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REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

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Page 1: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

REFLECTED IMPEDANCE & POWEREQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMERLecture No. 11

By. Sajid Hussain Qazi

Page 2: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

REFLECTED IMPEDANCE

In the previous section we found that,

Dividing the first by the second, we have

Page 3: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

REFLECTED IMPEDANCE

However, since

Then,

The above equation states that the impedance of the primary circuit of an ideal transformer is the transformation ratio squared times the impedance of the load.

Equation-1

Page 4: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

REFLECTED IMPEDANCE

If a transformer is used, therefore, an impedance can be made to appear larger or smaller at the primary by placing it in the secondary of a step-down (a > 1) or step-up (a < 1) transformer, respectively.

Note that if the load is capacitive or inductive, the reflected impedance will also be capacitive or inductive.

Page 5: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

Power of Transformer

For the ideal iron-core transformer,

Page 6: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

Example:-

For the iron-core transformer of Figure shown

a. Find the magnitude of the

current in the primary and the

impressed voltage across the primary.

b. Find the input resistance of

the transformer.

Page 7: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

Example:-

Page 8: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

EQUIVALENT RESISTANCE, REACTANCE

If we now reflect the secondary circuit through the ideal transformer using Eq. (1), as shown in Figure below, we will have the load and generator voltage in the same continuous circuit.

Page 9: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

EQUIVALENT RESISTANCE, REACTANCE

The total resistance and inductive reactance of the primary circuit are determined by,

which result in the useful equivalent circuit of Figure shown.

Page 10: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

EQUIVALENT RESISTANCE, REACTANCE

The load voltage can be obtained directly from the circuit of Figure shown above through the voltage divider rule:

Equation-2

Page 11: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

Phasor Diagram of Transformer

The figure shown above will also allow us to calculate the generator voltage necessary to establish a particular load voltage.

The voltages across the elements of above figure have the phasor relationship indicated in Figure below...

Page 12: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

Phasor Diagram of Transformer

For an inductive load, the phasor diagram appears below, note that aVL leads I by the power-factor angle of the load.

Page 13: REFLECTED IMPEDANCE & POWER EQUIVALENT RESISTANCE, REACTANCE & PHASOR DIAGRAM OF TRANSFORMER Lecture No. 11 By. Sajid Hussain Qazi

Phasor Diagram of Transformer

The effect of Re and Xe on the

magnitude of Vg for a particular VL is

obvious from Eq. (2).

For increased values of Re or Xe, an

increase in Vg is required for the

same load voltage.

For Re and Xe=0, VL and Vg are

simply related by the turns ratio.