/17
Reading:
BLB Ch 10.1 – 10.9
Homework:
BLB 10: 23, 30, 45, 5, 71, 75, 82, 83, 84;
Supp 10: 1 – 15
Reminder:
No Angel Quiz on Thur 10/13
ALEKS Objective 8 due on Tue 10/18 Angel Quiz 8 due on Thur 10/20
Jensen Office Hour: 501 Chemistry Building
Thursday 10/13: cancelled
Tuesday 10/18: 10:30 – 11:30 am
Jensen Chem 110 Chap 10 Page: 2
Gas Molecules’ Characteristics
! Gas molecules are constantly moving
expand in whatever volume is available
mix completely with one another
! They are far apart (10 times as far as they are big)
can be easily compressed
! They move in straight lines
! They collide with each other
! They collide with walls: pressure
! Higher temperature yields faster motion
! Lower temperature yields slower motion and
eventually condensation
Gases are described in terms of: pressure (P),
temperature (T), volume (V), # moles (n)
All gases behave similarly at low pressure
Gases will mix in all proportions with other gases to
form homogeneous mixtures
Jensen Chem 110 Chap 10 Page: 3
Pressure
• Pressure: force per unit area
Force: Kg•m•s–2
, or Newton (N); Unit area: m2
• SI unit for pressure: 1 N•m–2
= 1 Pa (Pascal)
• Standard Atmospheric Pressure**:
1 atm = 1.013 x 105 Pa
1 atm = 760 torr (or mm Hg)
[1 atm = 14.7 lb/in2]
Jensen Chem 110 Chap 10 Page: 4
Measuring Pressure
Barometer used to measure Patm
The key idea is balance force on area
Patm " height (h) of column of liquid
Measure P in terms of height of Hg
1 atm = 760 torr “=” 760 mm Hg
[know this conversion!]
Patm PHg
Patm = PHg
dl= density of liquid (here: Hg)
g = gravitational constant
Patm = constant x h
Patm = Fatm/A
PHg = Fl/A = gdlh
so,
Jensen Chem 110 Chap 10 Page: 5
Mercury Manometer
Used to measure the difference in pressure
between open or closed end and that of a gas
in a vessel.
Closed Ended: Pg = h (mm Hg)
Open Ended: Which P is greater?
Pgas = Patm __ Ph Pgas = Patm __ Ph
Jensen Chem 110 Chap 10 Page: 6
Example: The height of the column of
mercury in the open-ended manometer shown is found to be 65 mm. If the external
pressure is 1.06 atm, what is the gas
pressure inside the bulb?
A. 0.85 atm
B. 0.97 atm
C. 1.15 atm
D. 1.71 atm
E. The pressure cannot be
determined from the information given.
Jensen Chem 110 Chap 10 Page: 7
Understanding Gases
State of gas is described by:
• n = moles of gas
• P = pressure
• V = volume of container
• T = (absolute) temperature (K = °C + 273.15)
STP: standard temperature & pressure
(T = 273.15 K; P = 1 atm)
Three foundational relationships:
! Boyle!s Law (P and V)
! Charles! Law (V and T)
! Avogadro!s Law (V and moles)
Combining these three to one equation
The ideal Gas Law (P, V, T, and moles):
P V = n R T
Jensen Chem 110 Chap 10 Page: 8
! Boyle’s Law (volume & pressure)
V of a fixed amount of gas at constant T is inversely
proportional to P
V " 1/P or
PV = constant
(T,n fixed)
! Charle’s Law (volume & temperature)
V of fixed amount of gas at constant P is
proportional to the absolute temperature
V " T or
V/T = constant
(P,n fixed)
Note: T in absolute
temperature (K)!
K = °C + 273.15
V 1/2V
Jensen Chem 110 Chap 10 Page: 9
! Avogadro’s Law (volume & moles)
V of gas at constant T and P is proportional to the
number of moles of gas:
V " n or
V/n = constant
(P,T fixed)
So far: V ! 1/P (Boyle!s law)
V ! T (Charles!s law)
V ! n (Avogadro!s law)
Combining these three to one equation:
Units of R (gas constant) are very important!
Ideal Gas Law: P V = n R T
V
n
Jensen Chem 110 Chap 10 Page: 10
Using Ideal Gas Law: P V = n R T
! Given 3 quantities, solve for the 4th
Example: What is the volume occupied by
1 mol of gas at exactly 0°C and 1atm (STP)?
Jensen Chem 110 Chap 10 Page: 11
Practice Example: How many molecules
comprise one breath of air with a volume of 2.5 L at body temperature (37 ºC) and a
pressure of 750 mm Hg?
A. 5.8 x 1022 B. 4.4 x 1025
C. 6.2 x 1024
D. 6.7 x 1022
E. 6.0 x 1023
Jensen Chem 110 Chap 10 Page: 12
! Changes in P, V, T
Given: initial conditions of Pi, Vi, Ti
final conditions of any two quantities
Find: Value for the third final value
Example: A sample of gas at 25 °C and
1.0 atm in a 2.5 L vessel is allowed to
expand until the pressure is 0.85 atm and
the temperature is 15 °C. What is the final
volume of the gas?
Jensen Chem 110 Chap 10 Page: 13
Practice Example: At 27 °C and 1.00 atm, a sample of He gas (2.35 mol) occupies 57.9 L.
What is the volume of this sample at 150 °C
and 1.00 atm?
A. 0.709 L
B. 1.41 L
C. 41.1 L
D. 57.9 L
E. 81.6 L
Jensen Chem 110 Chap 10 Page: 14
Summary: Ideal Gas Law PV = nRT
At STP (What T and P? _________________),
1mol of any gas has molar volume VSTP = _____ L.
Jensen Chem 110 Chap 10 Page: 15
Application of the Ideal Gas Law:
Density and Molar Mass
Ideal Gas Law: P V = n R T
Jensen Chem 110 Chap 10 Page: 16
Density and Molar Mass
At the same T and P, density is
_______________ to molar mass.
Example: Which of these gases has a density of 3.42 g/L at 30°C and 1.2 atm?
A. He
B. Cl2
C. F2
D. Kr
E. Xe
Jensen Chem 110 Chap 10 Page: 17
Practice Example: What is the density of
ammonia (NH3) gas in a 4.32 L container at 837 torr and 45 °C?
A. 3.86 g/L
B. 0.717 g/L C. 0.432 g/L
D. 0.194 g/L
E. 4.22 x 10–2 g/L
Jensen Chem 110 Chap 10 Page: 18
Gas Mixtures: Partial and Total Pressure
Partial pressure: the pressure a gas would
have if it was the only gas in the container
Dalton!s law of partial pressures:
total pressure of the gas mixture is equal
to the sum of partial pressures
Mole fraction: dimensionless & must sum to 1
Partial pressure:
Jensen Chem 110 Chap 10 Page: 19
Example: 3.0 L of He at 5.0 atm and 25°C
is combined with 4.5 L of Ne at 2.0 atm and 25°C at constant T into a 10L vessel. What
is the partial pressure of the He in the 10L
vessel?
What is the total pressure in the 10 L
vessel?
Jensen Chem 110 Chap 10 Page: 20
Practice Example: What is the partial
pressure of O2 in the vessel below?
Ptot = 756 torr Gas Mole fraction
T = 300.0 °C Ar 0.320
VTOT=5.00 L N2 0.270
CO2 0.150
Ne 0.160
O2 ?
A. 75.6 torr
B. 242 torr
C. 380 torr
D. 680 torr E. 756 torr
How many moles of CO2 are in this vessel?
Jensen Chem 110 Chap 10 Page: 21
Collecting gases over water
Ptotal = Pgas + PH2O
barometric pressure vapor pressure
If you know the barometric pressure, you can
determine the partial pressure of gas by using
the vapor pressure of H2O (Appendix B, Pvap of
H2O)
Jensen Chem 110 Chap 10 Page: 22
Example: A student collected 201 mL of H2
over water at 27 oC and a barometric pressure of 733 torr. The vapor pressure of
water at 27 oC is 26.74 torr. How many
grams of H2 were collected?
A. 20.0 g
B. 1.80 x 10!2 g
C. 130 g
D. 8.61 x 10!3 g E. 1.52 x 10!2 g
Jensen Chem 110 Chap 10 Page: 23
Kinetic Molecular Theory (KMT)
KMT explains why gases behave the way they do;
look at gases on a molecular level
The 5 key postulates of KMT
1. Molecules move in straight lines; but their
directions are ____________.
2. Molecules are small (The volume they occupy is
small compared to the total volume) – they have
_______ volume.
3. There are _______ intermolecular forces
(molecules do not attract or repel each other).
4. Molecules experience elastic collisions
5. Mean kinetic energy # " T (in K)
Jensen Chem 110 Chap 10 Page: 24
Temperature and Molecular Speed
# = average kinetic energy of molecule
u = average (root mean square) speed of molecule
m = mass of molecule (in kg)
" Distribution of molecular speeds: Some
molecules move more slowly; some move faster.
" When T increases, less molecules move
_________, more molecules move __________, so
the average molecular speed _______________.
Jensen Chem 110 Chap 10 Page: 25
KMT explains the behaviors of ideal gases
• At constant n and V; P increases as T increases.
T increases, # __________ , u ___________;
more collisions per unit time & harder collisions
so P increases
• At constant n and T, P decreases as V increases.
Constant T means constant # & u.
longer distances between collisions & fewer
collisions per unit time with walls
so P decreases (Boyle!s Law)
Jensen Chem 110 Chap 10 Page: 26
Average Molecular Speed, Molar Mass, and
Temperature
" At the same T, different gases have ________ average kinetic energy (#).
" At the same T, different gases have _________
average speeds (u)
" At a given temperature, the _______ a gas is, the
________ its average molecular speed will be.
Jensen Chem 110 Chap 10 Page: 27
Average Molecular Speed and Molar Mass
Example: What is the average speed of O2 at
20 °C? Note: use R = 8.314J/(mol•K) and M in
kg/mol.
Jensen Chem 110 Chap 10 Page: 28
Practice Example: All three gas containers
below have V = 1 L and T = 25 °C. Which of the following statements is/are true?
1. The average molecular speed is the same
in all three samples.
2. The pressure is the same for all three samples.
3. The average molecular kinetic energy is
the same in all three samples.
A. 1 only
B. 2 only
C. 3 only D. 1 and 2
E. 2 and 3
Jensen Chem 110 Chap 10 Page: 29
Other Properties of Gases
• Effusion: leakage of gas
through a small opening
• Diffusion: spread of gas
through space or second
substance.
Rate of effusion (or diffusion) " 1
M
Usually we compare the effusion (or diffusion)
rate of two gases:
Graham!s law:
$ Heavy molecules effuse (diffuse) more
slowly than lighter molecules
Jensen Chem 110 Chap 10 Page: 30
Effusion Rate and Molar Mass
Example: An unknown gas effuses at a rate of 0.112 times H2 gas at 25 °C. What is the molar
mass of the gas?
Jensen Chem 110 Chap 10 Page: 31
Practice Example: A sample of N2 gas (2.0 mmol) effused through a pinhole in 5.5 s. How long will it take for the same amount of CH4 to effuse under the same conditions?
A. 7.3 s B. 5.5 s C. 3.1 s D. 4.2 s E. 9.6 s
Jensen Chem 110 Chap 10 Page: 32
Collisions and Diffusion
" At STP molecules collide ~1010
times per
second. N2 speed = 500 m/s
but…
in 1 s it collides 1010
times
" This means that although molecular speeds
are high at STP, molecules don’t go very far
net distance traveled << (speed x time)
" Mean free path (MFP): distance between
collisions.
MFP is ~6x10
-8 m at 1 atm for air molecules
What happens to the MFP as density and P
decrease?