rare metals volume 27 issue 1 2008 [doi 10.1016%2fs1001-0521%2808%2960032-7] zhu, h -- damage and...
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-. A?
ELSFMER
?-cienceDirect
RARE
METALS,
Vol.
27, No.
I
Feb 2008,
p .
64
Damage and fracture mechanism of
6063
aluminum alloy under three kinds of
stress states
ZHU Hao, ZHU Liang,
and
CHEN
Jianhong
Key Laboratory of the Ministry of Educution of China or Nonferrous Metal Alloys, Lanzhou University of Technology, Lunzhou
7300S0
hina
Received 20 September
2006;
received in revised
form 5
Decem ber 2006; accepted
10
December 2006
Abstract
To study the damage and fracture mechanism of 6063 luminum alloy under different stress states, three kinds of re presentative triaxial stress
states have been adopted, namely smooth tensile, notch tensile, and pure shear. The results of the study indicate the following. During the
notch tensile test, a relatively higher stress triaxiality appears in the root of the no tch. With the applied load ing increasing, the volume frac-
tion of microv oids in the
root
of the notch increase s continuously. When it reach es the critical volume fraction
of
microvoids, the specimen
fractures. During the pure shea r test, the stress triaxiality almost equals to zero, and there is almo st no microvoids but a shear band a t the cen-
ter of the butterfly specimen.
The
shear band results from nonuniform deformation constantly under the shear stress. With stress concentra-
tion, cracks are produced w ithin the she ar band and
are
later coalesced. When the e quivalent plastic strain reaches the critical value (equiva-
lent plastic fracture strain), the butterfly specimen fractures. During the sm ooth tensile test, the stress triaxiality in the gau ge of the sp ecime n
remains constant at
0.33. Thus,
the volume of microvoids of the smooth tensile test is less than that
of the
notch tensile test and the smooth
specimen fractures due to shearing between m icrovoids. The G-T-N damage model and Johnson-Cook model are
used
to simulate the notch
tensile and shear test, resp ectively. The simulated engineering stress-strain curves fit the measu red engineering stress-strain curves very we ll.
In add ition, the emp irical dama ge evolution equation for the notch spec imen is obtained from the experimental data and F EM simulations.
Keywords: 6063 aluminum alloy; damage mechanism; fracture mechanism; G-T-N model; Johnson-Cook model
1. Introduction
Aluminum alloys are increasingly applied to produce
automobiles, since they are capable of reducing the mass of
vehicles, fuel consum ption, and environmen tal pollution. An
important quality for vehicles is crashworthiness [I] . During
the impacting process of
an
automobile, the stress state at
each part in its components is different. Moreover, the stress
state at each part changes with passing time. Different stress
states result in different damage and fracture forms. There
are
several reports
on
ductile damage and ductile fracture.
Ductile fracture (based on initiation, growth, and coales-
cence of voids) and shear fracture (based on shear band lo-
cahzation) are primary two kinds of fracture forms for duc-
tile materials [2-41. El-Magd
et
al
[ 5 ]
studied the d eforma-
tion and dam age behaviors of AA7075 alum inum alloy un-
der two loadings and found that deformation localization
and shear band caused the damage in AA7075 aluminum
alloy under compression loading and under tensile loadmg,
AA7075 aluminum alloy failed due to nucleation, growth,
Corresponding
author: ZHU
Hao
E-mail:
and coalescence of m icrovoids. Smerd et al. [6] found that
the damage forms of AA5754 and
AA5
182 aluminum alloys
were microvoids and fracture due to shea r amongst the mi-
crovoids through high strain rate tensile testing of automo -
tive aluminum alloy sheets. The damage forms of 606 3 alu-
minum alloy under crushmg loading change with the
changing of stress state. Thus, any o ne damage m odel can-
not adequately describe the dam age and deformation forms
of 6063 aluminum alloy and there are also few reports on
the damage and fracture of 6 063 aluminum alloy. This arti
cle studies the damage and fracture mechanism of 6063
aluminum alloy under three kinds of
stress
states. At the
same time, the G-T-N model and Johnson-cook model are
used to simulate the damage behaviors of notch tensile and
pure shear, respectively.
2. Experimental
The experimental material was 6063 T5) extruded alu-
minum alloy and its microstructure is shown in Fig. 1,
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Zhu H. et
aL,
Damage and fracture mechanism
of
6063 aluminum alloy under three kinds
of
stress states
65
which shows that the size of grains varied greatly, with the
maximum reaching 100 Fm, while the minimum was only
several microns. Its chemical composition was given in
wt.% as follows: Mg, 0.45-0.9; Si, 0.2-0.6; Zn, Cr, Ti and
Mn
< 0.1;
and Fe
< 0.35.
For the notch tensile test, dou-
ble-side notch specimens were used. Tensile direction was
parallel to the direction
of
extrusion. The shapes and dimen-
sions of smooth tensile specimens and the notch tensile
specimen are shown in Fig. 2. For the pure shear test, the
butterfly specimens and modified Arcan fixture were used
and their shapes and dimensions are shown in Fig.
3.
The
schematic diagram of the pure test using modified Arcan
fixture is shown in Fig. 4.
Fig.
1.
Microstructure of 6063 extru sion aluminum alloy.
L
Fig.
2.
Shapes and dimensions of a smooth tensile specimen a)
and a notch tensile specim en h).
The tests were performed on the smooth, notch, and but-
terfly specimens by the universal test machine with a cross
head speed of
0.5
mm/min at room temperature. The yield
stress, work hardening coefficient, and work hardening ex-
ponent were measured by the engineer stress-strain curve of
the smooth tensile test. The power-law hardening relation-
ship was used for
ABAQUS
calculations as material
Fig. 3. Butterfly specime n a) and modified Arcan fiitu re
b)
for the shear test.
Pure shear test
I
Fig. 4. Schem atic diagram
of
the pure test.
property.
3. Results and discussion
3.1.
Analysis of experimental curves
The engineer stress-stain curves of three kinds of experi-
ments are shown in Fig. 5. The yield stress ny=195.4 MPa
was drawn from the engineer stress-strain curve of the s-
mooth tensile test. The work hardening coefficient and work
hardening exponent were 281.8 and 0.07, respectively,
which were drawn from the true stress-strain curve
of
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RARE METALS, Vol.27 No.
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Feb 2008
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f
- 200
smooth tensile test.
Fig. 5 shows that the fracture strain of the smooth tensile
test is larger than that of the notch tensile test, and the yield
stress and peak stress of the smooth tensile test are less than
those of the notch tensile test. Those can be explained by Fig.
6,
which shows the stress triaxiality distribution curves of
three kinds of tests. The stress triaxiality of smooth tensile
keeps always 0.33, but the maximal stress aiaxiality of
notch tensile can be up to 0.515. The relatively larger stress
triaxiality makes the specimen s deformation difficult and
more stress is needed to reach the same strain. Therefore, the
larger stress triaxiality has a higher fracture driving force,
which results in the fracture of the specimen at a lower strain.
Thus, the fracture strain of notch tensile test is less than that
of
smooth tensile specimen [2,
71.
Fig. 6 also shows that the
stress triaxiality of the pure test is close to 0.1 (because it is
difficult to get the pure shear state in experiment). The frac-
ture strain of the pure shear test is far bigger than that of the
smooth tensile test.
3.2.
Metallographic
results
and discussion
To
study the damage mechanism, the specimens of the
smooth tensile, notch tensile, and shear tests were loaded
and then unloaded when the strain designated was reached.
The unloaded specimens were cut at the center along the
vertical planes parallel to the direction of applied load and
mounted and then polished on 180-grit paper. All the pol-
ishing was done by wet polishing papers to prevent particles
from extraction from the soft aluminum matrix. The metal-
lographic pictures are shown in Fig. 7,
n
t 1 5 0
a
.
m
Notch tensile
0
Smooth tensile
,,i it -A-
Pure shear ~
1-7
7 0
.0 0.2 0.4
0.6 0.8
1 0
E J Y ,
Fig. 5. Stress-strain curves of the tests.
otch tensile
- - - - .
mooth tensile
0.2
Pure shear
0.1
0.0 0.5
1.0
1.5 2.0 2.5 3.0
Path along central section
of
specimen / nm
Fig. 6. Curves of stress triaxiality distribution.
Fig. 7. Metallographic pictures
of
unloaded specimens: a) particle and void damage in a smooth tensile specimen with an unload-
ing strain of 0.1; b) particle and void damage in a notch tensile specimen with
an
unloading strain of0.09, c) shear band crack in a
pure shear specimen with an unloading strain of 1.05.
Fig. 7(a) shows the unloaded metallographic pictures of a
smooth tensile specimen, from which it can be seen that
there are a few microvoids in the smooth tensile specimen
and the volume of microvoids is relatively small. This is
because the stress triaxiality amongst the smooth tensile
specimen
is
relatively small and the driving force of voids
growing is normal stress. The higher the normal stress is, the
higher the stress triaxiality is, the more rapidly the voids
grow and the bigger the volume of voids. Fig. 7(b) shows
the unloaded metallographic picture of a notch tensile
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Zhu
H . etal.
Damage and fracture mechanism of 6063 aluminum alloy under three kinds of stress states
67
specimen, which shows that there are a lot of microvoids
amongst the unloaded notch specimen and the volume of
microvoids is bigger than that of the smooth tensile speci-
men. This is because the stress triaxiality amongst the notch
tensile specimen is higher than that amongst the smooth ten-
sile specimen. At the same time, the microvoids have started
to coalesce and then microcracks are produced due to coa-
lescence of microvoids. With coalescence of microcracks,
the notch specimen fractures. Fig. 7(c) shows that there is a
shear deformation band in the unloaded shear specimen and
the shear deformation band is a result from plastic deforma-
tion localization. Since the stress triaxiality amongst the pure
specimen is close to 0.1 and the less the stress triaxiality, the
larger the shear stress. The driving force of materials defor-
mation is the shear stress and the higher the shear stress, the
more easily the materials deform. At the same time, there is
a crack in the shear deformation band and the crack was
produced due to deformation incompatibility. With the
cracks extending and coalescence, the butterfly specimen
fractures.
Fig. 8 shows the typical fracture surfaces of smooth ten-
sile, notch tensile, and pure shear specimens, from which it
can be seen that the features of fracture surfaces of the s-
mooth tensile specimen, notch tensile specimen, and shear
specimen are obviously different. Figs. 8(a) and 8(b) show
the fracture surfaces of the smooth tensile specimen and Fig.
8(a) is the macroscopical fracture surface, which shows that
the macroscopical fracture surface
is
relatively smooth and
there is no obvious change in the direction of width and
thickness. It is revealed that the smooth specimen did not
neck before fracture. Therefore, the stress triaxiality of the
smooth tensile specimen can always remain constant. Fig.
8(b) shows the magnified fracture surface, where there are a
lot of dimples and also the volume of dimples
is
relatively
small. At the same time, the direction of the dimples is not
perpendicular to the direction of tensile loading. Therefore,
it can be concluded that the fracture mode of the smooth
tensile specimen is the voids shearing mechanism, which is
the combination of dimpled fracture and shear fracture. Figs.
8(c) and 8(d) show the fracture surfaces of the notch tensile
specimen and Fig. 8(c) shows its macroscopical fracture
surface, which shows that there is obvious change in the di-
rection of width and thickness for the notch tensile specimen
due to necking before fracture. Therefore, the maximum
Fig. 8. Fracture surfaces of three kinds of tests: a,
b)
fracture surfaces of the smooth tensile test; c, d) fracture surfaces o f the
notch tensile test; e, f) fracture surfaces of the shear test.
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RARE METALS, Vol. 27, No. 1 Feb 2008
stress triaxiality amongst the notch specimen can be up to
0.515. At the same time, it also can be seen that the macro-
scopical fracture surface takes on a cup-cone shape. It is
because the stress triaxiality along the path of m inimum
transverse area is different, as shown in Fig. 6 and the stress
triaxiality can reach the maximum value of 0.515 at the cen-
ter of the specimen. Therefore, the fracture mechanism is
voids-coalescence fracture at the center of the specimen,
while the fracture mechanism is shearing fracture on the
surface of the specimen and the parts close to it. Fig.
8 d)
shows the magnified fracture surface, which show s several
dimples on the fracture surfaces of the notch tensile spec i-
men and the dimples are the produce of microvoids. The d i-
rection of dimples is perpendicu lar to the direction of tensile
loading and the volume of dimples is bigger than that of the
smooth tensile specimen. In a word, for ductile materials,
the material instability starts with the forming of a necking.
It is followed by the initiation of fracture at the cente r of the
necking with linkage of adjacent voids due to hydrostatic
stress. The coalescence of voids usually forms a zig-zag
configuration and this is perpendicular to the loading direc-
tion. Figs. 8(e) and
8 f)
show the fracture surfaces of the
shear specimen and Fig. 8(e) is its macroscopical fracture
surface, which shows that the m acroscopical fracture surface
is very flat and smooth. Fig.
8 f)
shows the magnified frac-
ture surface, where there are typical snaky slipping and
ripple waves on the shear fracture surfaces and the direc-
tion of shear fracture surfaces is parallel to that of the
maximum shear stress. Under the shear stress, the micro-
voids are elongated and form the parabola or half-ellipse
dimples on the fracture surfaces [2-31. Therefore, it
is
re-
vealed that the fracture mechanism is shear fracture.
4. Finite element simulations
The G-T-N model [7-81 was used to give a numerical
description of the notch tensile test. The yield flow function
is
where Q is the macroscopical Mises equivalent stress,
P
is the macroscopical hydrostatic stress,
R 3 )
s the yield
stress of the undamaged matrix material,
41, qa
and
q3
are
modulation parameters considering the interaction of voids,
and
f *
is the volume fraction of voids revised.
In the notch tensile test, the parameters of the G-T-N
model flow function are set as the following.
ql
= 1.25, q 2 =
1
O
q3 = 1.625;
fo
nitial volume fraction of v oids, = 0.0025;
fc
volume fraction of voids at coalescence, = 0.035; &,
volume fraction of voids at fracture, = 0.0475;
n
volume
fraction of voids forming particles, = 0.02;
EN,
medium
strain for voids formation,
=
0.3;
SN,
standard deviation,
=
0.1.
The Johnson-Cook model [9- 1 ] was used to simulate the
pure shear test. T he Johnson-Cook constitutive relation and
fracture strain relation are as follows.
The constitutive relation:
r = A+
B E )
1
+
C l n E ) [ 1- T ) ]
EO
The fracture strain relation:
Ef = [
D l + D 2 e x p
D3-
) ] ( l + i ) D 4 ( l + D 5 T * )
3)
Here, T
=
T - ,
)
T m
-
T ) is the strain rate, gois
the reference strain rate,
T ,
is the reference temperature,
T , is the melt temperature, s the hydrostatic stress,
6 , s the e quivalent stress.
A ,
B ,
C , n m
l ,
D2
3, D4.
and
D5
re materials constants.
In the Johnson-Cook model: A = 176.45 MPa,
B
= 63.99
MPa, n = 0.07, = 0.0036, m = 0, D l 0.07413, 02 =
0.0892,
D3
-2.441, 0 4
=
-4.76, and
Ds 0.
Simulated re-
sults by ABAQUS are shown in Fig. 9.
Fig. 9(a) shows that the engineering stress-strain curves
of simulation with the G-T-N model is close to the m easured
engineering stress-strain curve of the notch tensile. It proves
that the G-T-N model can be used to simulate the damage
behavior of the notch tensile test. The engineering
stress-strain curve of simulation without adopting the G-T-N
damage mod el overestimates the stress of the notch tensile
test. Fig. 9(b) shows that the Johnson-Cook model can be
used to sim ulate the shear test. Fig. 9(c) shows the curve of
voids growth versus time by simulating the notch tensile test.
As can be seen in Fig. 9(c), voids grow stably before A, and
the curve produces fluctuation from A to B, indicating that
certain voids start to coalesce. During the process of growth,
several voids start to coalesce after
B,
so it results in fracture
of the specimen. The following em pirical dama ge evolution
equation in the root of the notch specimen is obtained from
the experimental data on void volume fraction and the cor-
responding local equivalent plastic strain and stress triaxial-
ity computed from FEM simulations:
(4)
where a b, and c are empirical constant whose values de-
pend on the alloys composition, heat treatment, and micro-
structure. Eq. (4) is only applied
to
6063 (T5) Al-alloy. In
this
experiments,
a =
-0.35, b
=
0.25, and
c =
1.32.
f =
a
+
bln(Z,,)
+c
Bm
6,
5.
Conclusions
(1) The damage mechanism and fracture mechanism are
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Zhu H. eta/. Damage and fracture mechanism of 6063 aluminum alloy under three kinds of stress states
69
J;=0.035
T
m Experiment
00
.
b
0 Without damage model
-V-
Curson model
0.00 0.02 0.04 0.06 0.08
Ec
F
>
I60
120
f:
80
eU
2
0 Experiment
0 Johnson-Cook model
0.030
1'
0.020
0.0 10
0.000
0.000 0.002 0.004 0.006
/oalescence
0.020 -
.....................................................uleation Gowh
0.0 10
-
0.000
0.000 0.002 0.004 0.006
Time / s
Fig. 9. Simulation
r sults
of FEM: a) notch tensile simula-
tion;
b)
shear simulation; c) VVFG void volume fraction due
to growth) versus time of notch tensile.
obviously different for smooth tensile, notch tensile, and
pure shear. In the smooth tensile test, the specimen fractures
due to shearing between microvoids. In the notch tensile test ,
the specimen fractures due to microvoid-coalescence. In the
pure test, the shear deformation band is produced at the cen-
ter of the butterfly specimen and the cracks are produced
and later coalesced in the shear band and result in fracture
of
the specimen.
(2) The
G-T-N
damage model and Johnson-Cook model
can be used to simulate the notch tensile test and pure shear
test, respectively.
3)The empirical damage evolution equation
in
the notch
specimen of 6063 (T5) Al-alloy is obtained:
f
=-0.35+0.251nFp+1.32 8,/o,).
This equation is only applied to 6063 T5)aluminum alloy.
Acknowledgement
'I
esearch is financially supported by the Ministry of
Science and Technology
of
China (No. 2004CCA04900).
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